H-Ex E.C Om: Math-EXE
H-Ex E.C Om: Math-EXE
m
d) Passing through (1, − 9) and (2, 4)
e) 𝑦-intercept = − 5 and the inclination of 135°
f) 𝑥-intercept = 6 and the inclination of 45°
2.
co
Find the equation of the straight line passing through (2, 1) and perpendicular to
the line 4𝑥 − 6𝑦 + 16 = 0 .
e.
ex
3. Find the equation of the straight line passing through (5, − 3) and perpendicular
to the line 3𝑥 − 𝑦 + 1 = 0 .
h-
4. Find the equation of the straight line passing through (4, − 2) and parallel to the
line 2𝑥 − 3𝑦 + 8 = 0 .
at
5. Find the equation of the straight line passing through (8, − 3) and parallel to the
line 𝑥 − 6𝑦 + 4 = 0 .
m
a) 𝐿1: 2𝑥 + 3𝑦 + 4 = 0, 𝐿2: 4𝑥 + 6𝑦 + 1 = 0
4
b) 𝐿1: 𝑥 + 9 =− 3
𝑦, 𝐿2: 6𝑥 = 13 − 8𝑦
c) 𝐿1: 3𝑥 − 9𝑦 − 4 = 0, 𝐿2: 2𝑥 + 6𝑦 + 7 = 0
c-intercept :
-
E
Equation of Straight Line EX1
y-intercept -E
:
m
jz
d) Passing through (1, − 9) and (2, 4)
e) 𝑦-intercept = − 5 and the inclination of 135°
f) 𝑥-intercept = 6 and the inclination of 45°
2.
co
Find the equation of the straight line passing through (2, 1) and perpendicular to
the line 4𝑥 − 6𝑦 + 16 = 0 .
e.
ex
3. Find the equation of the straight line passing through (5, − 3) and perpendicular
to the line 3𝑥 − 𝑦 + 1 = 0 .
h-
4. Find the equation of the straight line passing through (4, − 2) and parallel to the
line 2𝑥 − 3𝑦 + 8 = 0 .
at
5. Find the equation of the straight line passing through (8, − 3) and parallel to the
line 𝑥 − 6𝑦 + 4 = 0 .
m
a) 𝐿1: 2𝑥 + 3𝑦 + 4 = 0, 𝐿2: 4𝑥 + 6𝑦 + 1 = 0
4
b) 𝐿1: 𝑥 + 9 =− 3
𝑦, 𝐿2: 6𝑥 = 13 − 8𝑦
c) 𝐿1: 3𝑥 − 9𝑦 − 4 = 0, 𝐿2: 2𝑥 + 6𝑦 + 7 = 0
/C 4-0
y z =
Slope
. .
.
-
z ( 9)-
y -) + t
-
= =
4
+ 11
x
3y 0 7
- =
6 π(x ( 5))
-
0 =
E( -
( 9)-
y y
- -
- =
y
=
Ex +
y
=
+ p my + +6
4x -
7y+ 36
=
0
=
G +2
y
4y 29 0
+ =
x
-
Id .
Slope =
4-12)
1)
=
( 9) 13(x 1)
y
-
- = -
a
+ =
13x 13 -
y
=
13x 22
y
-
13x1 0
y 22
- - =
2. IyXm = .
3 = 3Xm) =
1 4. =
3 =
mu
mc =
3
z mu =
- my
=
=
E( 2) ( 3) 5(x 5) ( 2) =(x 4)
y 1 y
- -
-
= -
- -
= -
y
-
=
-
-
y
-
=
Ex 3+/ -
y
=
-
zx 5 3 - -
y
=
= E -
- 2
y
=
-
Ex -
2
y
-
=
-x - y
=
= 3 -
14
by 3y 2x
= -
x -
= -
(1+
3y+ 14 0 2x 3y 2 0
=
- - =
5
. mc = 6a
Slope of 4 : 6b Stope of 4 = 3
: =
·
.
mi
=
t Slope of 12 t
:
-
= -
Slope of 12 =
= =
34
y ( 3) = j(x) 8) : The slopeare the same
they are parallel :
The
slope are the same they
- -
,
an
,
-x E intersection
yz O
point parallel
-
=
:
+
x by + 26 0
-
=
62 .
Slope of1 :-
5 t =
2
of 5 -5
Slope
: - =
2 -
8
slope
=
0-CH)
E 4
yes
=
=
x
14
-
0) z= =( 0) -
y
-
,
= =x + 2
y
Ex y + z- = 0
m
zy 4
+ = 0
x -
co
c) d)
6
y
=
e.
