MATHEMATICS
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A.x = 21/2; y = 4 A. 45 m2
B. 36.98 m2
B.x = 41/3; y = 31/2
C. 40 m2
C.x = 21/4; y = 31/5
D. 22m2
D.x = 1; y = 1/2
The correct answer is option [D]. Solution: 3x + The correct answer is option [B]. Solution: Hint
4y = 5 ® [i], 7x + 2y = 8 ® [ii]. [The area of triangle if not right angle is Ö(s[s -
Multiply equation [i] by 7 and equation [ii] by 3 a][s - b][s - c]), where s = / ]; s = / = /
a+b+c
2 15 + 10 +
8
2
33
2
gives 21x + 28y = 35 ® [iii], 21x + 6y = Area = Ö( / [ / ][ / ][ / ]) = 36.98m
33
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3
2
13
2
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2
2
24 ® [iv]. QUESTION NO: 7
Subtract equation [iv] from equation [iii],
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partly constant and which partly varies inversely as the
time of flight of the balls. When a ball has been travelling
for 1/6 second its speed reaches 128km/h. When it has
been travelling for 1/2 second its speed is 46km/h. Find the
speed of the ball when it has been travelling for 1/4 second.
A. 158 km/mins
B. 88 km/mins
C. 88 km/h
D. 158 km/h
The correct answer is option [C]. Solution: Let the
speed be represented by S and the time of flight be t;
then S = a + / , where a and b are constants. Using
b
t
the equation solve for the contants and substitute into
the equation to find the speed when the time of flight
is / second.
1
4
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