Unit 1
Unit 1
Input device accepts the coded information as source program i.e. high level language. This is either
stored in the memory or immediately used by the processor to perform the desired operations. The
program stored in the memory determines the processing steps. Basically the computer converts one source
program to an object program. i.e. into machine language.
Finally the results are sent to the outside world through output device. All of these actions are
coordinated by the control unit.
T
Input unit: - The source program/high level language program/coded information/simply data is fed to a
computer through input devices keyboard is a most common type. Whenever a key is pressed, one
EN
corresponding word or number is translated into its equivalent binary code over a cable & fed either to
memory or processor.
Example:- Joysticks, trackballs, mouse, scanners etc are other input devices.
D
Memory unit: - Its function into store programs and data. It is basically to two types
U
1. Primary memory
2. Secondary memory
ST
1. Primary memory: - It Is the one exclusively associated with the processor and operates at the electronics
speeds programs must be stored in this memory while they are being executed. The memory contains a
large number of semiconductors storage cells. Each capable of storing one bit of information. These are
R
To provide easy access to a word in memory, a distinct address is associated with each word
location. Addresses are numbers that identify memory location.
Number of bits in each word is called word length of the computer. Programs must reside in the
memory during execution. Instructions and data can be written into the memory or read out under the
control of processor. Memory in which any location can be reached in a short and fixed amount of time
after specifying its address is called random-access memory (RAM).
The time required to access one word in called memory access time. Memory which is only readable
by the user and contents of which can‘t be altered is called read only memory (ROM) it contains operating
system. Caches are the small fast RAM units, which are coupled with the processor and are often contained
on the same IC chip to achieve high performance. Although primary storage is essential it tends to be
expensive.
2 Secondary memory: - Is used where large amounts of data & programs have to be stored, particularly
information that is accessed infrequently.
Examples: - Magnetic disks & tapes, optical disks (ie CD-ROM‘s), floppies etc.,
Arithmetic logic unit (ALU):-
Most of the computer operators are executed in ALU of the processor like addition, subtraction,
division, multiplication, etc. the operands are brought into the ALU from memory and stored in high speed
storage elements called register. Then according to the instructions the operation is performed in the
required sequence.
The control and the ALU are may times faster than other devices connected to a computer system.
This enables a single processor to control a number of external devices such as key boards, displays,
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 1 of 90
CS8491-Computer Architecture Department of CSE & IT
magnetic and optical disks, sensors and other mechanical controllers.
Output unit:-
These actually are the counterparts of input unit. Its basic function is to send the processed results
to the outside world.
Examples:- Printer, speakers, monitor etc.
Control unit:-
It effectively is the nerve center that sends signals to other units and senses their states. The actual
timing signals that govern the transfer of data between input unit, processor, memory and output unit are
generated by the control unit.
BASIC OPERATIONAL CONCEPTS
To perform a given task an appropriate program consisting of a list of instructions is stored in the
memory. Individual instructions are brought from the memory into the processor, which executes the
specified operations. Data to be stored are also stored in the memory.
Examples: - Add LOCA, R0
This instruction adds the operand at memory location LOCA, to operand in register R0 & places the
sum into register. This instruction requires the performance of several steps,
1. First the instruction is fetched from the memory into the processor
2. The operand at LOCA is fetched and added to the contents of R0
3. Finally the resulting sum is stored in the register R0
The preceding add instruction combines a memory access operation with an ALU Operations. In
some other type of computers, these two types of operations are performed by separate instructions for
T
performance reasons.
EN
Load LOCA, R1
Add R1, R0
D
Transfers between the memory and the processor are started by sending the address of the memory
U
location to be accessed to the memory unit and issuing the appropriate control signals. The data are then
transferred to or from the memory. CONTROL ALU … n- GPRs
ST
R
M
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 2 of 90
CS8491-Computer Architecture Department of CSE & IT
The other two registers which facilitate communication with memory are: -
1. MAR – (Memory Address Register):- It holds the address of the location to be accessed.
2. MDR – (Memory Data Register):- It contains the data to be written into or read out of the address
location.
Operating steps are
1. Programs reside in the memory & usually get these through the I/P unit.
2. Execution of the program starts when the PC is set to point at the first instruction of the program.
3. Contents of PC are transferred to MAR and a Read Control Signal is sent to the memory.
4. After the time required to access the memory elapses, the address word is read out of the memory and
loaded into the MDR.
5. Now contents of MDR are transferred to the IR & now the instruction is ready to be decoded and
executed.
6. If the instruction involves an operation by the ALU, it is necessary to obtain the required operands.
7. An operand in the memory is fetched by sending its address to MAR & Initiating a read cycle.
8. When the operand has been read from the memory to the MDR, it is transferred from MDR to the ALU.
9. After one or two such repeated cycles, the ALU can perform the desired operation.
10. If the result of this operation is to be stored in the memory, the result is sent to MDR.
11. Address of location where the result is stored is sent to MAR & a write cycle is initiated.
12. The contents of PC are incremented so that PC points to the next instruction that is to be executed.
T
Normal execution of a program may be preempted (temporarily interrupted) if some devices require
EN
urgent servicing, to do this one device raises an Interrupt signal.
An interrupt is a request signal from an I/O device for service by the processor. The processor
provides the requested service by executing an appropriate interrupt service routine.
D
The Diversion may change the internal stage of the processor its state must be saved in the memory
U
location before interruption. When the interrupt-routine service is completed the state of the processor is
restored so that the interrupted program may continue.
ST
CPU PERFORMANCE
The machine (or CPU) is said to be faster or has better performance running this program if the total
R
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 3 of 90
CS8491-Computer Architecture Department of CSE & IT
To maximize performance, we want to minimize response time or execution time for some task.
Thus, we can relate performance and execution time for a computer X:
T
EN
D
Measuring Performance
CPU execution time Also called CPU time. The actual time the CPU spends computing for a specific task.
U
System CPU time The CPU time spent in the operating system performing tasks on behalf of the program.
CPU Performance and Its Factors
Since we are confining ourselves to CPU performance at this point, the bottom-line performance measure is
CPU execution time. A simple formula relates the most basic metrics (clock cycles and clock cycle time) to
R
CPU time:
M
Instruction Performance
The performance equations above did not include any reference to the number of instructions needed for
the program. (We‘ll see what the instructions that make up a program look like in the next chapter.)
However, since the compiler clearly generated instructions to execute, and the computer had to execute the
instructions to run the program, the execution time must depend on the number of instructions in a
program. One way to think about execution time is that it equals the number
of instructions executed multiplied by the average time per instruction. Therefore, the number of clock
cycles required for a program can be written as
The term clock cycles per instruction, which is the average number of clock cycles each instruction takes to
execute, is often abbreviated as CPI. Since different instructions may take different amounts of time
depending on what they do, CPI is an average of all the instructions executed in the program. CPI provides
one way of comparing two different implementations of the same instruction set architecture, since the
number of instructions executed for a program will, of course, be the same.
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 4 of 90
CS8491-Computer Architecture Department of CSE & IT
PERFORMANCE EQUATION
We can now write this basic performance equation in terms of instruction count (the number of instructions
executed by the program), CPI, and clock cycle time:
These formulas are particularly useful because they separate the three key factors
that affect performance.
T
EN
D
U
The words of a computer‘s language are called instructions, and its vocabulary is called an instruction set.
Operands
1. Register Operands
R
T
2. Data Transfer Operations
These operations help in moving the data between memory and registers.
EN
Example 1: Example 2:
D
U
ST
R
3. Logical Operations
M
4. Conditional Operations
1. Branch to a labeled instruction if a condition is true. Otherwise, continue sequentially.
beq rs, rt, L1
if (rs == rt) branch to instruction labeled L1;
bne rs, rt, L1
if (rs != rt) branch to instruction labeled L1;
j L1
2. Unconditional jump to instruction labeled L1. Set result to 1 if a condition is true. Otherwise, set to 0.
slt rd, rs, rt
if (rs < rt) rd = 1; else rd = 0;
slti rt, rs, constant
if (rs < constant) rt = 1; else rt = 0;
3. Use in combination with beq, bne
slt $t0, $s1, $s2 # if ($s1 < $s2)
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 6 of 90
CS8491-Computer Architecture Department of CSE & IT
bne $t0, $zero, L # branch to L
Jump Instructions
4. Procedure call: jump and link.
jal ProcedureLabel
Address of following instruction put in $ra.
Jumps to target address.
5. Procedure return: jump register
jr $ra
Copies $ra to program counter.
Can also be used for computed jumps.
e.g., for case/switch statements.
REPRESENT INSTRUCTIONS IN A COMPUTER SYSTEM
Instructions are encoded in binary Called machine code.
MIPS instructions:
Encoded as 32-bit instruction words.
Small number of formats encoding operation code (opcode), register numbers.
Register numbers
$t0 – $t7 are reg‘s 8 – 15
$t8 – $t9 are reg‘s 24 – 25
$s0 – $s7 are reg‘s 16 – 23
1. R-Format:
T
EN
Instruction Fields:
op: operation code (opcode)
rs: first source register number
D
2. I-Format:
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 7 of 90
CS8491-Computer Architecture Department of CSE & IT
In the table above, ―reg‖ means a register number between 0 and 31, ―address‖ means a 16-bit address,
and ―n.a.‖(not applicable) means this field does not appear in this format. Note that add and sub
instructions have the same value in the op field; the hardware uses the function field to decide the variant
of the operation: add (32) or subtract (34).
3. J-Format:
j target- J-type is short for "jump type". The format of an J-type instruction looks like:
opcode target
B31-26 B25-0
The semantics of the j instruction (j means jump) are:
PC <- PC31-28 IR25-0 00
where PC is the program counter, which stores the current address of the instruction being executed. You
update the PC by using the upper 4 bits of the program counter, followed by the 26 bits of the target (which
is the lower 26 bits of the instruction register), followed by two 0's, which creates a 32 bit address.
LOGICAL OPERATIONS
T
1. Logical Operations:
EN
D
U
ST
2. SHIFT:
R
4. OR:
Used to include bit in a word
Set some bits to 1, leave others unchanged
Eg: or $t0, $t1, $t2
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 8 of 90
CS8491-Computer Architecture Department of CSE & IT
5. NOT:
Useful to invert bits in a word
Change 0 to 1, and 1 to 0
DECISION MAKING
Based on the input data and the values created during computation, different instructions execute.
Decision making is commonly represented in programming languages using if statement, sometimes
combined with go to statements and labels. MIPS assembly language includes two decision-making
instructions, similar to an if statement with a go to. The first instruction is
beq register1, register2, L1
This instruction means go to the statement labeled L1 if the value in register1 equals the value in
register2. The mnemonic beq stands for branch if equal. The second instruction is
bne register1, register2, L1
It means go to the statement labeled L1 if the value in register1 does not equal the value in register2.
The mnemonic bne stands for bra nch if not equal. These two instructions are traditionally called
T
conditional branches.
EN
Example:
Compiling IF statements:
D
U
ST
R
M
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 9 of 90
CS8491-Computer Architecture Department of CSE & IT
More Conditional operations:
Set result to 1 if a condition is true
Otherwise, set to 0
slt rd, rs, rt
if (rs < rt) rd = 1; else rd = 0;
slti rt, rs, constant
if (rs < constant) rt = 1; else rt = 0;
Use in combination with beq, bne
slt $t0, $s1, $s2 # if ($s1 < $s2)
bne $t0, $zero, L # branch to L
Signed comparison: slt, slti
Unsigned comparison: sltu, sltui
Example
$s0 = 1111 1111 1111 1111 1111 1111 1111 1111
$s1 = 0000 0000 0000 0000 0000 0000 0000 0001
slt $t0, $s0, $s1 # signed
–1 < +1 $t0 = 1
sltu $t0, $s0, $s1 # unsigned
+4,294,967,295 > +1 $t0 = 0
T
MIPS ADDRESSING
Multiple forms of addressing are generically called as addressing modes. The method used to identify the
EN
location of an operand. The following are the various types of MIPS addressing modes.
1. Immediate addressing, where the operand is a constant within the instruction itself.
D
4. PC-relative addressing, where the branch address is the sum of the PC and a constant in the
Instruction.
5. Pseudo direct addressing, where the j ump address is the 26 bits of the instruction concatenated with
the upper bits of the PC.
R
The operands are shaded in color. The operand of mode 3 is in memory, whereas the operand for mode 2 is
M
a register. Note that versions of load and store access bytes, half words, or words. For mode 1, the operand
is 16 bits of the instruction itself. Modes 4 and 5 address instructions in memory, with mode 4 adding a 16-
bit address shifted left 2 bits to the PC and mode 5 concatenating a 26-bit address shifted left 2 bits with the
4 upper bits of the PC.
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 10 of 90
CS8491-Computer Architecture Department of CSE & IT
UNIT II ARITHMETIC FOR COMPUTERS
Addition and Subtraction – Multiplication – Division – Floating Point Representation – Floating Point
Operations – Subword Parallelism
ADDITION OPERATION :FAST ADDER
Fast adder circuit must speed up the generation of carry signals. Carry lookahead logic uses the concepts of
generating and propagating carries.
Giand Piare computed only from xi and yi and not ci, thus they can be computed in one gate delay after X
and Y are applied to the inputs of an n-bit adder.
Bit-stage cell
T
EN
D
U
ST
4-bit Adder
R
The complete 4-bit adder is shown in below figure where the B cell indicates Gi, Pi & Si generator. The
M
carries are implemented in the block labeled carry look-ahead logic. An adder implemented in this form is
called a carry lookahead adder. Delay through the adder is 3 gate delays for all carry bits and 4 gate delays
for all sum bits. In comparison, note that a 4-bit ripple-carry adder requires 7 gate delays for S3(2n-1)and 8
gate delays(2n) for c4.
Now, consider the design of a 4-bit parallel adder. The carries can be implemented as
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 11 of 90
CS8491-Computer Architecture Department of CSE & IT
T
EN
Hardware resemble the paper- and-pencil method
Move the multiplicand left one digit each step to add with intermediate products
Over 32 steps, a 32-bit multiplicand move 32-bits to left
D
Hence 64-bit Multiplicand register initialized with 32-bit multiplicand in right half and zero in the
U
left half
ST
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 12 of 90
CS8491-Computer Architecture Department of CSE & IT
Refined Version of Multiplication Hardware
T
EN
D
U
ST
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 13 of 90
CS8491-Computer Architecture Department of CSE & IT
BOOTH’S MULTIPLICATION ALGORITHM WITH SUITABLE EXAMPLE
Booth’s Algorithm Principle:
Performs additions and subtractions of the Multiplicand, based on the value of the multiplier bits.
The algorithm looks at two adjacent bits in the Multiplier in order to decide the operation to be
performed.
The Multiplier bits are considered from the least significant bit (right-most) to the most significant
bit; by default a 0 will be considered at the right of the least significant bit of the multiplier.
If Multiplicand has Md bits and Multiplier has Mp bits, the result will be stored in a Md+Mp bit
register and will be initialised with 0s
As repeated operations and shifts are performed on partial results, the result register is the
accumulator (A).
Booth‘s algorithm gives a procedure for multiplying signed binary integer. It is based on the fact
that strings of 0‘s in the multiplier require no addition but only shifting and a string of 1‘s in the
multiplier require both operations.
Algorithm
The Q0 bit of the register Q and Q-1 is examined:
If two bits are the same (1-1 or 0-0), then all of the bits of the A, Q and Q-1 registers are shifted to the
right 1 bit. This shift is called arithmetic shift right.
If two bits differ i.e., whether 0-1, then the multiplicand is adder or 1-0, then the multiplicand is
subtracted from the register A. after that, right shift occurs in the register A, Q and Q-1.
T
Flowchart of Booth’s Algorithm for 2’s complement multiplication
EN
D
U
ST
R
M
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 14 of 90
CS8491-Computer Architecture Department of CSE & IT
VARIOUS METHODS OF PERFORMING MULTIPLICATION OF N-BIT NUMBERS
In multiplication the two input arguments are the multiplier Q given by Q=qn-1 qn-2…q1q0 and the
multiplicand M given by M=mn-1 mn-2… m1mo.
1. The Paper and Pencil Method(for unsigned numbers)
This is the simplest method for performing multiplication of two unsigned numbers.
Example
Consider the multiplication of the two unsigned numbers 14 and 10.The process is shown below using the
binary representation of the two numbers
T
The above multiplication can be performed using an array of cells each consisting of an FA and an AND.
EN
Each cell computes a given partial product. Figure below shows the basic cell and an example array for a 4
x 4 multiplier array. If a given bit of the multiplier is 0 then there should be no need for computing the
corresponding partial product.
D
2. ADD-SHIFT Method
U
Multiplication is performed as a series of (n) conditional addition and shift operations such that if the given
bit of the multiplier is 0 then only a shift operation is performed, while if the given bit of the multiplier is 1
ST
Example
Multiplication of two unsigned numbers 11 and 13.The process is shown below in a table. A is a 4-
bit register and is initialized to 0s and C is the carry bit from the most significant bit position. The process is
repeated n=4 times (the number of bits in the multiplier Q).If the bit of the multiplier is ―1‖ then A=A+M
and the concatenation of AQ is shifted one bit position to the right. If on the other hand the bit is ―0‖ then
only a shift operation is performed on AQ. The structure of the operation is given in the figure below.
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 15 of 90
CS8491-Computer Architecture Department of CSE & IT
The control logic is used to determine the operation to be performed depending on the LSB in Q. An n-bit
adder is used to add the contents of register A and M
T
EN
D
The Figure shows a logic circuit arrangement that implements restoring division. An n-bit positive divisor
is loaded into register M and an n-bit positive dividend is loaded into register Q at the start of the
operation. Register A is set to 0. After the division is complete, the n-bit quotient is in register Q and the
remainder is in register A. The required subtractions are facilitated by using 2's-complement arithmetic.
