COMPUTER SCIENCE AND ENGINEERING

FACULTY OF ENGINEERING & TECHNOLOGY

OPERATING SYSTEM (203105204) B. Tech. 2nd YEAR
ENROLLMENT NO: 200303105047

FACULTY OF ENGINEERING AND TECHNOLOGY

BACHELOR OF TECHNOLOGY

OPERATING SYSTEM
(203105204)

IV SEMESTER
Computer Science & Engineering
Department

LABORATORY MANUAL
 COMPUTER SCIENCE AND ENGINEERING
FACULTY OF ENGINEERING & TECHNOLOGY
OPERATING SYSTEM (203105204) B. Tech. 2nd YEAR
ENROLLMENT NO: 200303105047

CERTIFICATE

This is to certify that

Mr./Ms PATEL ISHAN BHAVESHKUMAR. with enrollment no.

200303105047. has successfully completed his/her laboratory

experiments in the OPERATING SYSTEM (203105204) from the

department of COMPUTER SCIENCE AND ENGINEERING

during the academic year 2021-22.

Date of Submission:......................... Staff In charge:...........................

Head Of Department:...........................................
 COMPUTER SCIENCE AND ENGINEERING
FACULTY OF ENGINEERING & TECHNOLOGY
OPERATING SYSTEM (203105204) B. Tech. 2nd YEAR
ENROLLMENT NO: 200303105047

TABLE OF CONTENT

Page No
Sr. Date of Date of Marks
Experiment Title Sign
No Start Completion (out of 10)
From To
1. 1 Study of basic commands of 1 7
Linux
2. Study the basics of shell 8 12
programming
3. Write a Shell Script to print 13 13
given numbers sum of all digits.
Write a shell script to validate
4. the entered date.(eg, Date 14 14
format is : dd-mm-yyyy)
Write a shell script to check
5. entered string is palindrome or 15 15
not.

Write a shell script to say Good

6. morning/Afternoon/Evening as 16 16
you log in to system.

7. Write a C program to create a

17 17
child process
Finding out biggest number
8. from given three numbers 18 18
supplied as command line
arguments
9. Printing the patterns using for 19 20
loop.
Shell script to determine
10. 21 21
whether given file exist or not.

11. Implementation of FCFS 22 23

algorithm
12. Implementation of Round 24 28
Robin Algorithm.
13. Implementation of Banker’s 29 31
Algorithm.
 COMPUTER SCIENCE AND ENGINEERING
FACULTY OF ENGINEERING & TECHNOLOGY
OPERATING SYSTEM (203105204) B. Tech. 2nd YEAR
ENROLLMENT NO: 200303105047

EXPERIMENT – 1
AIM : Study of basic commands of linux
Shell Script : Allows the user to execute commands by typing them manually at a terminal,
or automatically inprograms called shell scripts.
A shell is not an operating system. It is a way to interface with the operating system and run
commands.

BASIC LINUX COMMANDS

1) Pwd : print working directory

DESCRIPTION:

pwd prints the full pathname of the current working directory.

SYNTAX:
Pwd
OUTPUT:

2) cd: Change Directory

DESCRIPTION:
It allows you to change your working directory. You use it to move around within
the hierarchy of your file system.
SYNTAX:
cd directory_name
OUTPUT:

3) cd ..
DESCRIPTION:
Move up one directory.

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 COMPUTER SCIENCE AND ENGINEERING
FACULTY OF ENGINEERING & TECHNOLOGY
OPERATING SYSTEM (203105204) B. Tech. 2nd YEAR
ENROLLMENT NO: 200303105047

SYNTAX:
cd ..
OUTPUT:

4) ls : list all the files and directories

DESCRIPTION:
List all files and folders in the current directory in the column format.
SYNTAX:
ls [options]
OUTPUT:

5) cat
DESCRIPTION:
cat stands for "catenate". It reads data from files, and outputs their contents. It is the
simplest way to display the contents of a file at the command line.
SYNTAX:
cat filename
OUTPUT:

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 COMPUTER SCIENCE AND ENGINEERING
FACULTY OF ENGINEERING & TECHNOLOGY
OPERATING SYSTEM (203105204) B. Tech. 2nd YEAR
ENROLLMENT NO: 200303105047

6) head
DESCRIPTION:
head, by default, prints the first 10 lines of each FILE to standard output. With more
than one FILE, it precedes each set of output with a header identifying the file name.
If no FILE is specified, or when FILE is specified as a dash ("-"), head reads from
standard input.
SYNTAX:
head [option]...[file/directory]
OUTPUT:

7) Tail
DESCRIPTION:

tail is a command which prints the last few number of lines (10 lines by default) of a
certain file, then terminates.

