Diffraction 2024
Diffraction 2024
we come
Obstacles
·
across in daily life
Bulidiuse , Vehicles >
-
order of methe
&
((()( =>
Illuminated
Rings
on 118 DOS
·
,
me
-
-
-
↑
·
-
⑲ i icalhee
E
Pla
- Foul
To &
T A
· * D -Listine
both minima
condi
·
NX
· =>
N
·
&
&
&
-
· ⑨ = ·
day
D
- N
-
=>
-
S
·
...
&
:..
#
-
- - -
-
MainFormula .
- Screen
2
First↓
minin a
·
N
with of
cential
Maximum
·
First Minima
Minima
bis it -
position of
01= Angular N=1
divergence of light
on
>
Angulad
.
-
one side
Sino = NX always
-
241
* Y
=
Maximum
B - -
S
=D
hi trugular
S
re
a
Angata
position
-
of 1st Minima
-
--
Minima
-
EX
-
(
a +
Angular position of
N=
1)
Sind =
4
↑
--
V-
first onder Maximum
DX
&
&
=t N=2
52
a=
-
X-
Smaer- -
n
*
a
·
&
V (x)
-
T S
S
Here
W w =D
-
a
-
=f
a
- - -
f
-
W
Mediu
X = 500X109MEXITM DEM
A
- ↑
#
-
In A 25 Xm
-
y =
- >
-
=
solr
Minima
=
X 2
M MM
25x
at
0024
Y S
= 0 2MM .
>
-
-
-
-
↑
-
-
-
-
- *
- Practice
X
See key sheet
#
=>
123
111f
E
(ois man
nue
1 23
, ,
,
E
DIB Aud Sind
= NX
S
·
An = &Sing
BIB =)X
·
aS
&
&
S
·
·
Neett MAIN
①
°
[x] a)
-
mu
GP)
↓
was
=>
Next
-
sold
:
pase
p
6 xov
x =
↑ 50x12
D
=
·
-
Einst
-
third 12mm
,
E c micron
Minima
-
5391 3
-
a a
-
lx =
Dox
a
25/0 Em
·
a=
25 m
.
S =
y
-
&
3500
=>
25mI(904
X zapin Am
Fi
ency
An
M
D >
-
( + 1)D
.
(5) ( +1) + 2
&
3 =
D
#2 = 3000
0 =>
=>
109 x10HZ
109 MHZ
screen
an
A -
slit
orim
O= - o.
~
M
= 0 . 5M
-Im
=
-
&
W = width o Central Maxima
E 2 XD
a
=>
=
5X1BmE5MM
3) 3 d order
↓
miniria
=D
N =3
second order ,
Maxima N a
N =2
Reed y
mi
ed anin
= y -
gap = 0
. 5 XD
a
S
=
om]
= 2 . 5 mm
③
↑ -
N
X = 5000
10
Ba
storded
II
N
-
=
X maxima
S2
1
condary
First Maint
Minima ]00
Ist &, - ) X
- a since ( +
NX
a Sino
asino ()
#
-
-
31/2
&
↑
Sinoz
I
=
02 = sir
(3/in)
20 =?
>
-
-
-
-
-
-
--
&
=
-
05 zcu
applicate
a
D
=
=
4
105 M
Of only when
O
M
a small
or ↑ Xa
I
First minima &
N= 1
-
-
inc Minima
his tommula not
-
1
sphead
a
Sind
= 00 Send a
used in Fraunhotels diffraction
08
Leng
Ganao = on x150m
= Gxm
=
0 0 mm 0 01x1m
=
.
= 185m
a =
.
0 2m.
20cm
.
f D = =
=
2153 m = 2xj4m
1002 = Im
f
.
D =
/
=
I
↑
-
D
&Y
Read
0 (1)
=>
10- 4
S
2x
=
2x16-3 m
E 2mm
Physics-IIA
4) 7248 A0
EXERCISE-IIA
EXERCISE -IIA 8. The distance between the first and the sixth
minima in the diffraction pattern of a single slit is
Diffraction and resolving power: 0.5mm. The screen is 0.5m away from the slit. If
1. A slit of width ‘a’ is illuminated by white light. wavelength of the light used is 5000 A0, then the
0
The first minimum for red light ( !"= 6500A ) will slit width will be
fall at !"= 300 Then ‘a’ will be 1) 5 mm 2) 2.5 mm
1) 3250 A0 2) 1.3 micron 3) 1.25 mm 4) 1.0 mm
3) 6.5 × 10–4 mm 4) 2.6 × 10–4 m 9. The angular resolution of a 10 cm diameter
2. If I0 is the intensity of principle maximum in the telescope at a wavelength of 5000 A° is of the
order of
single slit diffraction pattern, then what will be its
intensity when the slit width is doubled 1) 106 rad 2) 10–2 rad
1) I0 2) I0/2 3) 2I0 4) 4I0 3) 10–4 rad 4) 10–6 rad
a = 10 - 60 = 40
z
(U)
Ct
= 25
in
C) % change = 10
=
(25-1) In
-
= 150 %
·
↑
180=F Rad
Angular diversence of
O
E20 2 10= Mod
Parall
=
Beat
T
0= 1 T Rad
To
Gir Minima
- &
a Sino = N/
O$ mall a o= ()x
-
Mad
Oran
Toxi
-
11
-
20
= a
a = 36x156n =
36
pract
- Physics-IIA
23. A parallel beam of fast moving eletrons is incident
29. In a single slit diffraction pattern, a light of
normally on a narrow slit. A flueroscent screen is o
placed at a large distance from the slit. If the speed wavelength 6000 A is used. The distance between
of the electron is increased, which of the following the first and third minima in the diffraction pattern
statennts is correct ? is found to be 3 mm when the screen is placed
1) Diffraction pattern is not observed on the screen 50cm away from slits. The width of the slit is
in the case of electrons. ___ # 10 -4 m
2) The angular width of the central maximum of 1) 1 2) 2 3) 3 4) 4
the diffraction pattern will increase.
3) The angular width of central maximum will ANSWERS
decrease
4) The angular width of central maximum will be 1) 2 2) 4 3) 4 4) 3 5) 4
unaffected. 6) 3 7) 4 8) 2 9) 4 10) 3
24. In an experiment of single slit diffraction pattern,
11) 4 12) 2 13) 3 14) 4 15) 3
first minimum for red light coincides with first
maximum of some other wavelength. If wavelength 16) 2 17) 2 18) 4 19) 3 20) 1
of red light is 6600A0, then wavelength of first 21) 1 22) 4 23) 3 24) 2 25) 4
maximum will be :
1) 5500A0 2) 4400A0 3) 3300A0 4) 6600A0 26) 2 27) 3 28) 1 29) 2
spread
1) 60 mm 2) 24 mm 3) 120 mm 4) 12 mm explanation of ‘A’
3) ‘A’ is true and ‘R’ is false see
27. A microwave of wavelength 2.0cm falls normally
on a slit of width 4.0cm. The angular speed of the
-
4) Both A and R are false back
central maxima of the diffraction pattern obtained >
Diffraction and Resolving power :
on a screen 1.5m away from the slit, will be
Dagel .