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B Factorising Quadratics

The document provides a guide on factorizing quadratic expressions, detailing methods for both cases where the coefficient of x^2 is 1 and when it is not. It includes worked examples illustrating the factorization process and emphasizes checking for common factors. Additionally, it presents exercises for practice in factorizing various quadratic expressions.

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0% found this document useful (0 votes)
41 views4 pages

B Factorising Quadratics

The document provides a guide on factorizing quadratic expressions, detailing methods for both cases where the coefficient of x^2 is 1 and when it is not. It includes worked examples illustrating the factorization process and emphasizes checking for common factors. Additionally, it presents exercises for practice in factorizing various quadratic expressions.

Uploaded by

gota
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as PDF, TXT or read online on Scribd
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A Level Mathematics for OCR A file:///C:/Users/skannan/Desktop/Soorya/Production/20200702/9781316...

Gateway to A Level – GCSE


revision
B. Factorising quadratics
You need to be able to factorise quadratic expressions of the form + + .

If the coefficient of is 1, look for a factorisation of the form ( − )( − ). The numbers and
are such that their product is and they add up to .

Worked example 1
Factorise − 7 + 12

Solution Comments

− + Look at factors of . You need two negative


numbers to give + 12.
12 = ( − 1) × ( − 12)
= ( − 2) × ( − 6)
= ( − 3) × ( − 4)

= ( − 3)( − 4) − 3 and − 4 add up to − .

If the coefficient of is not 1 , you need to adapt this procedure slightly. First look for two
numbers that multiply to and add up to . Then split the middle term and factorise in pairs.

Worked example 2
Factorise 6 + 11 − 10

Solution Comments

×(− ) = − 60 You need two numbers that multiply to


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−60 and add up to 11. This means you


need one positive and one negative
number, with the positive number being
larger.

The two numbers are − 4 and 15 Look at factors of 60:


( − 4 + 15 = 11) − 60 = ( − 1) × 60
= ( − 3) × 20
= ( − 4) × 15

6 + − 10 = 6 − + − 10 Split the middle term: 11 = − 4 + 15

Factorise in pairs: The first two terms


= 2 (3 − 2) + 5(3 − 2) have a common factor 2 and the last two
terms have a common factor 5.

= (3 − 2)(2 + 5) Finally, take out the common factor


(3 − 2).

An alternative method is to simply look for numbers that work. If the coefficients are small prime
numbers this can be quite quick, but otherwise the method shown in Worked example 2 is more
efficient.

Worked example 3
Factorise 5 +9 −2

Solution Comments

5 + 9 − 2 = (5 )( ) The only way to factorise 5 is 5 × 1.

= (5 − 1)( + 2) The missing numbers in brackets are 1 and 2.


One is positive one is negative.
Try possible combinations until you find one that
gives the middle term +9 .

Before you use one of these methods, you should check whether there is a common factor that
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can be taken out of all three terms. For example:

7 − 35 + 42 = 7( − 5 + 6)
= 7( − 2)( − 3)

A special example of factorising a quadratic is the difference of two squares:

− = ( − )( + )

Worked example 4
Factorise 9 − 25

Solution Comments

9 − 25 = (3 − 5)(3 + 5) 9 is the square of 3 and 25 is the square of 5.

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EXERCISE B

Factorise these expressions:

1 a +2 −3

b − 2 − 35

c − 8 − 20

d + 13 + 40

2 a 2 − 4 − 30

b 5 + 5 − 30

c 2 − 4 − 16

d 3 − 18 + 27

3 a − 81

b − 100

c 16 − 49

d 36 − 81

4 a 3 − 14 − 5

b 2 − −3

c 5 − 14 − 3

d 2 + − 10

e 6 −5 +1

f 15 + 13 + 2

g 6 − − 15

h 10 + − 21

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