The extra bit position at the left end of both A and M accommodates the sign bit during subtractions.
Algorithm for Restoring Division:
Do n times:
{ left shift A and Q by 1 bit
A A - M;
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 16 of 90
CS8491-Computer Architecture Department of CSE & IT
if A < 0 ( an-1 = 1) , then q0 0, A A+M , (restore)
else
q0 1;}
Note: When A and Q are left shifted, the MSB of Q becomes the LSB of A, and the MSB of A is lost. The LSB
of Q is made available for the next quotient bit.
Example: 8 divide by 3=2 (2/3)
T
EN
D
U
ST
shifted and the next subtraction is carried out. But if the subtraction produces a negative result (A<0), the
M
dividend need be first restored by adding the divisor back before left shift A and Q and the next
subtraction:
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 17 of 90
CS8491-Computer Architecture Department of CSE & IT
The quotient (0010)2 is in register Q, and the reminder (0010)2 is in register A. The restoring division
requires two operations (subtraction followed by an addition to restore) for each zero in the quotient. But
non-restoring division only requires one operation (either addition or subtraction) for each bit in quotient.
FLOATING POINT ADDITION OPERATION
T
First, the exponent of one operand is subtracted from the other using the small ALU to determine which is
EN
larger and by how much. This difference controls the three multiplexors; from left to right, they select the
larger exponent, the significand of the smaller number, and the significand of the larger number. The
smaller significand is shifted right, and then the significands are added together using the big ALU. The
D
normalization step then shifts the sum left or right and increments or decrements the exponent. Rounding
U
then creates the final result, which may require normalizing again to produce the final result.
ST
The first step shifts the significand of the smaller number to the right until its corrected exponent matches
that of the larger number
• If sum is not normalized adjust it
• Adjust the exponent
• Whenever the exponent is increased or decreased check for overflow or underflow(Exponent
should fits in its field)
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 18 of 90
CS8491-Computer Architecture Department of CSE & IT
T
EN
D
U
ST
R
M
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 19 of 90
CS8491-Computer Architecture Department of CSE & IT
SUBWORD PARALLELISM
A subword is a lower precision unit of data contained within a word. In subword parallelism,
multiple subwords are packed into a word and then process whole words. With the appropriate subword
boundaries this technique results in parallel processing of subwords. Since the same instruction is applied
to all subwords within the word, This is a form of SIMD(Single Instruction Multiple Data) processing. It is
possible to apply subword parallelism to noncontiguous subwords of different sizes within a word. In
practical implementation is simple if subwords are same size and they are contiguous within a word. The
data parallel programs that benefit from subword parallelism tend to process data that are of the same size.
For example,
If word size is 64bits and subwords sizes are 8,16 and 32 bits. Hence an instruction operates on eight
8bit subwords, four 16bit subwords, two 32bit subwords or one 64bit subword in parallel.
Subword parallelism is an efficient and flexible solution for media processing because algorithm
exhibit a great deal of data parallelism on lower precision data.
It is also useful for computations unrelated to multimedia that exhibit data parallelism on lower
precision data.
Graphics and audio applications can take advantage of performing simultaneous operations on
short vectors
Also called data-level parallelism, vector parallelism, or Single Instruction, Multiple Data (SIMD)
ST
R
M
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 20 of 90
CS8491-Computer Architecture Department of CSE & IT
T
EN
D
U
ST
R
M
Processor datapath control signals can be classified according to which part of the processor they control:
State controls
Combinational controls
A processor's datapath is conceptually organized into two parts:
State elements hold information about the state of the processor during the current clock cycle. All
registers are state elements.
Combinational logic determines the state of the processor for the next clock cycle. The ALU is
combinational logic.
Single-cycle organization
It is characterized by the fact that each instruction is executed in a single clock cycle. It is not a realistic
implementation — it requires two separate memories: one for data and one for instructions. Also, the clock
cycle has to be made quite long in order for all of the signals generated in a cycle to reach stable values.
Multi-cycle organization
This organization uses multiple clock cycles for executing each instruction. Each cycle does only a small
part of the work required so the cycles are much shorter. Much of the circuitry is the same as the single-
cycle implementation. However, more state components must be added to hold data that is generated in an
early cycle but used in a later cycle.
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 21 of 90
CS8491-Computer Architecture Department of CSE & IT
Pipelined organization
Like the multicycle organization, the pipelined organization uses multiple clock cycles for executing each
instruction. By adding more state components for passing data and control signals between cycles, the
pipelined organization turns the circuitry into an assembly line. After the first cycle of one instruction has
completed you can start the execution of another instruction, while the first moves to its next cycle. Several
instructions can be in different phases of execution at the same time.
Register renaming organization
Register renaming is an extension of the pipelining idea. It deals with the data dependence problem for a
pipeline — the fact that instructions in the pipeline produce data needed by other instructions in the
pipeline.
T
EN
D
U
ST
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 22 of 90
CS8491-Computer Architecture Department of CSE & IT
T
When the 1bit control to a two way multiplexor is asserted, the multiplexor selects the input
EN
corresponding to 1. Otherwise, if the control is deasserted, the multiplexor selects the 0 input. Remember
that the state elements all have the clock as an implicit input and that the clock is used in controlling writes.
Gating the clock externally to a state element can create timing problems
D
The setting of the control lines is completely determined by the opcode fields of the instruction.
U
ST
R
M
The first row of the table corresponds to the R-format instructions (add, sub, AND, OR, and slt).
For all these instructions, the source register fields are rs and rt, and the destination register field is
rd; this defines how the signals ALUSrc and RegDst are set.
Furthermore, an R-type instruction writes a register (RegWrite = 1), but neither reads nor writes
data memory. When the Branch control signal is 0, the PC is unconditionally replaced with PC + 4;
otherwise, the PC is replaced by the branch target if the Zero output of the ALU is also high. The
ALUOp field for R‑type instructions is set to 10 to indicate that the ALU control should be
generated from the funct field.
The second and third rows of this table give the control signal settings for lw and sw. These
ALUSrc and ALUOp fields are set to perform the address calculation. The MemRead and
MemWrite are set to perform the memory access. Finally, RegDst and RegWrite are set for a load to
cause the result to be stored into the rt register.
The branch instruction is similar to an R-format operation, since it sends the rs and rt registers to the
ALU. The ALUOp field for branch is set for a subtract (ALU control = 01), which is used to test for equality.
Notice that the MemtoReg field is irrelevant when the RegWrite signal is 0: since the register is not being
written, the value of the data on the register data write port is not used. Thus, the entry MemtoReg in the
last two rows of the table is replaced with X for don‘t care. Don‘t cares can also be added to RegDst when
RegWrite is 0. This type of don‘t care must be added by the designer, since it depends on knowledge of
how the datapath works.
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 23 of 90
CS8491-Computer Architecture Department of CSE & IT
BUILDING DATAPATH
There are two basic types of logic components: combinational components and state components.
A combinational component behaves like a simple function. Its outputs depend only on the current
values of its inputs.
A state component behaves more like an object method. Its output also depends on the past history
of its inputs.
Combinational Components
The following are the combinational components in the diagram.
Multiplexers
Sign Ext
Adder
ALU
Control
ALU Control
PC Update Control
1.1 Multiplexers
T
A multiplexer is a logic component with multiple data inputs (X and Y), a single control input (Sel),
EN
and a single output (Out). At any time its output is the same as one of its inputs which is determined by
the control input. The number of bits in the output signal can in principle be any number. Each data input
has the same number of bits. A multiplexer can in principle have any number of data inputs. The control
D
signal has as many bits as needed for the selection. One bit suffices for just 2 data inputs, 2 bits suffices for
U
3 or 4 data inputs, and 3 bits suffices for 5 to 8 data inputs. In MIPS Single-Cycle Diagram, the three
multiplexers in the MIPS diagram all have just two 32-bit data inputs and their outputs are the same size.
ST
Since they have only two data inputs, their control inputs are just one bit.
1.2 Sign Extension
The Sign Ext component performs sign extension, converting a 16-bit 2's complement number to a 32-
R
bit 2's complement number. The low-order 16 bits of the output are the same as the input. The high-order
M
16 bits of the output are all copies of the sign (high-order) bit of the input.
1.3 Adder
An adder just performs binary addition of its two inputs to produce a sum output.
ALU
The ALU (Arithmetic-Logic Unit) can perform a number of different operations, combining its
two data inputs (X and Y) into a single primary output (Out). Typical operations include additions,
subtractions, and bitwise logical operations. The ALU also has a secondary output (cc) that encodes a
comparison of its inputs. It is a 2-bit signal. One bit is true when X = Y, the other when X > Y. The cc output
is only valid when the ALU is directed to do a subtraction.
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 24 of 90
CS8491-Computer Architecture Department of CSE & IT
The operation performed by the ALU is determined by a control signal (Op). For comparisons the control
signal usually directs the ALU to do a subtraction.
1.5 Control
The (main) control component uses the opcode field of the instruction to generate most of the control
signals.
T
EN
D
PC Update Control
U
The PC Update Control component handles program counter update as directed by a Branch control
signal and a comparison code (CC) signal from the ALU. It selects among addresses constructed from the
ST
incremented PC (PC+4), the instruction imm field, and the instruction targ field.
MIPS Single-Cycle Diagram
The comparison code is also a single bit: the zero output of the ALU, which indicates equality when
R
the ALU is directed to subtract. The implementation in following Figure only supports a branch on
M
equality and no jumps. In Figure, jumps are supported by adding a Jump control signal. We can view this
as converting the Branch signal into a 2-bit signal, though perhaps it should be renamed. Supporting a
variety of branch conditions requires additional information from the ALU about the comparison and
additional Branch control bits to indicate when branching should occur.
2. State Components
2.1 The Program Counter (PC)
The PC is just a simple 32-bit register. Its output (pc) is used as the address for Instruction Memory. It also
feeds into an adder to generate the default pc+4 value address of the next instruction. This is one of the
several inputs to the PC Update Control that it uses to generate its newpc output.
Program Counter Update
When the clock (not shown) starts a new cycle pc changes to match the newpc input. The newpc input is
generated by the PC Update Control circuitry.
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 25 of 90
CS8491-Computer Architecture Department of CSE & IT
2.2 Registers
The Registers component is a register bank — a component that contains multiple registers and provides
read and write access to them.
In the MIPS processor there are 32 registers in the Registers component. Each register consists of 32 flip-
flops, each storing 1 bit of data. In addition the component contains two read ports and one write port.
Read Port
The input signal RdReg1 and the output signal RdData1 make up the first read port. The input
signal RdReg2 and the output signal RdData2 make up the second read port.
The input signals, RdReg1 and RdReg2, are 5-bit signals that specify a register number.
The output signals, RdData1 and RdData2, are 32-bit signals. Their values are the contents of the
register specified by the port input signal.
Write Port
The input signals, WrReg and WrData, and the control input signal WrEn make up the write port.
WrReg specifies the register number for the register to be written.
WrData specifies the data to be written to the register.
WrEn enables the write when its value is 1. The write does not happen if WrEn is 0. This signal
is necessary because not all instructions write to a register.
T
EN
D
U
2.3Data Memory
The Data Memory component is actually just an interface to the bus that interconnects the processor, main
ST
memory, and I/O devices. Since other devices use this bus, an enable signal is required for both memory
reads and memory writes.
Note that the Address input is shared by both the read port and the write port.
R
Read Port
M
The input signal, Address, the output signal, RdData, and the control input signal RdEn make up the read
port.
The input signal Address is a 32-bit signal that specifies a memory address.
The output signal RdData is a 32-bit signal. Its value is the data at the address specified by
the Address input signal.
RdEn enables the read when its value is 1. The write does not happen if RdEn is 0. This signal is
necessary to ensure the processor does not access the bus except when it needs to.
Write Port
The input signals, Address and WrData, and the control input signal WrEn make up the write port.
The input signal Address is a 32-bit signal that specifies a memory address.
WrData specifies the data to be written at that address.
WrEn enables the write when its value is 1. The write does not happen if WrEn is 0. This signal
is necessary to ensure the processor does not access the bus except when it needs to.
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 26 of 90
CS8491-Computer Architecture Department of CSE & IT
2.4 Instruction Memory
Instruction Memory has a simple task: given a memory address input, fetch the instruction at that
address. Consequently, the interface to Instruction Memory is just a single read port. The input
signal Address is a 32-bit signal that specifies an instruction address. The output signal Instruction is a
32-bit signal. Its value is the instruction at the address specified by the Address input signal. For
convenience, the instruction is then broken up into its fields. Instruction Memory does not show a read
enable because it is automatic — in a single-cycle implementation an instruction is read every cycle.
DATA PATH AND ITS CONTROL
We can design the control unit logic, but before we do that, let‘s look at how each instruction uses the
datapath. In datapath of an R-type instruction, such as add $t1,$t2,$t3, everything occurs in one clock
cycle, we can think of four steps to execute the instruction; these steps are ordered by the flow of
information:
1. The instruction is fetched, and the PC is incremented.
2. Two registers, $t2 and $t3, are read from the register file; also, the main control unit computes the setting
of the control lines during this step.
3. The ALU operates on the data read from the register file, using the function code (bits 5:0, which is the
funct field, of the instruction) to generate the ALU function.
4. The result from the ALU is written into the register file using bits 15:11 of the instruction to select the
destination register ($t1).
T
EN
D
U
ST
R
M
Similarly, we can illustrate the execution of a load word, such as lw $t1, offset($t2)
1. An instruction is fetched from the instruction memory, and the PC is incremented.
2. A register ($t2) value is read from the register file.
3. The ALU computes the sum of the value read from the register file and the sign-extended, lower 16
bits of the instruction (offset).
4. The sum from the ALU is used as the address for the data memory.
5. The data from the memory unit is written into the register file; the register destination is given by bits
20:16 of the instruction ($t1).
Finally, we can show the operation of the branch-on-equal instruction, such as beq $t1,$t2,offset, in the
same fashion. It operates much like an R‑format instruction, but the ALU output is used to determine
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 27 of 90
CS8491-Computer Architecture Department of CSE & IT
whether the PC is written with PC + 4 or the branch target address.
1. An instruction is fetched from the instruction memory, and the PC is incremented.
2. Two registers, $t1 and $t2, are read from the register file.
3. The ALU performs a subtract on the data values read from the register file. The value of PC + 4 is
added to the sign-extended, lower 16 bits of the instruction (offset) shifted left by two; the result is the
branch target address.
4. The Zero result from the ALU is used to decide which adder result to store into the PC.
The simple datapath with the control unit :
The input to the control unit is the 6‑bit opcode field from the instruction. The outputs of the control
unit consist of three 1‑bit signals that are used to control multiplexors (RegDst, ALUSrc, and MemtoReg),
three signals for controlling reads and writes in the register file and data memory (RegWrite, MemRead,
and MemWrite), a 1‑bit signal used in determining whether to possibly branch (Branch), and a 2‑bit control
signal for the ALU (ALUOp). An AND gate is used to combine the branch control signal and the Zero
output from the ALU; the AND gate output controls the selection of the next PC. Notice that PCSrc is now
a derived signal, rather than one coming directly from the control unit.
INSTRUCTION PIPELINE WORKS
A pipelined computer executes instructions concurrently.
Consider a pipeline processor, which process each instruction in four steps;
F: Fetch, Read the instruction from the memory
D: decode, decode the instruction and fetch the source operand (S)
O: Operate, perform the operation
T
W: Write, store the result in the destination location
EN
D
U
ST
R
M
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 28 of 90
CS8491-Computer Architecture Department of CSE & IT
2. A substantial improvement in performance can be achieved by overlapping the execution of successive
instructions using a technique called pipelining. Pipelining is an effective way of organizing
concurrent activity in a computer system.
3. In a computer pipeline, each step in the pipeline completes the execution of a part of the instruction.
Different steps are completing different instructions in parallel. Each of these steps is called a pipeline
stage (or) pipeline segment.
4. Pipelining yields a reduction in the average execution time per instruction. It is an implementation
technique that exploits parallelism among the instructions in a sequential instruction stream.
Pipelining would not decrease the time required to complete the execution of one instruction, but
when we have multiple instructions to execute, the improvement in throughput decreases the total
time to complete the execution of the entire program.
Pipeline Performance (or) Speedup
The potential increase in performance resulting from pipelining is proportional to the number of
pipeline stages. If all the stages take about the same amount of time and there is enough work to do, then
the speed-up due to pipelining is equal to the number of stages in the pipeline.
If the stages are perfectly balanced, then the time between instructions on the pipelined processor –
assuming ideal conditions – is equal to
Under ideal conditions and with a large number of instructions, the speed-up from pipelining is
approximately equal to the number of pipeline stages; a five-stage pipeline is nearly five times faster.
Pipelining improves performance by increasing instruction throughput, as opposed to decreasing
T
the execution time of an individual instruction, but instruction throughput is the important metric because
EN
real programs execute billions of instructions.
MIPS PROCESSOR – PIPELINE STAGES
The same principles apply to processors where the pipeline instructions are in execution. MIPS
D
2. Read registers while decoding the instruction. The regular format of MIPS instructions allows
ST
A pipelined processor allows multiple instructions to execute at once, and each instruction uses a
different functional unit in the datapath. This increases throughput, so programs can run faster. One
instruction can finish executing on every clock cycle, and simpler stages also lead to shorter cycle times.
Example – Single-Cycle versus Pipelined Performance
Consider a simple program segment consists of eight instructions: lw, sw, add, sub, AND, OR, slt
and beq. Compare the average time between instructions of a single-cycle implementation, in which all
instructions take 1 clock cycle, to a pipelined implementation. The operation times for the major functional
units in this example are 200 ps for memory access, 200 ps for ALU operation, and 100 ps for register file
read or write.
