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Calculations

The document outlines a project layout for a pipeline system, detailing parameters such as flow capacity, pipe lengths, and diameters between various cities. It includes calculations for pressure, velocity, and thickness for different segments of the pipeline, as well as hydrostatic test pressures and bursting pressures. The data is presented in a structured format with specific values for each segment, emphasizing the engineering considerations for the pipeline design.

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Ahmed Kahraba
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© © All Rights Reserved
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47 views18 pages

Calculations

The document outlines a project layout for a pipeline system, detailing parameters such as flow capacity, pipe lengths, and diameters between various cities. It includes calculations for pressure, velocity, and thickness for different segments of the pipeline, as well as hydrostatic test pressures and bursting pressures. The data is presented in a structured format with specific values for each segment, emphasizing the engineering considerations for the pipeline design.

Uploaded by

Ahmed Kahraba
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as DOCX, PDF, TXT or read online on Scribd
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Project layout

S C C C C
1 3 4

C C
6 ∘ 3
5
T b=520 K , P b=14.7 Psia , T f =540 R , Q=200 M ft /day

P1=130 Psia , P2=80 Psia ,G=0.732 , Z=0.91 , F=0.72


3
200 M ft /day
S 49.712 mile
C
1
From source to city 1

H 1=610.2288 ft , L=49.712 mile , H 2 =1850.3712 ft

s=0.0375 G
( H 2−H 1
Tf Z )
=0.0375 × 0.732× (
1850.3721−610.2288
450 ×0.91
=0.0693 )

L(e s−1) 49.712 ( e0.0693 −1 )


Le = = =51.477 mile
s 0.0693

[ ] [ ]
1.02 0.51
Tb P21−e s P22 2.53
Q=737 × E × 0.961
D¿
Pb G Le T fZ

Solve to get D¿ D¿ =37.838 inch

P Do
From table Dout =42 inch , t= =0.0542inch
2× SETF

t Design =0.375inch from table


D¿ ]new =Dout −2 t=41.25inch

Pb GQ
Re =.5134[ ] [ µ D ] G=.732 , Q( m3/ day) ꓹ D¿ (mm) ꓹ Pb (KPA) ꓹ
Tb inner
T b (K) (SI)
Q Pb ZT
U = 14.7349[ ]
2 [ ][ ] , Q( m3/ day) ꓹ D¿ (mm) ꓹ Pb
D¿ T b P∈¿ ¿
(KPA) ꓹ P (KPA) ꓹ T b (K) ꓹ Tf (K) (SI UNIT)
U ER , MAX

(USCS)
= 100
√ ZRT
29 GP
ꓹ R =10.73 ꓹ Tf (RANKINE) ꓹ P=130 PSI , Z =.91 , G=.732

t (thickness)
MAOP=2ƒσ min DOUTER
, ƒ=.72 ,σ min=70000 SMYS, t( inch), DOUTER (inch)

Ht ( hydrostatic test pressure) =1.25 MAOP


t (thickness)
Bp (brusting pressure) =2σ min Dinner
,σ min=70000 SMYS ,t(inch), D INNER (inch)
(USCS)
t (thickness)
Py (plastic collapse pressure) =2σ max Dinner
, ,σ max=92100 ,t(inch),
D INNER (inch) (USCS)

Parameters Symbol Result

Flow Q 3
200 M ft /day
Capacity

Pipe lenght L 80 km
Inner Di 41.25 inch
Diamter

Outer Do 42 inch
Diamter

Inlet Pi 130 psia


Pressure

Outer Po 80 psia
Pressure

Flow u 8.118 m/s


Velocity

Errossial uer 41.584 m/sec


Velocity
MAOP

Bursting Bp
Pressure

Plastic Py
collapse
Pressure

Hydro Test Ht
Pressure

From city 1 to city 2


H 1=1850.3712 ft , H 2=1804.44 ft , L=59.6544 mile

s=0.0375 G
( Tf Z )
H 2−H 1
=0.0375 × 0.732× (
1804.44−1850.3712
450 ×0.91 )
=−0.002566

L(e s−1) 59.6544 ( e−0.002566−1 )