SYNTAX:

tail [option]...[file/directory]
OUTPUT:

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 COMPUTER SCIENCE AND ENGINEERING
FACULTY OF ENGINEERING & TECHNOLOGY
OPERATING SYSTEM (203105204) B. Tech. 2nd YEAR
ENROLLMENT NO: 200303105047

8) mv : Moving (and Renaming) Files

DESCRIPTION:
The mv command lets you move a file from one directory location to another. It also
lets you rename a file (there is no separate rename command).
SYNTAX:
mv [option] source directory
OUTPUT:

9) mkdir : Make Directory

DESCRIPTION:
If the specified directory does not already exist, mkdir creates it. More than one
directory may be specified when calling mkdir.
SYNTAX:
mkdir [option] directory
OUTPUT:

10) cp : Copy Files

DESCRIPTION:
The cp command is used to make copy of files and directories.
SYNTAX:
cp [option] source directory
OUTPUT:

11) rmdir : Romove Directory

DESCRIPTION:
The rmdir command is used to remove a directory that contains other files or
directories.
SYNTAX:
rm directory_name

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 COMPUTER SCIENCE AND ENGINEERING
FACULTY OF ENGINEERING & TECHNOLOGY
OPERATING SYSTEM (203105204) B. Tech. 2nd YEAR
ENROLLMENT NO: 200303105047

OUTPUT:

12) gedit
DESCRIPTION:
The gedit command is used to create and open a file.
SYNTAX:
gedit filename.txt
OUTPUT:

13) man
DESCRIPTION:
Displays on online manual page or manpage.
SYNTAX:
man command
OUTPUT:

14) echo
DESCRIPTION:
Display text on the screen.
SYNTAX:
echo yourtext

OUTPUT:

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 COMPUTER SCIENCE AND ENGINEERING
FACULTY OF ENGINEERING & TECHNOLOGY
OPERATING SYSTEM (203105204) B. Tech. 2nd YEAR
ENROLLMENT NO: 200303105047

15) clear
DESCRIPTION:
Used to clear the screen
SYNTAX:
Clear
OUTPUT:

16) whoami
DESCRIPTION:
whoami prints the effective user ID. This command prints the username associated
with the current effective user ID.
SYNTAX:
whoami [option]
OUTPUT:

17) wc
DESCRIPTION:
wc (word count) command, can return the number of lines, words, and characters in a
file.
SYNTAX:
wc [option]... [file]...
OUTPUT:

18) grep
DESCRIPTION:
grep command uses a search term to look through a file.

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 COMPUTER SCIENCE AND ENGINEERING
FACULTY OF ENGINEERING & TECHNOLOGY
OPERATING SYSTEM (203105204) B. Tech. 2nd YEAR
ENROLLMENT NO: 200303105047

SYNTAX:
grep [option]... Pattern [file]...
OUTPUT:

19) free
DESCRIPTION:
Display RAM details in Linux machine.
SYNTAX:
Free
OUTPUT:

20) pipe ( | )
DESCRIPTION:
Pipe command is used to send output of one program as a input to another. Pipes “|”
help combine 2 or more commands.
SYNTAX:
Command 1 | command 2
OUTPUT:

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 COMPUTER SCIENCE AND ENGINEERING
FACULTY OF ENGINEERING & TECHNOLOGY
OPERATING SYSTEM (203105204) B. Tech. 2nd YEAR
ENROLLMENT NO: 200303105047

EXPERIMENT -2
AIM : Study the basics of shell programming.

What is a Shell?
An Operating is made of many components, but its two prime components are -
• Kernel
• Shell

A Kernel is at the nucleus of a computer. It makes the communication between the hardware
and
software possible. While the Kernel is the innermost part of an operating system, a shell is the
outermost one.
A shell in a Linux operating system takes input from you in the form of commands, processes
it, and
then gives an output. It is the interface through which a user works on the programs,
commands, and
scripts. A shell is accessed by a terminal which runs it.
When you run the terminal, the Shell issues a command prompt (usually $), where you can
type
your input, which is then executed when you hit the Enter key. The output or the result is
thereafter
displayed on the terminal.