Figure 3.29 shows the time required for each of the eight instructions. The single-cycle design must
allow for the slowest instruction – in Figure 3.29 it is lw – so the time required for every instruction is 800
ps. Thus, the time between the first and fourth instructions in the non-pipelined design is 3 x 800 ns or 2400
ps.
Figure 3.29 Total time for each instruction calculated from the time for each component
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 29 of 90
CS8491-Computer Architecture Department of CSE & IT
Figure 3.30 Single-Cycle, Non-Pipelined Execution in top versus Pipelined Execution in bottom.
All the pipeline stages take a single clock cycle, so the clock cycle must be long enough to
accommodate the slowest operation. Just as the single-cycle design must take the worst-case clock cycle of
T
800 ps, even though some instructions can be as fast as 500 ps, the pipelined execution clock cycle must
have the worst-case clock cycle of 200 ps, even though some stages take only 100 ps. Pipelining still offers a
EN
fourfold performance improvement; the time between the first and fourth instructions is 3 x 200 ps or 600
ps.
Pipelining suggests that a five-stage pipeline should offer nearly a fivefold improvement over the
D
800 ps non-pipelined time, or a 160 ps clock cycle. The above example shows that the stages may be
U
imperfectly balanced.
PIPELINED DATAPATH & its CONTROL
ST
The goal of pipelining is to allow multiple instructions execute at the same time. It may need to
perform several operations in a clock cycle such as increment the PC and add registers at the same time,
fetch one instruction while another one reads or writes data, etc,.
R
Pipelined Datapath
M
The division of an instruction into five stages means a five-stage pipeline, which in turn means that
up to five instructions will be in execution during any single clock cycle. Thus, it must separate the
datapath into five pieces, with each piece named corresponding to a stage of instruction execution.
1. IF: Instruction Fetch
2. ID: Instruction decode and register file read
3. EX: Execution or Address Calculation
4. MEM: Data Memory Access
5. WB: Write Back
In figure 3.1, these five components correspond roughly to the way the datapath is drawn;
instructions and data move generally from left to right through the five stages as they complete
execution.
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 30 of 90
CS8491-Computer Architecture Department of CSE & IT
T
datapath.
EN
The selection of the next value of the PC, choosing between the incremented PC and the branch
address from the MEM stage.
Data flowing from left does not affect the current instruction; only later instructions in the
D
pipeline are influenced by these reverse data movements. Note that the first right-to-left flow of data can
U
own datapath, and then to place these data paths on a timeline to show their relationship. Figure 3.2
shows the execution of the instructions by displaying their private data paths on a common timeline.
R
M
This figure seems to suggest that three instructions need three datapaths. Instead, add registers to
hold data so that portions of a single datapath can be shared during instruction execution. The
instruction memory is used during only one of the five stages of an instruction, allowing it to be shared
by following instructions during the other four stages. To retain the value of an individual instruction for
its other four stages, the value read from instruction memory must be saved in a register. Similar
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 31 of 90
CS8491-Computer Architecture Department of CSE & IT
arguments apply to every pipeline stage must be placed in registers.
Figure 3.3 shows the pipelined datapath with the pipeline registers highlighted. All instructions
advance during each clock cycle from one pipeline register to the next. The registers are named for the
two stages separated by that register. For example, the pipeline register between the IF and ID stages is
called IF/ID.
T
EN
Figure 3.3 The pipelined version of the datapath
D
Notice that there is no pipeline register at the end of the write-back stage. All instructions must
U
update some state in the processor – the register file, memory or the PC – so a separate pipeline register
is redundant to the state that is updated. Every instruction updates the PC, whether by incrementing it or
ST
by setting to a branch target address. The PC can be thought of as a pipeline register; one that feeds the IF
stage of the pipeline.
Unlike the shaded pipeline registers in the above figure, however, the PC is part of the visible
R
architectural state, its contents must be saved when an exception occurs, while the contents of the
M
1. Instruction Fetch:
Figure 3.34 shows the instruction being read from memory using the address in the PC and then being
placed in the IF/ID pipeline register. The PC address is incremented by 4 and then written back into the
PC to be ready for the next clock cycle. This incremented address is saved in the IF/ID pipeline register
in case it is needed later for an instruction, such as beq. The computer cannot know which type of
instruction is being fetched, so it must prepare for any instruction, passing potentially needed
information down the pipeline.
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 32 of 90
CS8491-Computer Architecture Department of CSE & IT
Figure 3.34 First stage (IF) of a Load instruction, with the active portions of the datapath
2. Instruction Decode and Read Register File Read: Figure 3.35 shows the instruction decode portion of
the IF/ID pipeline register supplying the 16-bit immediate field, which is sign-extended to 32-bits, and
the register numbers to read the two registers. All three values are stored in the ID/EX pipeline register,
along with the incremented PC address. We again transfer everything that might be needed by any
T
instruction during a later clock cycle.
EN
D
U
ST
R
M
Figure 3.35 Second stage (ID) of a Load instruction, with the active portions of the datapath in Figure 3.33 highlighted
1. Execute or Address Calculation: Figure 3.36 shows that the load reads the contents of register 1
and the sign-extended immediate from the ID/EX pipeline register and adds them using the
ALU. That sum is placed in the EX/MEM pipeline register.
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 33 of 90
CS8491-Computer Architecture Department of CSE & IT
Figure 3.36 Third stage (EX) of a Load instruction, with the active portions of the datapath in Figure 3.33 highlighted
2. Memory Access: Figure 3.37 shows the load instruction reading the data memory using the
address from the EX/MEM pipeline register and loading the data into the MEM/WB pipeline
register.
T
EN
D
U
ST
Figure 3.37 Fourth stage (MEM) of a Load instruction, with the active portions of the datapath in Figure 3.33 highlighted
R
3. Write-Back: Figure 3.38 shows the final step – reading the data from the MEM/WB pipeline
register and writing it into the register file in the middle of the figure.
M
Figure 3.38 Fifth stage (WB) of a Load instruction, with the active portions of the datapath in Figure 3.33 highlighted
1. Instruction Fetch: the instruction is read from memory using the address in the PC and then is
placed in the IF/ID pipeline register. This stage occurs before the instruction is identified, so the
figure 3.34 works for store as well.
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 34 of 90
CS8491-Computer Architecture Department of CSE & IT
Figure 3.39 First stage (IF) of a Store instruction, with the active portions of the datapath in Figure 3.33 highlighted – same as Figure 3.34
2. Instruction Decode and Read Register File: The instruction in the IF/ID pipeline register
supplies the register numbers for reading two registers and extends the sign of the 16-bit
immediate. These three 32-bit values are all stored in the ID/EX pipeline register. Figure 3.35 for
load instruction also shows the operations of the second stage for stores.
These first two stages are executed by all instructions, since it is too early to know the type of the
instruction.
T
EN
D
U
ST
Figure 3.40 Second stage (ID) of a Store instruction, with the active portions of the datapath in Figure 3.33 highlighted – same as Figure 3.35
3. Execute and Address Calculation: Figure 3.41 shows the third step of a store instruction in which
the effective address is placed in the EX/MEM pipeline register.
R
M
Figure 3.41 Third stage (EX) of a Store instruction, with the active portions of the datapath in Figure 3.33 highlighted
4. Memory Access: Figure 3.42 shows the data being written to memory. Note that the register
containing the data to be stored was read in an earlier stage and stored in ID/EX. The only way to
make the data available during the MEM stage is to place the data into the EX/MEM pipeline
register in the EX stage, just as we stored the effective address into EX/MEM.
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 35 of 90
CS8491-Computer Architecture Department of CSE & IT
Figure 3.42 Fourth stage (MEM) of a Store instruction, with the active portions of the datapath in Figure 3.33 highlighted
5. Write-Back: Figure 3.43 how the final step of the store. For this instruction, nothing happens in
the write-back stage. Since every instruction behind the store is already in progress, we have no
way to accelerate those instructions. Hence, an instruction passes through a stage even if there is
nothing to do, because later instructions are already progressing at the maximum rate.
T
EN
D
U
ST
R
M
Figure 3.43 Fifth stage (WB) of a Store instruction, with the active portions of the datapath in Figure 3.33 highlighted
The store instruction again illustrates that to pass information from an early pipe stage to a later pipe
stage, the information must be placed in a pipeline register; otherwise the information is lost when the
next instruction enters that pipeline stage. For the store instruction we needed to pass one of the registers
read in the ID stage to the MEM stage, where it is stored in memory. The data was first placed in the
ID/EX pipeline register and then passed to the EX/MEM pipeline register. Both load and store illustrate
a second key point: each logical component of the datapath – such as instruction memory, register read
ports, ALU, data memory and register write port – can be used only within a single pipeline stage.
Otherwise, we would have a structural hazard. Hence these components, and their control, can be
associated with a single pipeline stage.
To provide control in a pipelined datapath, the following task has to be followed:
The first step is to label the control lines on the existing datapath.
Borrow/ Use the control lines from the simple datapath.
Use the same ALU control logic, branch logic, destination-register-number multiplexor,
and control lines.
Figure 3.49 shows the pipelined datapath of a MIPS processor with the control signal identified.
In the case of a single-cycle implementation, we assume that the PC is written on each clock cycle, so
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 36 of 90
CS8491-Computer Architecture Department of CSE & IT
there is no separate write signal for the PC. By the same argument, there are no separate write signals for
the pipeline registers (IF/ID, ID/EX. EX/MEM, and MEM/WB), since the pipeline registers are also
written during each clock cycle.
T
EN
D
U
ST
The pipelined datapath of Figure 3.49, with the control signals connected to the control portions of the pipe line registers
Types of Hazards
M
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 37 of 90
CS8491-Computer Architecture Department of CSE & IT
Data Hazards
Data hazards arise when the execution of an instruction depends on the results of a previous
instruction in the pipeline.
Consider the following sequence of instructions:
sub $2, $1, $3
and $1, $2, $5
or $13, $6, $2
add $14, $2, $2
sw $15, 100($2)
Register $2 is used in all the five instruction, so last four instructions has to wait until the first
instruction was executed. The last four instructions are all dependent on the result in register $2 of the
first instruction. If register $2 had the value 10 before the subtract instruction and -20 afterwards, the
programmer intends that -20 will be used in the following instructions that refer to register $2.
Figure 3.52 illustrates the execution of these instructions using a multiple clock-cycle pipeline
representation. To demonstrate the execution of this instruction sequence in our current pipeline, the top
of this figure shows the value of register $2, which changes during the middle of clock cycle 5, when the
sub instruction writes its result.
The last potential hazard can be resolved by the design of the register file hardware: what
happens when a register is read and written in the same clock cycle? Assume that the write is in the first
half of the clock cycle and the read is in the second half, so the read delivers what is written. As is the
case for many implementations of register files, there is no data hazard in this case.
T
EN
D
U
ST
R
M
Figure 3.52 Pipelined dependences in a five-instruction sequence using simplified datapaths to show the dependences
This figure shows that the values read for register $2 would not be the result of the sub
instruction unless the read occurred during clock cycle 5 or later. Thus, the instructions that would get
the correct value of -20 are add and sw; the AND and OR instructions would get the incorrect value of
10. Using this style of drawing, such problems become apparent when a dependence line goes backward
in time.
However, the desired result is available at the end of the EX stage or clock cycle 3. Thus, it is
possible to execute this segment without stalls if simply forward the data as soon as it is available to any
units that need it before it is available to read from the register file. Consider only the challenge of
forwarding to an operation in the EX stage, which may be either an ALU operation or an effective
address calculation. This means that when an instruction tries to use a register in its EX stage that an
earlier instruction intends to write in its WB stage, actually need the values as inputs to the ALU.
A notation that names the fields of the pipeline registers allows for a more precise notation of
dependences. For example, ―ID/EX.RegisterRs‖ refers to the number of one register whose value is
found in the pipeline register ID/EX; that is, the one from the first read port of the register file. The first
part of the name, to the left of the period, is the name of the pipeline register; the second part is the name
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 38 of 90
CS8491-Computer Architecture Department of CSE & IT
of the field in that register.
Using this notation, the two pairs of hazard conditions are
1a. EX/MEM.RegisterRd = ID/EX.RegisterRs
1b. EX/MEM.RegisterRd = ID/EX.RegisterRt
2a. MEM/WB.RegisterRd = ID/EX.RegisterRs
2b. MEM / WB.RegisterRd = ID/EX.RegisterRt
The first hazard will occur in register $2 between the result of sub $2, $1, $3 and the first read
operand of and $12, $2, $5. This hazard can be detected when the add instruction is in the EX stage and
the prior instruction is in the MEM stage, so this belongs to hazard 1a:
EX/MEM.RegisterRd = ID/EX.RegisterRs = $2.
The remaining hazards are as follows:
The sub-or is a type 2b hazard: MEM/WB.RegisterRd = ID/EX.RegisterRt = $2.
The two dependences on sub-add are not hazards because the register file supplies the proper
data during the ID stage of add.
There is no data hazard between sub and sw because sw reads $2 the clock cycle after sub
writes $2.
Let‘s now write both the conditions for detecting hazards and the control signals to resolve them:
Data Hazards and Stalls
One case where forwarding cannot work is when an instruction tries to read a register following a
load instruction that writes the same register. Figure 3.57 illustrates the problem. The data is still being
read from memory in clock cycle 4 while the ALU is performing the operation for the following
instruction. Something must stall the pipeline for the combination of load followed by an instruction that
T
reads its result.
EN
D
U
ST
R
M
Hence, in addition to a forwarding unit, need a hazard detection unit. It operates during the ID
stage so that it can insert the stall between the load and its use. Checking for load instructions, the
control for the hazard detection unit is this single condition:
ID/EX.MemRead and
((ID/EX.RegisterRt = IF/ID.RegisterRs) or (ID/EX.RegisterRt = IF/ID.RegisterRt))
If detected, stall and insert bubble
If the instruction in the ID stage is stalled, then the instruction in the IF stage must also be stalled;
otherwise, lose the fetched instruction. Preventing these two instructions from making progress is
accomplished simply by preventing the PC register and the IF/ID pipeline register from changing.
Provided these registers are preserved, the instruction in the IF stage will continue to read using the
same PC, and the registers in the ID stage will continue to be read using the same instruction fields in the
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 39 of 90
CS8491-Computer Architecture Department of CSE & IT
IF/ID pipeline register.
The back half of the pipeline starting with the EX stage must be doing something; what it is doing
is executing instructions that have no effect: nop‘s. By deasserting all nine control signals (setting them to
0) in the EX, MEM, and WB stages will create a ―do nothing‖ or nop instruction. By identifying the
hazard in the ID stage, we can insert a bubble into the pipeline by changing the EX, MEM, and WB
control fields of the ID/EX pipeline register to 0. These control values are forwarded at each clock cycle
with the proper effect: no registers or memories are written if the control values are all 0.
Figure 3.58 shows what really happens in the hardware: the pipeline execution slot associated
with the AND instruction is turned into a nop and all instructions beginning with the AND instructions
are delayed one clock cycle. Like an air bubble in a water pipe, a stall bubble delays everything behind it
and proceeds down the instruction pipe one stage each cycle until it exits at the end.
T
EN
D
U
ST
Figure 3.58 The way stalls are really inserted into the pipeline
Figure 3.59 highlights the pipeline connections for both the hazard detection unit and the
R
forwarding unit. As before, the forwarding unit controls the ALU multiplexors to replace the value from
a general-purpose register with the value from the proper pipeline register. The hazard detection unit
M
controls the writing of the PC and IF/ID registers plus the multiplexor that chooses between the real
control values and all 0‘s. The hazard detection unit stalls and deasserts the control fields if the load-use
hazard test above is true.
Figure 3.59 Pipelined control overview, showing the two multiplexors for forwarding, the hazard detection unit, and the forwarding unit
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 40 of 90
CS8491-Computer Architecture Department of CSE & IT
Control Hazards
Control hazards occur when execute branch instructions in a pipeline process. It arises from the
need to make a decision based on the results of one instruction while others are executing.
Figure 3.60 shows a sequence of instructions and indicates when the branch would occur in this
pipeline. An instruction must be fetched at every clock cycle to sustain the pipeline, yet in our design the
decision about whether to branch doesn‘t occur until the MEM pipeline stage. This delay in determining
the proper instruction to fetch is called a control hazard or branch hazard or instruction hazard.
T
EN
Figure 3.60 The impact of the pipeline on the branch instruction
Control hazards are relatively simple to understand, they occur less frequently than data hazards,
D
and there is nothing as effective against control hazards as forwarding is against data hazards. We look
U
at two schemes for resolving control hazards and one optimization to improve these schemes.
Branch Not Taken:
ST
Stalling until the branch is complete is too slow. A common improvement over branch stalling is
to assume that the branch will not be taken and thus continue execution down the sequential instruction
stream. If the branch is taken, the instructions that are being fetched and decoded must be discarded.
R
Execution continues at the branch target. If branches are untaken half the time, and if it costs little to
discard the instructions, this optimization halves the cost of control hazards.
M
To discard instructions, merely change the original control values to 0s, similar to the one used to
stall for a load-use data hazard. The difference is that change the three instructions in the IF,ID, and EX
stages when the branch reaches the MEM stage. Discarding instructions, means it must be able to flush
instructions in the IF, ID, and EX stages of the pipeline.
Reducing the Delay of Branches:
One way to improve branch performance is to reduce the cost of the taken branch. So far, we have
assumed the next PC for a branch is selected in the MEM stage, but if we move the branch execution
earlier in the pipeline, then fewer instructions need be flushed. The MIPS architecture was designed to
support fast single-cycle branches that could be pipelined with a small branch penalty.
Moving the branch decision up requires two actions to occur earlier:
Computing the Branch Target Address and
Evaluating the Branch Decision.