Le = = =59.579 mile
s −0.002566
[ ] [ ]
1.02 0.51
Tb P21−e s P22 2.53
Q=737 × E × 0.961
D¿
Pb G Le T fZ

Solve to get D¿ D¿ =33.25 inch

P Do
From table Dout =34 inch , t= =0.0438 inch
2× SETF

t Design =0.375inch from table


D¿ ]new =D out −2 t =33.25 inch

Pb GQ
Re =.5134[ ] [
T b µ D inner
] G=.732 , Q( m3/ day) ꓹ D¿ (mm) ꓹ Pb (KPA) ꓹ
T b (K) (SI)

Q Pb ZT
U = 14.7349[ ]
2 [ ][ ] , Q( m3/ day) ꓹ D¿ (mm) ꓹ Pb
D¿ T b P∈¿ ¿
(KPA) ꓹ P (KPA) ꓹ T b (K) ꓹ Tf (K) (SI UNIT)

U ER , MAX

(USCS)
= 100
√ ZRT
29 GP
ꓹ R =10.73 ꓹ Tf (RANKINE) ꓹ P=130 PSI , Z =.91 , G=.732

t (thickness)
MAOP=2ƒσ min DOUTER
, ƒ=.72 ,σ min=70000 SMYS, t( inch), DOUTER (inch)

Ht ( hydrostatic test pressure) =1.25 MAOP


t (thickness)
Bp (brusting pressure) =2σ min Dinner
,σ min=70000 SMYS ,t(inch), D INNER (inch)
(USCS)
t (thickness)
Py (plastic collapse pressure) =2σ max Dinner
, ,σ max=92100 ,t(inch),
D INNER (inch) (USCS)
Parameters Symbol Result

Flow Q 3
137 M ft /day
Capacity

Pipe lenght L 96 km
Inner Di 33.25 inch
Diamter

Outer Do 34 inch
Diamter

Inlet Pi 130 psia


Pressure

Outer Po 80 psia
Pressure

Flow u 7.6 m/s


Velocity

Errossial uer 41.584 m/sec


Velocity

MAOP

Bursting Bp
Pressure

Plastic Py
collapse
Pressure

Hydro Test Ht
Pressure
From city 1 to city 6

H 1=1850.3712 ft , H 2=328.08 ft , L=12.428 mile

s=0.0375 G
( Tf Z )
H 2−H 1
=0.0375 × 0.732× (
328.08−1850.3712
450 ×0.91
=−0.085 )

L(e s−1) 12.428 ( e−0.085−1 )


Le = = =11.912 mile
s −0.002566

[ ] [ ]
1.02 0.51
Tb P21−e s P22 2.53
Q=737 × E × 0.961
D¿
Pb G Le T fZ

Solve to get D¿ D¿ =17.512inch


P Do
From table Dout =18inch , t= =0.023 inch
2× SETF

t Design =0.25inch from table


D¿ ]new =Dout −2 t=17.5 inch

Pb GQ
Re =.5134[ ] [ µ D ] G=.732 , Q( m3/ day) ꓹ D¿ (mm) ꓹ Pb (KPA) ꓹ
Tb inner
T b (K) (SI)

Q Pb ZT
U = 14.7349[ ]
2 [ ][ P∈¿ ¿ ] , Q( m3/ day) ꓹ D¿ (mm) ꓹ Pb
D¿ T b
(KPA) ꓹ P (KPA) ꓹ T b (K) ꓹ Tf (K) (SI UNIT)

U ER , MAX

(USCS)
= 100
√ ZRT
29 GP
ꓹ R =10.73 ꓹ Tf (RANKINE) ꓹ P=130 PSI , Z =.91 , G=.732

t (thickness)
MAOP=2ƒσ min DOUTER
, ƒ=.72 ,σ min=70000 SMYS, t( inch), DOUTER (inch)

Ht ( hydrostatic test pressure) =1.25 MAOP


t (thickness)
Bp (brusting pressure) =2σ min Dinner
,σ min=70000 SMYS ,t(inch), D INNER (inch)
(USCS)
t (thickness)
Py (plastic collapse pressure) =2σ max Dinner
, ,σ max=92100 ,t(inch),
D INNER (inch) (USCS)
Parameters Symbol Result