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 COMPUTER SCIENCE AND ENGINEERING
FACULTY OF ENGINEERING & TECHNOLOGY
OPERATING SYSTEM (203105204) B. Tech. 2nd YEAR
ENROLLMENT NO: 200303105047

The Shell wraps around the delicate interior of an Operating system protecting it from
accidental
damage. Hence the name Shell.
Types of Shell
There are two main shells in Linux:
1. The Bourne Shell: The prompt for this shell is $ and its derivatives are listed below:

 POSIX shell also is known as sh

 Korn Shell also knew as sh

 Bourne Again SHell also knew as bash (most popular)

2. The C shell: The prompt for this shell is %, and its subcategories are:

• C shell also is known as csh

• Tops C shell also is known as tcsh

What is Shell Scripting?

Shell scripting is writing a series of command for the shell to execute. It can combine lengthy
and repetitive sequences of commands into a single and simple script, which can be stored
and executed anytime. This reduces the effort required by the end user.

Let us understand the steps in creating a Shell Script

1. Create a file using a vi editor(or any other editor). Name script file with
extension .sh

2. Start the script with #! /bin/sh

3. Write some code.

4. Save the script file as filename.sh
5. For executing the script type bash filename.sh

"#!" is an operator called shebang which directs the script to the interpreter location. So, if
we use"#! /bin/sh" the script gets directed to the bourne-shell.

Let's create a small script -

#!/bin/sh
ls

Let's see the steps to create it –

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 COMPUTER SCIENCE AND ENGINEERING
FACULTY OF ENGINEERING & TECHNOLOGY
OPERATING SYSTEM (203105204) B. Tech. 2nd YEAR
ENROLLMENT NO: 200303105047

Command 'ls' is executed when we execute the scrip sample.sh file.

Adding shell comments
Commenting is important in any program. In Shell programming, the syntax to add a
comment is
#comment
Let understand this with an example.

What are Shell Variables?

As discussed earlier, Variables store data in the form of characters and numbers. Similarly,
Shell

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 COMPUTER SCIENCE AND ENGINEERING
FACULTY OF ENGINEERING & TECHNOLOGY
OPERATING SYSTEM (203105204) B. Tech. 2nd YEAR
ENROLLMENT NO: 200303105047

variables are used to store information and they can by the shell only.
For example, the following creates a shell variable and then prints it:
variable ="Hello"
echo $variable
Below is a small script which will use a variable.
#!/bin/sh
echo "what is your name?"
read name
echo "How do you do, $name?"
read remark
echo "I am $remark too!"
Let's understand, the steps to create and execute the script

As you see, the program picked the value of the variable 'name' as Joy and 'remark' as
excellent.

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 COMPUTER SCIENCE AND ENGINEERING
FACULTY OF ENGINEERING & TECHNOLOGY
OPERATING SYSTEM (203105204) B. Tech. 2nd YEAR
ENROLLMENT NO: 200303105047

This is a simple script. You can develop advanced scripts which contain conditional
statements,
loops, and functions. Shell scripting will make your life easy and Linux administration a
breeze.

Summary:
• Kernel is the nucleus of the operating systems, and it communicates between hardware and
software
• Shell is a program which interprets user commands through CLI like Terminal
• The Bourne shell and the C shell are the most used shells in Linux
• Shell scripting is writing a series of command for the shell to execute
• Shell variables store the value of a string or a number for the shell to read
• Shell scripting can help you create complex programs containing conditional statements,
loops, and functions

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 COMPUTER SCIENCE AND ENGINEERING
FACULTY OF ENGINEERING & TECHNOLOGY
OPERATING SYSTEM (203105204) B. Tech. 2nd YEAR
ENROLLMENT NO: 200303105047

EXPERIMENT-3
AIM: Write a Shell Script to print given numbers sum of all digits.
CODE:
# !/bin/bash
echo "Enter a number"
read n
len='expr "$n" : '.*''
for i in $len
do
a=$(( $n % 10 ))

n=$(( $n/ 10 ))

s=$(( $s + $a ))
done
echo "summation is " $s

OUTPUT:

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 COMPUTER SCIENCE AND ENGINEERING
FACULTY OF ENGINEERING & TECHNOLOGY
OPERATING SYSTEM (203105204) B. Tech. 2nd YEAR
ENROLLMENT NO: 200303105047