Computing the Branch Target Address:
The easy part of this change is to move up the branch address calculation. We already have the
PC value and the immediate field in the IF/ID pipeline register, so we just move the branch adder from
the EX stage to the ID stage; of course, the branch target address calculation will be performed for all
instructions, but only used when needed.
Evaluating the Branch Decision:
The harder part is the branch decision itself. For branch equal, we would compare the two
registers read during the ID stage to see if they are equal. Equality can be tested by first exclusive ORing
their respective bits and then ORing all the results. Moving the branch test to the ID stage implies
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 41 of 90
CS8491-Computer Architecture Department of CSE & IT
additional forwarding and hazard detection hardware, since a branch dependent on a result still in the
pipeline must still work properly with this optimization.
For example, to implement branch on equal, we will need to forward results to the equality test
logic that operates during ID. There are two complicating factors:
During ID, we must decode the instruction, decide whether a bypass to the equality unit is
needed, and complete the equality comparison so that if the instruction is a branch, we can set the
PC to the branch target address. Forwarding for the operands of branches was formerly handled
by the ALU forwarding logic, but the introduction of the equality test unit in ID will require new
forwarding logic.
Because the values in a branch comparison are needed during ID but may be produced later in
time, it is possible that a data hazard can occur and a stall will be needed.
Despite these difficulties, moving the branch execution to the ID stage is an improvement, because it
reduces the penalty of a branch to only one instruction if the branch is taken, namely, the one currently
being fetched.
To flush the instructions in the IF stage, add a control line, called IF.Flush, that zeros the
instruction field of the IF/ID pipeline register. Clearing the register transforms the fetched instruction
into a nop, an instruction that has no action and changes no state.
Branch Prediction:
Branch prediction is a technique for predicting branch penalty associated with conditional
branches is to attempt to predict whether or not a particular branch will be taken or not. There are two
forms of branch prediction techniques. They are
Static Branch Prediction
T
Dynamic Branch Prediction
EN
Static Branch Prediction
The simplest form of branch prediction is to assume that the branch will not take place and to
continue to fetch instructions in sequential address order, until the branch condition is evaluated,
D
instruction execution along the predicted path must be done on a speculative basis.
For the simple five-stage pipeline, possibly coupled compiler-based prediction is probably
U
adequate. With deeper pipelines, the branch penalty increases when measured in clock cycles. Similarly,
ST
with multiple issue, the branch penalty increases in terms of instructions lost. This combination means
that in an aggressive pipeline, a simple static prediction scheme will probably waste too much
performance.
R
approach is to look up the address of the instruction to see if a branch was taken the last time this
instruction was executed, and if so, to begin fetching new instructions from the same place as the last
time. This technique is called dynamic branch prediction.
One-bit Prediction Scheme:
One implementation of that approach is a branch prediction buffer or branch history table. A
branch prediction buffer is a small memory indexed by the lower portion of the address of the branch
instruction. The memory contains a bit that says whether the branch was recently taken or not.
This is the simplest form of buffer, in fact, if the prediction is the right one – it may have been put
there by another branch that has the same low-order address bits. However, this doesn‘t affect
correctness.
This simple 1-bit prediction scheme has a performance shortcoming: even if a branch is almost
always taken, we can predict incorrectly twice, rather than once, when it is not taken.
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 42 of 90
CS8491-Computer Architecture Department of CSE & IT
Figure 3.61 The ID stage of clock cycle 3 determines that a branch must be taken, so it selects 72 as the next PC address and zeros the
T
instruction fetched for the next clock cycle
Two-bit Prediction Scheme:
EN
The accuracy of the predictor would match the taken branch frequency for these highly regular
branches. To remedy this weakness, the 2-bit prediction schemes are often used. In a 2-bit scheme, a
prediction must be wrong twice before it is changed.
D
Data Hazards
When a planned instruction cannot execute in the proper clock cycle because data that is needed
ST
to execute the instruction is not yet available. A data hazard is any condition in which either the source
or the destination operands of an instruction are not available at the time expected in the pipeline. As a
result, some operation has to be delayed and the pipeline stalls. In a computer pipeline, data hazards
R
arise from the dependence of one instruction on an earlier one that is still in the pipeline. For example,
suppose an add instruction followed immediately by a subtract instruction that uses the sum ($s0).
M
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 43 of 90
CS8491-Computer Architecture Department of CSE & IT
Figure 3.49 The pipelined data path with the control signals identified
To specify control for the pipeline, need only to set the control values during each pipeline stage.
Because each control line is associated with a component active in only a single pipeline stage, divide the
control lines into five groups according to the pipeline stage.
1. Instruction Fetch: The control signals to read instruction memory and to write the PC are always
T
asserted, so there is nothing special to control in this pipeline stage.
2. Instruction Decode / Register File Read: As in the previous stage, the same thing happens at
EN
every clock cycle, so there are no optional control lines to set.
3. Execution / Address Calculation: The signals to be set are RegDst, ALUop, and ALUSrc. These
D
signals select the result register, the ALU operation, and either read data 2 or a sign-extended
immediate for the ALU.
U
4. Memory Access: The control lines set in this stage are Branch, MemRead, and MemWrite. These
ST
signals are set by the branch equal, load, and store instructions, respectively. The PCSrc selects
the next sequential address unless control asserts Branch and the ALU result was 0.
5. Write Back: The two control lines are MemtoReg, which decides between sending the ALU result
or the memory value to the register file, and RegWrite, which writes the chosen value.
R
Since the control lines start with the EX stage, create the control information during instruction
M
decode. Figure 3.50 shows that these control signals are then used in the appropriate pipeline stage as
the instruction moves down the pipeline, just as the destination register number for loads moves down
the pipeline.
Figure 3.51 shows the full datapath with the extended pipeline registers and with the control lines connected to the proper stage
Implementing control means setting the nine control lines to these values in each stage for each
instruction. The simplest way to do this is to extend the pipeline registers to include control information.
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 44 of 90
CS8491-Computer Architecture Department of CSE & IT
CONTROL HAZARDS
Control hazards occur when execute branch instructions in a pipeline process. It arises from the
need to make a decision based on the results of one instruction while others are executing. Figure 3.60
shows a sequence of instructions and indicates when the branch would occur in this pipeline. An
instruction must be fetched at every clock cycle to sustain the pipeline, yet in our design the decision
about whether to branch doesn‘t occur until the MEM pipeline stage. This delay in determining the
proper instruction to fetch is called a control hazard or branch hazard or instruction hazard.
T
EN
Figure 3.60 The impact of the pipeline on the branch instruction
Control hazards are relatively simple to understand, they occur less frequently than data hazards,
D
and there is nothing as effective against control hazards as forwarding is against data hazards. Two
schemes for resolving control hazards and one optimization to improve these schemes.
U
Stalling until the branch is complete is too slow. A common improvement over branch stalling is
to assume that the branch will not be taken and thus continue execution down the sequential instruction
stream. If the branch is taken, the instructions that are being fetched and decoded must be discarded.
R
Execution continues at the branch target. If branches are untaken half the time, and if it costs little to
discard the instructions, this optimization halves the cost of control hazards.
M
To discard instructions, merely change the original control values to 0s, similar to the one did to
stall for a load-use data hazard. The difference is that must also change the three instructions in the IF,ID,
and EX stages when the branch reaches the MEM stage. Discarding instructions, means must be able to
flush instructions in the IF, ID, and EX stages of the pipeline.
Reducing the Delay of Branches:
One way to improve branch performance is to reduce the cost of the taken branch. So far,
assumed the next PC for a branch is selected in the MEM stage, but if move the branch execution earlier
in the pipeline, then fewer instructions need be flushed. The MIPS architecture was designed to support
fast single-cycle branches that could be pipelined with a small branch penalty.
Moving the branch decision up requires two actions to occur earlier:
Computing the Branch Target Address and
Evaluating the Branch Decision.
Computing the Branch Target Address:
The easy part of this change is to move up the branch address calculation. It is already have the
PC value and the immediate field in the IF/ID pipeline register, so just move the branch adder from the
EX stage to the ID stage; of course, the branch target address calculation will be performed for all
instructions, but only used when needed.
Evaluating the Branch Decision:
The harder part is the branch decision itself. For branch equal, we would compare the two
registers read during the ID stage to see if they are equal. Equality can be tested by first exclusive ORing
their respective bits and then ORing all the results. Moving the branch test to the ID stage implies
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 45 of 90
CS8491-Computer Architecture Department of CSE & IT
additional forwarding and hazard detection hardware, since a branch dependent on a result still in the
pipeline must still work properly with this optimization.
For example, to implement branch on equal, need to forward results to the equality test logic that
operates during ID. There are two complicating factors:
1. During ID, decode the instruction, decide whether a bypass to the equality unit is needed, and
complete the equality comparison so that if the instruction is a branch, then set the PC to the
branch target address. Forwarding for the operands of branches was formerly handled by the
ALU forwarding logic, but the introduction of the equality test unit in ID will require new
forwarding logic.
2. Because the values in a branch comparison are needed during ID but may be produced later in
time, it is possible that a data hazard can occur and a stall will be needed.
Despite these difficulties, moving the branch execution to the ID stage is an improvement, because it
reduces the penalty of a branch to only one instruction if the branch is taken, namely, the one currently
being fetched.
To flush the instructions in the IF stage, add a control line, called IF.Flush, that zeros the
instruction field of the IF/ID pipeline register. Clearing the register transforms the fetched instruction
into a nop, an instruction that has no action and changes no state.
Branch Prediction:
Branch prediction is a technique for predicting branch penalty associated with conditional
branches is to attempt to predict whether or not a particular branch will be taken or not. There are two
forms of branch prediction techniques. They are
1. Static Branch Prediction
T
2. Dynamic Branch Prediction
EN
Static Branch Prediction :
The simplest form of branch prediction is to assume that the branch will not take place and to
continue to fetch instructions in sequential address order, until the branch condition is evaluated,
D
instruction execution along the predicted path must be done on a speculative basis.
Assuming a branch is not taken is one simple form of branch prediction. In that case, predict that
U
branches are untaken, flushing the pipeline when go wrong. For the simple five-stage pipeline, possibly
ST
coupled compiler-based prediction is probably adequate. With deeper pipelines, the branch penalty
increases when measured in clock cycles. Similarly, with multiple issues, the branch penalty increases in
terms of instructions lost. This combination means that in an aggressive pipeline, a simple static
R
With more hardware it is possible to try to predict branch behavior during program execution.
One approach is to look up the address of the instruction to see if a branch was taken the last time this
instruction was executed and if so, to begin fetching new instructions from the same place as the last
time. This technique is called dynamic branch prediction.
One-bit Prediction Scheme:
One implementation of that approach is a branch prediction buffer or branch history table. A
branch prediction buffer is a small memory indexed by the lower portion of the address of the branch
instruction. The memory contains a bit that says whether the branch was recently taken or not.
This is the simplest form of buffer, in fact, if the prediction is the right one – it may have been put
there by another branch that has the same low-order address bits. However, this doesn‘t affect
correctness.
Prediction is just a hint that we hope is correct, so fetching begins in the predicted direction. If the
hint turns out to be wrong, the incorrectly predicted instructions are deleted, the prediction bit is
inverted and stored back, and the proper sequence is fetched and executed.
This simple 1-bit prediction scheme has a performance shortcoming: even if a branch is almost always
taken, can predict incorrectly twice, rather than once, when it is not taken.
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 46 of 90
CS8491-Computer Architecture Department of CSE & IT
T
Figure 3.61 The ID stage of clock cycle 3 determines that a branch must be taken, so it selects 72 as the next PC address and zeros the
EN
instruction fetched for the next clock cycle
The accuracy of the predictor would match the taken branch frequency for these highly regular
branches. To remedy this weakness, the 2-bit prediction schemes are often used. In a 2-bit scheme, a
U
prediction must be wrong twice before it is changed. Figure 3.62 shows the finite-state machine for a 2-bit
ST
prediction scheme.
R
M
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 47 of 90
CS8491-Computer Architecture Department of CSE & IT
T
branching has lost popularity compared to more expensive but more flexible dynamic approaches.
EN
Simultaneously, the growth in available transistors per chip has made dynamic prediction relatively
cheaper.
EXCEPTION HANDLING
D
Types of Exceptions:
U
The two types of exceptions that our current implementation can generate are :
a. Execution of an undefined instruction and
ST
b. Arithmetic overflow.
Undefined Instruction Exception
The basic action that the processor must perform when an exception occurs is to save the address
R
of the offending instruction in the exception program counter (EPC) and then transfer control to the
operating system at some specified address.
M
The OS can then take the appropriate action, which may involve providing some service to the
user program, taking some predefined action in response to an overflow, or stopping the execution of the
program and reporting an error. After performing whatever action is required because of the exception,
the operating system can terminate the program or may continue its execution, using the EPC to
determine where to restart the execution of the program.
For the OS to handle the exception, it must know the reason for the exception, in addition to the
instruction that caused it. There are two main methods used to communicate the reason for an exception.
1. The method used in the MIPS architecture is to include a status register (called the cause register),
which holds a field that indicates the reason for the exception.
2. A second method is to use vectored interrupts. In a vectored interrupt, the address to which control
is transferred is determined by the cause of the exception.
For example, to accommodate the two exception types listed above, define the following two exception
vector addresses:
T
EN
D
U
ST
R
M
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 49 of 90
CS8491-Computer Architecture Department of CSE & IT
(EPC). In reality, save the address+4, so the exception handling routine must first subtract 4 from the
saved value.
Figure (a) shows the events, starting with the add instruction in the EX stage. The overflow is
detected during that phase, and 8000 0180 is forced into the PC. Clock cycle 7 shows that the add and
following instructions are flushed, and the first instruction of the exception code is fetched. With five
instructions active in any clock cycle, the challenge is to associate an exception with the appropriate
instruction. Moreover, multiple exceptions can occur simultaneously in a single clock cycle. The solution
is to prioritize the exceptions so that it is easy to determine which is serviced first. In most MIPS
implementations, the hardware sorts exceptions so that the earliest instruction is interrupted.
I/O device requests and hardware malfunctions are not associated with a specific instruction, so
the implementation has some flexibility as to when to interrupt the pipeline. Hence, the mechanism used
for other exceptions works just fine.
The EPC captures the address of the interrupted instructions, and the MIPS cause register records
all possible exceptions in a clock cycle, so the exception software must match the exception to the
instruction. An important clue is known in which pipeline stage a type of exception can occur. For
example, an undefined instruction is discovered in the ID stage, and invoking the operating system
occurs in the EX stage. Exceptions are collected in the Cause register in a pending exception field so that
the hardware can interrupt based on later exceptions, once the earliest one has been serviced.
T
EN
D
U
ST
R
M
Figure(a): The result of an exception due to arithmetic overflow in the add instruction
Imprecise Exceptions
It is also called as imprecise interrupt. Interrupts or exceptions in pipelined computer that are not
associated with the exact instruction that was the cause of the interrupt or exception.
Precise Exceptions:
It is also called as precise interrupt. An interrupt or exception that is always associated with the
correct instruction in pipelined computers.
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 50 of 90
CS8491-Computer Architecture Department of CSE & IT
UNIT IV PARALLELISM
Parallel processing challenges – Flynn‗s classification – SISD, MIMD, SIMD, SPMD, and Vector
Architectures - Hardware multithreading – Multi-core processors and other Shared Memory
Multiprocessors - Introduction to Graphics Processing Units, Clusters, Warehouse Scale Computers and
other Message-Passing Multiprocessors.
CHALLENGES IN PARALLEL PROCESSING
Instruction Level Parallel Processing:
Architectural technique that allows the overlap of individual machine operations ( add, mul,
load, store …)
Multiple operations will execute in parallel (simultaneously)
Goal: Speed Up the execution
Example:
load R1 R2 add R3 R3, ―1‖
add R3 R3, ―1‖ add R4 R3, R2
add R4 R4, R2 store [R4] R0
Sequential execution (Without ILP)
Add r1, r2 r8 4 cycles
Add r3, r4 r7 4 cycles Total of 8 cycles
ILP execution (overlap execution)
Add r1, r2 r8
T
Add r3, r4 r7 Total of 5 cycles
EN
ILP Architectures
Sequential Architectures: the program is not expected to convey any explicit information regarding
parallelism. (Superscalar processors)
D
Dependence Architectures: the program explicitly indicates the dependences that exist between
U
Overlap individual machine operations (add, mul, load…) so that they execute in parallel
Transparent to the user
M
T
BNE R1, R2, LOOP
Control Dependence
EN
A control dependence determines the ordering of an instruction i, with respect to a branch instruction so
that the instruction i is executed in correct program order.
D
Example:
If p1 { S1; };
U
If p2 { S2; };
ST
Resource Dependence
An instruction is resource-dependent on a previously issued instruction if it requires a hardware
M
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 52 of 90
CS8491-Computer Architecture Department of CSE & IT
one slot.
The ALU and data transfer instructions are issued at the same time.
Here we have assumed the same five-stage structure as used for the single-issue pipeline. Although
this is not strictly necessary, it does have some advantages.
In particular, keeping the register writes at the end of the pipeline simplifies the handling of
exceptions and the maintenance of a precise exception model, which become more difficult in multiple-
issue processors.
T
EN
Reorder the instructions to avoid as many pipeline stalls as possible. Assume branches are predicted, so
D
The first three instructions have data dependences, and so do the last two. The following table shows the
best schedule for these instructions. Notice that just one pair of instructions has both issue slots used. I t
ST
takes four clocks per loop iteration; at four clocks to execute five instructions, we get the disappointing
CPI of 0.8 versus the best case of 0.5., or an I P C of 1.25 versus 2.0. Notice that in computing CPI or IPC,
we do not count any nops executed as useful instructions. Doing so would improve CPI, but not
R
performance!
