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Biometry PQ

The document is an examination paper for a Biometry course, consisting of multiple-choice questions and sections requiring detailed answers. It covers various statistical concepts, including data analysis, hypothesis testing, and different statistical tests. The exam is structured to assess students' understanding of biometry principles and their application in real-world scenarios.

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ulibrahim1998
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0% found this document useful (0 votes)
10 views11 pages

Biometry PQ

The document is an examination paper for a Biometry course, consisting of multiple-choice questions and sections requiring detailed answers. It covers various statistical concepts, including data analysis, hypothesis testing, and different statistical tests. The exam is structured to assess students' understanding of biometry principles and their application in real-world scenarios.

Uploaded by

ulibrahim1998
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
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| VAMPH802 BIOMETRY EXAMINATION 2o18-18 SESSION | REG.NO: z | ENT cU:3 i ime: 3 Hours j 2020 Hime:3 Hours i Bater2"* March, 2020 INSTRUCTIONS: Answer“ALL. questions in the Spaces Provided. For multiple choice questions, ONLY ONE letter corresponding to selected option, i circle . SECTION A (3894 No, born glive/Iittor a 4A A 8 ON Ops AMOI 3 AS OoN OD] . i977 1978 Am The chert above presents data on pig mortality recorded.by a far 2007). Use the data to answer questionis 4-4 “ot mer over.a period of 2 years (Thrustield, The data can be called.a.time series data Z6\ Shean end median because : © | Medianand mode 2. It is @ record of more than one year d. | Demarcation’ -of the’ central limit itis @ recording of the:same variable‘én | theorem the same elements overa period of time. 1 None of the above ©. The data is recorded in units of several } + months ‘The variable is continuous over time The shaded portions of the chart indicate Allof the above 2-| Periods of higher piglet mortality bij Petiods of lower piglet mortality, : &-1'Seasonal vatiation in pig mortality 2. The two horizontal lines re the 4.1 Effect of onset of hot mont! 2. Range &{ Periods of higher parturiti hs of the year ion | Page 1 of 10 | | NAME:_ The chart type is often called # Shewhart chart b. Margin of error plots | © Line graph 4d. Demarcated chart ©. Margins of error charts Scatter diagram is Aplotoftretdoveriime | 5. Useful when the data is, Incomplete /* Useful in determining. whettler two “variables correlate \ &: Best presentation formultinomfal data @ Also calle 'd performance charts i Multinomial experimen characteristics {shave the following te | Consists of midentical tials, | 4. Each trial results in one’ of ie possible Outcomes, where k> 2 | © The trials are independent d. The _ probabliities of." the Warious Outcome’ remain constant for ech trial * hi All.of the above i 7. -Amictobioidgtst wishes to:comparé'aerobial z Bacterial ‘counts. of three: different: food. -» Sources. He obtaindd the counts recardedas CFU/ml, ‘He realized that thts variable does 's not normally-distributed ahidhé wishes to determine. whether there, are’ ‘sil differences using ANOVA, he first ne 2, Determine the mears‘of the threel 26 Calculate the median. 4°.) | ‘AC. Transform the data t6:logio V7 A Remove ‘all outlier values’ and take: the means : None of the above ificant d to lcounts, \ e 'n June 2008, a study reported the data below én the oxercise habits of Nigerians. Assume that the study results were true for’the June:2009 population of Nigerians. Suppose'a recent random safnple of 458 ‘Nigerians produced the following’results| Sxercise frequency.” | Number of people | Zorfewer! | 3.6r4 days days a week, 197 IF you are. testing the hypothesis that: the Current. distribution: of exercise frequency Aiffers from that of June 2009, In calcylating the: Expected values for Chi square test statistic then you will use: 3, £5 (tow total x column total/grand total E=np G Eelogye d. E=SUM.