iii) He studied characters that were manifested as

two opposite traits.

iv) He took seven characters with contrasting traits.

1. Physical bases of inheritance is 10. True breeding line is one that have undergone
(1) Gene (2) DNA continuous
(3) Protein (4) None of these (1) cross pollination and shows stable trait
over successive generations
2. Genetics is the branch of Biology that deals with (2) self-pollination and shows stable trait over
(1) Inheritance of characters from one generation to successive generations
offspring’s (3) artificial pollination and shows stable trait in
(2) variations of characters from one generation to alternating generations
offspring’s (4) None of these.
PRINCIPLES OF INHERITANCE AND VARIATIONS
(3) Both land 2 11. Which is a wrong set of characters used in Mendel's
(4) None of these hybridization experiment
Character Dominant trait Recessive trait
3. Extent by which a progeny differs from the parents is
a) Seed colour green yellow
called
b) Flower colour violet white
(1) Inheritance (2) Selection
c) Pod shape full constricted
(3) Variation (4) Heredity
d) Flower position axial terminal
4. Passing of characters from one generation to other is (1) None of these (2) A
known as (3) C (4)D
(1) Variation (2) Selection
(3) Recombination (4) Inheritance 12. How many pod characters were taken in Mendel's
experiment
5. Sahiwal is a species of (1) one (2) two
(1) Pea plant (2) Chick pea (3) zero (4)three
(3) Cow (4) Horse
13. How many flower characters were taken in Mendel's
6. Sahiwal cows are found in experiment
(1) Punjab (2) U.P
(3) Assam (4) Rajasthan (1) one (2) two
(3) zero (4)three
7. Gregor Mendel conducted hybridization experiments
14. Which of the following was not the contrasting
on which of the following recessive trait in the Mendel's experiment
(1) Pisum sativum (2) Chick pea (1) dwarf plant (2) green seed colour
(3) Insects (4) Dog plant (2) yellow pod colour (4) axial flower

8. For how many years G. Mendel performed 15. Emasculation is

hybridization experiments (1) deletion of Y chromosome in male
(1) 5 years (2) 3 years (2) absence of male characters
(3) 7 years (4) 10 years (3) removal of anthers
(4) removal of stigma
9. Which of the following is incorrect
i) Mendel's experiment’s had a small sampling size,
which gave greater credibility to his data.
ii) Confirmation of his inferences from experiments
on successive generations of his test plant
proved that his results points to a general rule of 16. F1 generation stands for
inheritance. (1) Final1 progeny (2) Filial1 progeny
(3) Functional1 progeny (4) none of these

17. In Mendel's experiment the study of inheritance of

one gene (cross between tall and dwarf plant)
showed
(1) 50% tall and 50% dwarf plants in FI progeny
 (2) 75% tall and 25% dwarf plants in FI progeny 28. In monohybrid cross (TTxtt) the FI and F2 generation
(3) All dwarf plants each have hew many small squares in Punnett
(4) All all plants square
(1) 4 in FI and 16 in F2
18. In monohybrid cross performed by Mendel (2) 4 in FI and 8 in F2
emasculation was performed on (3) 4 each in FI and F2
(1) female plants (4) 2 in FI and 4 in F2
(2) male plants
29. In a monohybrid cross (TTxtt) recessive parent
(3) both plants
(4) none of the plant of parent generation character is expressed in
(1) FI generation
19. Purpose of doing emasculation was
(2) F2 generation
(1) to perform only cross pollination between the
(3) Both FI and F2 generation
parent generation
(2) to perform only self-pollination between the parent (4) Sometimes in FI sometimes in F2
generation
30. Self-pollination of F2 generation dwarf plants
(3) to store the pollen of female plants
(4) none of these produced by a monohybrid cross (Tt x tt)
(1) produced only dwarf plants (homozygous) in F3
20. In the monohybrid cross (TTxtt) the blending of and F4 generation
contrasting trait was seen at (2) produced only dwarf plants (heterozygous) in F3
(1) FI generation and F4 generation
(2) F2 generation (3) This concluded that genotype of dwarf in F2 was
(3) In both FI and F2 generation heterozygous
(4) Neither FI nor F2 generation (4) a and c are true