EXPERIMENT-4
AIM: Write a Shell Script to validate the entered date (eg. Date format is: dd-mm-
yyyy).
CODE :
echo "Enter the date: "
read a
echo "Enter the month: "
read b
echo "Enter the year: "
read c
if(($a>=1 && $a<=31 && $b>=1 && $b<=12 && $c>=1 && $c<=2022))
then
echo "It is a valid date"
else
echo "It's not a valid date"
fi
OUTPUT:

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 COMPUTER SCIENCE AND ENGINEERING
FACULTY OF ENGINEERING & TECHNOLOGY
OPERATING SYSTEM (203105204) B. Tech. 2nd YEAR
ENROLLMENT NO: 200303105047

EXPERIMENT-5
AIM: Write a shell script to check entered string is palindrome or not.
CODE :
echo "Enter a string"
read str
str1=`echo $str|rev`
if [ $str == $str1 ]
then
echo "Palindrome"
else
echo "not palindrome"
fi
OUTPUT:

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 COMPUTER SCIENCE AND ENGINEERING
FACULTY OF ENGINEERING & TECHNOLOGY
OPERATING SYSTEM (203105204) B. Tech. 2nd YEAR
ENROLLMENT NO: 200303105047

EXPERIMENT-6
AIM: Write a Shell script to say Good morning/Afternoon/Evening as you log in to
system.
CODE:
h=$(date +"%H")
if [ $h -gt 6 -a $h -le 12 ]
then
echo good morning
elif [ $h -gt 12 -a $h -le 16 ]
then
echo good afternoon
elif [ $h -gt 16 -a $h -le 20 ]
then
echo good evening
else
echo good night
fi
OUTPUT:

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 COMPUTER SCIENCE AND ENGINEERING
FACULTY OF ENGINEERING & TECHNOLOGY
OPERATING SYSTEM (203105204) B. Tech. 2nd YEAR
ENROLLMENT NO: 200303105047

EXPERIMENT-7
AIM: Write a C program to create a child process.
CODE:
#include <stdio.h>
#include <stdlib.h>
#include <sys/types.h>
#include <unistd.h>
int main(void){
int pid;
int status;
printf("Hello World");
pid = fork( );
if(pid == -1){
perror("bad fork");
exit(1);
}
if(pid == 0){
printf("I am the child process= %d\n",getpid());
}
else{
printf("I am the parent process= %d\n",getppid());
}
OUTPUT:

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 COMPUTER SCIENCE AND ENGINEERING
FACULTY OF ENGINEERING & TECHNOLOGY
OPERATING SYSTEM (203105204) B. Tech. 2nd YEAR
ENROLLMENT NO: 200303105047

EXPERIMENT-8
AIM: Finding out biggest number from given three numbers supplied as command line
arguments.
CODE:
if [ "$#" = 0 ]
then
echo "No arguments passed."
exit 1
fi
maxEle=$1
for arg in "$@"
do
if [ "$arg" -gt "$maxEle" ]
then
maxEle=$arg
fi
done
echo "Largest value among the arguments passed is: $maxEle"
OUTPUT:

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 COMPUTER SCIENCE AND ENGINEERING
FACULTY OF ENGINEERING & TECHNOLOGY
OPERATING SYSTEM (203105204) B. Tech. 2nd YEAR
ENROLLMENT NO: 200303105047

EXPERIMENT-9
AIM: Printing the patterns using for loop.
CODE (for left skewed star pattern):
echo "Enter the number "
read n
i=1
j=1
for ((i=1;i<=n;i++))
do
for ((j=1;j<=i;j++))
do
echo -n "* "
done
echo
done
OUTPUT:

CODE (for right skewed star pattern):

echo "Enter a number "
read n
i=1
j=1
for ((i=1;i<=n;i++))

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 COMPUTER SCIENCE AND ENGINEERING
FACULTY OF ENGINEERING & TECHNOLOGY
OPERATING SYSTEM (203105204) B. Tech. 2nd YEAR
ENROLLMENT NO: 200303105047

do
for((j=1;j<=n;j++))
do
if (($j+$i >= ($n+1)))
then
echo -n "*"
else
echo -n " "
fi
done
echo
done
OUTPUT:

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 COMPUTER SCIENCE AND ENGINEERING
FACULTY OF ENGINEERING & TECHNOLOGY
OPERATING SYSTEM (203105204) B. Tech. 2nd YEAR
ENROLLMENT NO: 200303105047

