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QUANTITATIVE APTITUDE – PROFIT AND LOSS MAINS SET-1 (Eng)

Quantitative Aptitude

1. Selling price of article B is 11(1/9) % more B. Rs.1380

than selling price at article A. If the shopkeeper C. Rs.1440
made 20% profit on article B and selling price of D. Rs.1480
article A was Rs.40 more than the cost price of E. None of these
article B, then, find the cost price of article A.
Shopkeeper sold article A at profit of 25%. 4. A shopkeeper sold equal number of mobile
A.Rs.289 and laptop and the cost price of a laptop and
B. Rs.467 mobile is equal. If the shopkeeper gets the profit
C. Rs.432 of a laptop is Rs.6400 more than the he gets the
D. Rs.423 profit from a mobile and the selling price of a
E. Rs.442 laptop is Rs.9250. The shopkeeper offers a
discount of laptop is 7.5% on its marked price
2. A shopkeeper bought two watches for and the shopkeeper offer two successive
Rs.3000. Then he sold one at a loss of 10% and discounts of 5% and 6% on marked price of
another at a profit of 45%. If overall profit is 12% mobile. If the marked price of a mobile and
then find the ratio of the cost price of two laptop is equal and the cost price of a mobile is
watches. Rs.6250, then find how much total discount he
A.3:4 gave on mobile and laptop?
B.2:5 A. Rs.35400
C.3:2 B. Rs.34600
D.5:8 C. Rs.36400
E.4:1 D. Rs.34500
E. None of these
3. The ratio of the cost price of Battery and
Charger is 6:5. The shopkeeper marked the 5. A trader marks his goods such that he can
Charger 20% above its cost price and gave a make a profit of 25% after giving a 15%
5% discount on the marked price of the charger. discount. But the trader gives an 18% discount.
If the shopkeeper sold the battery at a profit of Find the new profit percentage?
15% and the selling price of the charger is A.15%
Rs.1140, then find the selling price of the B.15.2%
battery? C.35.2%
A. Rs.1340 D.20.58%

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QUANTITATIVE APTITUDE – PROFIT AND LOSS MAINS SET-1 (Eng)

E.22.69% A. Rs.4000
B. Rs.2000
6. A marked the price of articles by 40% and C. No profit, No loss
sold 30% of the articles at this price and 30% of D. Rs.1500
the articles at a discount of 14.28% and the rest E. None of these
at a discount of 25%. What is net profit?
A.20% 9. A shopkeeper marked an article x% above
B.14% the cost price and sold it after two consecutive
C.36% discounts of 25% and 20%. In this transaction,
D.25% the shopkeeper had a profit of 20%. Find the
E.21% cost price of the article if the selling price of the
article is Rs. 114x.
7. The prices of TV and AC are marked 40% A. Rs. 9500
and 50% above its cost price respectively and B. Rs. 9000
the cost price of both the articles is equal. If 20% C. Rs. 10000
discount is given on both the items, then the D. Rs. 12000
profit percentage on TV is what percent E. None of these
more/less than the profit percentage on AC?
A.74.35% 10. An article is marked up by ___% above its
B.66.66% cost price. It is then sold after giving a discount
C.45% of Rs.150 such that there is a profit of ___%, the
D.50% cost price of the article is an integer.
E. none of these The values given in which of the following
options will fill the blanks in the same order in
8. A shopkeeper bought 37 TVs and Washing which is it given to make the statement true:
machine together. The ratio of the cost price of I. 20, 8
TV and Washing machine is 12:25. He marked II. 35, 21
up the TV by 40% and the Washing machine by III. 40, 32
Rs.8000 and no discount is provided. He sold A. Only I
80% of the total number of TVs and 8 Washing B. Only I and III
machines at Rs.6 lakh. The remaining 4 C. Only II and III
Washing machines are unsold due to some D. Only III
fault. Find his overall profit or loss. E. All I, II and III

