Positive Feedback
 When input and feedback signal both are in same phase, It is
  called a positive feedback.
 Positive feedback is used in analog and digital systems.
 A primary use of +ve feedback is in the production of oscillators.
                 +         Vi
           Vs      Σ               A(f)                    Vo
                  +
                           Vf   SelectiveNetwork
                                     β(f)
                                                   Vo    A
 Vo = AVi = A(Vs + V f ) and V f = βVo
                                                      =
                                                   Vs 1 − Aβ
      Barkhausen Criterion: for oscillator βA=1 and +ve feedback
                                                                   2
 Oscillator Circuit
  Oscillator is an electronic circuit which converts dc signal into ac
   signal.
  Oscillator is basically a positive feedback amplifier with unity loop
   gain.
  For an inverting amplifier- feedback network provides a phase shift
   of 180°° while for non-inverting amplifier- feedback network provides
   a phase shift of 0°° to get positive feedback .
       Vo    A              If βA=1 then Vo = ∞ ;
          =                                                 Very high output with zero input.
       Vs 1 − Aβ
Use positive feedback through frequency-selective feedback network to ensure sustained oscillation at ω0
Use of Oscillator Circuits
  Clock input for CPU, DSP chips …
  Local oscillator for radio receivers, mobile receivers, etc
  As a signal generators in the lab
  Clock input for analog-digital and digital-analog converters                                        3
Oscillators
  If the feedback signal is not
   positive and gain is less than
   unity, oscillations dampen out.
  If the gain is higher than unity
   then oscillation saturates.
Type of Oscillators
Oscillators can be categorized according to the types of feedback
network used:
 RC Oscillators: Phase shift and Wien Bridge Oscillators
 LC Oscillators: Colpitt and Hartley Oscillators
 Crystal Oscillators                                               4
RC Oscillators
          R                       −1  XC
Vo = (          )Vin   and   φ = tan ( )
       R − jX c                       R
   Φ =0o if Xc=0 and Φ =90o if R=0
  However adjusting R to zero is impractical because it would lead
   to no voltage across R, thus in a RC circuit, phase shift is always
   ≤ 90o and it is a function of frequency.
  Hence to get 180o phase shift from the feedback network, we
   need 3 RC circuits.
  RC oscillators build by using inverting amplifier and 3 RC
   circuits is known as phase shift oscillator.
                                                                    5
    RC Oscillators: Phase shift Oscillator
    Use of       an   inverting                      Rf
     amplifier.
                                        R1
    The    additional   180o                     −            C      C   C
     phase shift is provided
     by an RC ladder network.                     +
                                                                      R   R   R
     It can be used for very
     low     frequencies and
     provides good frequency
     stability.
         A phase shift of 180°° is obtained at a frequency f, given by
                                               1
                                      f =
                                            2πCR 6
                                                           vo     1
                                                              =−
         At this frequency the gain of the network is      vi    29
                                                                              6
 RC Oscillators: Phase shift Oscillator
 At node V2
                          I3
V2 = Vo + I 3 X c = Vo +
                         jwC
             V
 But I 3 = o
              R
                  1
 V2 = Vo (1 +          )
               jω CR
            V V V             1             Vo      1
 I 2 = I 3 + 2 = o + o (1 +      )     I 2 = (2 +      )
             R R R          jωCR            R     jωCR
   At node V1                I2              3    1
                  V1 = V2 +      = Vo (1 +     − 2 2 2)
                            jω C           jωcR ω C R
                                                           7
RC Oscillators: Phase shift Oscillator
            I2              3    1
 V1 = V2 +      = Vo (1 +     − 2 2 2)
           jω C           jωcR ω C R
              V1 V0      4    1
    I1 = I 2 + = ( 3 +     − 2 2 2)
              R R      jωcR ω C R
            I1              6     5       1
 Vi = V1 +      = Vo (1 +     − 2 2 2−   3 3 3
                                               )
           jω C           jωcR ω C R   jω C R
 Output voltage should be real hence imaginary part equal to zero.
     6     1                                               1
       −  3 3 3
                =0               6ω 2C 2 R 2 = 1      ω=
   jωcR jω C R                                           RC 6
 At this frequency: Vi =-29 Vo therefore, Av = -29                   8
RC Oscillators: Wien Bridge Oscillator
                   Rf
                                                     Z1
   R1
              −                          R1     C1                  Z2
              +
                                    Vi                    C2   R2        Vo
                   C     R
                               Vo
          R             Z1
    C         Z2
                                              Feedback Network
 Feedback network is a lead-lag circuit where R1, C1 form the lag
portion and R2, C2 form the lead portion. Thus feedback network
provides 0o phase shift.
                                                                         9
 RC Oscillators: Wien Bridge Oscillator
                1                 1                                 Z1
 Let   X C1 =           X C2   =     and
              ωC1                ωC2                     R1    C1                  Z2
  Z1 = R1 − jX C1
      1
                         −1                        Vi                    C2   R2        Vo
              1        − jR2 X C 2
 Z2 =  +            =
       R2 − jX C 2    R2 − jX C 2
Therefore, the feedback factor,
  Vo   Z2             (− jR2 X C 2 / R2 − jX C 2 )
β= =         =
  Vi Z1 + Z 2 ( R1 − jX C1 ) + (− jR2 X C 2 / R2 − jX C 2 )
                      − jR2 X C 2
 β=
       ( R1 − jX C1 )( R2 − jX C 2 ) − jR2 X C 2
                          R2 X C 2
 β=
    R1 X C 2 + R2 X C1 + R2 X C 2 + j ( R1 R2 − X C1 X C 2 )
                                                                                   10
RC Oscillators: Wien Bridge Oscillator
For Barkhausen Criterion, imaginary part = 0,                           R1 R2 − X C1 X C 2 = 0
           1 1
 R1R2 =           ω = 1 / R  R  C C                                     0.34
          ωC1 ωC2          1  2  1 2
                                                                        0.32
                                                    Feedback factor β
                                                                        0.3
Supposing, R1=R2=R and XC1= XC2=XC,                                     0.28
                                                                                       β=1/3
                                                                        0.26
              RX C
    β=                                                                  0.24
       3RX C + j ( R 2 − X C2 )                                         0.22
                                                                        0.2
At this frequency: β = 1 / 3 and phase shift = 0o                                      f(R=Xc)
                                                                          1
 Due to Barkhausen Criterion, gain Avβ=1
                                                                         0.5             Phase=0
 Where Av : Gain of the amplifier
                                                            Phase
                             Rf        Rf                                 0
Av β = 1 ⇒ Av = 3 = 1 +                     =2
                             R1        R1                               -0.5
                                                                         -1
                                                                                                 Frequency 11
Stabilization method for Wien Bridge Oscillator
               Rf                                                   R               C
       R1                    R3
                    −                                                   +
                                       Vo
                    +                                 R      C          −
                        C    R
                                                                            R2
               R
        C                                                                        Blub
When dc power is first applied, both zener diode is off.
                        R f + R3        R3   Because
                                                            Rf
         Av = 1 +                  = 3+                          =2
                            R1          R1                  R1
Initially, a small +ve feedback signal develops from noise or turn-on transients. This
feedback signal is amplified and continually reinforced , resulting in a buildup of the output
voltage. When the output voltage reaches the zener breakdown voltage , zener diode
conducts and effective short out R3 and thus lowers the close loop voltage gain to 3.
                                                                                            12