d and f – Block Elements

Q -1 ​ hat will be the charge on Fe if the magnetic

W x+

moment is -
​(A) + 2 ​ ​(B) + 3
​(C) Zero ​ ​(D) None of these
Sol.[A]
Q - Which of the following oxides is basic?
​(A) Mn O 2 3 ​ ​(B) MnO
​(C) MnO 2 ​ ​(D) Mn O 2 7

Sol.[B]
Q - Which of the following ions are colourless-
​(A) V
3+ ​(B) Mn ​(C) Sc
2+ ​(D) Ti 3+
2+

Sol.[C]
Q - Manganese show oxidation state from + 2 to + 7. The
most oxidizing state known in aqueous solution is
(A) + 7 ​(B) + 4 ​(C) + 3 ​(D) + 2
ANS – A
Q - Mohr's salt is a -
​(A) Normal salt ​(B) Acid salt
​(C) Basic salt ​(D) Double salt
Sol.[D]
Q - When (NH ) Cr O is subjected to heat, compound formed
4 2 2 7

are-
​(A) NH , Cr O
3 ​(B) H O (NH ) CrO
2 3 ​ 2 , 4 2 4

​(C) N , Cr O
2 ​(D) All of these
2 3

Sol.[C] ​
Q - Amongst TiF62– , CoF63–, Cu2Cl2 and NiCl42– (At. No. Ti =
 22, Co = 27, Cu = 29, Ni = 28), the colourless species are
–
​(A) TiF62– & Cu2Cl2 ​(B) Cu2Cl2 & NiCl42–
​(C) TiF62– & CoF63– ​(D)CoF63– & NiCl42–
Sol.[A]
Q - Cr2O72– CrO42– Cr2O72–. pH value of X & Y–
​(A) 4 and 5 ​ ​(B) 4 and 8
​(C) 8 and 4 ​ ​(D) 8 and 9
Sol.[C]
Q - In alkaline solution MnO4– changes to–
​(A) MnO42– ​(B) MnO2
​(C) Mn2O3 ​ ​(D) MnO
Sol.[B]
Q - FeSO4 solution give brown colour ring in testing nitrates
or nitrites. This is–
​(A) [Fe(H2O)5 NO]2+ ​
​(B) [Fe(H2O)5 (NO)2]2+
​(C) [Fe(H2O)4 (NO)2 ]2+
​(D) [Fe(H2O)4 NO]2+
Sol.[A]
Q - Chromite ore has a spinel structure and is the chromium
analogue of magnetite, Fe3O4. This ore, when fused with
molten NaOH in presence of air, forms–
​(A) Cr2O3 ​ ​(B) Na2Cr2O7
​(C) Na2CrO4 ​(D) CrO7
Sol.[C]
Q- ​Generally transition metals act as catalyst because of
–
​(A) free valencies
​(B) large surface area ​
​(C) unpaired d- electrons
​(D) all of these
Sol.[D]
Q - TiI4 on heating gives –
​(A) TiI2 + I2 ​(B) Ti + 2I2
​(C) TiI3 + I2 ​(D) None of these
Sol.[B]
Q - catalysts used in contact process of manufacture of
sulphuric acid are –
​(A) NO ​ ​(B) V2O5
​(C) Mo ​ ​(D) Platinised asbestos
Sol.[B]
Q - For making good quality mirrors, plates of float glasses
are used. These are obtained by floating moltan glass
over a liquid metal which does not solidify before glass.
The metal used can be –
​(A) Na ​(B) Mg ​(C) Hg ​(D) Sn
Sol.[C]
Q - NO2 is formed on reaction of dil. HNO3 with the following
metal– ​
​(A) Cu ​(B) Hg ​(C) Ag ​(D) Fe
Sol.[D]
Q - Copper sulphate solution reacts with KCN to
give– ​ ​ ​ ​
​(A) Cu(CN)2 ​(B) CuCN
​(C) K2[Cu(CN)4] ​(D) K3[Cu(CN)4]
Sol.[D]
Q - Which compound does not dissolve in hot dilute HNO3
? ​ ​ ​ ​
​(A) HgS ​(B) PbS ​(C) CuS ​(D) CdS
Sol.[A]
Q- In the dichromate dianion, ​
​(A) 4 Cr– O bonds are equivalent
​(B) 6 Cr–O bonds are equivalent
​(C) all Cr–O bonds are equivalent
 ​(D) all Cr–O bonds are non- equivalent
Sol.[B] ​
Q - Amongst the following, identify the species with an atom
in + 6 oxidation state– ​ ​
(A) MnO4– ​ ​(B) Cr(CN)63–
​(C) NiF62– ​ ​(D) CrO2Cl2
Sol.[D] ​
Q - The complex ion which has no ‘d’ electrons in the central
metal atom is– ​ ​
​(A) [MnO4]– ​
​(B) [Co(NH3)6]3+
​(C) [Fe(CN)6]3– ​
​(D) [Cr (H2O)6]3+ ​
Sol.[A]
Q Which of the following compounds exhibit the same colour
in the aqueous solution ?
​ ​ ​ ​ ​ ​
​(A) VOCl2 & FeCl2 ​(B) FeCl2 & CuCl2
​(C) MnCl2 & FeCl2 ​(D) VOCl2 & CuCl2
Sol.[D]
Q - Silver bromide dissolves in hypo solution forming–
​(A) Ag2S2O3 ​(B) Ag2S
​(C) Na3[Ag(S2O3)2] ​(D) NaAgS2O3
Sol.[C]
Q - In the standardization of Na2S2O3 using K2Cr2O7 by
iodometry, the equivalent weight of K2Cr2O7
is– ​ ​ ​
​(A) (molecular weight) / 2
​(B) ( molecular weight) / 6
​(C) (molecular weight) / 3
​(D) same as molecular weight
ANS - B
Q - Which among the following ions has maximum value of
 magnetic moment–
​(A) Cu2+ ​ ​(B) Mn2+
​(C) Cr2+ ​ ​(D) Ti2+
Sol.[B]
Q - Fe is made passive by –
​(A) Dil.H2SO4 ​(B) Dil.HCl
​(C) Aqua regia ​(D) Conc.H2SO4
Sol.[C]
 f-block Elements
-