Flow Q 3
63 M ft /day
Capacity

Pipe lenght L 20 km
Inner Di 17.5 inch
Diamter

Outer Do 18 inch
Diamter

Inlet Pi 130 psia


Pressure

Outer Po 80 psia
Pressure

Flow u 11.75 m/s


Velocity

Errossial uer 41.584 m/sec


Velocity

MAOP

Bursting Bp
Pressure

Plastic Py
collapse
Pressure

Hydro Test Ht
Pressure
From city 2 to city 3

H 1=1804.44 ft , H 2=754.584 ft , L=93.21mile

s=0.0375 G
( H 2−H 1
Tf Z )=0.0375 × 0.732× (
754.584−1804.44
450 × 0.91
=−0.0586 )

L(e s−1) 93.21 ( e0.0693 −1 )


Le = = =90.531 mile
s 0.0693

[ ] [ ]
1.02 0.51
Tb P21−e s P22 2.53
Q=737 × E × 0.961
D¿
Pb G Le T fZ

Solve to get D¿ D¿ =35.93 inch

P Do
From table Dout =36 inch , t= =0.046 inch
2× SETF

t Design =0.375inch from table


D¿ ]new =Dout −2 t=35.25 inch

Pb GQ
Re =.5134[ ] [ µ D ] G=.732 , Q( m3/ day) ꓹ D¿ (mm) ꓹ Pb (KPA) ꓹ
Tb inner
T b (K) (SI)

Q Pb ZT
U = 14.7349[ ]
2 [ ][ P∈¿ ¿ ] , Q( m3/ day) ꓹ D¿ (mm) ꓹ Pb
D¿ T b
(KPA) ꓹ P (KPA) ꓹ T b (K) ꓹ Tf (K) (SI UNIT)

U ER , MAX

(USCS)
= 100
√ ZRT
29 GP
ꓹ R =10.73 ꓹ Tf (RANKINE) ꓹ P=130 PSI , Z =.91 , G=.732

t (thickness)
MAOP=2ƒσ min DOUTER
, ƒ=.72 ,σ min=70000 SMYS, t( inch), DOUTER (inch)

Ht ( hydrostatic test pressure) =1.25 MAOP


t (thickness)
Bp (brusting pressure) =2σ min Dinner
,σ min=70000 SMYS ,t(inch), D INNER (inch)
(USCS)
t (thickness)
Py (plastic collapse pressure) =2σ max Dinner
, ,σ max=92100 ,t(inch),
D INNER (inch) (USCS)

Parameters Symbol Result


Flow Capacity Q 3
137 M ft /day

Pipe lenght L 150 km


Inner Diamter Di 35.25 inch
Outer Diamter Do 36 inch
Inlet Pressure Pi 130 psia
Outer Pressure Po 80 psia
Flow Velocity u 5.56 m/s

Errossial Velocity uer 41.584 m/sec

MAOP

Bursting Pressure Bp

Plastic collapse Py
Pressure

Hydro Test Pressure Ht

From city 3 to city 4


H 1=754.584 ft , H 2=360.888 ft , L=80.1606 mile

s=0.0375 G
( H 2−H 1
Tf Z )
=0.0375 × 0.732× (
360.888−754.584
450 ×0.91
=−0.02199 )

L(e s−1) 80.1606 ( e−0.02199−1 )


Le = = =79.284 mile
s −0.02199

[ ] [ ]
1.02 0.51
Tb P21−e s P22 2.53
Q=737 × E × 0.961
D¿
Pb G Le T fZ

Solve to get D¿ D¿ =31.023 inch

P Do
From table Dout =32inch , t= =0.0412inch
2× SETF

t Design =0.375inch from table


D¿ ]new =Dout −2 t=31.25 inch

Pb GQ
Re =.5134[ ] [ µ D ] G=.732 , Q( m3/ day) ꓹ D¿ (mm) ꓹ Pb (KPA) ꓹ
Tb inner
T b (K) (SI)