(0;402+03)/n @ §(D(0-£)2/6) 8. The hypothesis best suit using: «Chi square test for independence S._Chi square goodness of fit tests © Chi square test for homogeneity Chi squire test for similarity © None of the above 10.:The. major Sifferences between the (Chi ‘square tests Include 2. Number of outcomes. bt ‘Statement of the null hypothesis se ite, ds. Values of n ~~ Differences.:-between’ observed" and expected values Ai. The’. appropriate’: degree . of freedom determination’ for’ Chi square test tor independence 12, Brobability “sampling could involve the following'except: ‘as Use of table of random numbers | NAME Classifying the population into strata Use of a sampling frime Gi. Giving every element equal ‘chance of being selected y Snow-ball sampling HK 13. when a test has two: rejection reglons in Goth ends of the curve, it-is said to be: Binomial test B.A multinomial test C. A repetitive test dv Aright tailed test ate. CO None of the above u~ 14. The following: is true “about the nutt hypothesis 2, Is similar to the alternate hypothesis ‘when the data fs normally distributed b._ Ie can only be'a one-tailed hypothesis [AO Assumes the péputation parameter-to.be: true-unless-declared false a Its use results in type.ll error e,_ Is applicable only to the sample not the population parameter: 3K 15/In Logistic Regression, the output is usyally expressed as: f 2. Attributable risk Correlation coefficient 12 Odds Ratio d. Relative Risk ey Logistic coefficient . Correlation matrix in generated ‘following "| which of this analysis a, Partial correlation b. Logistic regression Multiple correlation d. Multiple regression BR Linear correlation UY 17. The higher the precision of atest the 3a. Larger the number of samples b, “The more accurate the: population estimation re re 1 Fis. ito, baa AtLof the above. © 18. stafidard error is |-2. Same as standard deviat |b. Same as variance j& Ise measure of deviation lls a measure of précision population estimate he above |. None I 19: Poti zorilation volves Comparing only parts 0 ‘compounding variable |. whole of y | Comparing only parts of y wit whole of x | ce cHolding: constant: the effect of [i interfering variables 1-4. Simultaneous: determination of sl |. interacting variables. 1 isolating the effect of the ‘most | i 20, Vafiables thet distort the mean due to their disproportionate magnitude in a data are called a, Disproportionate values .. Interfering values |-e-Outlier-valuies [ds Wide'range values .. ic Non-inclusive values AB 21. Kebskall-wallis analysis of variance by:canks istUsed to-compare: | a. Before and after data | be> Data with’3 independent means poe Data with-3.or more independent | means Data with 3 or more independent means that may or may not be normally distributed €, Data of non-random variables 22, si fundamental difference between 2-test Ax The closer the sample nd anf Chi square test in sequence is population mean . &._ The Lower the alpha value ! Page3of10 | cir pric e is used for normally.digtributed all tollege’ textbooks with thelr 2 wile the others not PE between N65O and N1450 5 L2#F One determines ifferencas while 2. 68% . 2 other associ b: 99.7% c. One is two tailed while the bther is <. 975% one-tailed &. 50% d.- One i left tailed while the bther Is e. 95% righttalled fe, None ofthe above 1 Rank Correlation compares the (PO 8 3 non-parametric. | linear correlation '. Equivalent to Pearson correlation if sample is large. ¢. Used for demographic data dniy 27. The average systolic*blood pressure for | 4000.women who were screened for high ti hebyshev’s: theorem, find at least what REG. NO___—$_$_$_ blood pressure was found to be 187 mm Hg with 2 standard deviation of 22. Using percentage of women in this group have a systolic blood pressure between 143 and 231 mm He. 4. Used for binomial date only + : a. 45% fe. Allof the above | b. 67%" i 95% ‘ 24, The following statements! are trud about d. 75% the Geometric mean except t e. 84% 2. Is a mean suitable for data following « Poisson Distribution b, Best mean: when the data fester values = B 28. c. pplcable when the’ ait does not folio aormal distribution” When researchers try to contact members of a hidden population by finding out wheie such people. congregate,: the. sampling “technique they are using is: 233i" Reyinformant sampling <0... 4 4. “Is equivalent’to:thé median of thé data® Abe. Snoww-ball sampling @. Is:the. At rootof thé product lof the % numbers in the data, t 25. While Harmonic Mean is” > i 4, "Probability sampling | e., None of the above Targeted sampling a.. The mean of execassively largeinumbers 29;-Ifa teseatcher classifies men and womertas b. The mean of rates.