LP Combined Variation
LP Combined Variation
To solve problems involving combined variation the following steps can be followed:
1. Identify the variables present and make a representation for each variable.
2. Translate statements into mathematical equation.
3. Find the constant variation k using the first set of the given value.
4. Rewrite the formula with the value of k.
5. Solve for the value of missing variable.
6. Check the answer obtained.
B. Materials Powerpoint Presentation, strips, video presentation, activity sheets and calculator
C. References Grade 9 Math Learners and Teacher’s Guide
D. Value Focus Accuracy
E. Integration MAPEH ( Music and Arts), Science ( Physics )
III. DEVELOPMENTAL ACTIVITY
EXPECTED
TEACHERS ACTIVITY ANSWERS/TEACHER
S NOTE
Greetings!
Prayer
Checking of Attendance
.
Setting of Classroom rules
1. Listen when someone is talking.
2. Raise your hand to speak, or to get up out of the chair
3. Follow directions when first giving
4. Be respectful to each other
5. Work quietly
A. Preliminary
DRILL: SPEED TEST Indicator # 2
Activities Used a range of
Multiply:
1. 3(4) = 12 teaching strategies
that enhance learner
2. 8(-6) = -48
achievement in literacy
3. 2(-3) = -6 and numeracy skills.
4. -3(-6) = 18
5. 5(-1) = -5 Note: Teacher
Divide: enhances students’
1. 9 ÷(−3) = -3 numeracy skills
through multiplication
2. −3 ÷(−1) = 3
and division using
3. −8 ÷(−2) = 4 speed test.
4. 8 ÷(4) = 2
5. −1 ÷1 = -1
C. Motivation
Now, I want you to watch this video entitled “Minsan from Ang
Huling El Bimbo”. Watch the video carefully because there are
questions afterwards.
Checking
2 Indicator # 2
ky
x= Used a range of
z teaching strategies
2
8 (9) that enhance learner
108= achievement in literacy
6 and numeracy skills.
8 (81)
108= Note: The teacher
6 gives a worded
648 problem to enhance
108=
6 the literacy skills of the
108=108 students as well as the
numeracy skills.
In Manapla National High School, the number of girls varies
directly as the number of boys and inversely as the number of
teachers. When there were 50 girls, there were 20 teachers and 10
boys. How Many boys were there when there were 10 girls and
100 teachers?
Solving for k
g = 50
t = 20
b = 10
kb
g=
t
k (10)
50 =
20
(50)(20) = (10)k
1000 = (10)k
1000 ( 10 ) k
=
10 10
100 = k
ks
d=
f
Indicator # 1
II. How Well Do You Understand? Applied knowledge
1. The force of attraction F of a body varies directly as its mass m of content within and
and inversely as the square of the distance d from the body when across curriculum
m = 8 kilograms d = 5 meters, and F = 100 Newtons. Find F when teaching areas.
Note: The teacher
m = 2 kilograms and d = 15 meters.
integrates Physics-
the topic
Gravitational Force
(Science 8, Quarter 1-
Week 3, Forces and
Motion-)MELC
S8FE-Ia-16)
Solution no. 1 Solving F
Variables k = 312.5
F = force of attraction m = 2 kgs.
m = mass d = 15 meters
d = distance
(312.5)(2)
Equation F=
(15)2
km 625
F= 2 F=
d 225
Solving k F=2.78 Newton
F = 100 Newton or
m = 8 kg. 25
d = 5 meters F= Newton
9
k (8)
100¿
52
k (8)
100=
25
Indicator # 9
2500=k ( 8 ) Used strategies for
k = 312. 5 providing timely,
accurate and
constructive feedback
to improve learner
performance.
Math Challenge
Note: The teacher
If z varies directly as the square of x and inversely as the monitors the students’
square root of y, and z is 3 when x is 6 and y is 16, find z when learning progress
x is 12 and y is 25. through correcting
their work/solution in
problem solving to
The following are the values of k and z that Chad and Ken got make sure if the lesson
when they solve the problem. objectives are being
met. It is more likely to
provide students with
Who do you think got the correct values of k and z? justify a continually improving
your answer learning experience.
Providing constructive
feedback to improve
Chad’s Solution Ken’s Solution their learning
Equation of variation Equation of variation performance.
kx 2 kx 2
z= z=
√y √y
Solving k Solving k
z = 3, x = 6, y = 16 z = 3, x = 6, y = 16
2 2
k (6) k (6)
3= 3=
√16 √16
36 k 12 k
3= 3=
4 4
12=36 k 12=12 k
3=k 1=k
Solving z Solving z
k = 3, x = 12, y = 25 k = 1, x = 12, y = 25
2 2
kx kx
z= z=
√y √y
2 2
3(12) 1(12)
z= z=
√25 √25
3(144) 1(24)
z= z=
5 5
432 24
z= z=
5 5
z=86.4 z=4.8
Building a House
The number of
The number of
workers (w)
“w varies directly with e and workers (w)
varies inversely
inversely with d” varies directly
to the number of
to the expense
days (d) ke
w= (e)
d
number of workers (w)
k
w= w=ke
d
number of days (d) expense (e)
V. Assignment
Answer the following questions.