magnetic moment–
O ​(A) Cu2+ ​ ​(B) Mn2+
.

​(C) Cr2+ ​ ​(D) Ti2+

✓Sol.[B]
Q - Fe is made passive by –
​(A) Dil.H2SO4 ​(B) Dil.HCl
​(C) Aqua regia ​(D) Conc.H2SO4
Sol.[C]

Q 28 .

Q . 29

3. O

✓
 0.38

0.32

Q 33
.

D is Ans .

034

Q 35

Bb

✓
37

38

-
39
✓

:
41

✓
 Question :
Integer type
-

-
-

Q
4

O
Z

34
Q

A
40

Q .

Q stable as Eun as it has half filled electronic

.

Europium is

configuration .

in fats is
electrons
of unpaired
.

n no
Value
of
a .tn = .

me 7 ( Atomic numbers)
satisfying
-_

electrons
Q .
No -

of
so
state of ee are Ae
, ty
most common oxidation
Q .

is
+7 zety
.
 Solutions
what will feat it M FT ¥4
-

be
charge
-

at the on
-

m =p

impaired
electrons A
Number
of
=

-
[Ar) ye
Fe electronic
configuration : 3d

of unpaired
's
then number e

can be zero 00 -12

charge
will be 9 .

must answer

charge
what is so
is been asked
* here it

value
a
nonzero
.

* Answer is
option A

Q2 Basic oxides -

oxides will be most basic in

(east oxidation state

maturer ④ is correct
option
.
.

d. 3 colourless ions
,
can be due to number of unpaired
electrons to be zero .

electron in valence stele so

Scoot has zero
Only
d-d transistor of electron is
present
-

no
colourless as

state will be in
0.4 most
oxidising of Manganese +7

KMn0y .

option A

0.5 Mohr 's salt is Double salt one

of the type of addition

compound .

@ my)zS0y .
fecsoy) -

6h20

0.6
(N Hy) 2420 , D- Nzt Crzogt H2O

correct
option ① is
 Coffs Nicky
-

0.7
Amongst Tifft Creek and
-

colourless
d- d transition will be the condition for
*
having no

compound .

NO d d
-
transition .