21. According to Mendel ’'factors" which are stably passed 31. To determine the genotype of tall plant of F2
down unchanged from parent to offspring is through generation Mendel performed
(1) Gametes
(1) back cross (2) reciprocalcross
(2) Somatic cells
(3) Emasculation (5) test cross (4) dihybridcross
(4) Asexual reproduction
32. Test cross of F2 generation tall plants produced 50%
22. Genes which code for a pair of contrasting traits are tall and 50% dwarf plants. The genotype of F2
known as generation tall plant would be
(1) Factors (2) Alleles (1) Tt (2) tt
(3) Hybrids (4) None of these (3) TT (4) Dd
23. Which will be the dominant phenotype of F2
33. Test cross of F2 generation tall plants produced 50%
generation of a monohybrid cross (TTxtt)
(1) Tall (2) TT tall and 50% dwarf plants. The tall plants thus
(3) Tt and TT (4) None of these produced will be
(1) homozygous
24. The allelic pair of genes which are identical are known (2) heterozygous
as
(3) 50% homozygous 50% heterozygous
(1) Homozygous (2) Heterozygous
(3) Dominant (4) Recessive

25. Cross between genes controlling a single character of

same generation is known as
(1) Test cross (2) Dihybrid cross
(3) Monohybrid cross (4) back cross

26. Gametes are produced by the process of

(1) Asexual reproduction (2) Meiosis
(3) Mitosis (4) Binary fission

27. R.C. Punnett was of which nationality

(1) German (2) American
(3) British (4) Russian
 41. Phenotype ratio of a monohybrid cross in case of
(4) 75% homozygous 25% heterozygous Incomplete dominance in F2 generation will be
(1) 1:3 (2) 3:1
34. Organism showing dominant phenotype (2) 2:2 (4) 1:2:1
(heterozygous) is crossed with the recessive
parent it will produce 42. The monohybrid cross of red and white flowers in
(1) 25% dominant and 75 % recessive snapdragon plant produced flowers of how many
offspring’s colors in F2 generation
(1) three, red , white and orange
(2) 50% dominant and 50 % recessive offspring’s
(2) two red and white
(3) 75% dominant and 75 % recessive
(3) three, red, white and pink
offspring’s
(4) all red
(4) all dominant offspring
43. Human blood group AB is an example of
35. In a test cross between dominant F2 and (1) Law of dominance
recessive parent showed all flowers of dominant
(2) Law of incomplete dominance
character The dominant phenotype of F2
(3) Law of independent assortment
generation is
(4) None of these
(1) Heterozygous
(2) Homozygous 44. In codominance the FI generation resembles
(3) Showing incomplete dominance (1) Dominant parent
(4) None of these (2) Recessive parent
(3) Shows in between character of both parents
36. Statement incorrect for law of dominance (4) None of these
(1) Characters are controlled by factors.
(2) Factors occurs in pair and if contrasting then 45. The blood group is controlled by
one are will dominate and other is recessive. (1) Gene A (2) Gene B
(3) This law is used to explain the expression of (2) Gene O (4) Gene I
both parental characters in monohybrid cross
(TTxtt), which is in 3:1 ratio in FI and F2 46. How many alleles are there for blood group
generation. determining genes
(4) The genotype shown in F2 is 1:2:1 (1) 2 (2) 4
(3) 3 (4) None of the above
37. Appearance of the parental recessive character
also in F2 generation after a monohybrid cross 47. Which molecule are present on RBC which are
(TT x tt) is explained by important for blood group determination in human
(1) law of dominance (1) Protein (2) Sugar
(2) law of incomplete dominance (3) Lipid (4) All of these
(3) codominance 48. If IA and lo are the alleles present in a person
(4) none of these which blood group is expressed
(1) B (2) A
(3) 0 (4) AB
38. Law of incomplete dominance was done in
(1) Garden pea (2) Chick pea 49. If offspring have IA and IB both the alleles for
(1) Dog (4) Dog plant blood group the blood group will be
(1) A (2) B
39. Snap dragon is the common name of
(2) O (4) AB
(1) Antirrhinum sp.
(2) Drosophila melanogaster
50. How many phenotypes of blood groups generated
(3) Piper betel
due to three alleles of gene for expressing sugar
(4) Crataeva nurvala
on RBC in a population

40. When in a monohybrid cross the FI does not (1) 3 (2) 6

match to any of the parent and shows character (3) 4 (4) None of these
in between the two this is
(1) law of dominance
(2) Codominance
(3) Law of segregation

(4) Law of incomplete dominance

51. How many genotype of human blood group are
possible in population due to three alleles
(1) 4 (2) 3
(3) 6 (4) None ofthese