M
The scheduled code as it would look on a two-issue MIPS pipeline. The empty slots are nops.
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 53 of 90
CS8491-Computer Architecture Department of CSE & IT
T
EN
Dynamic pipeline scheduling chooses which instructions to execute next, possibly reordering them to
avoid stalls. In such processors, the pipeline is divided into three major units: an instruction fetch and
issue unit, multiple functional units (a dozen or more in high-end designs in 2008), and a commit unit.
D
The first unit fetches instructions, decodes them, and sends each instruction to a corresponding
U
functional unit for execution. Each functional unit has buffers, called reservation stations, which
hold the operands and the operation.
ST
As soon as the buffer contains all its operands and the functional unit is ready to execute, the
result is calculated.
When the result is completed, it is sent to any reservation stations waiting for this particular
R
result as well as to the commit unit, which buffers the result until it is safe to put the result into
M
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 54 of 90
CS8491-Computer Architecture Department of CSE & IT
Flynn’s Classification Of Computer Architectures
SISD or Single Instruction stream, Single Data stream. A uniprocessor.
SIMD or Single Instruction stream, Multiple Data streams. A multiprocessor. The same
instruction is applied to many data streams, as in a vector processor or array processor.
MIMD or Multiple Instruction streams, Multiple Data streams. A multiprocessor.
SPMD Single Program, Multiple Data streams. The conventional MIMD programming model,
where a single program runs across all processors.
VECTOR
SISD
SISD (Singe-Instruction stream, Singe-Data stream)
SISD corresponds to the traditional mono-processor ( von Neumann computer). A single data stream
is being processed by one instruction stream OR
A single-processor computer (uni-processor) in which a single stream of instructions is generated from
the program.
T
EN
where CU= Control Unit, PE= Processing Element, M= Memory
SIMD
D
U
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 55 of 90
CS8491-Computer Architecture Department of CSE & IT
MISD
MISD (Multiple-Instruction streams, Singe-Data stream)
Each processor executes a different sequence of instructions.
In case of MISD computers, multiple processing units operate on one single-data stream
In practice, this kind of organization has never been used.
MIMD
MIMD (Multiple-Instruction streams, Multiple-Data streams)
Each processor has a separate program.
An instruction stream is generated from each program.
Each instruction operates on different data.
This last machine type builds the group for the traditional multi-processors. Several processing
units operate on multiple-data streams.
T
EN
D
U
ST
VECTOR
An older and more elegant interpretation of SIMD is called a vector architecture, which has been closely
identified with Cray Computers. It is again a great match to problems with lots of data-level parallelism.
R
Rather than having 64 ALUs perform 64 additions simultaneously, like the old array processors, the
M
vector architectures pipelined the ALU to get good performance at lower cost. The basic philosophy of
vector architecture is to collect data elements from memory, put them in order into a large set of
registers, operate on them sequentially in registers, and then write the results back to memory. A key
feature of vector architectures is a set of vector registers. Thus, a vector architecture might have 32 vector
registers, each with 64 64-bit elements.
T
or 256 8-bit data elements. Generally, vector architectures are a very efficient way to execute data parallel
EN
processing programs; they are better matches to compiler technology than multimedia extensions; and
they are easier to evolve over time than the multimedia extensions to the x86 architecture.
HARDWARE MULTITHREADING
D
Hardware multithreading allows multiple threads to share the functional units of a single
processor in an overlapping fashion. To permit this sharing, the processor must duplicate the
U
For example,
1. Each thread would have a separate copy of the register file and the PC.
2. The memory itself can be shared through the virtual memory mechanisms, which already support
R
multiprogramming.
There are two main approaches to hardware multithreading.
M
Fine-grained Multithreading:
It switches between threads on each instruction, resulting in interleaved execution of multiple
threads. This interleaving is often done in a roundrobin fashion, skipping any threads that are stalled at
that time. To make fine-grained multithreading practical, the processor must be able to switch threads
on every clock cycle.
Advantage
o It can hide the throughput losses that arise from both short and long stalls, since instructions from
other threads can be executed when one thread stalls.
Disadvantage
o It slows down the execution of the individual threads, since a thread that is ready to execute
without stalls will be delayed by instructions from other threads.
Coarse-grained multithreading :
It switches threads only on costly stalls, such as second-level cache misses. This change relieves the
need to have thread switching be essentially free and is much less likely to slow down the execution of
an individual thread, since instructions from other threads will only be issued when a thread encounters
a costly stall. Coarse-grained multithreading suffers, however, from a major drawback: it is limited in its
ability to overcome throughput losses, especially from shorter stalls.
Limitation:
o The pipeline start-up costs of coarse-grained multithreading.
o Because a processor with coarse-grained multithreading issues instructions from a single thread,
when a stall occurs, the pipeline must be emptied or frozen.
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 57 of 90
CS8491-Computer Architecture Department of CSE & IT
o The new thread that begins executing after the stall must fill the pipeline before instructions will
be able to complete.
o Due to this start-up overhead, coarse-grained multithreading is much more useful for reducing
the penalty of high-cost stalls, where pipeline refill is negligible compared to the stall time.
Simultaneous multithreading (SMT):
It is a variation on hardware multithreading that uses the resources of a multiple-issue, dynamically
scheduled processor to exploit thread-level parallelism at the same time it exploits instruction-level
parallelism.
Motivation of SMT:
SMT is that multiple-issue processors often have more functional unit parallelism available than a
single thread can effectively use. Furthermore, with register renaming and dynamic scheduling,
multiple instructions from independent threads can be issued without regard to the dependences
among them. The resolution of the dependences can be handled by the dynamic scheduling capability.
SMT is always executing instructions from multiple threads, leaving it up to the hardware to associate
instruction slots and renamed registers with their proper threads.
For example,
1. The Sun UltraSPARC T2 (Niagara 2) microprocessor is an example of a return to simpler
microarchitectures and hence the use of fine-grained multithreading.
2. Second, a key performance challenge is tolerating latency due to cache misses. Fine-grained
computers like the UltraSPARC T2 switch to another thread on a miss, which is probably more effective
in hiding memory latency than trying to fill unused issue slots as in SMT.
3. The goal of hardware multithreading is to use hardware more efficiently by sharing components
T
between different tasks. Multicore designs share resources as well. For example, two processors might
share a floating- point unit or an L3 cache. Such sharing reduces some of the benefits of multithreading
EN
compared with providing more non-multithreaded cores.
MULTI-CORE PROCESSORS AND OTHER SHARED MEMORY MULTIPROCESSORS
D
A shared memory multiprocessor (SMP) is one that offers the programmer a single physical
address space across all processors—which is nearly always the case for multicore chips—although a
U
more accurate term would have been shared-address multiprocessor. Processors communicate through
ST
shared variables in memory, with all processors capable of accessing any memory location via loads and
stores. Figure 6.7 shows the classic organization of an SMP. Note that such systems can still run
independent jobs in their own virtual address spaces, even if they all share a physical address space.
Centralized Shared Memory Architecture
R
Advantages
Each processor has its own local memory system
More total bandwidth in the memory system than in a centralized memory system
The latency to complete a memory request is lower─ each processor‘s memory is located
physically close to it
Disadvantages
Only some of the data in the memory is directly accessible by each processor, since a processor
T
can only read and write its local memory system
EN
Requires communication through the network and leads to the coherence problem─ major source
of complexity in shared-memory systems
Possible that could exist in different processors‘ memories • Leads to different processors having
D
All computers are now parallel computers. Multi-core processors represent an important new trend
ST
in computer architecture. Decreased power consumption and heat generation. Minimized wire lengths
and interconnect latencies. They enable true thread-level parallelism with great energy efficiency and
scalability. To utilize their full potential, applications will need to move from a single to a multi-
R
threaded model. Parallel programming techniques likely to gain importance. The difficult problem is
M
not building multi-core hardware, but programming it in a way that lets mainstream applications
benefit from the continued exponential growth in CPU performance. The software industry needs to get
back into the state where existing applications run faster on new hardware.
Challenges resulting from Multicore:
Relies on effective exploitation of multiple-thread parallelism
o Need for parallel computing model and parallel programming model
Aggravates memory wall
Memory bandwidth
o Way to get data out of memory banks
o Way to get data into multi-core processor array
Memory latency
Fragments L3 cache
Pins become strangle point
o Rate of pin growth projected to slow and flatten
o Rate of bandwidth per pin (pair) projected to grow slowly
Requires mechanisms for efficient inter-processor coordination
o Synchronization
o Mutual exclusion
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 59 of 90
CS8491-Computer Architecture Department of CSE & IT
o Context switching
Advantages:
1. Cache coherency circuitry can operate at a much higher clock rate than is possible if the signals
have to travel off-chip.
2. Signals between different CPUs travel shorter distances, those signals degrade less.
3. These higher quality signals allow more data to be sent in a given time period since individual
signals can be shorter and do not need to be repeated as often.
4. A dual-core processor uses slightly less power than two coupled single-core processors.
Disadvantages
1. Ability of multi-core processors to increase application performance depends on the use of
multiple threads within applications.
2. Most Current video games will run faster on a 3 GHz single-core processor than on a 2GHz dual-
core processor (of the same core architecture.
3. Two processing cores sharing the same system bus and memory bandwidth limits the real-world
performance advantage.
4. If a single core is close to being memory bandwidth limited, going to dual-core might only give
30% to 70% improvement.
5. If memory bandwidth is not a problem, a 90% improvement can be expected.
INTRODUCTION TO GRAPHICS PROCESSING UNITS
A major justification for adding SIMD instructions to existing architectures was that many
T
microprocessors were connected to graphics displays in PCs and workstations, so an increasing fraction
EN
of processing time was used for graphics. Hence, as Moore‘s law increased the number of transistors
available to microprocessors, it made sense to improve graphics processing.
Moreover, at the very high end were expensive graphics cards typically from Silicon Graphics that
D
could be added to workstations, to enable the creation of photographic quality images. These high-end
U
graphics cards were popular for creating computer-generated images that later found their way into
television advertisements and then into movies. Thus, video graphics controllers had a target to shoot for
ST
as processing resources increased, much as supercomputers provided a rich resource of ideas for
microprocessors to borrow in the quest for greater performance.
A major driving force for improving graphics processing was the computer game industry, both
R
on PCs and in dedicated game consoles such as the Sony PlayStation. The rapidly growing game market
M
encouraged many companies to make increasing investments in developing faster graphics hardware,
and this positive feedback led graphics processing to improve at a faster rate than general-purpose
processing in mainstream microprocessors.
Given that the graphics and game community had different goals than the microprocessor
development community, it evolved its own style of processing and terminology. As the graphics
processors increased in power, they earned the name Graphics Processing Units or GPUs to distinguish
themselves from CPUs. Here are some of the key characteristics as to how GPUs vary from CPUs:
■ GPUs are accelerators that supplement a CPU, so they do not need be able to perform all the tasks of a
CPU. This role allows them to dedicate all their resources to graphics. It‘s fine for GPUs to perform some
tasks poorly or not at all, given that in a system with both a CPU and a GPU, the CPU can do them if
needed. Thus, the CPU-GPU combination is one example of heterogeneous multiprocessing, where not
all the processors are identical. (Another example is the IBM Cell architecture which was also designed to
accelerate 2D and 3D graphics.)
■ The programming interfaces to GPUs are high-level application programming interfaces (APIs), such
as OpenGL and Microsoft‘s DirectX, coupled with high-level graphics shading languages, such as
NVIDIA‘s C for Graphics (Cg) and Microsoft‘s High Level Shader Language (HLSL). The language
compilers target industry-standard intermediate languages instead of machine instructions. GPU driver
software generates optimized GPU-specific machine instructions. While these APIs and languages evolve
rapidly to embrace new GPU resources enabled by Moore‘s law, the freedom from backward binary
instruction compatibility enables GPU designers to explore new architectures without the fear that they
will be saddled with implementing failed experiments forever. This environment leads to more rapid
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 60 of 90
CS8491-Computer Architecture Department of CSE & IT
innovation in GPUs than in CPUs.
■ Graphics processing involves drawing vertices of 3D geometry primitives such as lines and triangles
and shading or rendering pixel fragments of geometric primitives. Video games, for example, draw 20 to
30 times as many pixels as vertices.
■ Each vertex can be drawn independently, and each pixel fragment can be rendered independently. To
render millions of pixels per frame rapidly, the GPU evolved to execute many threads from vertex and
pixel shader programs in parallel.
■ The graphics data types are vertices, consisting of (x, y, z, w) coordinates, and pixels, consisting of (red,
green, blue, alpha) color components. GPUs represent each vertex component as a 32-bit floating-point
number. Each of the four pixel components was originally an 8-bit unsigned integer, but recent GPUs
now represent each component as single-precision floating-point number between 0.0 and 1.0.
■ The working set can be hundreds of megabytes, and it does not show the same temporal locality as
data does in mainstream applications. Moreover, there is a great deal of data-level parallelism in these
tasks. These differences led to different styles of architecture
■ Perhaps the biggest difference is that GPUs do not rely on multilevel caches to overcome the long
latency to memory, as do CPUs. Instead, GPUs rely on having enough threads to hide the latency to
memory. That is, between the time of a memory request and the time that data arrives, the GPU executes
hundreds or thousands of threads that are independent of that request.
■ GPUs rely on extensive parallelism to obtain high performance, implementing many parallel
processors and many concurrent threads.
■ The GPU main memory is thus oriented toward bandwidth rather than latency. There are even
separate DRAM chips for GPUs that are wider and have higher bandwidth than DRAM chips for CPUs.
T
In addition, GPU memories have traditionally had smaller main memories than conventional
EN
microprocessors. In 2008, GPUs typically have 1 GB or less, while CPUs have 2 to 32 GB. Finally, keep in
mind that for general-purpose computation, you must include the time to transfer the data between CPU
memory and GPU memory, since the GPU is a coprocessor.
D
■ Given the reliance on many threads to deliver good memory bandwidth, GPUs can accommodate
many parallel processors as well as many threads. Hence, each GPU processor is highly multithreaded.
U
■ In the past, GPUs relied on heterogeneous special purpose processors to deliver the performance
ST
needed for graphics applications. Recent GPUs are heading toward identical general-purpose processors
to give more flexibility in programming, making them more like the multicore designs found in
mainstream computing.
■ Given the four-element nature of the graphics data types, GPUs historically have SIMD instructions,
R
like CPUs. However, recent GPUs are focusing more on scalar instructions to improve programmability
M
and efficiency.
■ Unlike CPUs, there has been no support for double precision floating-point arithmetic, since there has
been no need for it in the graphics applications. In 2008, the first GPUs to support double precision in
hardware were announced. Nevertheless, single precision operations will still be eight to ten times faster
than double precision, even on these new GPUs, while the difference in performance for CPUs is limited
to benefits in transferring fewer bytes in the memory system due to using narrow data.
COMPUTER ARCHITECTURE OF WAREHOUSE-SCALE COMPUTERS
Networks are the connective tissue that binds 50,000 servers together. Analogous to the memory
hierarchy of Chapter 2, WSCs use a hierarchy of networks. Figure 6.5 shows one example. Ideally, the
combined network would provide nearly the performance of a custom high-end switch for 50,000 servers
at nearly the cost per port of a commodity switch designed for 50 servers.
The 19-inch (48.26-cm) rack is still the standard framework to hold servers, despite this standard
going back to railroad hardware from the 1930s. Servers are measured in the number of rack units (U)
that they occupy in a rack. One U is 1.75 inches (4.45 cm) high, and that is the minimum space a server
can occupy. A 7-foot (213.36-cm) rack offers 48 U, so it‘s not a coincidence that the most popular switch
for a rack is a 48-port Ethernet switch. This product has become a commodity that costs as little as $30
per port for a 1 Gbit/sec Ethernet link in 2011 Note that the bandwidth within the rack is the same for
each server, so it does not matter where the software places the sender and the receiver as long as they
are within the same rack. This flexibility is ideal from a software perspective. These switches typically
offer two to eight uplinks, which leave the rack to go to the next higher switch in the network hierarchy.
Thus, the bandwidth leaving the rack is 6 to 24 times smaller—48/8 to 48/2—than the bandwidth within
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 61 of 90
CS8491-Computer Architecture Department of CSE & IT
the rack. This ratio is called oversubscription. Alas, large oversubscription means programmers must be
aware of the performance consequences when placing senders and receivers in different racks. This
increased software-scheduling burden is another argument for network switches designed specifically
for the datacenter.
Storage
A natural design is to fill a rack with servers, minus whatever space you need forthe commodity Ethernet
rack switch. This design leaves open the question of where the storage is placed. From a hardware
construction perspective, the simplest solution would be to include disks inside the server, and rely on
Ethernet connectivity for access to information on the disks of remote servers. The alternative would be
to use network attached storage (NAS), perhaps over a storage network like Infiniband. The NAS
solution is generally more expensive per terabyte of storage, but it provides many features, including
RAID techniques to improve dependability of the storage. As you might expect from the philosophy
T
expressed in the prior section, WSCs generally rely on local disks and provide storage software that
EN
handles connectivity and dependability. For example, GFS uses local disks and maintains at least three
replicas to overcome dependability problems. This redundancy covers not just local disk failures, but
also power failures to racks and to whole clusters. The eventual consistency flexibility of GFS lowers the
D
cost of keeping replicas consistent, which also reduces the network bandwidth requirements of the
storage system. Local access patterns also mean high bandwidth to local storage. Beware that there is
U
confusion about the term cluster when talking about the architecture of a WSC. WSC is just an extremely
ST
large cluster. Cluster to mean the next-sized grouping of computers, in this case about 30 racks. In this
chapter, to avoid confusion we will use the term array to mean a collection of racks, preserving the
original meaning of the word cluster to mean anything from a collection of networked computers within
R
The switch that connects an array of racks is considerably more expensive than the 48-port commodity
Ethernet switch. This cost is due in part because of the higher connectivity and in part because the
bandwidth through the switch must be much higher to reduce the oversubscription problem. A switch
that has 10 times the bisection bandwidth—basically, the worst-case internal bandwidth—of a rack
switch costs about 100 times as much.