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Answer Key with Explanation

1. Answer: C CP of battery = 6x
Let selling price of A is 9x, so selling price B is CP of Charger = 5x
10x 5x * 120/100 * 95/100 = 1140
Cost price of B =10x*100/120=50x/6 x = 200
We can say, 9x-50x/6= Rs.40 SP of battery = 6 * 200 * 115/100 = Rs.1380
Or, 4x/6=40
Or, x=60 4. Answer: C
Selling price of A =60*9= Rs.540 Number of laptop = x
Cost price of A =540*100/125= Rs.432 Number of mobile = x
CP of x mobile = 6250 * x
2. Answer: C CP of x laptop = 6250 * x
Let cost price one watch is x and another is SP of a laptop = 9250
3000-x SP of x laptop = 9250x
So, we can say, MP of a laptop = 9250 * 100/(100 – 7.5) =
x*90/100+[3000-x] Rs.10000
*145/100=3000*112/100=Rs.3360 MP of x laptop = 10000 * x
Or,55x/100=990 Profit of laptop = 9250x – 6250x = 3000x
Or, x= Rs.1800 SP of mobile = 10000x * 95/100 * 94/100 =
Price of another watch is=3000-1800=1200 8930x
Required ratio =1800:1200=3:2 Profit of mobile = 8930x – 6250x = 2680x
3. Answer: B 3000x – 2680x = 6400

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QUANTITATIVE APTITUDE – PROFIT AND LOSS MAINS SET-1 (Eng)

x = 20 Profit percentage on TV = 12%

Discount = (10000 * 20 – 9250 * 20) + (10000 * Selling price of AC = 150 × 80/100 = 120
20 – 8930 * 20) Profit percentage on AC = 20%
= 15000 + 21400 The required percentage = (20 - 12)/12 × 100 =
= Rs.36400 8/12 × 100 = 66.66%.

5. Answer: D 8. Answer: C
Let cost price is 100x Total number of washing machine = 8+4 =12
Profit percentage is 25% Total number of TV = 37- 12 =25
So the selling price =125x Let Cost price of TV = 12x
So the marked price =125x*100/85=147.05x Cost price of Washing machine = 25x
Now discount is 18%, Total selling price
So the selling price = 147.05x*82/100=120.58x [25*(80/100)*12x*(140/100)]+[8 *(25x+8000)] =
So the new profit percentage =20.58% Rs.600000
X = 1000
6. Answer: A So, Cost price of TV and Washing machine is
Let the total items be 100 and the cost price of Rs.12000 and Rs.25000 respectively
each item is Rs.1 Total cost price = 25*12000 + 12* 25000 =
So, total cost price =Rs.100 Rs.600000
30% of the items was sold 40% above the cost Hence, no profit or no loss.
price= 30 * 140/100 = Rs.42
30% at 14.28% discount = 30 * 140/100 * 9. Answer: A
85.72/100 = Rs.36 Let the cost price of the article be Rs. y.
40% at 25% discount = 40 * 140/100 * 75/100 = Selling price of the article = Rs. 1.20y
Rs.42 Marked price of the article = 1.20y/(0.75 x 0.80)
Total selling price = 42+42+36 = Rs.120 = Rs. 2.0y
So, profit percentage = 20% So the value of 'x'% = (2.0y - y)/y x 100 = 100%
so, x=100
Selling price of the article = 114 x 100 = Rs.
7. Answer: B
11400
Let the cost price of TV and AC be Rs.100.
Cost price of the article = 11400/1.20y*y = Rs.
M.P of TV = Rs.140
9,500
M.P of AC = Rs.150
Hence, option A.
Selling price of TV = 140 × 80/100 = 112

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QUANTITATIVE APTITUDE – PROFIT AND LOSS MAINS SET-1 (Eng)