52. If parents have O and AB blood group their children

can have the possibility of having which blood group.
(1) Only A
(2) Only B
(3) Only AB
(4) Can be of either A or B blood group

53. Blood group is a good example of

(1) Incomplete dominance
(2) Multiple allelism.
(3) Four alleles
(4) Reciprocal cross

54. State which of the following is not true

a) Dominance is an autonomous feature of a gene or
the product
b) A single gene product may produce only one
effect
c) Blood group AB is an example of codominance
d) More than two alleles exist in a population for a
single gene
(1) a (2) a and c
(2) b and d (4) a and b

55. In a dihybrid cross gametes will have

(1) Two alleles of the same character
(2) One allele only
(3) Four alleles of two characters
(4) Two alleles of two different characters

56. The phenotype ratio of F2 for a single character used

in dihybrid will be
(1) 15:1 (2) 9:3:3:1
(3) 3:1 (4) 1:2:1

57. What is the genotype ratio of dihybrid cross

(RRYYxrryy)
(1) 1:2:2:4:1:2:1:2M (2) 1:1:1:1
(3) 1:2:1 (4) 9:7

58. In a dihybrid cross the genotype : phenotype ratio of F2 generation is

(1) 3:1 (2) 1:2:1
(3) 9:4 (4) 16:4
(c) Recombination (d) Dihybrid cross
59. In dihybrid cross (RRYYxrryy) the pure dominant
species in genotype will be 62. F2 generation of dihybrid cross (RRYYxrryy) shows
(1) Two offspring (2) 9 offspring which genotype offspring in maximum number
(3) 12 offerings (4) None of the above (1) pure recessive
(2) pure dominant
60. In dihybrid cross (RRYYxrryy) the ratio of pure (3) pure hybrid dominant
dominant species: pure recessive species in F 2 (4) pure recessive dominant
generation genotype will be
(1) 3:1 (2) 1:2 63. How many types of gametes can be formed by a plant
(3) 1:1 (4) None of these with AaBb genotype
(1) two (2) one
(3) four (4) six

64. Mendels work was published in the year

61. For Law of independent assortment cross used was
(1) 1863 (2) 1865
(a) Monohybrid cross (b) Trihybrid cross
 (3) 1890 (4) 1902 (3) Fruit fly (4) Chick pea

65. Mendel's work was not recognized because 75. Advantages of having D. melanogaster in Morgan’s
(1) Communication was not easy at that time experiment
(2) Concept of genes as unit of inheritance was not i. Short life cycle
well established. ii. Single mating produces many offspring
(3) Chemical nature of genes was not provided by iii. Sex can be distinguished easily
Mendel iv. hereditary variations can be seen by low power
(4) All of these microscopes
(1) only i, ii and iv are true
66. meiosis is (2) only ii, iii and iv are true
(1) equivalent division (3) only i, ii and iii are true
(2) non-equivalent division (4) all are true
(3) reduction division
(4) 2 and 3 both
76. In his experiment Morgan used female flies with
(1) brown bodied, red eyed
67. Knowledge about which process helped in better (2) yellow bodied, white eyed
understanding of Mendel's law in 1900 (3) brown bodied, white eyed
(1) cell elongation (2) cell division (4) yellow bodied, red eyed
(3) cell adhesion (4) all the above
68. Two alleles are gene pairs located at 77. Morgan performed which type of cross for
(1) homologous site on homologous chromosomes verification of chromosomal theory of inheritance
(2) heterologous site on homologous chromosome (1) monohybrid cross (2) dihybrid cross
(3) both 1 and 2 (2) test cross (4) trihybrid cross
(4) none of these
78. The phenotype ratio of F2 generation of Morgan's cross
69. Movement of chromosome is in parallel to the in D. melanogaster was
movement of genes this was observed by
(1 ) 1:2:1
(1) T.H. Morgan (2) W.sutton
(2) 1:2:1:2:2:4:1:2:1
(2) 6.J. Mendel (4) Hugo de Vries (3) 9:3:3:1
(4) Significantly deviated from 9:33:1
70. Scientists who was not involved in the rediscovery of
mendels results on the inheritance of characters 79. The deviation in phenotypic ratio in Morgan's dihybrid
(1) De Vries (2) T.Boveri cross was attributed to
(3) Correns (4) Von Tshermak (1) Aneuploidy
(2) Disease in experimental fruit fly
71. What is not true about germ cells produced during
meiosis

