5l <l:l <l:< - ?
<- l l+7 
5<- ;oou 
o0 <l:l0 l+7 ll4l5  
4l*- : <l:l0 l+7 ll4l5 <l-l7 
 
Category  Higher Secondary   -4  -4  -4  -4 :  :  :  : 8 88 8 7l  7l  7l  7l Time -4 Hours 
 
Suggestions: Earlier problems are intended to be easier than later problems; try 
the beginning problems First; all problems have equal weight 
 
1.  ~ 2008|7 <l\* *l l *l+ *** ~ 2008|7 **l l *l+ 
|*l *l < |*l+ **7lz  The sum of the first 2008 odd positive integer 
is  subtracted  from  the  sum  of  the  first  2008  even  positive  integers.  Find  the 
result. 
2.  =*|7 ~ 5l |*1, <|7 |n ~ 5l *7*|7 |* 2, |7|7 |n ~ 5l *7*|7 |* 3, 
,  l"|7  |n  ~ 5l  *7*|7  |*  49  =  l"|7  |n  ~ 5l 
*7*|7  |*  50  |l  N*  <*l  ~ 5l**  =*|7  *l*l  l*  **  *l  *** 
9>* =*|7 =*|7 ** ~ 5l *"l < *~* *|7 ~ 5l |* |17 <"l l* *, 
*  **l  =*  *l*  N7  10|7  ~ 5l  "l*l  <**z One  coin  is  labeled  with  the 
number  1,  two  different  coins  are  labeled  with  the  number  2,  three  different 
coins  are  labeled  with  the  number  3,...,forty-nine  different  coins  are  labeled 
with the  number 49, and ffty different coins are labeled with the number 50. 
All of these coins are then put into a black bag. The coins are then randomly 
drawn  one  by  one.  We  need  10  coins  of  any  type.  What  is  the  minimum 
number  of  coins  that  must  be  drawn  to  make  sure  that  we  have  at  least  10 
coins of one type? 
3.   <l l* a  =*|7 l Nl m = 4a + 3 " m, 11-= <|7* a
4
-** 11 ll 
l  *l  <*  **7l  N|"8  l**z  |3l|7  ~l  *  Let  a  be  an  integer.  The 
number m which has the form m = 4a + 3 is a multiple of 11. If we divide a
4
 by 
11, what is the remainder? Show with proof. 
 
4.  ) (x f =*|7  |7  -||l  +l"  1 ) 1 ( ) (   =  +   x f x f  <* 
1
0
) (   dx x f  -=  ~l 
|  *  The  function  ) (x f  is  a  complicated  nonlinear  function.  It  satisfies, 
1 ) 1 ( ) (   =  +   x f x f . Evaluate 
1
0
) (   dx x f  
 
5.  N~l " 7l l< N<*~9 9ll **ll  N~l ** "l~|~ " *~* "l~|" 9ll 
** *>* ll **ll* ~ (= >l* =*, = *l **ll * 
5l <l:l <l:< - ?<- l l+7 
5<- ;oou 
o0 <l:l0 l+7 ll4l5  
4l*- : <l:l0 l+7 ll4l5 <l-l7 
 
||7  |**  ll  =  *l  **ll*  =*<    *>*  ll  **  **z 
Asmaa, and her brother Ahmed are chess players. Asmaa's son Shamim and 
her daughter Sharmeen are also chess players. The worst player's twin (who 
is  one  of  the  4  chess  players)  and  best  player  are  of  the  opposite  sex.  The 
worst player and the best player are the same age. Who is the worst player? 
 
6.  1,2 " 3 =< |7|7 NF |9* =*|7 5 NF ||"8 l 7| *l < l|7*7 *~* 
1,2 " 3 =*l ** N*< =*~ **7l|7 5 NF ||"8 l 7| *l l*z (l<l 
- *  l ~*<  1,2  " 3  *< *<*l *~ l *l **7 l* The  three 
numbers 1,2,3 are used to make a 5 digit number. The five digit number must 
contain at least one 1, at least one 2, and at least one 3. How many such five 
digit  numbers  can  be  made?  (Hint:  First  count  the  number  of  words  missing 
either a 1 or a 2 or a 3.) 
 
7. 
2
2 . 5 1   n
m
= + ~|**  l  ~l<l  ) , (   n m  *  **7  <*  (A)  1
2
 n ?         
(B)  ) 1 (   + n  "  ) 1 (    n = < *l l **l, l|* =*|7 *l N N|7 **l 
7l * * (C) |9 
2
1 
=
 n
a  < 7*  ? ) 1 (   = + a a  (D) |9  a **l < 7*  1 + a  
*l l **lz (E) (C) " (D) ***   1 = a l  1 1 = + a  <"l *| Yz (F)  a -= 
"*~l= Yl ~l|7 * **l =  m "  n  *| <"l |> 7l * **l We want to 
find  all  integer  solutions  (m;  n)  to 
2
2 . 5 1   n
m
= + .  First:  (A)  Find  an  expression 
for  1
2
 n  ;  (B)  are  ) 1 (   + n  and  ) 1 (    n  both  even,  or  both  odd,  or  is  one  even 
and the other odd? (C) Let 
2
1 
=
 n
a , Find an expression for  ) 1 (   + a a ; (D) If  a  
is odd, is  1 + a  even or odd? (E) From parts (C) and (D), is it possible for  1 = a , 
or  ? ) 1 (   = + a a  (F) Find the only possible values  a  can take and then find what 
m and  n  should be. 
 
8.  ABCD >7   * * AC " BD, E |_*7 *9 *** AB = 39; AE = 45; AD = 
60;  BC  =  56  <*  CD=?  ABCD  is  a  convex  quadrilateral.  The  diagonals  AC 
and BD intersect at E. AB = 39; AE = 45; AD = 60; BC = 56. Find the length 
of CD. 
 
9:    ABCD  >7   *    AB  =  BC  =  CD  7* AC<>BD.  >7   *  **  *9|_  E.  |9 
AE = DE = <BAD+<ADC=  <, 7*  =z  Let ABCD be a convex quadrilateral 
5l <l:l <l:< - ?<- l l+7 
5<- ;oou 
o0 <l:l0 l+7 ll4l5  
4l*- : <l:l0 l+7 ll4l5 <l-l7 
 
with  AB  =  BC  =  CD.  Note,  AC  <>  BD.  Let  E  be  the  intersection  point  of  the 
diagonals of ABCD. AE = DE if <BAD+<ADC= , Find   
 
 
 
 
 
 
 
Problem 10: A quadrilateral ABCD with \BAD + \ADC > 180 circumscribes a 
circle of center I. A line through I meets AB and CD at points X and Y 
respectively. 
If IX = IY then what is (AX  DY )=(BX  CY )?