EXPERIMENT-10
AIM: Shell script to determine whether given file exist or not.
Description : In this code name of whichever file is written in if condition should be present
in your ubuntu system otherwise it will print file doesn’t exist.
CODE:
if [ -f "loop.sh" ]
then
echo "File exist"
else
echo "File don't exist"
fi
OUTPUT:

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 COMPUTER SCIENCE AND ENGINEERING
FACULTY OF ENGINEERING & TECHNOLOGY
OPERATING SYSTEM (203105204) B. Tech. 2nd YEAR
ENROLLMENT NO: 200303105047

EXPERIMENT-11
AIM: Implementation of FCFS Algorithm.
CODE (FCFS):
#include <iostream>
#include <algorithm>
#include <bits/stdc++.h>
using namespace std;
int main(){
int n, s = 0, p = 0;
cout << "Enter the number of processes: ";
cin >> n;
int at[n], bt[n], ct[n], tat[n], wt[n];
for (int i = 0; i < n; i++) {
cout << "Enter the arrival time of process " << i + 1 << endl;
cin >> at[i];
}
for (int i = 0; i < n; i++){
cout << "Enter the burst time of process " << i + 1 << endl;
cin >> bt[i];
}
int temp, temp1;
for (int i = 0; i < n - 1; i++){
for (int j = 0; j < n - 1 - i; j++){
if (at[j] > at[j + 1]) {
temp = at[j];
at[j] = at[j + 1];
at[j + 1] = temp;
temp1 = bt[j];
bt[j] = bt[j + 1];

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 COMPUTER SCIENCE AND ENGINEERING
FACULTY OF ENGINEERING & TECHNOLOGY
OPERATING SYSTEM (203105204) B. Tech. 2nd YEAR
ENROLLMENT NO: 200303105047

bt[j + 1] = temp1;
}
}
}
for (int i = 1; i < n; i++){
ct[0] = bt[0];
ct[i]=ct[i-1] + bt[i];
}
for (int i = 0; i < n; i++){
tat[i] = ct[i] - at[i];
}
for (int i = 0; i < n; i++){
wt[i] = tat[i] - bt[i];
}
for (int i = 0; i < n; i++){
s += tat[i];
}
for (int i = 0; i < n; i++){
p += wt[i];
}
cout << "completion time" << endl;
for (int i = 0; i < n; i++){
cout << ct[i] << endl;
}
cout << "turn around time" << endl;
for (int i = 0; i < n; i++){
cout << tat[i] << endl;
}
cout << "Waiting time" << endl;

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 COMPUTER SCIENCE AND ENGINEERING
FACULTY OF ENGINEERING & TECHNOLOGY
OPERATING SYSTEM (203105204) B. Tech. 2nd YEAR
ENROLLMENT NO: 200303105047

for (int i = 0; i < n; i++){

cout << wt[i] << endl;
}
cout << "Average turn around time : " << s / n << endl;
cout << "Average waiting time : " << p / n << endl;
}
OUTPUT:

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 COMPUTER SCIENCE AND ENGINEERING
FACULTY OF ENGINEERING & TECHNOLOGY
OPERATING SYSTEM (203105204) B. Tech. 2nd YEAR
ENROLLMENT NO: 200303105047

EXPERIMENT-12
AIM: Implementation of Round Robin Algorithm.
#include <iostream>
#include <algorithm>
#include <bits/stdc++.h>
using namespace std;
int main(){
int n, s = 0, p = 0, tq, max = 0, m, stack = 0;
cout << "Enter the number of processes: ";
cin >> n;
int at[n], bt[n], ct[n], tat[n], wt[n], tempbt[n];
for (int i = 0; i < n; i++){
cout << "Enter the arrival time of process " << i + 1 << endl;
cin >> at[i];
}
for (int i = 0; i < n; i++){
cout << "Enter the burst time of process " << i + 1 << endl;
cin >> bt[i];
tempbt[i] = bt[i];
if (bt[i] > max) {
max = bt[i];
}
}
printf("Enter the time quantum\n");
scanf("%d", &tq);
int temp, temp1;
for (int i = 0; i < n - 1; i++){
for (int j = 0; j < n - 1 - i; j++){
if (at[j] > at[j + 1]) {