(3) Mutation
(4) Linkage

(1) They are haploid 80. Initial experiments for sex determination were
(2) Chromosome segregate dependently on each pair performed in
of chromosomes during meiosis (1) garden pea (2) dog plant
(3) They are four in number (3) human (4) insects
(4) During the process of meiosis gametes are
produced 81. Which statement is true for Henking’s experiment for
sex determination
72. What is true about Chromosomal theory of Inheritance i. The experiments were performed during 1891
(1) It was given by W.sutton and T. Bovery ii. He traced specific cytological structure during the
(2) It is based on Mendel's law and chromosomal process of spermatogenesis
iii. Experiment was performed on insects.
segregation during meiosis
iv. He observed that 25% of the sperms received a
(3) Cell division knowledge was helpful in postulating
particular factor which he named X body.
the law
v. Significance of X body was explained by other
(4) All of these scientists later.

73. Chromosomal Theory of inheritance was verified by (1) All are true
(1) Von Tshermak (2) T.H Morgan (2) Only I ,ii, iii, and v are true
(3) G.J. Mendel (4) Carl Correns (3) Only I ,iii, iv, and v are true
(4) None of these
74. Experimental organism used by T.H. Morgan was
(1) Garden Pea (2) Snap dragon 82. In large number of insects sex determination is of which
 type
(1) XY (2) WZ
(2) XO (4) WO

83. In XO type sex: determination male and female have

(1) Equal number of chromosomes
(2) Females have one more chromosome
(3) Males have on more chromosome
(4) Females have two extra chromosomes

84. In insects eggs have

(1) Autosomes +1 chromosome
(2) Autosomes + 2 chromosome
(3) Autosomes only
(4) None of these

85. When insects having X chromosome in Male sperm

fertilizes the egg it produces
(1) Male with X chromosome
(2) Female with XX chromosome
(3) Female with one less chromosome
(4) None of these

86. Insects produces how many types of sperms

(1) One type each with X chromosome
(2) Two types 50% with X and 50% with Y
chromosome
(3) Two types 50% with W and 50% with Z
chromosome
(4) None of these
 iii. Each pair have one chromosome from each
parent
iv. Males are homogametic while females are
heterogametic
87. Homogametic sex chromosomes are present in (1) All are true (2) i, ii, iv are true
females of (3) i, ii, iii are true (4) i, iii, iv are true
(1) Human and birds
(2) Humans and D. melanogaster 96. Which of the following is responsible for alteration
(3) Birds and insects in DNA sequences
(4) None of these (1) Monohybrid cross (2) replication
(3) mutation (4) none of these
88. Male birds are
(1) Heterogametic 97. Alteration in chromosome is achieved by
(2) Homogametic (1) insertion of a segment of DNA
(3) Contains ZW chromosomes (2) deletion of a segment of DNA
(4) Both a and c are correct (3) duplication of a segment of DNA
(4) all of these
89. Female birds contains
(1) ZZ chromosomes (2) XX chromosomes 98. Example of point mutation is
(2) XO chromosomes (4) None of these (1) Malaria (2) Sickle cell anemia
(2) Typhoid (4) None of these
90. Male heterogamety is not found in
(1) Homo sapiens 99. Which of the following is a mutagen
(2) Galus galus domesticus (1) UV radiation
(3) D. melanogaster (2) Polyaromatic hydrocarbon
(4) Insects (3) Reactive oxygen species
(4) All of these
91. How many statement is incorrect for Sex determination
in human 100. Which statement is true for pedigree analysis
i. XY type
(1) This was made for studying the inheritance pattern
ii. Male possess one Y chromosome and one X
of traits in human
chromosome
(2) Control crosses were not possible in human so
iii. Males have some gametes with X chromosome
inheritance pattern study from family history was
and some with Y chromosome
studied
iv. This is an example of male homogamety
(3) Analysis of Inheritance of particular trait in several
(1) i, ii and iii (2) i and iv
generations of family is called Pedigree analysis
(2) ii and iii (4) ii and iv
(4) All of these

