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Answer 17932

The document outlines the probability calculations for drawing specific combinations of cards from a standard 52-card deck. It details the probabilities for drawing a king, queen, jack, and ace; two kings and two aces all diamonds; two red and two black cards; and two clubs and two diamonds. The document also notes that the probability of drawing two kings and two aces all diamonds is zero due to the limited number of those cards in the deck.

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0% found this document useful (0 votes)
37 views2 pages

Answer 17932

The document outlines the probability calculations for drawing specific combinations of cards from a standard 52-card deck. It details the probabilities for drawing a king, queen, jack, and ace; two kings and two aces all diamonds; two red and two black cards; and two clubs and two diamonds. The document also notes that the probability of drawing two kings and two aces all diamonds is zero due to the limited number of those cards in the deck.

Uploaded by

Sarif Hussain
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
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Conditions

Four cards are drawn at random from a pack of 52 cards. Find the probability that this consists
of:
a. a king, a queen, a jack and an ace.
b. two kings and two ace all diamonds.
c. two red and two blacks.
d. two clubs and two diamonds

Solution

The classic definition of probability claims, that the probability of some random event A is equal to a
rate of all favorable outcomes for this event to all possible outcomes.

a) The probability of 1st card is a king is 4/52, the probability of the second card is a queen is 4/51,
jack – 4/50, ace – 4/49.

This is 4 independent events, and the probability of their occasion at the same time is a product of
values above:

b) The probability of two kings and two ace – all diamonds – is equal to 0, as in a card pack there is
only one king is diamond and only one ace.
c) The probability of drawing 2 red cards is equal to:

The probability of drawing 2 black cards after first and second were red is equal to:

The probability of 2 red and 2 blacks:

d) The probability of 2 clubs is:

The probability of 2 diamonds after first and second were clubs is:

The probability of 2 clubs and 2 diamonds is:

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