One reason is that the cost of switch bandwidth for n ports can grow as n2. Another reason for the high
costs is that these products offer high profit margins for the companies that produce them. They justify
such prices in part by providing features such as packet inspection that are expensive because they must
Operate at very high rates. For example, network switches are major users of content-addressable
memory chips and of field-programmable gate arrays (FPGAs), which help provide these features, but
the chips themselves are expensive. While such features may be valuable for Internet settings, they are
generally unused inside the datacenter.
WSC Memory Hierarchy
Figure 6.6 shows the latency, bandwidth, and capacity of memory hierarchy inside a WSC, and Figure
6.7 shows the same data visually. These figures are based on the following assumptions.
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 62 of 90
CS8491-Computer Architecture Department of CSE & IT
T
EN
D
Each server contains 16 GBytes of memory with a 100-nanosecond access time and transfers at 20
Bytes/sec and 2 terabytes of disk that offers a 10-millisecond access time and transfers at 200 Bytes/sec.
U
There are two sockets per board, and they share one 1 Gbit/sec Ethernet port.
ST
■ Every pair of racks includes one rack switch and holds 80 2U servers. Networking software plus switch
overhead increases the latency to DRAM to 100 microseconds and the disk access latency to 11
milliseconds. Thus, the total storage capacity of a rack is roughly 1 terabyte of DRAM and 160 terabytes
of disk storage. The 1 Gbit/sec Ethernet limits the remote bandwidth to DRAM or disk within the rack to
R
100 MBytes/sec.
M
■ The array switch can handle 30 racks, so storage capacity of an array goes up by a factor of 30: 30
terabytes of DRAM and 4.8 petabytes of disk. The array switch hardware and software increases latency
to DRAM within an array to 500 microseconds and disk latency to 12 milliseconds. The bandwidth of the
array switch limits the remote bandwidth to either array DRAM or array disk to 10 MBytes/sec.
Figures 6.6 and 6.7 show that network overhead dramatically increases latency from local DRAM to rack
DRAM and array DRAM, but both still have more than 10 times better latency than the local disk. The
network collapses the difference in bandwidth between rack DRAM and rack disk and between array
DRAM and array disk. The WSC needs 20 arrays to reach 50,000 servers, so there is one more level of the
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 63 of 90
CS8491-Computer Architecture Department of CSE & IT
networking hierarchy. Figure 6.8 shows the conventional Layer 3 routers to connect the arrays together
and to the Internet. Most applications fit on a single array within a WSC. Those that need more than one
array use sharding or partitioning, meaning that the dataset is split into independent pieces and then
distributed to different arrays. Operations on the whole dataset are sent to the servers hosting the pieces,
and the results are coalesced by the client computer.
other Message-Passing Multiprocessors
Message passing is a technique for invoking behavior (i.e., running a program) on a computer. In
contrast to the traditional technique of calling a program by name, message passing uses an object
model to distinguish the general function from the specific implementations. The invoking program
sends a message and relies on the object to select and execute the appropriate code. The justifications for
using an intermediate layer essentially falls into two categories: encapsulation and distribution.
Encapsulation is the idea that software objects should be able to invoke services on other objects
without knowing or caring about how those services are implemented. Encapsulation can reduce the
amount of coding logic and make systems more maintainable. E.g., rather than having IF-THEN
statements that determine which subroutine or function to call a developer can just send a message to the
object and the object will select the appropriate code based on its type.
One of the first examples of how this can be used was in the domain of computer graphics. There
are all sorts of complexities involved in manipulating graphic objects. For example, simply using the
right formula to compute the area of an enclosed shape will vary depending on if the shape is a triangle,
rectangle, eclipse, or circle. In traditional computer programming this would result in long IF-THEN
statements testing what sort of object the shape was and calling the appropriate code. The object-oriented
way to handle this is to define a class called Shape with subclasses such as Rectangle and Ellipse (which
T
in turn have subclasses Square and Circle) and then to simply send a message to any Shape asking it to
EN
compute its area. Each Shape object will then invoke the subclass's method with the formula appropriate
for that kind of object.
Distributed message passing provides developers with a layer of the architecture that provides
D
common services to build systems made up of sub-systems that run on disparate computers in different
locations and at different times. When a distributed object is sending a message, the messaging layer can
U
Finding the app using different operating systems and programming languages, at different locations
from where the message originated.
Saving the message on a queue if the appropriate object to handle the message is not currently
R
running and then invoking the message when the object is available. Also, storing the result if
needed until the sending object is ready to receive it.
M
Controlling various transactional requirements for distributed transactions, e.g. ACID-testing the
data.
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 64 of 90
CS8491-Computer Architecture Department of CSE & IT
A memory hierarchy consists of multiple levels of memory with different speeds and sizes. The
faster memories are more expensive per bit than the slower memories and thus are smaller.
A structure that uses multiple levels of memories; as the distance from the processor increases, the
size of the memories and the access time both increase.
T
EN
Fig:1 The basic structure of memory hierarchy
D
Today, there are three primary technologies used in building memory hierarchies.
U
Main memory is implemented from DRAM (dynamic random access memory), while levels closer
ST
to the processor (caches) use SRAM (static random access memory). The third technology, used to
implement the largest and slowest level in the hierarchy, is usually magnetic disk. (Flash memory is
used instead of disks in many embedded devices)
R
DRAM is less costly per bit than SRAM, although it is substantially slower. The price difference
M
arises because DRAM uses significantly less area per bit of memory, and DRAMs thus have larger
capacity.
Because of the differences in cost and access time, it is advantageous to build memory as a hierarchy
of levels. In fig 1 it shows the faster memory is close to the processor and the slower, less expensive
memory is below it.
The goal is to present the user with as much memory as is available in the cheapest technology,
while providing access at the speed offered by the fastest memory.
The data is similarly hierarchical: a level closer to the processor is generally a subset of any level
further away, and all the data is stored at the lowest level.
The upper level—the one closer to the processor—is smaller and faster than the lower level, since
the upper level uses technology that is more expensive.
The below fig shows that the minimum unit of information that can be either present or not present
in the two-level hierarchy is called a block or a line.
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 65 of 90
CS8491-Computer Architecture Department of CSE & IT
Fig 2 Every pair of levels in the memory hierarchy can be thought of as having an upper and lower level. Transfer an entire block when we
copy something between levels.
Hit: If the data requested by the processor appears in some block in the upper level,this is called a
hit..
Miss: If the data is not found in the upper level, the request is called a miss.
The lower level in the hierarchy is then accessed to retrieve the block containing the requested data.
The hit rate, or hit ratio, is the fraction of memory accesses found in the upper level; it is often used
as a measure of the performance of the memory hierarchy.
The miss rate (1 hit rate) is the fraction of memory accesses not found in the upper level.
Since performance is the major reason for having a memory hierarchy, the time to service hits and misses
T
is important:
EN
Hit time is the time to access the upper level of the memory hierarchy, which includes the time
needed to determine whether the access is a hit or a miss.
D
The miss penalty is the time to replace a block in the upper level with the corresponding block
from the lower level, plus the time to deliver this block to the processor.
U
Because the upper level is smaller and built using faster memory parts, the hit time
ST
will be much smaller than the time to access the next level in the hierarchy, which is the
major component of the miss penalty.
Programs exhibit both temporal locality, the tendency to reuse recently accessed data items, and
R
spatial locality, the tendency to reference data items that are close to other recently accessed
items.
M
Memory hierarchies take advantage of temporal locality by keeping more recently accessed data
items closer to the processor. Memory hierarchies take advantage of spatial locality by moving
blocks consisting of multiple contiguous words in memory to upper levels of the hierarchy.
Fig.3 This diagram shows the structure of a memory hierarchy: as the distance
from the processor increases, so does the size.
The above fig shows that a memory hierarchy uses smaller and faster memory technologies close
to the processor. Thus, accesses that hit in the highest level of the hierarchy can be processed
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 66 of 90
CS8491-Computer Architecture Department of CSE & IT
quickly. Accesses that miss go to lower levels of the hierarchy, which are larger but slower.
If the hit rate is high enough, the memory hierarchy has an effective access time close to that of
the highest (and fastest) level and a size equal to that of the lowest level.
In most systems, the memory is a true hierarchy, meaning that data cannot be present in
level i unless it is also present in level i + 1.
MEMORY TECHNOLOGIES
SRAM Technology
DRAM Technology
1. As early DRAMs grew in capacity, the cost of a package with all the necessary address lines was
T
an issue. The solution was to multiplex the address lines, thereby cutting the number of address
EN
pins in half.
2. One-half of the address is sent first, called the row accessstrobe (RAS). The other half of the
address, sent during the column access strobe (CAS), follows it.
D
3. These names come from the internal chip organization, since the memory is organized as a
rectangular matrix addressed by rows and columns.
U
ST
R
M
4.
5. An additional requirement of DRAM derives from the property signified by its first letter, D, for
dynamic.
6. To pack more bits per chip, DRAMs use only a single transistor to store a bit. Reading that bit
destroys the information, so it must be restored. This is one reason the DRAM cycle time is much
longer than the access time.
7. In addition, to prevent loss of information when a bit is not read or written, the bit must be
―refreshed‖ periodically. Fortunately, all the bits in a row can be refreshed simultaneously just by
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 67 of 90
CS8491-Computer Architecture Department of CSE & IT
reading that row. Hence, every DRAM in the memory system must access every row within a
certain time window, such as 8 ms.
8. Memory controllers include hardware to refresh the DRAMs periodically. This requirement
means that the memory system is occasionally unavailable because it is sending a signal telling
every chip to refresh. The time for a refresh is typically a full memory access (RAS and CAS) for
each row of the DRAM. Since the memory matrix in a DRAM is conceptually square, the number
of steps min a refresh is usually the square root of the DRAM capacity.
9. DRAM designers try to keep time spent refreshing to less than 5% of the total time. So far we
have presented main memory as if it operated like a Swiss train, consistently delivering the goods
exactly according to schedule.
10. Refresh belies that analogy, since some accesses take much longer than others do. Thus, refresh is
another reason for variability of memory latency and hence cache miss penalty.
11. Although we have been talking about individual chips, DRAMs are commonly sold on small
boards called dual inline memory modules (DIMMs). DIMMs typically contain 4–16 DRAMs, and
they are normally organized to be 8 bytes wide (+ ECC) for desktop systems.
1. To improve bandwidth, there has been a variety of evolutionary innovations over time.
2. The first was timing signals that allow repeated accesses to the row buffer without another row
access time, typically called fast page mode. Such a buffer comes naturally, as each array will
buffer 1024–2048 bits for each access. Conventional DRAMs had an asynchronous interface to the
T
memory controller, and hence every transfer involved overhead to synchronize with the
controller.
EN
3. The second major change was to add a clock signal to the DRAM interface, so that the repeated
transfers would not bear that overhead. Synchronous DRAM (SDRAM) is the name of this
D
optimization. SDRAMs typically also had a programmable register to hold the number of bytes
requested, and hence can send many bytes over several cycles per request.
U
4. The third major DRAM innovation to increase bandwidth is to transfer data on both the rising
ST
edge and falling edge of the DRAM clock signal, thereby doubling the peak data rate. This
optimization is called double data rate (DDR).
Measuring and improving the performance of cache memory.
R
CACHE PERFORMANCE
Cache Performance can be improved by
M
Reducing the miss rate: larger block size, larger cache size, and higher associativity
Reducing the miss penalty: multilevel caches and giving reads priority over writes
Reducing the time to hit in the cache: avoiding address translation when indexing the cache
Average memory access time (AMAT) is a useful measure to evaluate the performance of a memory-
hierarchy configuration.
AMAT=Time for a hit +miss rate* miss penalty
Classifying Misses: 3 Cs
Compulsory
Cold start misses or first reference misses: The first access to a block can NOT be in the
cache, so there must be a compulsory miss.
These are suffered regardless of cache size.
Capacity
If the cache is too small to hold all of the blocks needed during execution of a program,
misses occur on blocks that were discarded earlier.
In other words, this is the difference between the compulsory miss rate and the miss rate
of a finite size fully associative cache.
Conflict
If the cache has sufficient space for the data, but the block can NOT be kept because the set
is full, a conflict miss will occur.
This is the difference between the miss rate of a non-fully associative cache and a fully-
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 68 of 90
CS8491-Computer Architecture Department of CSE & IT
associative cache.
These misses are also called collision or interference misses.
Six Basic Cache Optimizations ( 6 ways to improve cache performance)
First Optimization: Larger Block Size to Reduce Miss Rate
Second Optimization: Larger Caches to Reduce Miss Rate
Third Optimization: Higher Associativity to Reduce Miss Rate
Fourth Optimization: Multilevel Caches to Reduce Miss Penalty
Fifth Optimization: Giving Priority to Read Misses over Writes to Reduce Miss Penalty
Sixth Optimization: Avoiding Address Translation during Indexing of the Cache to Reduce Hit Time
First Optimization: Larger Block Size to Reduce Miss Rate
The simplest way to reduce miss rate is to increase the block size. Larger block sizes will reduce
also compulsory misses. This reduction occurs because the principle of locality has two components:
temporal locality and spatial locality.
T
EN
D
U
ST
Larger blocks take advantage of spatial locality. At the same time, larger blocks increase the miss
penalty. Since they reduce the number of blocks in the cache, larger blocks may increase conflict
R
Clearly, there is little reason to increase the block size to such a size that it increases the miss rate.
There is also no benefit to reducing miss rate if it increases the average memory access time.
Second Optimization: Larger Caches to Reduce Miss Rate
When a miss occurs, the cache controller must select a block to be replaced with the desired data. A
benefit of direct-mapped placement is that hardware decisions are simplified. Only one block frame is
checked for a hit, and only that block can be replaced. With fully associative or set-associative
placement, there are many blocks to choose from on a miss. There are three primary strategies employed
for selecting which block to replace:
Random:
To spread allocation uniformly, candidate blocks are randomly selected.
Some systems generate pseudorandom block numbers to get reproducible behavior, which is
particularly useful when debugging hardware.
Least-recently used(LRU):
To reduce the chance of throwing out information that will be needed soon, accesses to blocks are
recorded.
Relying on the past to predict the future, the block replaced is the one that has been unused for
the longest time.
LRU relies on a corollary of locality:
If recently used blocks are likely to be used again, then a good candidate for disposal is the least-
recently used block.
First in, first out (FIFO):
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 69 of 90
CS8491-Computer Architecture Department of CSE & IT
Because LRU can be complicated to calculate, this approximates LRU by determining the oldest
block rather than the LRU.
A virtue of random replacement is that it is simple to build in hardware.
As the number of blocks to keep track of increases, LRU becomes increasingly expensive and is
frequently only approximated.
Third Optimization: Higher Associativity to Reduce Miss Rate
To show the benefit of associativity, conflict misses are divided into misses caused by each decrease in
associativity.
Here are the four divisions of conflict misses and how they are calculated:
Eight-way: Conflict misses due to going from fully associative (no conflicts) to eight-way associative
Four-way: Conflict misses due to going from eight-way associative to four way associative
Two-way: Conflict misses due to going from four-way associative to two way associative
One-way: Conflict misses due to going from two-way associative to one way associative (direct mapped)
Average memory access time = Hit timeL1 + Miss rateL1 × Miss penaltyL1 and
Miss penaltyL1 = Hit timeL2 + Miss rateL2 × Miss penaltyL2, so
Average memory access time = Hit timeL1 + Miss rateL1 × (Hit timeL2 + Miss rateL2 × Miss penaltyL2)
In this formula, the second-level miss rate is measured on the leftovers from the first-level cache.
T
To avoid ambiguity, these terms are adopted here for a two-level cache system:
Local miss rate: This rate is simply the number of misses in a cache divided by the total number
EN
of memory accesses to this cache.
Global miss rate: The number of misses in the cache divided by the total number of memory
accesses generated by the processor. Using the terms above, the global miss rate for the first-level
D
cache is still just Miss rate L1, but for the second-level cache it is Miss rate L1 × Miss rate L2.
U
ST
R
M
T
Mapping Function
EN
Direct Mapping
D
U
ST
R
M
It is the simplest technique in which block j of the main memory maps onto block „j‟ modulo 128 of
the cache. Thus whenever one of the main memory blocks 0,128,256 is loaded in the cache,it is stored in
block 0. Block 1,129,257 are stored in cache block 1 and so on. The contention may arise when,
When the cache is full
When more than one memory block is mapped onto a given cache block position.
The contention is resolved by allowing the new blocks to overwrite the currently resident block.
Placement of block in the cache is determined from memory address. The memory address is divided
into 3 fields. They are,
Low Order 4 bit field(word)->Selects one of 16 words in a block.
7 bit cache block field->When new block enters cache,7 bit determines the cache position in
which this block must be stored.
5 bit Tag field->The high order 5 bits of the memory address of the block is stored in 5 tag
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 71 of 90
CS8491-Computer Architecture Department of CSE & IT
bits associated with its location in the cache.
As execution proceeds, the high order 5 bits of the address is compared with tag bits associated with
that cache location. If they match, then the desired word is in that block of the cache. If there is no match,
then the block containing the required word must be first read from the main memory and loaded into
the cache.
Merit:
It is easy to implement
Demerit:
It is not very flexible.
Associative Mapping:
In this method, the main memory block can be placed into any cache block position. 12 tag bits will
identify a memory block when it is resolved in the cache. The tag bits of an address received from the
processor are compared to the tag bits of each block of the cache to see if the desired block is persent.