10. Answer: B According to the question,

For statement l: 1.35x - 1.21x = 150
Let the cost price of the article be Rs. X Or, x = 150/0.14 = Rs.1071.42
Therefore, marked price of the article = Rs.1.20x Therefore, statement II is false.
The selling price of the article = Rs.1.08x For statement III:
According to the question, Let the cost price of the article be Rs. X
1.20x - 1.08x = 150 Therefore, the marked price of the article = Rs.
Or, x = 150/0.12 = Rs.1250 1.40x
Therefore, the statement I is true. The selling price of the article = Rs. 1.32x
For statement II: According to the question
Let the cost price of the article be Rs. X 1.40x - 1.32x = 150
Therefore, the marked price of the article = Rs. Or, x = 150/0.08 = Rs.1875
1.35x Therefore, statement III is true.
The selling price of the article = Rs. 1.21x

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QUANTITATIVE APTITUDE – PROFIT AND LOSS MAINS SET- 2 (Eng)
Quantitative Aptitude

1. The cost price of mobile is 20% less than the of the cost price of the watch to Pen is 2: 1 and
cost price of laptop after allowing two the discount offered for the watch is 20%, then
successive discounts 25% and 20% what is the marked price of Pen?
respectively. If the cost price of a watch is 30% A. Rs.550
less than that of the cost price of laptop after B. Rs.650
allowing two successive discounts of 20% and C. Rs.450
20% respectively, then the cost price of mobile D. Rs.350
is approximately what percent more than that of E. None of these
the cost price of watch?
A. 9% 4. Article P and article Q each sold at 20% profit,
B. 7% while marked price of P is 55% less than that of
C. 5% Q. Article P sold after discount of (Z – 10) %,
D. 1% while Q at (Y + 25) % discount. Ratio of selling
E. None of these price of P and Q is 3:5 respectively. Combined
cost price of both articles is 3200, and Z is twice
2. An article is bought by A and B for the same of Y. Find the value of Z?
price from a shop. A and B marked up by 50% A.25
and 25% more than the cost price respectively. B.30
B did not give any discount, while the discount C.27
given by A is 20 percent of the price. Find by D.36
how much percent the selling price of A is more E. None of these
or less than the selling price of B.
A. 4% less 5. A shopkeeper purchased two articles A and B
B. 10% more at a total of Rs.1200. He sold article A at 10%
C. 10% less loss and article B at 15% profit and earned a
D. 4% more total profit of Rs.80. Find the difference between
E. 4.25% less the cost prices of both the articles?
A. Rs.500
3. The selling price of the Watch is Rs.920. The B. Rs.600
ratio of the marked price to the cost price of the C. Rs.400
watch is 23: 20 and the ratio of the marked price D. Rs.700
to the cost price of the Pen is 11: 10. If the ratio E. None of these

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QUANTITATIVE APTITUDE – PROFIT AND LOSS MAINS SET- 2 (Eng)

Directions (6-10): Study the following information and answer the given questions.
There are 5 types of electronics items in a store they are TV, fridge, AC, Cooler and geyser. The total
number of items is 2160.
The pie chart shows the distribution of the number of different electronics items.

The table shows the MRP, Discount and profit/loss percentage on the 5 different electronics items.
Some values are missing in the table.

6. If the seller sold all the TV for Rs.33600 more, C. Rs.1680

then he would have gained a profit of 10%. D. Rs.1850
What is the selling price of a TV? E. None of these
A. Rs.1620
B. Rs.1630

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QUANTITATIVE APTITUDE – PROFIT AND LOSS MAINS SET- 2 (Eng)

7. The difference between the selling prices of a

cooler and a geyser is Rs.12200, when a geyser 9. Cost price of a geyser is 25% more than the
is sold at a profit of 18%. If the cost price of the selling price of fridge. If the cost price of a fridge
cooler is Rs.11800 more than the geyser, then is Rs.12450, then find the cost price of a
find the total cost price of all cooler.( The selling geyser?
price of cooler is more than that of geyser) A. Rs.14317.5
A. Rs.80.166 lakh B. Rs.14214.5
B. Rs.80.176 lakh C. Rs.14216.5
C. Rs.80.186 lakh D. Rs.15218.5
D. Rs.80.196 lakh E. Rs. 15210.5
E. None of these
10. If the cost price of a TV and a cooler is
8. If the selling price of all fridges together is Rs.5420 and Rs.2540 then find the average
Rs.81.9 lakh, then find the difference between selling price of all TV and All cooler
the marked price and the cost price of a fridge (approximately).
(approximately). A. Rs.4310
A. Rs.2632 B. Rs.4330
B. Rs.2638 C. Rs.4350
C. Rs.2642 D. Rs.4370
D. Rs.2649 E. Rs.4320
E. Rs. 2668