92. Female heterogamety is present in 101. Which statement is not true for Mendelian disorders
(1) Drosophila melanogaster (1) Determined by alteration in single gene.
(2) Homo sapiens (2) The pattern of inheritance is traced by Punnett
(3) Gallus gallus domesticus square analysis
(4) None of these (3) Hemophilia and sickle cell anemia are sex linked
93. What determines the sex of the child recessive Mendelian disorder
(1) chromosome present in mother (4) These disorders may be dominant or recessive
(2) Nutrition of the mother during pregnancy
(3) Genetic makeup of the egg which is fertilized 102. Which statement is true for X linked recessive trait
(4) Genetic makeup of the sperm which fertilizes the (1) shows inheritance from carrier female to male
egg progeny
(2) Hemophilia is an example of this type of
94. In birds with female heterogamety what determines the inheritance
male sex of the offspring (3) Hemophilia is a disorder in which person’s blood
(1) Chromosome present in sperm which fertilizes the clotting ability is hampered
egg (4) All are true
(2) Chromosome present in egg which is fertilized by
the sperm
(3) Temperature of body at the time of fertilization
(4) All of these 103. An example of autosomal dominant trait is
(1) Myotonic dystrophy (2) Hemophilia
(3) Sickle cell anemia (4) none of these

104. Family pedigree of Queen Victoria shows inheritance

95. State which statement is true. Humans have I. 46 of which disease
chromosomes (1) Hemophilia
ii. 22 pair are autosomes and one pair sex (2) Sickle cell anemia
chromosomes (3) Phenylketonuria
 (4) Thalassemia (3) abnormal arrangement of one or more chromosome
(4) all of these
105. In sickle cell anemia if the code for valine is GUG then
what would have been the code of coding DNA strand 114. During cell division, failure of segregation of chromatids
of the m RNA results in
(1) CTC (2) CUC (1) aneuploidy (2) aploidy
(2) GAG (4) None of these (3) haploidy (4) none of these
106. HbS peptide for sickle cell anemia have alteration
at which amino acid of the beta globin chain 115. Which of the following is an aneuploid
1) Sickle cell anaemia
(1) 4 (2) 7
2) Hemophilia
(3) 6 (4) None of these
3) Down’s syndrome
4) Phenylketonuria
107. In Sickle cell anemia Glutamate is changed to
(1) Alanine (2) Glycine
116. Failure of cytokinesis results in
(2) Lysine (4) Valine
(1) Aneuploidy (2) Aploidy
(3) Polyploidy (4) None of these
108. The template strand sequence of DNA of Sickle cell
anemia having valine (amino acid code GUG) in place 117. Which of the following is incorrect for Down's syndrome
of glutamate will be i. It is an example of Trisomy
(1) CTC (2) GAG ii. There is an additional one chromosome at
(2) GUG (4) None of these chromosome 18
iii. The affected individual is short statured with small
109. The insertion of which base in the template strand DNA round head, wowed tongue and partially open
for glutamate causes sickle cell anemia mouth
(1) Adenine in place of thymine iv. Physical, and mental development is retarded
(2) Thymine in place of Adenine (1) iv (2) i
(3) Guanine in place of Thymine (3) ii (4) iii
(4) None of these
118. Trisomy is
110. X linked recessive disorder i. Additional copy of one chromosome is present in a
(1) Transfers character from male parent to male child pair
(2) Female carriers to male child ii. It’s a type of chromosomal disorder
(3) Female carriers to female child iii. It is due to failure of cytokinesis
(4) Both 2 and 3 iv. The chromatids are not able to segregate
during cell division and results in trisomy
111. Autosome linked recessive trait v. Down's syndrome is a good example
i. It is transferred when both the parents are carrier of
the gene i.e. heterozygous 1) All are true 2) i, ii, iii, iv are true
ii. Only the homozygous offspring for recessive alleles 3) i, ii, iv and v are true 4) i, iii, iv, v are true
show the diseased phenotype
iii. Hemophilia is an example of this genetic disorder
iv. It is transferred from heterozygous mother to the
male child only
(1) All are true (2) i, iii are not true
(3) i, ii, iv are true (4) i and ii are true

112. Phenylketonuria
i. Inborn error of metabolism
ii. It is an autosomal recessive genetic disorder
iii. Affected individual converts phenyl alanine to
phenyl pyruvic add and other derivatives
iv. It causes mental retardation
(1) All are true 2) i, iii, iv are true
(3) ii, iii, iv are true 4) i, ii, iv are true