Q Pb ZT
U = 14.7349[ ]
2 [ ][ P∈¿ ¿ ] , Q( m3/ day) ꓹ D¿ (mm) ꓹ Pb
D¿ T b
(KPA) ꓹ P (KPA) ꓹ T b (K) ꓹ Tf (K) (SI UNIT)

U ER , MAX

(USCS)
= 100
√ ZRT
29 GP
ꓹ R =10.73 ꓹ Tf (RANKINE) ꓹ P=130 PSI , Z =.91 , G=.732
t (thickness)
MAOP=2ƒσ min DOUTER
, ƒ=.72 ,σ min=70000 SMYS, t( inch), DOUTER (inch)

Ht ( hydrostatic test pressure) =1.25 MAOP


t (thickness)
Bp (brusting pressure) =2σ min Dinner
,σ min=70000 SMYS ,t(inch), D INNER (inch)
(USCS)
t (thickness)
Py (plastic collapse pressure) =2σ max Dinner
, ,σ max=92100 ,t(inch),
D INNER (inch) (USCS)

Parameters Symbol Result

Flow Q 3
100 M ft /day
Capacity

Pipe lenght L 129 km


Inner Di 31.25 inch
Diamter

Outer Do 32 inch
Diamter

Inlet Pi 130 psia


Pressure

Outer Po 80 psia
Pressure
Flow u 6.25 m/s
Velocity

Errossial uer 41.584 m/sec


Velocity

MAOP

Bursting Bp
Pressure

Plastic Py
collapse
Pressure

Hydro Test Ht
Pressure

From city 3 to city 6


H 1=754.584 ft , H 2=426.504 ft , L=19.8848 mile

s=0.0375 G
( Tf Z )
H 2−H 1
=0.0375 × 0.732× (
426.504−754.584
450 × 0.91 )
=−0.01833
L(e s−1) 19.8848 ( e−0.01833 −1 )
Le = = =19.705 mile
s −0.01833

[ ] [ ]
1.02 2 s 2 0.51
Tb P1−e P2 2.53
Q=737 × E × 0.961
D¿
Pb G Le T fZ

Solve to get D¿ D¿ =15.82inch

P Do
From table Dout =16 inch , t= =0.0206 inch
2× SETF

t Design =0.25inch from table


D¿ ]new =D out −2 t =15.5 inch

Pb GQ
Re =.5134[ ] [
T b µ D inner
] G=.732 , Q( m3/ day) ꓹ D¿ (mm) ꓹ Pb (KPA) ꓹ
T b (K) (SI)

Q Pb ZT
U = 14.7349[ ]
2 [ ][ ] , Q( m3/ day) ꓹ D¿ (mm) ꓹ Pb
D¿ T b P∈¿ ¿
(KPA) ꓹ P (KPA) ꓹ T b (K) ꓹ Tf (K) (SI UNIT)

U ER , MAX

(USCS)
= 100
√ ZRT
29 GP
ꓹ R =10.73 ꓹ Tf (RANKINE) ꓹ P=130 PSI , Z =.91 , G=.732

t (thickness)
MAOP=2ƒσ min DOUTER
, ƒ=.72 ,σ min=70000 SMYS, t( inch), DOUTER (inch)

Ht ( hydrostatic test pressure) =1.25 MAOP


t (thickness)
Bp (brusting pressure) =2σ min Dinner
,σ min=70000 SMYS ,t(inch), D INNER (inch)
(USCS)
t (thickness)
Py (plastic collapse pressure) =2σ max Dinner
, ,σ max=92100 ,t(inch),
D INNER (inch) (USCS)

Parameters Symbol Result

Flow Q 3
37 M ft /day
Capacity

Pipe lenght L 32 km
Inner Di 15.5 inch
Diamter

Outer Do 16 inch
Diamter

Inlet Pi 130 psia


Pressure

Outer Po 80 psia
Pressure

Flow u 8.344 m/s


Velocity

Errossial uer 41.584 m/sec


Velocity

MAOP
Bursting Bp
Pressure

Plastic Py
collapse
Pressure

Hydro Test Ht
Pressure

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