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 COMPUTER SCIENCE AND ENGINEERING
FACULTY OF ENGINEERING & TECHNOLOGY
OPERATING SYSTEM (203105204) B. Tech. 2nd YEAR
ENROLLMENT NO: 200303105047

temp = at[j];
at[j] = at[j + 1];
at[j + 1] = temp;
temp1 = bt[j];
bt[j] = bt[j + 1];
bt[j + 1] = temp1;
}
}
}
int i = 0;
m = (max / tq) + 1;
while (m > 0) {
if (bt[i] > 0) {
if ((bt[i] - tq) <= 0) {
if (i == 0) {
ct[i] = stack + bt[i];
stack = ct[i];
bt[i] = 0;
if (i == n - 1) {
i = 0;
m--;
}
i++;
continue;
}
else{
ct[i] = stack + bt[i];
stack = ct[i];
bt[i] = 0;

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 COMPUTER SCIENCE AND ENGINEERING
FACULTY OF ENGINEERING & TECHNOLOGY
OPERATING SYSTEM (203105204) B. Tech. 2nd YEAR
ENROLLMENT NO: 200303105047

if (i == n – 1){
i = -1;
m--;
}
i++;
continue;
}
}
else {
ct[i] = stack + tq;
stack = ct[i];
bt[i] = bt[i] - tq;
if (i == n - 1) {
i = -1;
m--;
}
i++;
continue;
}
}
else {
if (i == n - 1)
{
i = -1;
m--;
}
i++;
}
}

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 COMPUTER SCIENCE AND ENGINEERING
FACULTY OF ENGINEERING & TECHNOLOGY
OPERATING SYSTEM (203105204) B. Tech. 2nd YEAR
ENROLLMENT NO: 200303105047

for (int i = 0; i < n; i++){

tat[i] = ct[i] - at[i];
}
for (int i = 0; i < n; i++){
wt[i] = tat[i] - tempbt[i];
}
for (int i = 0; i < n; i++){
s += tat[i];
}
for (int i = 0; i < n; i++){
p += wt[i];
}
cout << "completion time" << endl;
for (int i = 0; i < n; i++){
cout << ct[i] << endl;
}
cout << "turn around time" << endl;
for (int i = 0; i < n; i++){
cout << tat[i] << endl;
}
cout << "Waiting time" << endl;
for (int i = 0; i < n; i++){
cout << wt[i] << endl;
}
cout << "Average turn around time : " << s / n << endl;
cout << "Average waiting time : " << p / n << endl;
}

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 COMPUTER SCIENCE AND ENGINEERING
FACULTY OF ENGINEERING & TECHNOLOGY
OPERATING SYSTEM (203105204) B. Tech. 2nd YEAR
ENROLLMENT NO: 200303105047

OUTPUT:

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 COMPUTER SCIENCE AND ENGINEERING
FACULTY OF ENGINEERING & TECHNOLOGY
OPERATING SYSTEM (203105204) B. Tech. 2nd YEAR
ENROLLMENT NO: 200303105047

EXPERIMENT-13
AIM: Implementation of Banker’s Algorithm.
CODE:
#include <stdio.h>
#include <stdlib.h>
int main()
{
int Max[10][10], need[10][10], alloc[10][10], avail[10], completed[10];
int p, r, i, j, process, count;
count = 0;
printf("Enter the no of processes : ");
scanf("%d", &p);
for(i = 0; i< p; i++)
completed[i] = 0;
printf("\n\nEnter the no of resources : ");
scanf("%d", &r);
printf("\n\nEnter the Max Matrix for each process : ");
for(i = 0; i < p; i++)
{
printf("\nFor process %d : ", i + 1);
for(j = 0; j < r; j++)
scanf("%d", &Max[i][j]);
}
printf("\n\nEnter the allocation for each process : ");
for(i = 0; i < p; i++)
{
printf("\nFor process %d : ",i + 1);
for(j = 0; j < r; j++)
scanf("%d", &alloc[i][j]);

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 COMPUTER SCIENCE AND ENGINEERING
FACULTY OF ENGINEERING & TECHNOLOGY
OPERATING SYSTEM (203105204) B. Tech. 2nd YEAR
ENROLLMENT NO: 200303105047

}
printf("\n\nEnter the Available Resources : ");
for(i = 0; i < r; i++)
scanf("%d", &avail[i]);
for(i = 0; i < p; i++)
{
for( j = 0; j < r; j++)
printf("%d ", Max[i][j]);
printf("\t\t");
for( j = 0; j < r; j++)
printf("%d ", alloc[i][j]);
printf("\n");
}
}
OUTPUT:

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