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Answer Key with Explanation

1. Answer: B 1.2P/1.2Q = 3/5

Cost price of laptop=100x So, P/Q = 3/5
After two successice discount= So, Cost price of P = 3/8 x 3200 = 1200
100x*75/100*80/100=60x CP of Q = 5/8 x 3200 = 2000
Cost price of mobile=60x*80/100=48x Ratio of MRP of P and Q = 45:100 = 9:20
After two successive discount= And ratio of Selling price of P and Q = 3:5
100x*80/100*80/100=64x Now,
Cost price of watch=64x*70/100=44.8x [9 x (100 – 2Y + 10)]/ [20 x (100 – Y – 25)] = 3/5
Required percentage=48x-44.8x/44.8x*100=7% (110 – 2Y)/ (75 – Y) = 4/3
2Y = 30
2. Answer: A So, Y = 15
Cost price of the article be x Z = 30
Marked price by A = 1.5x and by B = 1.25x
Selling price of A = 1.5x – discount = 1.5x – 1.5x 5. Answer: C
* 20/100 Let CP of article A = ‘x’ rupees
= 1.5x – 0.3x = 1.2x So, CP of article B = (1200 – x) rupees
Selling price of B = 1.25x From the question:
Percentage = (1.25x - 1.2x/1.25x)*100 = 4% less x * (90/100) + (1200 – x) * (115/100) = 1280
18x + 27600 – 23x = 25600
3. Answer: A x = 400
CP of Watch = 2x CP of article A = Rs.400
CP of Pen = x CP of article B = 1200 – 400 = Rs.800
SP of Watch = 920 Required difference = 800 – 400 = Rs.400
Marked price of Watch = 920/80 * 100 = 1150
CP of Watch = 1150/23 * 20 = Rs.1000 6. Answer: C
CP of Pen = 1000/2 = 500 Number of TV in the store = 2160 × 70/360 =
Marked price of Pen = 500/10 * 11 = Rs.550 420
Number of fridges in the store = 2160 × 84/360 =
4. Answer: B 504
Let cp of P and Q is = P and Q respectively Number of AC in the store = 2160 × 94/360 =
Ratio of SP of P and Q = 3:5 564
Now,

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QUANTITATIVE APTITUDE – PROFIT AND LOSS MAINS SET- 2 (Eng)

Number of coolers in the store = 2160 × 62/360 ⇒ x = 9750

= 372 Cost price of a cooler = x + 11800 = 9750 +
Number of geysers in the store = 2160 × 50/360 11800 = Rs.21550
= 300 Cost price of all cooler = 21550 × 372 =
Let the cost price of 1 TV be x. Rs.80.166 lakh
Selling price of 1 TV = x × 105/100 = 1.05x
Price increase on 1 TV = 33600/420 = Rs.80 8. Answer: D
Now, Number of TV in the store = 2160 × 70/360 =
Selling price of 1 TV = 1.05x + 80 420
⇒ x × 110/100 = 1.05x + 80 Number of fridges in the store = 2160 × 84/360 =
⇒ 1.1x = 1.05x + 80 504
⇒ x = 80/0.05 = 1600 Number of AC in the store = 2160 × 94/360 =
Selling price of TV = 1600 × 105/100 = Rs.1680 564
Number of coolers in the store = 2160 × 62/360
7. Answer: A = 372
Number of TV in the store = 2160 × 70/360 = Number of geysers in the store = 2160 × 50/360
420 = 300
Number of fridges in the store = 2160 × 84/360 = Selling price of a fridge = 8190000/504 =
504 Rs.16250
Number of AC in the store = 2160 × 94/360 = Discount = 20%
564 80% of the MRP = 16250
Number of coolers in the store = 2160 × 62/360 MRP = (16250/80) × 100 = Rs.20312.5
= 372 Loss = 8%
Number of geysers in the store = 2160 × 50/360 Cost price = 100 × 16250/92 = Rs. 17663.04
= 300 Difference between the marked price and the
Let the cost price of the geyser be Rs.x. cost price of a fridge = 20312.5 – 17663.04 =
Cost price of a cooler = x + 11800 2649.46 ≈ Rs.2649
Selling price of a geyser = x × 118/100 = 1.18x
Selling price of a cooler = (x + 11800) × 110/100 9. Answer: A
= 1.1x + 12980 Number of TV in the store = 2160 × 70/360 =
According to the Question, 420
(1.1x + 12980) – 1.18x = 12200 Number of fridges in the store = 2160 × 84/360 =
⇒ 0.08x = 780 504

