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Let S Solve

The document outlines exercises related to prime factorization, including filling in blanks, true/false statements, selecting correct answers, drawing factor trees, and using the division method to find prime factors. It provides detailed answers and explanations for various numbers, demonstrating the process of identifying prime factors. Additionally, it emphasizes the definitions and properties of prime factors.

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0% found this document useful (0 votes)
22 views5 pages

Let S Solve

The document outlines exercises related to prime factorization, including filling in blanks, true/false statements, selecting correct answers, drawing factor trees, and using the division method to find prime factors. It provides detailed answers and explanations for various numbers, demonstrating the process of identifying prime factors. Additionally, it emphasizes the definitions and properties of prime factors.

Uploaded by

agsabre1010
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as DOCX, PDF, TXT or read online on Scribd
You are on page 1/ 5

Let's solve the exercise step by step:

Part 1: Fill in the blanks


a. 2, 3, 5 are prime factors of 30.
 The prime factors of 30 are 2, 3, and 5 because 30 = 2 × 3 × 5.
b. The prime factors of 41 are 1 and 41.
 41 is a prime number, and its only prime factors are 1 and 41.
c. There are 2 prime factors of 58.
 The prime factors of 58 are 2 and 29 (58 = 2 × 29).
d. The prime factors of 10 are 2 and 5.
 10 = 2 × 5, so its prime factors are 2 and 5.
e. Prime factors can never be a composite number.
 Prime factors are always prime numbers, not composite.
Part 2: State whether the following are true or false
a. The prime factor of a number divides the number completely.
 True: By definition, a prime factor divides the number exactly with no remainder.
b. The prime factors of 100 are 2, 3, 5, 5, 10.
 False: The correct prime factors of 100 are 2 and 5 (100 = 2 × 2 × 5 × 5).
c. A factor tree is used to find prime factors.
 True: A factor tree is a method of breaking down a number into its prime factors.
d. Prime factors of numbers are prime numbers.
 True: By definition, prime factors are prime numbers.
e. 2 is the only prime factor of the number 6.
 False: The prime factors of 6 are 2 and 3 (6 = 2 × 3).
Summary of answers:
 1. Fill in the blanks:

o a. 2, 3, 5
o b. 1 and 41
o c. 2
o d. 2 and 5
o e. composite
 2. True or False:

o a. True
o b. False
o c. True
o d. True
o e. False
Let me know if you need any further explanations! Let's go through each question step by step:

Part 3: Select the correct answer from the given options


a. 3, 3, 3, and 5 are prime factors of:
 The prime factors are 3, 3, 3, and 5. So, the number they form is 3 × 3
× 3 × 5 = 135.

o Correct answer: D (135)


b. The prime factors of 110 are:
 The prime factors of 110 are 2, 5, and 11 (110 = 2 × 5 × 11).

o Correct answer: B (2, 5, 11)


c. The prime factors of 50 are 2, 5 and:
 The prime factors of 50 are 2 and 5 (50 = 2 × 5 × 5).

o Correct answer: C (5)


d. The prime factor is always:
 The prime factor of any number is always a prime number, because it
divides the number without a remainder.

o Correct answer: A (a prime number)

Summary of answers:
 a. D (135)
 b. B (2, 5, 11)
 c. C (5)
 d. A (a prime number)
Let me know if you need any further explanations! Let's break down and solve the exercise:

Part 1: Prime factorisation means


Prime factorisation refers to breaking a number into prime factors.
 Correct answer: D (breaking a number into prime factors)
Part 4: Draw factor trees to show the prime factors of the given numbers.
We'll break down each number into its prime factors. Here's how we do it:
a. 15:
 15 = 3 × 5 (both 3 and 5 are prime numbers).
b. 20:
 20 = 2 × 10, and 10 = 2 × 5.
 So, 20 = 2 × 2 × 5 (prime factors are 2 and 5).
c. 14:
 14 = 2 × 7 (both 2 and 7 are prime numbers).
d. 8:
 8 = 2 × 4, and 4 = 2 × 2.
 So, 8 = 2 × 2 × 2 (prime factor is 2).
e. 21:
 21 = 3 × 7 (both 3 and 7 are prime numbers).
f. 22:
 22 = 2 × 11 (both 2 and 11 are prime numbers).
g. 16:
 16 = 2 × 8, and 8 = 2 × 4, and 4 = 2 × 2.
 So, 16 = 2 × 2 × 2 × 2 (prime factor is 2).
h. 27:
 27 = 3 × 9, and 9 = 3 × 3.
 So, 27 = 3 × 3 × 3 (prime factor is 3).
Part 5: Draw as many different factor trees as you can to show the prime factors of
these numbers.
a. 40:
 40 = 2 × 20, and 20 = 2 × 10, and 10 = 2 × 5.
 So, 40 = 2 × 2 × 2 × 5 (prime factors are 2 and 5).
b. 48:
 48 = 2 × 24, and 24 = 2 × 12, and 12 = 2 × 6, and 6 = 2 × 3.
 So, 48 = 2 × 2 × 2 × 2 × 3 (prime factors are 2 and 3).
c. 60:
 60 = 2 × 30, and 30 = 2 × 15, and 15 = 3 × 5.
 So, 60 = 2 × 2 × 3 × 5 (prime factors are 2, 3, and 5).
d. 24:
 24 = 2 × 12, and 12 = 2 × 6, and 6 = 2 × 3.
 So, 24 = 2 × 2 × 2 × 3 (prime factors are 2 and 3).
e. 50:
 50 = 2 × 25, and 25 = 5 × 5.
 So, 50 = 2 × 5 × 5 (prime factors are 2 and 5).
f. 72:
 72 = 2 × 36, and 36 = 2 × 18, and 18 = 2 × 9, and 9 = 3 × 3.
 So, 72 = 2 × 2 × 2 × 3 × 3 (prime factors are 2 and 3).
Part 6: Find the prime factors of these numbers using the division method.
a. 84:
 84 ÷ 2 = 42, 42 ÷ 2 = 21, 21 ÷ 3 = 7.
 So, 84 = 2 × 2 × 3 × 7 (prime factors are 2, 3, and 7).
b. 117:
 117 ÷ 3 = 39, 39 ÷ 3 = 13.
 So, 117 = 3 × 3 × 13 (prime factors are 3 and 13).
c. 333:
 333 ÷ 3 = 111, 111 ÷ 3 = 37.
 So, 333 = 3 × 3 × 37 (prime factors are 3 and 37).
d. 126:
 126 ÷ 2 = 63, 63 ÷ 3 = 21, 21 ÷ 3 = 7.
 So, 126 = 2 × 3 × 3 × 7 (prime factors are 2, 3, and 7).
e. 520:
 520 ÷ 2 = 260, 260 ÷ 2 = 130, 130 ÷ 2 = 65, 65 ÷ 5 = 13.
 So, 520 = 2 × 2 × 2 × 5 × 13 (prime factors are 2, 5, and 13).
f. 99:
 99 ÷ 3 = 33, 33 ÷ 3 = 11.
 So, 99 = 3 × 3 × 11 (prime factors are 3 and 11).
Summary:
 Prime factorisation means: D (breaking a number into prime
factors)
 Prime factor trees for the numbers:

o 15 → 3 × 5
o 20 → 2 × 2 × 5
o 14 → 2 × 7
o 8→2×2×2
o 21 → 3 × 7
o 22 → 2 × 11
o 16 → 2 × 2 × 2 × 2
o 27 → 3 × 3 × 3
 Factor trees for the numbers:

o 40 → 2 × 2 × 2 × 5
o 48 → 2 × 2 × 2 × 2 × 3
o 60 → 2 × 2 × 3 × 5
o 24 → 2 × 2 × 2 × 3
o 50 → 2 × 5 × 5
o 72 → 2 × 2 × 2 × 3 × 3
 Prime factors using division method:

o 84 → 2 × 2 × 3 × 7
o 117 → 3 × 3 × 13
o 333 → 3 × 3 × 37
o 126 → 2 × 3 × 3 × 7
o 520 → 2 × 2 × 2 × 5 × 13
o 99 → 3 × 3 × 11
Let me know if you'd like any further details!

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