This is called associative mapping. It gives complete freedom in choosing the cache location. A new
block that has to be brought into the cache has to replace(eject)an existing block if the cache is full. In this
method, the memory has to determine whether a given block is in the cache. A search of this kind is
called an associative Search.
Merit:
It is more flexible than direct mapping technique.
Demerit:
Its cost is high.
T
EN
D
U
ST
R
M
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 72 of 90
CS8491-Computer Architecture Department of CSE & IT
The cache which contains 1 block per set is called Direct Mapping. A cache that has „k‟ blocks
per set is called as „k-way set associative cache‟. Each block contains a control bit called a valid bit.
The Valid bit indicates that whether the block contains valid data. The dirty bit indicates that whether
the block has been modified during its cache residency. Valid bit=0->When power is initially applied to
system. Valid bit =1->When the block is loaded from main memory at first time. If the main memory
block is updated by a source & if the block in the source is already exists in the cache,then the valid bit
will be cleared to „0‟. If Processor & DMA uses the same copies of data then it is called as the Cache
Coherence Problem.
Merit:
The Contention problem of direct mapping is solved by having few choices for block placement.
The hardware cost is decreased by reducing the size of associative search
T
EN
Fig: Set-Associative Mapping
D
Address Translation:
ST
In address translation, all programs and data are composed of fixed length units called Pages. The
Page consists of a block of words that occupy contiguous locations in the main memory. The pages are
commonly range from 2K to 16K bytes in length. The cache bridge speed up the gap between main
R
memory and secondary storage and it is implemented in software techniques. Each virtual address
generated by the processor contains Virtual Page Number (Low order bit) and offset (High order bit).
M
Virtual Page number+ Offset specifies the location of a particular byte (or word) within a page.
Page Table:
It contains the information about the main memory address where the page is stored & the
current status of the page.
Page Frame:
An area in the main memory that holds one page is called the page frame.
Page Table Base Register:
It contains the starting address of the page table. Virtual Page Number + Page Table Base
register, Gives the address of the corresponding entry in the page table. (ie) it gives the starting address
of the page if that page currently resides in memory.
Control Bits in Page Table:
The Control bit specifies the status of the page while it is in main memory.
Function:
The control bit indicates the validity of the page (i.e) it checks whether the page is actually loaded
in the main memory. It also indicates that whether the page has been modified during its residency in the
memory; this information is needed to determine whether the page should be written back to the disk
before it is removed from the main memory to make room for another page. The Page table information
is used by MMU for every read & write access. The Page table is placed in the main memory but a copy
of the small portion of the page table is located within MMU. This small portion or small cache is called
Translation LookAside Buffer(TLB). This portion consists of the page table enteries that corresponds to
the most recently accessed pages and also contains the virtual address of the entry.
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 73 of 90
CS8491-Computer Architecture Department of CSE & IT
T
EN
D
U
ST
R
M
When the operating system changes the contents of page table, the control bit in TLB will invalidate
the corresponding entry in the TLB. Given a virtual address, the MMU looks in TLB for the referenced
page. If the page table entry for this page is found in TLB, the physical address is obtained immediately.
If there is a miss in TLB, then the required entry is obtained from the page table in the main memory &
TLB is updated. When a program generates an access request to a page that is not in the main memory,
then Page Fault will occur. The whole page must be brought from disk into memry before an access can
proceed. When it detects a page fault, the MMU asks the operating system to generate an interrupt. The
operating System suspend the execution of the task that caused the page fault and begin execution of
another task whose pages are in main memory because the long delay occurs while page transfer takes
place. When the task resumes, either the interrupted instruction must continue from the point of
interruption or the instruction must be restarted. If a new page is brought from the disk when the main
memory is full, it must replace one of the resident pages. In that case, it uses LRU algorithm which
removes the least referenced Page. A modified page has to be written back to the disk before it is
removed from the main memory. In that case, write –through protocol is used.
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 74 of 90
CS8491-Computer Architecture Department of CSE & IT
VIRTUAL MEMORY
Techniques that automatically move program and data blocks into the physical main memory when
they are required for execution is called the Virtual Memory. The binary address that the processor
issues either for instruction or data are called the virtual / Logical address. The virtual address is
translated into physical address by a combination of hardware and software components. This kind of
address translation is done by MMU(Memory Management Unit). When the desired data are in the
main memory, these data are fetched /accessed immediately. If the data are not in the main memory,
the MMU causes the Operating system to bring the data into memory from the disk. Transfer of data
between disk and main memory is performed using DMA scheme.
T
EN
Fig: Virtual Memory Organisation
Address Translation:
D
In address translation, all programs and data are composed of fixed length units called Pages. The
Page consists of a block of words that occupy contiguous locations in the main memory. The pages are
U
commonly range from 2K to 16K bytes in length. The cache bridge speed up the gap between main
ST
memory and secondary storage and it is implemented in software techniques. Each virtual address
generated by the processor contains Virtual Page Number (Low order bit) and offset(High order bit).
Virtual Page number+ Offset specifies the location of a particular byte (or word) within a page.
R
Page Table:
It contains the information about the main memory address where the page is stored & the current
M
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 75 of 90
CS8491-Computer Architecture Department of CSE & IT
T
EN
D
U
ST
R
M
When the operating system changes the contents of page table, the control bit in TLB will invalidate
the corresponding entry in the TLB. Given a virtual address, the MMU looks in TLB for the referenced
page. If the page table entry for this page is found in TLB, the physical address is obtained immediately.
If there is a miss in TLB, then the required entry is obtained from the page table in the main memory &
TLB is updated. When a program generates an access request to a page that is not in the main memory,
then Page Fault will occur. The whole page must be brought from disk into memory before an access
can proceed. When it detects a page fault, the MMU asks the operating system to generate an interrupt.
The operating System suspend the execution of the task that caused the page fault and begin execution
of another task whose pages are in main memory because the long delay occurs while page transfer
takes place. When the task resumes, either the interrupted instruction must continue from the point of
interruption or the instruction must be restarted. If a new page is brought from the disk when the main
memory is full, it must replace one of the resident pages. In that case, it uses LRU algorithm which
removes the least referenced Page. A modified page has to be written back to the disk before it is
removed from the main memory. In that case, write –through protocol is used.
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 76 of 90
CS8491-Computer Architecture Department of CSE & IT
Accessing I/O Devices
The components of a computer system communicate with each other through an interconnection
network. The interconnection network consists of circuits needed to transfer information between the
processor, the memory unit, and a number of I/O devices. Load and Store instructions use addressing
modes to generate effective addresses that identify the desired locations. idea of using addresses to
access various locations in the memory can be extended to deal with the I/O devices. Each I/O device
must appear to the processor as consisting of some addressable locations, just like the memory. Some
addresses in the address space of the processor are assigned to these I/O locations, rather than to the
main memory.
These locations are usually implemented as bit storage circuits organized in the form of registers
called I/O registers. Since the I/O devices and the memory share the same address space, this
arrangement is called memory-mapped I/O. With memory-mapped I/O, any machine instruction that
can access memory can be used to transfer data to or from an I/O device.
T
EN
A computer system
For example, if DATAIN is the address of a register in an input device, the instruction
Load R2, DATAIN reads the data from the DATAIN register and loads them into processor
D
interface, which provides the means for data transfer. The interface includes some registers that can be
accessed by the processor. One register may serve as a buffer for data transfers, another may hold
M
information about the current status of the device, and yet another may store the information that
controls the operational behaviour of the device. These data, status, and control registers are accessed by
program instructions as if they were memory locations. Typical transfers of information are between I/O
registers and the registers in the processor.
Program-Controlled I/O:
Consider a task that reads characters typed on a keyboard, stores these data in the memory, and
displays the same characters on a display screen. A simple way of implementing this task is to write a
program that performs all functions needed to realize the desired action. This method is known as
program-controlled I/O. In addition to transferring each character from the keyboard into the memory,
and then to the display, it is necessary to ensure that this happens at the right time. An input character
must be read in response to a key being pressed. For output, a character must be sent to the display only
when the display device is able to accept it. The rate of data transfer from the keyboard to a computer is
limited by the typing speed of the user, which is unlikely to exceed a few characters per second. The rate
of output transfers from the computer to the display is much higher. It is determined by the rate at
which characters can be transmitted to and displayed on the display device The difference in speed
between the processor and I/O devices creates the need for mechanisms to synchronize the transfer of
data between them.
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 77 of 90
CS8491-Computer Architecture Department of CSE & IT
One solution to this problem involves a signaling protocol. KBD_DATA be the address label of an
8-bit register that holds the generated character. Also, let a signal indicating that a key has been pressed be
provided by setting to 1 a flip-flop called KIN, which is a part of an eight-bit status register,
KBD_STATUS. The processor can read the status flag KIN to determine when a character code has been
placed in KBD_DATA. When the processor reads the status flag to determine its state, we say that the
processor polls the I/O device. The display includes an 8-bit register, which we will call DISP_DATA, used
to receive characters from the processor. It also must be able to indicate that it is ready to receive the next
character, this can be done by using a status flag called DOUT, which is one bit in a status register,
DISP_STATUS.
T
EN
D
U
ST
R
INTERRUPTS
M
An interrupt is an event that causes the execution of one program to be suspended and the
execution of another program to begin. In program‐ controlled I/O, when the processor continuously
monitors the status of the device, the processor will not perform any function. An alternate approach
would be for the I/O device to alert the processor when it becomes ready. The Interrupt request line will
send a hardware signal called the interrupt signal to the processor. On receiving this signal, the processor
will perform the useful function during the waiting period. The routine executed in response to an
interrupt request is called Interrupt Service Routine. The interrupt resembles the subroutine calls.
The processor first completes the execution of instruction i. Then it loads the PC (Program
Counter) with the address of the first instruction of the ISR. After the execution of ISR, the processor has
to come back to instruction i + 1. Therefore, when an interrupt occurs, the current contents of PC which
point to i +1 is put in temporary storage in a known location. A return from interrupt instruction at the
end of ISR reloads the PC from that temporary storage location, causing the execution to resume at
instruction i+1. When the processor is handling the interrupts, it must inform the device that its request
has been recognized so that it removes its interrupt request signal. This may be accomplished by a
special control signal called the interrupt acknowledge signal. The task of saving and restoring the
information can be done automatically by the processor. The processor saves only the contents of
program counter & status register (ie) it saves only the minimal amount of information to maintain the
integrity of the program execution. Saving registers also increases the delay between the time an
interrupt request is received and the start of the execution of the ISR. This delay is called the Interrupt
Latency. Generally, the long interrupt latency in unacceptable. The concept of interrupts is used in
Operating System and in Control Applications, where processing of certain routines must be accurately
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 78 of 90
CS8491-Computer Architecture Department of CSE & IT
timed relative to external events. This application is also called as real-time processing.
The processor first completes the execution of instruction i. Then it loads the PC (Program
Counter) with the address of the first instruction of the ISR. After the execution of ISR, the processor has
to come back to instruction i + 1. Therefore, when an interrupt occurs, the current contents of PC which
point to i +1 is put in temporary storage in a known location. A return from interrupt instruction at the
end of ISR reloads the PC from that temporary storage location, causing the execution to resume at
instruction i+1. When the processor is handling the interrupts, it must inform the device that its request
has been recognized so that it removes its interrupt request signal. This may be accomplished by a
special control signal called the interrupt acknowledge signal. The task of saving and restoring the
T
information can be done automatically by the processor. The processor saves only the contents of
EN
program counter & status register (ie) it saves only the minimal amount of information to maintain the
integrity of the program execution. Saving registers also increases the delay between the time an
interrupt request is received and the start of the execution of the ISR. This delay is called the Interrupt
D
Latency. Generally, the long interrupt latency in unacceptable. The concept of interrupts is used in
Operating System and in Control Applications, where processing of certain routines must be accurately
U
timed relative to external events. This application is also called as real-time processing.
ST
Interrupt Hardware
R
M
Fig: An equivalent circuit for an open drain bus used to implement a common interrupt request line.
A single interrupt request line may be used to serve n devices. All devices are connected to the
line via switches to ground. To request an interrupt, a device closes its associated switch, the voltage on
INTR line drops to 0(zero). If all the interrupt request signals (INTR1 to INTRn) are inactive, all switches
are open and the voltage on INTR line is equal to Vdd. When a device requests an interrupts, the value of
INTR is the logical OR of the requests from individual devices.
(ie)INTR = INTR1+…………+INTRn
INTR->It is used to name the INTR signal on common line it is active in the low voltage state.
Open collector (bipolar ckt) or Open drain (MOS circuits) is used to drive INTR line. The Output of the
Open collector (or) Open drain control is equal to a switch to the ground that is open when gates input is
in 0 state and closed when the gates input is in 1 state. Resistor R is called a pull-up resistor because it
pulls the line voltage up to the high voltage state when the switches are open. Enabling and Disabling
Interrupts: The arrival of an interrupt request from an external device causes the processor to suspend
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 79 of 90
CS8491-Computer Architecture Department of CSE & IT
the execution of one program & start the execution of another because the interrupt may alter the
sequence of events to be executed. INTR is active during the execution of Interrupt Service Routine.
There are 3 mechanisms to solve the problem of infinite loop which occurs due to successive
interruptions of active INTR signals.
The following are the typical scenario.
The device raises an interrupt request.
The processor interrupts the program currently being executed.
Interrupts are disabled by changing the control bits is PS (Processor Status register)
The device is informed that its request has been recognized & in response, it deactivates
the INTR signal.
The actions are enabled & execution of the interrupted program is resumed.
Edge-triggered
The processor has a special interrupt request line for which the interrupt handling circuit responds
only to the leading edge of the signal. Such a line said to be edge-triggered.
Handling Multiple Devices
When several devices requests interrupt at the same time, it raises some questions. They are
How can the processor recognize the device requesting an interrupt?
Given that the different devices are likely to require different ISR, how can the processor
obtain the starting address of the appropriate routines in each case?
Should a device be allowed to interrupt the processor while another interrupt is being
serviced?
How should two or more simultaneous interrupt requests be handled?
T
Polling Scheme:
EN
If two devices have activated the interrupt request line, the ISR for the selected device (first device)
will be completed & then the second request can be serviced. The simplest way to identify the
interrupting device is to have the ISR polls all the encountered with the IRQ bit set is the device to be
D
serviced. IRQ (Interrupt Request) -> when a device raises an interrupt requests, the status register IRQ is
set to 1.
U
Merit:
ST
It is easy to implement.
Demerit:
The time spent for interrogating the IRQ bits of all the devices that may not be requesting any
R
service.
Vectored Interrupt:
M
Here the device requesting an interrupt may identify itself to the processor by sending a special
code over the bus & then the processor start executing the ISR. The code supplied by the processor
indicates the starting address of the ISR for the device. The code length ranges from 4 to 8 bits. The
location pointed to by the interrupting device is used to store the staring address to ISR. The processor
reads this address, called the interrupt vector & loads into PC. The interrupt vector also includes a new
value for the Processor Status Register. When the processor is ready to receive the interrupt vector code,
it activate the interrupt acknowledge (INTA) line.
Interrupt Nesting: Multiple Priority Scheme
In multiple level priority scheme, we assign a priority level to the processor that can be changed
under program control. The priority level of the processor is the priority of the program that is currently
being executed. The processor accepts interrupts only from devices that have priorities higher than its
own. At the time the execution of an ISR for some device is started, the priority of the processor is raised
to that of the device. The action disables interrupts from devices at the same level of priority or lower.
Privileged Instruction
The processor priority is usually encoded in a few bits of the Processor Status word. It can also be
changed by program instruction & then it is write into PS. These instructions are called privileged
instruction. This can be executed only when the processor is in supervisor mode. The processor is in
supervisor mode only when executing OS routines. It switches to the user mode before beginning to
execute application program.
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 80 of 90
CS8491-Computer Architecture Department of CSE & IT
Privileged Exception
User program cannot accidently or intentionally change the priority of the processor & disrupts
the system operation. An attempt to execute a privileged instruction while in user mode, leads to a
special type of interrupt called the privileged exception.
Fig: Implementation of Interrupt Priority using individual Interrupt request acknowledge lines
Each of the interrupt request line is assigned a different priority level. Interrupt request received
over these lines are sent to a priority arbitration circuit in the processor. A request is accepted only if it
has a higher priority level than that currently assigned to the processor.
Simultaneous Requests: Daisy Chain
T
EN
D
U
ST
The interrupt request line INTR is common to all devices. The interrupt acknowledge line INTA is
connected in a daisy chain fashion such that INTA signal propagates serially through the devices.
When several devices raise an interrupt request, the INTR is activated & the processor responds by
R
setting INTA line to 1. this signal is received by device. Device1 passes the signal on to device2 only if it
M
does not require any service. If devices1 has a pending request for interrupt blocks that INTA signal &
proceeds to put its identification code on the data lines. Therefore, the device that is electrically closest
to the processor has the highest priority.
Merits
It requires fewer wires than the individual connections.
Arrangement of Priority Groups
Here the devices are organized in groups & each group is connected at a different priority level.
Within a group, devices are connected in a daisy chain. At the devices end, an interrupt enable bit in a
control register determines whether the device is allowed to generate an interrupt requests. At the
processor end, either an interrupt enable bit in the PS (Processor Status) or a priority structure
determines whether a given interrupt requests will be accepted.
Initiating the Interrupt Process
Load the starting address of ISR in location INTVEC (vectored interrupt). Load the address LINE
in a memory location PNTR. The ISR will use this location as a pointer to store the i/p characters in the
memory. Enable the keyboard interrupts by setting bit 2 in register CONTROL to 1. Enable interrupts in
the processor by setting to 1, the IE bit in the processor status register PS.