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QUANTITATIVE APTITUDE – PROFIT AND LOSS MAINS SET- 2 (Eng)

Number of AC in the store = 2160 × 94/360 = Number of coolers in the store = 2160 × 62/360
564 = 372
Number of coolers in the store = 2160 × 62/360 Number of geysers in the store = 2160 × 50/360
= 372 = 300
Number of geysers in the store = 2160 × 50/360 Profit on TV = 5%
= 300 Selling price of a TV = 5420 × 105/100 =
Cost price of a fridge = Rs.12450 Rs.5691
Selling price of a fridge = 12450 × 92/100 = Selling price of all TV = 5691 × 420 =
Rs.11454 Rs.23,90,220
Cost price of a geyser = 11454 × 125/100 = Profit on cooler = 10%
Rs.14317.5 Selling price of a cooler = 2540 × 110/100 =
Rs.2794
10. Answer: B Selling price of all coolers = 2794 × 372 =
Number of TV in the store = 2160 × 70/360 = Rs.10,39,368
420 Average selling price of all TV and All cooler =
Number of fridges in the store = 2160 × 84/360 = (2390220 + 1039368)/(420 + 372) =
504 3429588/792 = Rs.4330.28 ≈ Rs.4330
Number of AC in the store = 2160 × 94/360 =
564

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QUANTITATIVE APTITUDE – PROFIT AND LOSS MAINS SET-3 (Eng)
-Quantitative Aptitude

1. A shopkeeper sold two articles P and Q after E.Rs. 1632

discount of 10% and 40% respectively thus
earning profit of 2Z% and (3Z – 25) %. If cost 4. Babu and Ajay started a business by
price of P is 50% more than that of Q, and investing Rs. (8x + 18000) and Rs. (4x + 9000),
marked price of both the article is same, then respectively. They decided that they will donate
find the value of (Z + 15)? 50% of their total profits and the rest will be
A.25 divided between them in the ratio of their
B.40 investments. If annual profit received by Babu is
C.50 Rs. 20000 more than that by Ajay, then find
D.30 total annual profit earned by them together?
E. None of these A.Rs. 80000
B.Rs. 120000
2. A shopkeeper cheats seller by taking P C.Rs. 100000
grams more at every 800-gm quantity and also D.Rs. 160000
cheats customer by giving (P + 100) gm less on E. Can’t be determined.
every 800 gm, thus earning profit of 100%. Find
the Value of (3P + 800) grams? 5. Cost price of an article is Rs.400 and it is
A.1400 marked up by 50% above its cost price. If
B.2000 percentage of profit earned by selling the article
C.1700 and percentage of discount given on the article
D.1200 is same. What is the percentage of discount
E. None of these given on marked price of the article?
A.20%
3. Ravi and Shankar invested some amount in a B.25%
business in the ratio of 4:7,If Ravi and Shankar C.15%
invested the amount for 8 years and 10 years, D.22%
respectively and profit share of Ravi was Rs. E.30%
624, then find the profit share of Shankar?
A.Rs. 1365 6. If a merchant bought 21 bananas for Rs.126
B.Rs. 1728 and on selling 18 bananas, total selling price is
C. Rs. 1265 Rs.126. What is the percentage of profit earned
D. Rs. 1944 by the merchant?

