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Chemistry - Class Test-5

This document outlines a Class Test for Chemistry focusing on Chemical Bonding, Salt Analysis, and Coordination, with a total duration of 30 minutes and a maximum score of 60 marks. It includes multiple sections with various types of questions, including multiple-choice questions, matching lists, and numerical value answers, each with specific marking schemes. The test assesses knowledge on topics such as hybridization, polarization, and the properties of chemical species.

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0% found this document useful (0 votes)
17 views3 pages

Chemistry - Class Test-5

This document outlines a Class Test for Chemistry focusing on Chemical Bonding, Salt Analysis, and Coordination, with a total duration of 30 minutes and a maximum score of 60 marks. It includes multiple sections with various types of questions, including multiple-choice questions, matching lists, and numerical value answers, each with specific marking schemes. The test assesses knowledge on topics such as hybridization, polarization, and the properties of chemical species.

Uploaded by

babumota079
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as PDF, TXT or read online on Scribd
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Class Test-5

25A* & 25DA* Batch


[Chemistry]
Duration: 30 Minutes [Chemical Bonding , Salt Analysis, Coordination] MAX. MARKS: 60

Section A (Maximum Marks : 15)


• This section contains four (05) questions.
• Each question has four options (A), (B), (C) And (D). Only one of these four options os the
correct answer.
• For each question, choose the option corresponding to the correct answer.
• Answer to each question will be evaluated according to the following marking scheme:
Full marks: +3 If only the correct option is chosen;
Zero marks: 0 If none of the options is chosen (I.E. the question is unanswered);
Negative marks: “1 in all other cases.
1. Which of the following odd e– species is planar ?
(A) CH3+ (B) C lO3 (C) CF3 (D) None of these
3
2. Which of the following species has sp hybridisation :-
(A) C H3 (B) CF3 (C) ClO2 (D) None of these
3. In which of the following unpaired electron reside in unhybridised orbital
(A) ClO2 (B) ClO3 (C) CF3 (D) NO2

4. Na2SO3 and Na2S2O3 cannot be distinguished by


(A) addition of Pb(OAc)2 followed by heating (B) A & C
(C) addition of AgNO3 followed by heating (D) None
5. Find the correct option in which both ligands form same member rings with central metal ion -
–2 – – – 2–
(A) ox , Cl (B) en, gly (C) Py, Br (D) CO3 , en

Section B (Maximum Marks : 20)


• This section contains five (05) questions.
• Each question has four options (A), (B), (C) and (D). One or more than one of these four
option(s) is(are) correct answer(s).
• For each question, choose the option(s) corresponding to (all) the correct answer(s).
• Answer to each question will be evaluated according to the following marking scheme:
Full marks : +4 Only if (all) the correct option(s) is(are) chosen;
Partial marks : +3 If all the four options are correct but only three options are chosen;
Partial marks : +2 If three or more options are correct but only two options are chosen,
both of which are correct;
Partial marks : +1 If two or more options are correct but only one option is chosen and it
is a correct option;
Zero marks : 0 If none of the options is chosen (I.E. the question is unanswered);
Negative marks : “2 In all other cases.
• For example, in a question, if (A), (B) and (D) are the only three options corresponding to
correct answers, then
Choosing only (A), (B) and (D) will get +4 marks;
Choosing only (A) and (B) will get +2 marks;
Choosing only (A) and (D) will get +2 marks;
Choosing only (B) and (D) will get +2 marks;
Choosing only (A) will get +1 mark;
Choosing only (B) will get +1 mark;
Choosing only (D) will get +1 mark;
Choosing no option (I.E. the question is unanswered) will get 0 marks; and
Choosing any other combination of options will get “2 marks.

Motion Education | 394-Rajeev Gandhi Nagar | : 1800-212-1799 | url : www.motion.ac.in | Page No. # 1
6. Polarisation may be called as the distortion of the shape of an anion by an adjacently placed cation.
Which of the following statements is/are not correct?
(A) Minimum polarization is brought about by a cation of low radius
(B) A large cation is likely to bring about a large degree of polarisation
(C) Maximum polarization is brought about by a cation of high charge
(D) A small anion is likely to undergo a large degree of polarisation
7. Which of the following overlapping results non bonding M.O. (if overlapping axis is x-axis) :
(A) s of A & py of B (B) pz of A & pz of B (C) py of A & pz of B (D) dxy of A & s of B

8. Which of the following metal is/are not inert towards reaction with H2O.
(A) Be (B) Na (C) Ca (D) K
9. Which of the following methods can be used to produce phosphine gas ?
(A) Ca3P2 + H2O ⎯⎯→ (B) PH4I + KOH ⎯⎯→
(C) Heating of H3PO2 (D) White P + NaOH ⎯⎯⎯⎯inert
atmosphere