Exception of ISR
Read the input characters from the keyboard input data register. This will cause the interface
circuits to remove its interrupt requests. Store the characters in a memory location pointed to by PNTR
& increment PNTR. When the end of line is reached, disable keyboard interrupt & inform program
main. Return from interrupt.
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 81 of 90
CS8491-Computer Architecture Department of CSE & IT
T
To initiate the transfer of a block of words , the processor sends,
EN
Starting address
Number of words in the block
D
Direction of transfer
• When a block of data is transferred , the DMA controller increment the memory address for
U
successive words and keep track of number of words and it also informs the processor by raising an
ST
interrupt signal.
• While DMA control is taking place, the program requested the transfer cannot continue and the
processor can be used to execute another program.
R
• After DMA transfer is completed, the processor returns to the program that requested the
M
transfer.
Registers in a DMA Interface
R/W determines the direction of transfer :
When R/W =1, DMA controller read data from memory to I/O device.
R/W =0, DMA controller perform write operation.
Done Flag=1, the controller has completed transferring a block of data and is ready to receive
another command.
IE=1, it causes the controller to raise an interrupt (interrupt Enabled) after it has completed
transferring the block of data.
IRQ=1, it indicates that the controller has requested an interrupt
Use of DMA controllers in a computer system
A DMA controller connects a high speed network to the computer bus, and the disk controller for
two disks, also has DMA capability and it provides two DMA channels.
To start a DMA transfer of a block of data from main memory to one of the disks, the program
write‘s the address and the word count information into the registers of the corresponding
channel of the disk controller.
When DMA transfer is completed, it will be recorded in status and control registers of the DMA
channel (ie) Done bit=IRQ=IE=1.
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 82 of 90
CS8491-Computer Architecture Department of CSE & IT
Cycle Stealing:
Requests by DMA devices for using the bus are having higher priority than processor requests.
Top priority is given to high speed peripherals such as, Disk and High speed Network Interface and
Graphics display device. Since the processor originates most memory access cycles, the DMA controller
can be said to steal the memory cycles from the processor. This interviewing technique is called Cycle
stealing.
Burst Mode:
The DMA controller may be given exclusive access to the main memory to transfer a block of data
without interruption. This is known as Burst/Block Mode.
Bus Master:
The device that is allowed to initiate data transfers on the bus at any given time is called the bus
master
Bus Arbitration:
It is the process by which the next device to become the bus master is selected and the bus
mastership is transferred to it.
Types:
There are 2 approaches to bus arbitration. They are
i)Centralized arbitration ( A single bus arbiter performs arbitration)
Centralized Arbitration:
T
Here the processor is the bus master and it may grants bus mastership to one of its DMA controller.
EN
A DMA controller indicates that it needs to become the bus master by activating the Bus Request line
(BR) which is an open drain line. The signal on BR is the logical OR of the bus request from all devices
D
connected to it. When BR is activated the processor activates the Bus Grant Signal (BGI) and indicated
U
the DMA controller that they may use the bus when it becomes free. This signal is connected to all
devices using a daisy chain arrangement. If DMA requests the bus, it blocks the propagation of Grant
ST
Signal to other devices and it indicates to all devices that it is using the bus by activating open collector
line, Bus Busy (BBSY).
A simple arrangement for bus arbitration using a daisy chain
R
Sequence of signals during transfer of bus mastership for the devices. The timing diagram shows
M
the sequence of events for the devices connected to the processor is shown. DMA controller 2 requests
and acquires bus mastership and later releases the bus. During its tenture as bus master, it may perform
one or more data transfer. After it releases the bus, the processor resources bus mastership.
Distributed Arbitration:
It means that all devices waiting to use the bus have equal responsibility in carrying out the
arbitration process.
Each device on the bus is assigned a 4 bit id. When one or more devices request the bus, they
assert the Start-Arbitration signal & place their 4 bit ID number on four open collector lines, ARB0 to
ARB3. A winner is selected as a result of the interaction among the signals transmitted over these lines.
The net outcome is that the code on the four lines represents the request that has the highest ID number.
The drivers are of open collector type. Hence, if the i/p to one driver is equal to 1, the i/p to another
driver connected to the same bus line is equal to 0 (ie) bus the is in low-voltage state Eg: Assume two
devices A & B have their ID 5 (0101), 6(0110) and their code is 0111.
Each device compares the pattern on the arbitration line to its own ID starting from MSB. If it
detects a difference at any bit position, it disables the drivers at that bit position. It does this by placing
„0‟ at the i/p of these drivers. In our eg. A detects a difference in line ARB1, hence it disables the drivers
on lines ARB1 & ARB0. This causes the pattern on the arbitration line to change to 0110 which means that
B has won the contention.
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 83 of 90
CS8491-Computer Architecture Department of CSE & IT
T
EN
D
U
ST
R
M
The device that recognizes this address responds to the commands issued on the
control lines.
The processor uses the control lines to request either a Read or a Write operation,
and the requested data are transferred over the data lines.
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 84 of 90
CS8491-Computer Architecture Department of CSE & IT
BUS OPEARTION
A bus requires a set of rules, often called a bus protocol. The bus protocol determines when a device
may place information on the bus, when it may load the data on the bus into one of its registers These
rules are implemented by control signals. One control line, usually labeled R/W, specifies whether a
Read or a Write operation is to be performed. One device plays the role of a master. This is the device
that initiates data transfers by issuing Read or Write commands on the bus. The device addressed by the
master is referred to as a slave.
SYNCHRONOUS BUS:
On a synchronous bus, all devices derive timing information from a control line called the bus clock
The signal on this line has two phases: a high level followed by a low level. The two phases constitute a
clock cycle. The first half of the cycle between the low-to-high and high-to-low transitions is often
referred to as a clock pulse.
T
EN
D
U
ST
During clock cycle 1, the master sends address and command information on the bus, requesting
a Read operation. The slave receives this information and decodes it. It begins to access the requested
data on the active edge of the clock at the beginning of clock cycle 2. The data become ready and are
R
placed on the bus during clock cycle 3. The slave asserts a control signal called Slave-ready at the same
M
time. The master, which has been waiting for this signal, loads the data into its register at the end of the
clock cycle. The slave removes its data signals from the bus and returns its Slave-ready signal to the low
level at the end of cycle 3. The bus transfer operation is now complete, and the master may send new
address and command signals to start a new transfer in clock cycle 4.
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 85 of 90
CS8491-Computer Architecture Department of CSE & IT
ASYNCHRONOUS BUS:
An alternative scheme for controlling data transfers on a bus is based on the use of a handshake
protocol between the master and the slave. A handshake is an exchange of command and response
signals between the master and the slave. A control line called Master-ready is asserted by the master to
indicate that it is ready to start a data transfer. The Slave responds by asserting Slave-ready.
t0—The master places the address and command information on the bus, and all devices on the bus
T
decode this information.
EN
t1—The master sets the Master-ready line to 1 to inform the devices that the address and command
information is ready. The delay t1 − t0 is intended to allow for any skew that may occur on the bus.
D
Skew occurs when two signals transmitted simultaneously from one source arrive at the destination
at different times.
U
t2—The selected slave, having decoded the address and command information, performs the
required input operation by placing its data on the data lines. At the same time, it sets the Slave-ready
ST
signal to 1.
t3—The Slave-ready signal arrives at the master, indicating that the input data are available on the
bus.
R
t4—The master removes the address and command information from the bus.
M
t5—When the device interface receives the 1-to-0 transition of the Master-ready signal, it removes the
data and the Slave-ready signal from the bus. This completes the input transfer.
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 86 of 90
CS8491-Computer Architecture Department of CSE & IT
BUS ARBITRATION
It is the process by which the next device to become the bus master is selected and the bus
mastership is transferred to it.
Types:
There are 2 approaches to bus arbitration. They are
i)Centralized arbitration ( A single bus arbiter performs arbitration)
ii)Distributed arbitration (all devices participate in the selection of next bus master).
Centralized Arbitration:
Here the processor is the bus master and it may grants bus mastership to one of its DMA
controller. A DMA controller indicates that it needs to become the bus master by activating the Bus
Request line (BR) which is an open drain line. The signal on BR is the logical OR of the bus request from
all devices connected to it. When BR is activated the processor activates the Bus Grant Signal (BGI) and
indicated the DMA controller that they may use the bus when it becomes free. This signal is connected
to all devices using a daisy chain arrangement. If DMA requests the bus, it blocks the propagation of
Grant Signal to other devices and it indicates to all devices that it is using the bus by activating open
collector line, Bus Busy (BBSY).
A simple arrangement for bus arbitration using a daisy chain
Sequence of signals during transfer of bus mastership for the devices
The timing diagram shows the sequence of events for the devices connected to the processor is
shown. DMA controller 2 requests and acquires bus mastership and later releases the bus. During its
tenture as bus master, it may perform one or more data transfer. After it releases the bus, the processor
resources bus mastership.
Distributed Arbitration:
T
EN
It means that all devices waiting to use the bus have equal responsibility in carrying out the arbitration
process.
D
Each device on the bus is assigned a 4 bit id. When one or more devices request the bus, they
assert the Start-Arbitration signal & place their 4 bit ID number on four open collector lines, ARB0 to
ARB3. A winner is selected as a result of the interaction among the signals transmitted over these lines.
The net outcome is that the code on the four lines represents the request that has the highest ID number.
The drivers are of open collector type. Hence, if the i/p to one driver is equal to 1, the i/p to another
driver connected to the same bus line is equal to 0 (ie) bus the is in low-voltage state Eg: Assume two
devices A & B have their ID 5 (0101), 6(0110) and their code is 0111.
Each device compares the pattern on the arbitration line to its own ID starting from MSB.
If it detects a difference at any bit position, it disables the drivers at that bit position. It does this
by placing „0‟ at the i/p of these drivers. In our eg., A detects a difference in line ARB1, hence it disables
the drivers on lines ARB1 & ARB0. This causes the pattern on the arbitration line to change to 0110 which
means that B has won the contention.
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 87 of 90
CS8491-Computer Architecture Department of CSE & IT
INTERFACE CIRCUITS
The I/O interface of a device consists of the circuitry needed to connect that device to the bus. On one
side of the interface are the bus lines for address, data, and control. On the other side are the connections
needed to transfer data between the interface and the I/O device. This side is called a port, and it can be
either a parallel or a serial port. A parallel port transfers multiple bits of data simultaneously to or from
the device. A serial port sends and receives data one bit at a time. An I/O interface does the following:
1. Provides a register for temporary storage of data
2. Includes a status register containing status information that can be accessed by the processor
3. Includes a control register that holds the information governing the behavior of the interface
4. Contains address-decoding circuitry to determine when it is being addressed by the processor
5. Generates the required timing signals
6. Performs any format conversion that may be necessary to transfer data between the processor
and the I/O device, such as parallel-to-serial conversion in the case of a serial port
PARALLEL INTERFACE
An interface circuit for an 8-bit input port that can be used for connecting a simple input device,
such as a keyboard. An interface circuit for an 8-bit output port, which can be used with an output device
such as a display. Interface circuits are connected to a 32-bit processor that uses memory-mapped I/O
and the asynchronous bus protocol.
Input Interface
T
There are only two registers: a data register, KBD_DATA, and a status register, KBD_STATUS.
The latter contains the keyboard status flag, KIN. A typical keyboard consists of mechanical switches that
EN
are normally open. When a key is pressed, its switch closes and establishes a path for an electrical signal.
A difficulty with such mechanical pushbutton switches is that the contacts bounce when a key is pressed,
D
resulting in the electrical connection being made then broken several times before the switch settles in
U
the closed position. The software detects that a key has been pressed when it observes that the keyboard
status flag, KIN, has been set to 1. The I/O routine can then introduce sufficient delay before reading the
ST
contents of the input buffer, KBD_DATA, to ensure that bouncing has subsided. When debouncing is
implemented in hardware, the I/O routine can read the input character as soon as it detects that KIN is
R
equal to 1. It consists of one byte of data representing the encoded character and one control signal called
Valid. When a key is pressed, the Valid signal changes from 0 to 1. The status flag is cleared to 0 when
M
the processor reads the contents of the KBD_DATA register. The interface circuit is connected to an
asynchronous bus on which transfers are controlled by the handshake signals Master-ready and Slave-
ready. The bus has one other control line, R/W, which indicates a Read operation when equal to 1.
Output Interface
It can be used to connect an output device such as a display. The display uses two handshake
signals, New-data and Ready, in a manner similar to the handshake between the bus signals Master-
ready and Slave-ready. When the display is ready to accept a character, it asserts its Ready signal, which
causes the DOUT flag in the DISP_STATUS register to be set to 1. When the I/O routine checks DOUT
and finds it equal to 1, it sends a character to DISP_DATA. This clears the DOUT flag to 0 and sets the
New-data signal to 1. In response, the display returns Ready to 0 and accepts and displays the character
in DISP_DATA
SERIAL INTERFACE
A serial interface is used to connect the processor to I/O devices that transmit data one bit at a time.
Data are transferred in a bit-serial fashion on the device side and in a bit-parallel fashion on the processor
side. The transformation between the parallel and serial formats is achieved with shift registers that
have parallel access capability. The input shift register accepts bit-serial input from the I/O device.
When all 8 bits of data have been received, the contents of this shift register are loaded in parallel into the
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 88 of 90
CS8491-Computer Architecture Department of CSE & IT
DATAIN register. Output data in the DATAOUT register are transferred to the output shift register,
from which the bits are shifted out and sent to the I/O device. The part of the interface that deals with
the bus is the same as in the parallel interface described earlier. Two status flags, which we will refer to
as SIN and SOUT, are maintained by the Status and control block. The SIN flag is set to 1 when new data
are loaded into DATAIN from the shift register, and cleared to 0 when these data are read by the
processor. The SOUT flag indicates whether the DATAOUT register is available. It is cleared to 0 when
the processor writes new data into DATAOUT and set to 1 when data are transferred from DATAOUT to
the output shift register. The double buffering used in the input and output paths in Figure 7.15 is
important. It is possible to implement DATAIN and DATAOUT themselves as shift registers, thus
obviating the need for separate shift registers
USB
The Universal Serial Bus (USB) is the most widely used interconnection standard. A large
variety of devices are available with a USB connector, including mice, memory keys, disk drives,
printers, and cameras. The commercial success of the USB is due to its simplicity and low cost. The
original USB specification supports two speeds of operation, called low-speed (1.5 Megabits/s) and full-
speed (12 Megabits/s). It supports data transfer rates up to 5 Gigabits/s.
T
o Accommodate a wide range of I/O devices and bit rates, including Internet connections, and
EN
audio and video applications
o Enhance user convenience through a ―plug-and-play‖ mode of operation
D
DEVICE CHARACTERISTICS:
U
The kinds of devices that may be connected to a computer cover a wide range of functionality. The
speed, volume, and timing constraints associated with data transfers to and from these devices vary
ST
significantly. One byte of data is generated every time a key is pressed, which may happen at any time.
These data should be transferred to the computer promptly. The event of pressing a key is not
R
synchronized to any other event in a computer system, the data generated by the keyboard are called
asynchronous. The sampling process yields a continuous stream of digitized samples that arrive at
M
regular intervals, synchronized with the sampling clock. Such a data stream is called isochronous,
meaning that successive events are separated by equal periods of time. A signal must be sampled
quickly enough to track its highest-frequency components.
Plug-and-Play
When an I/O device is connected to a computer, the operating system needs some information
about it. It needs to know what type of device it is so that it can use the appropriate device driver.
It also needs to know the addresses of the registers in the device‘s interface to be able to
communicate with it. The USB standard defines both the USB hardware and the software that
communicates with it. Its plug-and-play feature means that when a new device is connected, the system
detects its existence automatically.
USB Architecture
The USB uses point-to-point connections and a serial transmission format. When multiple devices
are connected, they are arranged in a tree structure. Each node of the tree has a device called a hub,
which acts as an intermediate transfer point between the host computer and the I/O devices. At the root
of the tree, a root hub connects the entire tree to the host computer. The leaves of the tree are the I/O
devices: a mouse, a keyboard, a printer, an Internet connection, a camera, or a speaker. The tree structure
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 89 of 90
CS8491-Computer Architecture Department of CSE & IT
makes it possible to connect many devices using simple point-to-point serial links.
T
The USB uses point-to-point connections and a serial transmission format. When multiple devices
are connected, they are arranged in a tree structure. Each node of the tree has a device called a hub,
EN
which acts as an intermediate transfer point between the host computer and the I/O devices. At the root
of the tree, a root hub connects the entire tree to the host computer. The leaves of the tree are the I/O
D
devices: a mouse, a keyboard, a printer, an Internet connection, a camera, or a speaker. The tree structure
U
makes it possible to connect many devices using simple point-to-point serial links.
ST
Electrical Characteristics
USB connections consist of four wires, of which two carry power, +5 V and Ground, and two carry
data. I/O devices that do not have large power requirements can be powered directly from the USB.
R
Two methods are used to send data over a USB cable. When sending data at low speed, a high voltage
M
relative to Ground is transmitted on one of the two data wires to represent a 0 and on the other to
represent a 1. The Ground wire carries the return current in both cases. Such a scheme in which a signal
is injected on a wire relative to ground is referred to as single-ended transmission. The speed at which
data can be sent on any cable is limited by the amount of electrical noise present. The term noise refers to
any signal that interferes with the desired data signal and hence could cause errors. Single-ended
transmission is highly susceptible to noise. The voltage on the ground wire is common to all the devices
connected to the computer. Signals sent by one device can cause small variations in the voltage on the
ground wire, and hence can interfere with signals sent by another device. Interference can also be caused
by one wire picking up noise from nearby wires. The High-Speed USB uses an alternative arrangement
known as differential signaling. The data signal is injected between two data wires twisted together.
St. Joseph’s College of Engineering & St. Joseph’s Institute of Technology Page 90 of 90