0% found this document useful (0 votes)
22 views2 pages

Midpoint Rectifier Derivation

Uploaded by

zahid
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as DOCX, PDF, TXT or read online on Scribd
0% found this document useful (0 votes)
22 views2 pages

Midpoint Rectifier Derivation

Uploaded by

zahid
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as DOCX, PDF, TXT or read online on Scribd
You are on page 1/ 2

Single-phase Full-wave Midpoint Controlled Rectifier

This document explains the step-by-step derivation of average and RMS voltage for a single-
phase full-wave midpoint controlled rectifier (from Bimbra Power Electronics).

1. Transformer Secondary Voltages


From the transformer secondary winding (center tap = n):

v_an = V_m sin(ωt)


v_bn = -V_m sin(ωt)
Therefore, v_ab = v_an - v_bn = 2V_m sin(ωt).

2. Output Voltage Waveform


The output voltage across the load is given by:

v_o(ωt) = V_m sin(ωt), for α ≤ ωt < α+π


v_o(ωt) = 0, otherwise.

Thus conduction occurs over π radians, controlled by firing angle α.

3. Average DC Voltage
The average DC output voltage is:

V0 = (1/2π) ∫[α to α+π] V_m sinθ dθ


= (V_m/2π)[-cosθ] from α to α+π
= (2V_m/π) cosα

Hence, average DC voltage depends on firing angle α.

4. RMS Voltage
The RMS value is defined as:

Vrms = sqrt( (1/2π) ∫[α to α+π] (V_m sinθ)^2 dθ )

Expanding:
Vrms^2 = (V_m^2 / 2π) ∫[α to α+π] sin^2θ dθ
= (V_m^2 / 2π) * (π/2)
= V_m^2 / 4

Therefore:
Vrms = V_m / 2

Note: RMS is independent of firing angle α.


5. Physical Intuition
(i) RMS depends on the square of sine over an interval of π radians, which always integrates
to π/2 regardless of α.
(ii) Average value depends on the cosine term, hence it decreases as α increases.

πAverage DC voltage: V0 = (2V_m/α) cosα


✔ RMS voltage: Vrms = V_m / 2 (independent of α)

You might also like