Stochastic Process:
State: the value assumed by the random variable are
called state.
Stochastic process consists of sequence of
experiments in which each experiment has a finite
number of outcomes with the given probabilities.
Probability Vector:
A vector V = (𝑉1, 𝑉2,……………………… 𝑉𝑛 ) is called a
probability vector if each one of its components are
non-negative and their sum is equal to unity or 1.
1 1 1 2 3
Eg: V= (1,0) , V= ( , ) , V = ( , , ) ,
2 2 6 6 6
V = ( 0.1 ,0.6 ,0.3 )
Stochastic Matrix:
A square matrix A=aij having every row in the form
of a probability vector is called a Stochastic Matrix.
1 0 0 1 1
1 0
Eg: A = [ ] B = [0 1 0] C = [ 2 2 ]
0 1 0 1
0 0 1
Regular Stochastic Matrix:
A Stochastic Matrix A is said to Regular Stochastic
Matrix, if all the enteries of some power An are positive.
0 1
Eg: A=[ 1 1 ]
2 2
0 1 0 1
2
Consider, A = A . A = [ 1 1 ] [ 1 1 ]
2 2 2 2
1 1
0+ 0+
2 2
=[ 1 1 1]
0+ +
4 2 4
1 1
A2 = [21 2
3]
4 4
∴ 𝐴 𝑖𝑠 𝑎 𝑅𝑒𝑔𝑢𝑙𝑎𝑟 𝑠𝑡𝑜𝑐ℎ𝑎𝑠𝑡𝑖𝑐 𝑚𝑎𝑡𝑟𝑖𝑥.
Properties of a regular stochastic matrix:
If A is the regular stochastic matrix of order n
i) A as a unique fixed point.
x = ( x1 , x2 , ……………,xn ) such that xA=x
ii) A as a unique probability vector.
V = ( V1 , V2 ,…………..., Vn ) such that VA=A
Problems:
1) Find the unique fixed probability vector for the
0 1 0
1 1 1
regular stochastic matrix A =[ 6 2 3]
2 1
0
3 3
Soln: we have to find V=(x , y ,z) where x+y+z=1→*
VA=V
0 1 0
1 1 1
[ x y z ] [6 2 3] =[x y z]
2 1
0
3 3
𝑦 𝑦 2𝑧 𝑦 𝑧
[0+ +0 , x+ + , 0+ + ]=[x y z]
6 2 3 3 3
𝑦 6𝑥+3𝑦+4𝑧 𝑦+𝑧
[ ]=[x y z]
6 6 3
𝑦 6𝑥+3𝑦+4𝑧 𝑦+𝑧
=x = y =z
6 6 3
y = 6x 6𝑥 + 3𝑦 + 4𝑧 = 6y y + z =3z
y = 2z
but y = 6x
6x = 2z
z = 3x
*→ x + y + z =1 y = 6x z = 3x
6 3
x + 6x + 3x =1 y= z=
10 10
10 x = 1
1
x=
10
∴ Unique fixed probability vector is
1 6 3
V=[x y z]=[ , , ]
10 10 10
2)Find the Unique fixed probability vector for the
1 1 1
2 4 4
regular stochastic matrix A= 0 [1 1]
2 2
0 1 0
Soln: we have V= [ x y z ] then x+y+z=1
VA=V
1 1 1
2 4 4
[x y z] [1 0 =[x y 1] z]
2 2
0 1 0
𝑥 𝑦 𝑥 𝑥 𝑦
[ + , +z , + ]=[x y z]
2 2 4 4 2
𝑥+𝑦 𝑥+4𝑧 𝑥+2𝑦
[ , , ]=[x y z]
2 4 4
𝑥+𝑦 𝑥+4𝑧 𝑥+2𝑦
=x , =y , =z
2 4 4
x + y = 2x , x+4z =4y , x+2y = 4z
x + y = 2x x + 2y = 4z
y=x x + 2x = 4z
3x = 4z
3𝑥
z=
4
x+y+z=1
3𝑥 4 3 4
x+x+ =1 y= z= ( )
4 11 4 11
3𝑥 3
4x + =1 z=
4 11
8𝑥+3𝑥
=1
4
11x = 4
4
x = 11
∴ Unique fixed probability vector is
4 4 3
V=[x,y,z]=[ , , ]
11 11 11