Module Title: Dynamics and Performance of Mechanical Systems
Module Code: 7ENT1081
                    Student ID: 23028135
Given Values
            Parameter                          Value            Source (Provided Tables)
         Shaft Speed (N)                      2415 rpm                 Table 1 (Y = 5)
    Number of Rolling Elements (n)               27                    Table 2 (Y = 5)
         Contact Angle (β)                      11°                    Table 3 (Y = 5)
                                                              Table 4 (X=3, Y=5 → D[5][3] = 99
             Pitch Diameter (D)                99 mm
                                                                            mm)
                                                              Table 5 (X=3, Y=5 → d[5][3] = 20
        Rolling Element Diameter (d)           20 mm
                                                                            mm)
First, converting the shaft speed to revolutions per second (RPS):
                                                  2415
                                  N=2415 rpm=          =40.25 RPS
                                                   60
Also converting the contact angle β into radians:
                                       °    11∗π
                                  β=11 =         =0.19199radians
                                             180
Question. 01
         Ball Pass Frequency Inner (BPFI)
It is given as:
                                        n
                                        2
                                               d
                                                    (
                                   BPFI= ∗N∗ 1+ cos ( β )
                                               D                 )
Substituting values:
                                             27
                                   BPFI=        ∗40.25 (1+ 0.1985 )
                                              2
                                       ¿ 13.5∗40.25∗1.1985
                                           ¿ 543.375∗1.1985
                                           BPFI=651.41 Hz
Question. 02
         Ball Pass Frequency Outer (BPFO)
It is given as:
                                        n
                                        2
                                               d
                                                    (
                                   BPFO= ∗N∗ 1− cos ( β )
                                               D                  )
Substituting values:
                                             27
                                   BPFO=        ∗40.25 ( 1−0.1985 )
                                              2
                                       ¿ 13.5∗40.25∗0.8015
                                           ¿ 543.375∗0.8015
                                     BPFO=435.45 Hz
Question. 03
       Ball Spin Frequency (BSF)
It is given as:
                                             ( (            ))
                                                               2
                                     D        d
                            BSF=        ∗N∗ 1− cos ( β )
                                     2d       D
Substituting values:
                                     99
                                         ∗40.25∗( 1−( 0.1985 ) )
                                                              2
                           BSF=
                                    2∗20
                                    ¿ 2.475∗( 1−0.0394 )
                                    ¿ 99.61875∗0.9606
                                       BSF=95.63 Hz
Question. 04
       Fundamental Train Frequency (FTF)
It is given as:
                                   1
                                   2
                                          d
                                              (
                              FTF = ∗N∗ 1− cos ( β )
                                          D                )
Substituting values:
                                  1
                             FTF = ∗40.25∗ ( 1−0.1985 )
                                  2
                                      ¿ 20.125∗0.8015
                                      FTF=16.12 Hz