Slope
=
800
(0 ,0)
8
ex
=
-
=
E
h-
y
-
0 =
&(x 0) -
y Ex
=
at
1
8. If the slope of the straight line 𝐿: 3𝑥 + 𝑏𝑦 − 18 = 0 is − 2
, find
a .
- - =
b. y- intercept
:
--
a) the value of 𝑏,
m
b 6
3
=
/ =
b) the 𝑦-intercept of 𝐿.
17
9. In each of the following, find the coordinates of the intersection of the two
straight lines 𝐿1 and 𝐿2.
an
a) 𝐿1: 2𝑥 + 𝑦 − 1 = 0, 𝐿2: 𝑥 − 𝑦 + 7 = 0
b) 𝐿1: 𝑦 =− 4𝑥 + 4, 𝐿2: 3𝑥 − 4𝑦 − 22 = 0
(0 ,
y) (340)
10. It is given a line 𝐿: 7𝑥 − 24𝑦 − 168 = 0. It cuts the 𝑥-axis at 𝐴 and the 𝑦-axis
at 𝐵. 𝑂 is the origin.
11. If 𝑃 is the intersection of the straight lines 𝐿1: 𝑦 =− 2𝑥, 𝐿2: 6𝑥 − 2𝑦 =− 30. 𝐿2
m
cuts the 𝑥-axis at 𝑄. 𝑂 is the origin.
(x 0)
,
co
I
b) Find the area of ∆𝑂𝑃𝑄.
(0 , 2)
12.
e.
The line 𝐿1: 4𝑥 + 2𝑦 – 4 = 0 intersects the 𝑦-axis at point 𝐴. Line 𝐿2 intersects
c) Find the equation for the horizontal line through the midpoint of 𝐴𝐵.
syy) i y
at
14. The slope of line 𝐿1 is − 2. Line 𝐿2 passes through 𝑀(4 , 3) and 𝐿1 ⊥ 𝐿2.
a) Find the equation for 𝐿2, express the answer in general form.
b) If 𝐿2 passes through 𝑁(𝑛 , 8), find the equation of the vertical line passing
through 𝑁.
7 2 =
24
y
= -
=
25
O .
y
.
6x -
2) 2)
- = -
30 6) 2(0)
- = -
30
10x = -
30 x
=
5
x= 3
Th
-
(-3 6)
.
Let <1 = -
3 into 11
1)
2) 3) -
P
y
=
-
5
Q
Ilb :
( 5 ,0)
-
Da
y
= --
4 = 2 Coordinates of A 10 , 2) :
Slope of 2
= -
E =
-2
12b of 2
Slope 2n = -
y
-
0 = -
2(x) -
( -
4))
2x 8
y
= - -
+8
2xL +
y 0
=
= (-2 , 1)
y = 1
-
13a Slope :
.
-78 =
>
8
y =(x 3)
- =
-
y
=
=x - E +
y
=
Ex -
dy 5x 63
-
=
63 0
5x
by
-
- =
Bb of B2 (2)
Slope
-z -
0
.
= =
7 -
( 9)
-
Slope of AB :
5
·: Slope of AB Scope of R(
not collinear
They are
Har-2 x mrz =
-1
MLz =z
y
-
3 =
z(x 4) -
Ex + 1
y
=
+z
=
0
x
zy
-
I Let = 8 x n =
y
-
=
n -
2 (2) +2
n
= 14
x = 14,
Math-EXE S4 chapter 2
Answers:
1. a) 𝑥 + 4𝑦 − 19 = 0 b) 𝑥 − 3𝑦 + 11 = 0
c) 4𝑥 − 7𝑦 + 36 = 0 d) 13𝑥 − 𝑦 − 22 = 0
e) 𝑥+𝑦+5=0 f) 𝑥−𝑦−6=0
2. 3𝑥 + 2𝑦 − 8 = 0
3. 𝑥 + 3𝑦 + 14 = 0
4. 2𝑥 − 3𝑦 − 14 = 0
m
5. 𝑥 − 6𝑦 − 26 = 0
6. a) 0 b) 0
co
c) 1
7. a) 𝑥 − 2𝑦 + 4 = 0 b) 𝑥=4
c) 𝑦=6 d) 4𝑥 − 3𝑦 = 0
e.
8. a) 6 b) 3
ex
9. a) (− 2, 5) b) (2, − 4)
13. a) 5𝑥 − 6𝑦 + 33 = 0 b) no
m
14. a) 𝑥 − 2𝑦 + 2 = 0 b) 𝑥 = 14