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A.37.5% 9. Article P is marked up by 80% and sold

B.66.67% aftergiving a discount of Rs. 600, while article Q
C.14.28% is sold at aprofit of 25% whose cost price is Rs.
D.33.33% 400more than that of P. Find the selling price of
E.16.67% article R, if it issold at 40% profit and having
cost price as same as marked price of article
7. A man bought a flower pot for Rs.x and sold it Pand also both Q and P are sold at same
at a profit of 20%. If he had bought the flower Selling price?
pot for Rs.500 more and sold it at a loss of 10%, A.Rs. 5240
the selling price would be Rs.150 more. Find B.Rs. 5080
the original cost price of the flower pot. C.Rs. 4860
A.Rs.1200 D.Rs. 5020
B.Rs.1800 E.None of these
C.Rs.1000
D.Rs.1500 10. A man bought two watches for Rs.5700. If
E.None of these the 1st watch was sold at 10% profit and the
2nd watch was sold at 25% profit then man
8. The cost price of a shirt is Rs.1600 and the could earn 20% profit in overall, then the man
price is marked up by 50%. The shopkeeper changed his mind and sold the 1st watch at
offered two successive discounts ‘x%’ and 25% 30% profit and the 2nd watch at 20% profit. Find
respectively. If the selling price of the shirt is the difference of selling prices of those two
Rs.1530, then find the value of ‘x’. watches?
A.25 A. Rs.2090
B.12 B. Rs.1450
C.15 C. Rs.1352
D.20 D. Rs.1650
E.27 E. None of these

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Answer Key with Explanation

1. Answer: B Hence, the answer is option A

Marked price of both articles is same, so ratio of
their selling price = 90%:60% = 3:2 3. Answer: A
Ratio of cost price of both articles = 3:2 Respective ratio of profit share of Ravi and
If ratio of CP and SP is same, then profit % of Shankar = 4 × 8: 7 × 10 = 16:35
both the articles must be same. Profit share of Shankar = 35/16 × 624 = Rs.
So, 2Z = 3Z – 25 1365.
Value of Z = 25
Required value = 25 + 15 = 40 4. Answer: B
Hence, the answer is option B Respective ratio of profit share of Babu and Ajay
at the end of the year = [(8x + 18000) × 12]: [(4x
2. Answer: A + 9000) × 12] = 2:1
At cost of 800 grams, he received = (P + 800 Let annual profit share of Babu and Ajay be Rs.
grams) 2p and Rs. p, respectively.
AT cost of 800 grams, he gives = (800 – P – ATQ;
100) = (700 – P) 2p – p = 20000
There is 100% profit, so ratio of SP/CP = 2/1 p = 20000
(800 + P)/ (700 – P) = 2/1 Required profit = (3 × 20000)/0.50 = Rs. 120000.
800 + P = 1400 – 2P
So, value of P = 200 5. Answer: A
Required value = (3 x 200) + 800 = 1400 CP = 400

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QUANTITATIVE APTITUDE – PROFIT AND LOSS MAINS SET-3 (Eng)

MP = 400*150/100 = 600 Let CP of P = 100a

600*(100 – x)/100 = 400*(100+x)/100 MP of P = 180% x 100a = 180a
x = 20% Selling price of P = (180a – 600)
Selling price of Q = 1.25 x (100a + 400)
6. Answer: E Now,
CP of a banana = 126/21 = 6 180a – 600 = 125a + 500
SP of a banana = 126/18 = 7 55a = 1100
Profit % = 1*100/6 = 16.67% Value of a = 20
So, Cost price of R = 180 x 20 = Rs. 3600
7. Answer: C Selling price of R = 140% x 3600 = Rs. 5040
(x + 500) * (90/100) – x * (120/100) = 150 Hence, answer is option E
[(9x + 4500)/10] – (12x/10) = 150
4500 – 3x = 1500 10. Answer: A
3000 = 3x
x = Rs.1000

