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Ch0 Mind Map

The document covers basic mathematical concepts including types of numbers, index notation, and divisibility rules. It explains how to express numbers using prime factorization and provides examples for determining divisibility by various integers. Additionally, it outlines the definitions and operations related to integers, such as addition, subtraction, multiplication, and division.

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28 views3 pages

Ch0 Mind Map

The document covers basic mathematical concepts including types of numbers, index notation, and divisibility rules. It explains how to express numbers using prime factorization and provides examples for determining divisibility by various integers. Additionally, it outlines the definitions and operations related to integers, such as addition, subtraction, multiplication, and division.

Uploaded by

tsoihoiling1104
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
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Download as DOCX, PDF, TXT or read online on Scribd
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Ch.

0 Basic Maths Integer(整數) Index notation


1. Expression  All number: positive number, negative  It is convenient to present the products.
2. Type of number number, 0 (except decimal number) The base must be a prime number.
3. Index Example:
4. L.C.M. & H.C.F Even number(雙數) Use index notation to express the following
5. Divisibility E.g. 0,2,4,6,8…. as a product of prime number.
42 x 6
Verb(and then) Noun(first) 中 Odd umber(單數) =2 ×3 ×7 × 2× 3 2 42
文 =22 ×32 ×7
3 21
+ a plus b Sum 和 Whole number(非負整數) 7
 All integer excluding negative integer  2  ‘Two Cube’.
3

−
Prime number
a minus b difference 差  4 2’Four Square’.
Natural number(自然數)
subtract a by b  Positive integer ONLY H.C.F & L.C.M
用短除搵
subtract a ¿ b Prime number(質數) HCF=2
 The factors of the number are one and LCM=2x3x2x3x5x2
× a×b Product 積 itself. *1 is not prime number 2 18 20 24
3 9 10 12
multify a by b Composite number(合成數) 2 3 10 4
 The number has more than 2 factors. 3 5 2
÷ divide a by b Quotient 商 prime factorization
Divisibility

尾數(1) Sum of all integers see whether 尾數(2) Mixed case


can be divisible by 3/9
2 3 5 6
最後一個尾數是否雙數 E.g. 最後的尾數是否 0 或 5 the number should be divisible by
E.g. 12348 E.g. both 2 and 3, so that the number can
4 1+2+3+4+8=18 100 be divisible by 6.
18 18 can be divisible by 3 175 E.g.
120 So, 12348 can be divisible by 3. 320 618
4 9 10 最後一個尾數是雙數
最後兩個尾數是否可被四整除 E.g. 976536 最後的尾數是否零  2
E.g. 9+7+6+5+3+6=36 E.g.
20 36 can be divisible by 9 140 6+1+8=15
116 So, 976536 can be divisible by 9. 1856390 15 can be divisible by 3
1524 25380  3
8
最後三個尾數是否可被 8 整除 ∵618 can be divisible by both 2 and 3
E.g. ∴618 can be divisible by 6.
120
2136
10152

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