113. Chromosomal disorders are caused due to

(1) addition of one or more chromosome
(2) deletion of one or more chromosome
 6. Person having genotype IA IB would show the
119. Which of the following statement is true for blood group as AB. This is because of:
Klinefelter's syndrome with XXY karyotype a. Pleiotropy
(1) One extra Y chromosome in females 23 pair b. Co-dominance
sex chromosome c. Segregation
(2) One extra Y chromosome in 21 pair of
autosome in male d. Incomplete dominance
(3) Such individual have overall feminine 7. Z Z / ZW type of sex determination is seen in:
development and some masculine a. Platypus b. Snails
development is also expressed. They are
sterile c. Cockroach d. Peacock
(4) One extra X chromosome in males 23 pair sex 8. A Across between two tall plants resulted in
chromosome offspring having few dwarf plants. What would be
the genotypes of both-the parents?
120. Turners syndrome is due to a. TTandTt b. TtandTt
(1) Aneuploidy (2) Monosomy
c. TTandTT d. Ttandtt
(2) Karyotype 22+ XO (4) All are true
9. In a dihybrid cross, if you get 9:3:3:1 ratio it
121. Turner's syndrome Is shown in denotes that:
(1) only females a. The allels of two genes are interacting with
(2) Only males each other
(3) Both male and female
(4) Total 47 chromosomes are present b. It is a multigenic inheritance
c. It is a case of multiple allelism
Exemplar Questions d. The allels of two genes are segregating
independently.
1. All genes located on the same chromosome: 10. Which of the following will not result in variations
a. Form different groups depending upon their among siblings?
relative distance
b. Form one linkage group a. Independent assortment of genes
c. Will not from any linkage groups b. Crossing over
d. Form interactive groups that affect the
phenotype c. Linkage
d. Mutation
2. Conditions of a karyotype 2n ± 1 and 2n ± 2 are
called: 11. Mendel's Law of independent assortment holds
a. Aneuploidy b. Polyploidy good for genes situated on the:
c. Allopolyploidy d. Monosomy a. non-homologous chromosomes
b. homologous chromosomes
3. Distance between the genes and percentage of
recombination shows:
c. extra nuclear genetic element
a. a direct relationship
b. an inverse relationship d. same chromosome
c. a parallel relationship
d. no relationship 12. Occasionally, a single gene may express more
than one effect. The phenomenon is called:
4. If a genetic disease is transferred from a
a. multiple allelism
phenotypically normal but carrier female to only
some of the male progeny, the disease is: b. mosaicism

a. Autosomal dominant c. pleiotropy

b. Autosomal recessive d. polygeny
c. Sex-linked dominant 13. In a certain taxon of insects some have 17
chromosomes and the others have 18
d. Sex-linked recessive
chromosomes. The 17 and 18 chromosome-
bearing organisms are:
5. In sickle cell anemia glutamic acid is replaced by
valine. Which one of the following triplets codes a. males and females, respectively
for valine? b. females and males, respectively
c. all males
d. all females
a. GGG b. AAG
c. GAA d. GUG 14. The inheritance pattern of a gene over generations
 among humans is studied by the pedigree a. phenotypes - 4; genotypes -16
analysis. Character studied in the pedigree b. phenotypes - 9; genotypes - 4
analysis is equivalent to: c. phenotypes - 4; genotypes - 8
a. quantitative trait
d. phenotypes - 4; genotypes – 9
b. Mendelian trait
c. polygenic trait 18. Mother and father of a person with 'O' blood group
have 'A' and 'B' blood group respectively. What
d. maternal trait would be the genotype of both mother and father?
a. Mother is homozygous for 'A' blood group and
15. It is said that Mendel proposed that the factor father is heterozygous for 'B'
controlling any character is discrete and b. Mother is heterozygous for 'A' blood group
independent. This proposition was based on the: and father is homozygous for 'B'
a. Results of F3 generation of a cross. c. Both mother and father are heterozygous for
b. Observations that the offspring of a cross 'A' and 'B' blood group, respectively
made between the plants having two
d. Both mother and father are homozygous for
contrasting characters shows only one
‘A’ and ‘B’ blood group, respectively
character without any blending.
c. self-pollination of F, offspring
d. cross pollination of parental generations

16. Two genes 'A' and 'B' are linked. In a dihybrid

cross involving these two genes, the F3 heterozygote is
crossed with homozygous recessive parental type (aa
bb). What would be the ratio of offspring in the next
generation?
a. 1:1:1:1 b. 9: 3:3:1
c. 3:1 d. 1:1

17. In the F2 generation of a Mendelian dihybrid cross

the number of phenotypes and genotypes are: