PN Junction Diode
PN Junction Diode
ELECTRICAL ENGINEERING
The pn-junction
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The plane dividing the two zones is called junction. This plane is
assumed to lie where the density of donors and acceptors is
equal.
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The “+” signs in the p-type material denote the majority holes.
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The holes diffusing across the junction into the n region recombine
with the majority electrons present there and ∴ disappear.
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The larger the barrier voltage, the smaller the no. of carriers
that will be able to overcome the barrier and hence the lower
the magnitude of diffusion current.
1 Ony
A barrier because a
itngoS
has.Obu
to r
aovercome for holes to diffuse into the n region
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ID = IS
In equilibrium, under open-circuit conditions, the equality of drift
and diffusion currents applies not just to the total currents
but also to their individual components.
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That is, the hole drift current must equal the hole diffusion
current,...
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If this were not the case, we would draw energy from the
isolated pn-junction, which would violate the principle of
conservation of energy.
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2
Biasing is the application of fixed dc supply to a terminal of an electronic
component toO ny angoS
establish.Obura operating conditions for the component
proper 31/98
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Holes are attracted by the −ve terminal and electrons by the +ve
terminal, increasing width of the depletion zone.
This reduces the no. of holes that diffuse into the n region
and the no. of electrons that diffuse into the p region.
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I = ID − IS
Thus;
▶ a pn-junction can conduct a substantial current in the
forward-bias region and that,
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For silicon diode, very little current I flows when the forward
voltage VF , is less than about 0.6 V .
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Reverse breakdown
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...that is, the reverse voltage remains very close to the value
VBR .
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3
Note that the subscript Z in VZ denotes zener. VZ is sometimes used to
denote VBR whether the breakdown mechanism is the zener effect or the
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Zener effect
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4
Tunnelling current occurs when electrons move thro’ a barrier that they clas-
sically shouldn’t be able to move thro’. That is, if they don’t have enough
energy to move On y
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O bura they won’t
barrier, 55/98
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Avalanche effect
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Diode approximations
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Also, the diode is assumed to drop 0.7 V for all currents that
pass through it
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r8 = 2.5 n o,
ov
+
+
RL = 100 0 \ljn = 10 V ~
IL=100mA
(a) (b)
V8 = 0.7 V r8 = 2.5 n
RL = 1000 RL = 100 0
~ \ljn = 10 V
VL = 9.3 V VL = 9 .07 v
IL = 93mA IL = 90.7mA
(c) (d)
Figure 15: Circuits used to illustrate the use of the first, second, and third
diode approximations in calculating the circuits’ voltage and current
values. (a) Original circuit. (b) First approximation of a diode. (c)
Second approximation of a diode. (d ) Third approximation of a diode.
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Diode resistance
If an ideal diode is considered then it should offer zero resistance
in the forward bias and infinite resistance in the reverse bias.
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That is, the resistance of a diode will change with the operating
conditions.
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Bulk resistance
The bulk resistance, rB , is the resistance of the p and n
materials.
Its value is dependent on the doping level and the size of the
p and n materials.
VF = VB + IF · rB (3)
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Example 1
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Example 2
5
The Q-point or the operating point of a device, a.k.a a bias point, or quiescent
point is the steady-state dc voltage or current at a specified terminal of
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VF 0.65 V
Point A: RF = = = 59.1 Ω (6)
IF 11 mA
VF 0.7 V
Point B: RF = = = 31.1 Ω (7)
IF 22.5 mA
Notice that as the diode conducts more heavily, the forward
resistance, RF , decreases.
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= IS e V /ηVT − IS thus
IS VD /ηVT
= e
ηVT
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ID
=
ηVT
Thus
∆VD ηVT
rac = =
∆ID ID
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DEPARTMENT OF
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Remember that
kT
VT =
q
where
▶ k is the Boltz Mann’s constant = 8.62 × 10−5 eV /K ,
▶ T is the temperature in Kelvin and
▶ q is the charge of electrons given as 1eV = 1.6 × 10−19 J.
Thus at T = 300 K ,
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...if the applied ac signal has a large voltage swing, then the
resistance offered by the diode known as average ac resistance.
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∆VD VDp−p
rav = =
∆ID IDp−p
where
▶ ∆VD or VDp−p is the voltage fluctuation and
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Diode testing
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Diode ratings
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