Test

Soutam ed Mon h
Tuly

LHC = (t2) (-)

2 - 2x-?
LHS =

. -x- 2 == X - 2X 3

henc k at adLaic
ob tim (c)

9. 2:

:2 +kdt 3 =

2 - uac
[ a = 2, B = k, C=3J

k2

26
A :2, (x tto) and(3xt )
A P.

(3t2)- C t{)
( t lo) - 2) =
tlo - 2X
= 2 Xt - lo 2

-3= -1

=6

AP:3,7, , 1S,
b=7 d= 7-3 =4
a = 3,

3+ 36

5. Given tha

dee
an

h So
a 2- =
-

h l= 25
2a +
2 s 2 t u9) =25
SI

Gives
SCm

To And pe mete

AC AR
P

P&

4
2. 2

ootin
 ED. EF

hemce ohs n

AR E F = AC. ED

tati
AB

e In an aith meie pgenh

tte d feenc etwen
is comto
Consewtve term
tuo
L coeod)

the
why
derired. Hence
 y The Jheoon does bat o
to

Henae Coect

by fo tui metod

kCA-5) +2(x- S) =0

2X(3- 2) + ( 2 -2)

21 +|o
 o tm of Hhe A.P:I, 8, 5,2
nth tern
given A-P.

-|5o-||
- |61

J
-16| - 3 = - 3

h= (64

n sh oull be intage
hence

i not a tem of Ves

Cqiven

8 m

PO
rae PR

UT

P
ST

|2 chm

Perimetu UTS = 27 h UT = q cn
-27 J|2
+S+UT = 27
UStsT+UT
how

PO
UT

6 6

RPT

mig call
2:4 PM, 2:52 PM, 2:S3 PMIo6Pm

mi
Hena in tewal btwes
tha als
makes an A-P. 6, l--
d =6-4= 2
tim

J2

- aft I Lawy
 e

and

tha

e2x ti5) 6[2xtI5] =o

gives

-E o t acceptall

=6

anel Cost
9-(7 Civey tutel at
=t7o0

alo iven th

the

Corse cute a2e ae 2

How digtrmb 4hese

on A P.
Aex, (-2)
a= , d- n=+

tomla

2 =2 2 - |

2)

2)

t (6u EI4, t| 20) t l o t o

E 6oéuo
Civen Ts lote
clas I

lats blonted by the

nbeu
naner o
wilfom

A
-P: 7, 6,
total blont lonted by al
hehci
=
|2
y w tomwla

Sn =

|2 + (l2-) 3]

234 elenty
 E R

Civen AD R C
To baa

hena by A A
prseu ty
1A EP

Pr t

A B

(Civen)
A A naety
ARD
 To frove

But
2AE p =

2PAE

by A A brety
Prav

2D = <E9Ge)

by AAb e y
sBF
Prav

19
, 4
Aan's APi -5, - 2, l,
lod hany AP 181, 184, 9 , -
Comm d telenu

cmmn d Hean a Ayaw- AP

- 2 - C- s) = -2+r =3
 of

33 )
=(9 +

35

To of i t (3 erm
A gono A -P.

ed = - 2 -(5) = - +s =3
h
 tesn I3
A th bo
33| h
=
=
tSt2
3 +3 -S
a
te Le B