10. Which of the following chemical species can act as non-classical ligand(s)
+
(A) CO (B) C2H4 (C) NO (D) PR3

Section C (Maximum Marks: 4)


• This section contains one (01) matching list sets.
• The set has one multiple choice question.
• The set has two lists: list-I and list-II.
• List-I has four entries (P), (Q), (R) and (S) and List-II has five entries (1), (2), (3), (4)
and (5).
• Four options are given in each multiple choice question based on list-I and list-II and only
one of these four options satisfies the condition asked in the multiple choice question.
• Answer to each question will be evaluated according to the following marking scheme:
Full marks : +4 only if the option corresponding to the correct combination is chosen;
Zero marks : 0 If none of the options is chosen (I.E. the question is unanswered);
Negative marks : 1 In all other cases.
11. Match the catalysts to the correct processes:-
Catalyst Process
(A) TiCl3 (I) Wacker process
(B) PdCl2 (II) Ziegler-Natta polymerization
(C) CuCl2 (III) Contact process
(D) V2O5 (IV) Deacon's process
(A)A-II, B-III, C-IV, D-I (B) A-III, B-I, C-II, D-IV
(C) A-III, B-II, C-IV, D-I (D)A-II, B-I, C-IV, D-III

Section D (Maximum Marks: 6)


• This section contains one (01) paragraphs.
• Based on each paragraph, there are two (02) questions.
• The answer to each question is a numerical value.
• For each question, enter the correct numerical value of the answer using the mouse and
the on-screen virtual numeric keypad in the place designated to enter the answer.
• If the numerical value has more than two decimal places, truncate/round-off the value to
two decimal places.
• Answer to each question will be evaluated according to the following marking scheme:
Full marks : +3 If only the correct numerical value is entered in the designated place;
Zero marks : 1 In all other cases.
Paragraph for question nos. 9 to 10
The reaction of straight K3[Fe (CN)6] with freshly prepared FeSO4 solution produces a dark blue precipitate
called Turnbull's blue. Reaction of straight K4[Fe(CN)6] with the FeSO4 solution in complete absence of air
produces a white preipitate X, which turns blue in air. Mixing the FeSO 4 solution with NaNO3,followed by a
slow addition of concentrated straight H2SO4 through the side of the test tube produces a brown ring.

Motion Education | 394-Rajeev Gandhi Nagar | : 1800-212-1799 | url : www.motion.ac.in | Page No. # 2
2 3
12. How many d sp hybridised Fe atom in Purssian Blue.

13. Oxidation state of iron is brown ring complex

Section E (Maximum Marks: 15)


• This section contains three (05) questions.
• The answer to each question is a numerical value.
• For each question, enter the correct numerical value of the answer using the mouse and
the onscreen virtual numeric keypad in the place designated to enter the answer.
• If the numerical value has more than two decimal places, truncate/round-off the value to
two decimal places.
• Answer to each question will be evaluated according to the following marking scheme:
Full marks : +3 If only the correct numerical value is entered in the designated place;
Zero marks : 0 In all other cases.
14. Find the number of correct statement(s) is/are :-
(I) Both double salts as well as complexes are formed by the combination of two or more stable compounds in
stoichiometric ratio
(II) double salts such as carnallite, KCl.MgCl2.6H2O, potash alum, KAl(SO4)2.12H2O, etc. dissociate into simple
ions completely when dissolved in water
4– 2+ –
(III) complex ions such as [Fe(CN)6] of K4Fe(CN)6, do not dissociate into Fe and CN ions
(IV) Mohr’s salt, FeSO4.(NH4)2SO4.6H2O does not, dissociate into simple ions completely when dissolved in
water
3+ –
(V) [CoCl2(NH3)4]Cl complex dissociate into Co and Cl ions

15. In the given following compounds, the total number of compounds which contains secondary valences of metals
is six :
PdCl2.4NH3 , NiCl2.6H2O , PtCl4.2HCl , CoCl3.4NH3 , PtCl2. 2NH3


16. Find the total number of 5-membered rings present in [Co(EDTA)] .
+4
17. Find the value of E.A.N of [Pd(NH3)6] (atomic number = 46) :

2+ – o
18. How many geometrical isomers are possible for [Pd (NH2–CH(CH3)– CO2 )2]

Motion Education | 394-Rajeev Gandhi Nagar | : 1800-212-1799 | url : www.motion.ac.in | Page No. # 3

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