8. Answer: C
MP = 1600*150 / 100 = 2400
SP = 1530
From 2nd discount, = 1:2

1530*100/75 = 2040 So, cost price of1st watch is =5700*1/3=Rs.1900

From 1st discount, Cost price of 2nd watch is =5700-1900=3800

2040*100/(100-x) = 2400 Required difference = 3800*120/100-

x = 15% 1900*130/100=Rs.2090

9. Answer: E

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QUANTITATIVE APTITUDE – PROFIT AND LOSS MAINS SET-4 (Eng)
Quantitative Aptitude

1. An article is marked ‘3x’ above the cost price C.18%

of Rs.300 and sold after giving ‘x+100’ discount. D.17.5%
The profit obtained is Rs.’x’. What will be the E.None of these
profit percent when the item is sold for ‘6x-100’?
A.65% 4. An article is marked up by x% above its cost
B.66.67% price. If the shopkeeper offers discount of 20%
C.33.33% and still earns a profit of 28%. So for earning
D.25% profit of 56%, how much discount must be
E. None of these offered by the shopkeeper in percentage?
A. 6%
2. If the ratio of the marked price to the cost B. 5%
price of the mobile is 6:5 and the shopkeeper C. 2.5%
offers a discount of 8% on the marked price of D. 12%
the mobile. If the difference between the selling E. Can’t be determined
and marked price of the mobile is Rs.2400, then
find the profit earned by the shopkeeper. 5. A shopkeeper marked up an article by ___%
A.Rs.2400 and sold it at two successive discounts of 5%
B.Rs.2500 and 15% on its marked price and earned a profit
C.Rs.2600 of Rs. 460. If the shopkeeper had sold the
D.Rs.2800 article at marked price, he would have received
E.None of these Rs. 8000.
Find the value, which can be filled in the blank?
3. A sold an article to B at 25% profit, B spends A. 33.33%
Rs. 840 on its maintenance, and marked his B. 25%
cost 66.66% more than cost price (price at C. 37.5%
which he bought + maintenance charges) and D. 16.67%
sold it to C after two successive discounts of E. 20%
15% and 25%, and making profit of Rs. 427.5.
Maintenance charges is ______ % of cost price 6. Cost price of an article P is 150% more than
of article for A? cost price of another article Q. If Q sold at
A.14% 13/10th of its cost price and P sold at 6% loss.
B.18.5% Selling price of P is Rs. 210 more than that of

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Q. Find the loss of P and profit of Q I). a) 20 b) Rs.375 c) Rs.240

respectively? II). a) 25 b) Rs.600 c) Rs.360
A. Rs. 60 and Rs. 30 III). a) 20 b) Rs.750 c) Rs.480
B. Rs. 30 and Rs. 60 A. Only I and II
C. Rs. 20 and Rs. 40 B. Only II and III
D. Rs. 40 and Rs. 20 C. Only I
E. None of these D. All are true
E. Only III
7. A buys watch1 and watch3. B buys watch2
and watch4. The cost price of watch1 and 9. A retailer bought 5400 pens and 6200 pencils
watch2 is equal and the cost price of watch3 at same price. He sold in such a way that he
and watch4 is equal. A marked up watch1 by can buy 330 pens with the sale of 280 pens and
60% then sold it at 20% discount. B sells he can buy only 420 pencils with the sale of 480
watch2 at 20% profit. The total selling price of pencils. What is the overall percentage of profit
watch1 and watch2 together is Rs.2480. B sells /loss made by him?
watch4 at 20% discount after marked up by A. 3.45%
50%. The total selling price of watch2 and B. 4.53%
watch4 is Rs.3600. Find the selling price of C. 2.67%
watch 3 when it sold at 25% profit? D. 1.89%
A. Rs. 2650 E. 2.76%
B. Rs. 2400
C. Rs. 2500 10. If a book was sold at 20% profit and the cost
D. Rs. 2250 price & selling price of the book is increased by
E. Rs. 2150 Rs. 40 and Rs. 96 respectively. The new profit
percentage is 33.33%. Find the original cost
Directions (8-10): All the questions have some price of book?
blanks and some values are given in I, II, and A. Rs.380
III. Which of the following option(s) is/are B. Rs.400
satisfied or not? C. Rs.360
8. A shopkeeper has earned 25% profit after D. Rs.420
giving ___a___ % discount on marked E. Rs.320
price___b____ of an item. The cost price of an
item is ___c____.

