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12.1 Courceware

The document outlines the Advanced Math A3 course, covering topics such as vectors, partial derivatives, and multiple integrals over 48 periods. It includes details on homework assignments, exam grading criteria, and specific chapters on three-dimensional coordinate systems, distance formulas, and equations of spheres. Reference books for the course are also provided.

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Musfiqur Noman
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0% found this document useful (0 votes)
15 views20 pages

12.1 Courceware

The document outlines the Advanced Math A3 course, covering topics such as vectors, partial derivatives, and multiple integrals over 48 periods. It includes details on homework assignments, exam grading criteria, and specific chapters on three-dimensional coordinate systems, distance formulas, and equations of spheres. Reference books for the course are also provided.

Uploaded by

Musfiqur Noman
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
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Download as PDF, TXT or read online on Scribd
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Advanced Math A3

付乳燕~ Fu Ruyan

E-mail: furuyan@cumt.edu.cn
Advanced Math
A3: 48 periods
Mon(3.4), Wed(3.4), Thu(5.6)

12. Vectors and the Geometry of Space

14. Partial Derivatives

15. Multiple Integrals


Reference Books:
1. Weir , Hass and Giordano, Thomas’ Calculus (Eleventh Edition) .

2. James Steward, Calculus (Seventh Edition).


About homework:
We assign homework after each class. Please hand in
it on every Monday.

Examining Method:
Attendance, speak, homework and other performance
in class account for 30%, and the final exam accounts
for70% in the hundred-mark system.
Chapter 12 Vectors and the Geometry of Space

§12.1 Three-Dimensional Coordinate Systems

§12.2 Vectors

§12.3 The Dot Product

§12.4 The Cross Product

§12.5 Lines and planes in Space


§12.1 Three-Dimensional Coordinate Systems

1. Three-dimensional rectangular coordinate system

2. Distance and Spheres in Space


y
First, we recall two-dimensional
rectangular coordinate system.
Any point in the plane can be b P ( a, b)
represented as an ordered pair (a,b)
of real numbers.
x
o a
Point P ( a, b)
1. Three-dimensional rectangular coordinate system

The x- and y-axes are horizontal and the z-axis is


vertical. (Fig 1)
The direction of z-axis is determined by the right-hand
rule. (Fig 2)
The three coordinate axes determine the three coordinate
planes: the xy-plane, the yz-plane and the xz-plane.
These three coordinate planes divide space into eight parts,
called octants.

Ⅲ z
zox plane
yoz plane


y Ⅰ
o
xoy plane

Ⅶ x Ⅵ


Eight octants
For any point P in space, we represent it by an ordered
triple (a,b,c) of real numbers,where a, b, and c are called
the coordinates of P.
11
P (a, b, c)
z
O(0,0,0)
c C
A(a,0,0)
 P
B
 y B(0, b,0)
o
A b
x a C (0,0, c)

10
The Cartesian product R  R  R  {( x, y, z ) x, y, z  R}
is the set of all ordered triples of real numbers and
is denoted by R 3, which is also the set of all
ponits in space.

z
Three-dimensional
rectangular coordinate
system
o 
y

x
In R 2 , the graph of an equation involving x and y
is a curve. For example,
x  1 a line; x  y  1 a circle;
2 2

In R 3 , an equation in x, y, and z represents a surface.

Example 1 What surfaces in R 3 are represented by


the following equations?

(1) z  3 (2) y5


Solution

(a) z  3, a palne in R 3 (b) y  5, a palne in R 3

Qu1: what is the graph of equation y  5 in R 2 ?


EXAMPLE 2 Graphing Equations.
What points P(x, y, z) satisfy the equations
x2  y2  4 and z 3

Solution
the circle x 2  y 2  4
in the plane z  3

Remark:
The equation x 2  y 2  4
represents a cylinder
2. Distance and Spheres in Space
The Distance Between P1 ( x1 , y1 , z1 ) and P2 ( x2 , y2 , z 2 ) is

P1 P2  ( x2  x1 ) 2  ( y2  y1 ) 2  ( z 2  z1 ) 2
EXAMPLE 3 Finding the Distance Between Two Points

The distance between P1(2,5,3) and P2(-1,1,3) is

P1 P2  (1  2) 2  (1  5) 2  (3  3) 2
 9  16
5
We can use the distance formula to write equations
for spheres in space.
The Standard Equation for the Sphere of Radius a and
Center ( x0 , y0 , z0 )
( x  x0 ) 2  ( y  y0 ) 2  ( z  z0 ) 2  a 2 .
In particular, if the cernter of the sphere is the origin O
and the radius is r, the eqution is

x y z r
2 2 2 2

EXAMPLE 4: Finding the Center and Radius of a Sphere


x2  y2  z 2  4x  6 y  2z  0
Solution
( x 2  4 x  4)  ( y 2  6 y  9)  ( z 2  2 z  1)  4  9  1
( x  2) 2  ( y  3) 2  ( z  1) 2  14
Center (2,3,1); Radius 14
Summary

• Three-dimensional rectangular system


• The formula of distance in space
• The equation of a sphere in space
Homework
1. Page 6~ exercise 10;
2. Page 7~ exercise 15.16

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