* Tita 3d°ys0
transition
3d6ys0 d- a
Cost in coff
-

d orbital
leet in luck 3d 48 fulfilled
d d transition
Nicely 3dB Uso
'
-
- .

"
Ni in

is correct Amw
So Tiff
-

and Clezclz option ④

8
•
Choi ¥ crop craft
-
-

into croup
-

crook break
-

In basic medium

acidic medium
it become into anhydrous pyro
and in

compound .

optime

-0-9 In alkaline solution Mnoj change

to -

Mnoz

Option ⑧ is correct -

0.10 Brown
Ring of Fe
complex .

"
( Fe ( H2O)g NO
]
No will exist in ti oxidation state as Not

and oxidation state of Fe is Fet ( ta )

⑨ is correct
option
.

• I '
-

Feo Choy
.
chromite ore

Feo Crzog
.
t NaOH t 02 -
Nazcroy 1- Fe 203-1420
 SO
Nazcroy is obtained .

is correct
option ④
-

Transition Element
• ' due to variable vacancies
of
Generally
2
'

compound transition
for the
formation of
good Surface
area

They provide
*

state ( alternate )
d- electrons
impaired
*
.

correct
option ④ is
.

will
Titty beating give
.

on
0.13

method of
( It is Van Arkel
A- Ti t 2 Is
Titty
preparation of pure Titanium )
.

⑧ is correct
option
.

ace 'd
• -
14 contact
process
is used to
prepare the
sulphuric

Vzog is arsed as
catalyst
in this
process .

is correct
option ⑨
.

0.15 Float glass is a sheet of glass made by floating molten glass on a bed of molten metal, typically tin, although
lead and other various low-melting-point alloys were used in the past. This method gives the sheet uniform
thickness and very flat surfaces.

metal like can also be used

leg
.

point
melting
So low

N Oz is
formed on reaction of del hwoz
. with the following
correction metal : -

Am
.

dit ← Not Cut NO 3)2 + H2O

.
h Nog

option ④ is correct
 cusoy kg @ CCN )y ) tank

excelsmust
keen
be given .

does not dissolve in hot dilute hnog ?

0.18 which compound
* Pb$ t HN Og - Pb @ 0312 t St Not H2O

420
Ciel Nos)zt St NOT
* Cust H Nog -

Not H2O
HN 03 Cdc Nos) + St
* Cds t -

dilate te Nos
dissolve in not .

does not
Hgs

diamine
dichromate
0.19

craft

r 9%0 developed
is
Resonance

of
-
o
-
-
o
-
due to conjugation a

can be
made .

structure
and a hybrid
all ① type bonds will be different compare
② f ②

% to ② type .

bond
⑨
②
And ② type
will have identical
length .

option ⑨ is correct Ans .

 O
oxidation state

fiction'¥µ
.

Crack +6
0.20

⑨ is Answer
option
.

has d- electron in
" oxidation state no

(Ninoy ] Mn
-

0.21

metal atom
central
.

is correct
Option ⑨
in solution :
colour aqueous
-

exhibits
compound
same
•
following
22

electron
body
→ v
-14 has
⑨ unpaired
-12
in Fe
electrons
Feck -
4
unpaired
electron
Creek - 3d9u5 of heat ① unpaired

correct
option ④
is

NAZI Ag ( 520372) t Na Br
-

2 Nazssoz -

Ag Br
t
0.23

correct
option ⑨
.

is

forward due to formation of complex

.

Reaction moves

d. 24 Naz 5406
Nazszoz -7

+6
cyst
Kzcrzoy →

infractor = 3×2

Equivalent weight =
weight
molecular

n¥
is correct
option ④

moment a- Ft)
0.25 Maximum value of magnetic
electrons
of number of unpaired
.

maximum values
so

electron ⑨ is correct
Mnf -1 3d59s° so 5
unpaired option
.

.
0.26 Fe is made passive by Aqua
Regia
3 Hut ipad Hnoz
wake) is the mixture of
Aqua
Regia
(
Royal
Iran we see that

formation of
oxide
layer
on
Due to

Aron become passive .

that oxidation of
* Due to oxidising
nature of Hnoz we see

Iron will
takes place .

is correct
②
.

Option