“ ' eitfier’ owning a car, truck, SUM or ©. The Mean of ratios : motorcycle, what type of test will help d. The’ reciprocal of “the “sum: bi the determine if pattern of ovmership vary by numbers in the serles | gende: FF The nth’ root ofthe: sum “OF ‘the a. Correlation: reciprocals "| bi: Regression c. 26. The prices of all collage textbooks ‘blow a bell-shaped distribution with 2 man of N1050:and/a'standard’ deviation: cf]N200. Using'the empirical rule, the percentage of “Page-a of 10: Chi square goodness of fit | A Chi'square test for independence | a ANOVA : a 20, Ranking is a suitable method in non- parametric tests becaus 47 The tests use hierarchy b, The test utilizes confidence interval c. The tests uses means . d. The test uses medians e, The test uses mode idall Coefficient of concordance is used to i a. Compare means of parametric data i », Compare means of non-parametric data AE Determine agreement of outcomes in groups J. Determine asso jation of parametric outcornes None of the above, : 3, 32. When Pearson Correlation Coefficient can i assume values i ja, Otot Sead z Be -Lto+d 4 * | : ¢. Strong correlation. es ' 6. Weak correlation | @, All of the above PageSof10 | ee REG. NO., T | SECTION B (312%) 41, The summary of norinally distributed CA scores from a presented as follows:..Mea under curve in all cases. Population of 120 Biometry students wes, 56 and standard deviation of 6, Find the following and show the area < Beg OA ZL a Percent of scores leis than 56 [5 marks) seu sel of fa a b. Atleast 70 (S'marks) Z 1 56. 10 . 3 i c., Between g0.and S0(Fimarka) | GG BA SA r fe 4 2 na abut form, group the following» stat parame eaulains, {8 marks) es * , ANOVA; Paired Sample T-Test; Mann. Whitney:U-test} Kruskal-Wallis tes sample T-test; Wilcoxon Test . Stab Walls test: indepe ndent Ce paaee ptr oe ae phe Pid Suey 26 25 | BEE | te a | =] [Srours | aa sas aa ae [oe Fr ws a] 1“ i Whet parametric test'would you use to é eat seme ‘mean scores between group J and only a bebe S : tet fe i Mention 3 assumptions made regarding the populations " Ee GN oe tae Te Hy bint ey Te 5 ower oe He pop et PASTS As a 5 We Ky el Chace name dly hippies n ~ t 4. Answer the questions below by fling ia the blanks (3 marl) © Leo lear boo ot fa. ‘Total area under curve of normal distribution i b. The appropriate statistical test for comparing means between prewaesination and post g epregeatiyn an vaccination antibody tre i A fe “Peoey pry 4 Pearson's coefficient correlation can only assumé value'betweet and Page 7 of 10, NAME aa SECTION c (3124 Girele the mostiappropriate answer on questions 1-6 A large mass of data ean be best Answer all questions, & 0 © summaries tol by mesh of a. Range «9 b. -“Ahistogram i 4,711.25 © The frequency table 45 \ 4. Standard norma distribution : fe. None of the above 6 Calculate the geometric mean of the somple data: 2.8, 2. Class A for biology cass had a standard 2 32 ° deviation of 2.4 on adtandardized test, be 64 ‘while ciass’B for biology élast had ©. 16 : standard deviation of 12 on:the Same War test. What ean be sald about tse two e.. 81 classes : 7,, The variance of a sample of 81 a. Class A is more homogendul than Observations equals 64. The standard class 8 deviation of the sample equals P© Class 8 is less heterogenedus thane a0 ee . class A i b. 32, 6. Class 8 did ess wlan the test-f ot than css A 4.39 Class A performed twice aslwell on (AE None of the above answers is the test as class B ; correct € Allofthe above f..” fs "SB. calculate Bima Th tie seh of data | 3s Consider.the follging: ditpt 1, oS gato ae 3,3,6,4, the mean and medisn fer this 25M, 12,13, 45:8 8,7,9,10 | data are 4 apa go | a 4and3 Piipe a IE Spy tg hays he b. 4.8 anda % 44 bt Qo 3,7 fc 4and3 Ys, Aya ay, 9 sands eo 36 } ee 8. Independent variables are Vat, i + Adistribution of 7 scores bisa median. Tebreserited'in table by of 21 if the highest score ineraaces a Row | point the median will become | i. Hortzontally 4 21 ( ce Left toright of the table b. 28 § : ere tig H €.". None of the above d. Cannot -bé “determined ‘without ‘ Fe 10 -Alecturer biostatistics asked students ee : in a class their ages. On the basis of his Inforination, the lecturer stotes | ‘Hat the average age of all the x J be Si: The sample, variance of thé following “sample of five numbeis 33,3333 4 S } ee variance median & range YA mode none of the above Page 90f0 NAME:_ semen tt : 2 REG. NG: 10. Complete this table as it rélates to nypothesis testing True situation’ : ee Decision Hos 7 Ho is false Tue cagt, Creed lease | Reject Ho" yeh sy fe 1 t fob | eck idee AC tH cnt Sey indicate the followings: Fo incorrect decision

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