1. Assume that y varies directly as x and inversely as z. How will y change when x
and z are each tripled?
Reflection/ Total
Number
Instructional Total Number
of Number of
Decision Number of
Year & Students Students that Mastery Instructional
of Students
Section Who Got Needs Level Decision
Students Who
75% & Remediation
in Class Took the
Above
Test
For instance, you have a Business Plan (Making of handicrafts)
Suppose you will make a handicrafts for a small business, you may consider these three things
Number of products (p)
Number of materials (m) Capital (c).
As the number of products increases the number of materials increases but at the same time as the number of products
increases the capital decreases.
The number of products (p) varies directly to the number of materials needed (m), it is a direct variation when it
comes to the number of materials and number of products. But when it comes to the capital the number of
products (p) varies inversely to the capital (c). If we combine these two different type of variations we can
create a what we called COMBINED VARIATION, wherein we can say that “p varies directly with m and
Business Plan inversely with c”.
The number of km
The number of We can interpreted p=
products (p) c
“p varies directly with m and products (p)
varies inversely
inversely with c” varies inversely
of materials
to the capital
needed (m) km
p= (c)
c
number of products (p)
p=km
k
p=
c
number of materials needed Capital (c)
(m)
Directions: Given a two-column
proof, supply the missing
part/statement to prove the Midline
Theorem.
Given: , E is the midpoint
∆ HNS , Ois the midpoint of HN
of NS
Prove: , OE ∥ HS
1
OE= HS
2
Building a house
We must consider the following
number of workers (w)
number of days (d) do we have to finish construction of a house and third will be what would be
expense (e)
As the numbers of workers increases the number of days decreases, when it comes to number of expenses, as
the number of workers increases your expenses also increases.
The number of workers (w) varies inversely to the number of days (d) to finish building the house
k
w=
d
The number of workers (w) varies directly to the expense (e) w=ke
“w
N
1
2 E
O
3 T
4
H S
varies directly with e and inversely with d”
.
Statements Reasons
1. ∆ HNS , O is the midpoint 1. Given
of HN , E is the midpoint of
NS
2. In a ray opposite ⃗
EO, 2. In a ray, point at a
there is a point T such given distance from
that OE = ET the endpoint of the
ray.
3. EN ≅ ES 3.
4. ∠ 2 ≅ ∠ 3 4.
5. ∆ ONE ≅ ∆ TSE 5.
6. ∠ 1 ≅ ∠ 4 6.
7. HN ∥ ST
7.
8. OH ≅ ON 8.
9. ON ≅ TS 9.
10. OH ≅ ST 10.
16. HS ≅ OT 16.
18. 1
(The segment
OE= HS
2 18.
joining the midpoints of
two sides of a triangle is
half as long as the third
side)
For verifying
1. The group shall draw and cut a different kind
of triangle out of bond paper.
O 2 E
3 T
4
H S
Statements Reasons
1. ∆ HNS , O is the midpoint of HN , E is 1. Given
the midpoint of NS
2. In a ray opposite ⃗
EO, there is a 2. In a ray, point at a given
point T such that OE = ET distance from the endpoint of the
ray.
3. EN ≅ ES 3.
4. ∠ 2 ≅ ∠ 3 4.
5. ∆ ONE ≅ ∆ TSE 5.
6. ∠ 1 ≅ ∠ 4 6.
7. HN ∥ ST 7.
8. OH ≅ ON 8.
9. ON ≅ TS 9.
10. OH ≅ ST 10.
11. Quadrilateral HOTS is a 11.
parallelogram.
12. OE ∥ HS 12.
13. OE + ET =OT 13.
14. OE +OE=OT 14.
For verifying
1. The group shall draw and cut a different kind of triangle out of bond
paper.
2. Choose a third side of a triangle. Mark each point of the other two sides
then connects the midpoints to from a segment
Does the segment drawn look parallel to the third side you chose?
_____________________________________________________________________________
_____________________________________________________________________________
3. Measure the segment drawn and the third side you chose.
Compare the lengths of the segments drawn and the third side you chose.
What did you observe?
_____________________________________________________________________________
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5. Reconnect the triangle with the other figure in such a way that their
common vertex was a midpoint and that congruent segments formed by a
midpoint coincide.
Make a conjecture to justify the new figure formed after doing the activity.
Explain your answer
_____________________________________________________________________________
_____________________________________________________________________________
What can you say about your findings in relation to those of your
classmates?
____________________________________________________________________________
Do you think that the findings apply to all kinds of triangles? Why?
_____________________________________________________________________________
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ACTIVITY CARD
GROUP 4