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Answer Key with Explanation

1. Answer: B CP = 5 * 5000 = 25000

Cost price of an article = Rs.300 Profit = 27600 – 25000 = Rs.2600
Marked price of an article = Rs.300+3x
Selling price of an article = 300+3x-(x+100) = 3. Answer: D
2x+200 Let cost price of article A= Rs. a
Profit obtained = x Cost price of article for B = (1.25a + 840)
ACQ, Price at which B sold the article = 5/3 x 85% x
2x + 200 – 300 = x 75% x (1.25a + 840) = 106.25% of (1.25a + 840)
X = 100 Now, 106.25% of (1.25a + 840) – 100% of
Selling price of an article = 6*100 – 100 = (1.25a + 840) = Rs. 427.50
Rs.500 So, (1.25a + 840) = 427.50/6.25 x 100 = 6840
Profit percentage = (500-300)/300*100 = 66.67% So value of a = 6000/1.25 = Rs. 4800
Hence the option is B. Required % = 840/4800 x 100 = 17.5%
Hence answer is option D
2. Answer: C
CP of mobile = 5x 4. Answer: C
MP of mobile = 6x Let the marked price of the article be 100x
SP of mobile = 6x * 92/100 = 5.52x SP = 100x*(80/100) = 80x
6x – 5.52x = 2400 Hence CP = 80x*(100/128) = 62.5x
x = 5000 New SP for the profit of 56% = 62.5x*(156/100)
SP = 5.52 * 5000 = 27600 = 97.5x

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Or, x=10
Hence new discount % = =
Selling price of watch4 =
2.5%
100y*(150/100)*(80/100)=120y
So, 120y+1200= Rs.3600
5. Answer: A
Or, y= 2400/120=>20
Let the CP of the article = ‘x’ rupees
Cost price of watch3 = Rs.2000
Let marked up percent = ‘y’%
So, selling price of watch3 =2000*(125/100)=
Marked price of the article = Rs.8000
Rs.2500
So,
[8000 * (95/100) * (85/100)] – x = 460
8. Answer: D
(1615*4) – x= 460
I). a) 20 b) Rs.375 c) Rs.240
x = 6000
So, the cost price of the item is Rs240.
CP of the article = Rs. 6000
So, selling price is 240*125/100=Rs300
MP of the article = Rs. 8000
The shopkeeper gives 20% discount.
Required percentage = [(8000 –
So, marked price = 300*(100/80)=375=b.
6000)/6000]*100 = 33(1/3) %
So, it is satisfied.
Similarly, if we check the other values we can
6. Answer: B
see all the values are satisfied.
Let CP of article Q = 100x
CP of article P = 250x
9. Answer: C
SP of article Q = 130x
From this question,
SP of article P = 235x
Profit % on pens, x = (330 – 280) *100 / 280 =
Difference of Sp of P and Q = 105x = Rs.210
125 / 7%
x=2
Loss % on pencils, y = (480 - 420) * 100 / 480 =
Loss of P = 15x = 2 * 15 = Rs.30
12.5%
Profit of Q = 30 * 2 = Rs.60
Overall % of profit/loss is 'Q’
Use allegation method for finding overall % of
7. Answer: C
profit or loss,
Let cost of watch1 and watch2 is 100x and
Total cost of 5400 pens = Total cost of 6200
watch3 and watch4 is 100y.
pencils
Selling price of watch1 =
From this, cost price is equal in both the cases,
100x*(160/100)*(80/100)=128x
Selling price of watch2 = 100x*(120/100)=120x
So, 248x=2480

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10. Answer: E
Let the CP of book is ‘X’
SP = 6X/5
4/3(X+40) = 6X/5 + 96
X =Rs. 320
1 * 125/7 + 1 * (-12.5) = 2Q
Q = 2.67% profit

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