Chapter 9: Columns
And as imagination bodies forth the forms of things unknown, The poets pen turns them to shapes And gives to airy nothingness a local habitation and a name. William Shakespeare A Midsummer Nights Dream Hamrock Fundamentals of Machine Elements
Equilibrium Regimes
P P 0 Re 0 We (a) (b) 0 P Re
We (c)
We
Figure 9.1 Depiction of equilibrium regimes. (a) Stable; (b) neutral; (c) unstable.
Hamrock Fundamentals of Machine Elements
Example 9.1
l
P mag
Figure 9.2 Pendulum used in Example 9.1.
Hamrock Fundamentals of Machine Elements
Column with Pinned Ends
P x P
y l dx y dy ds P M V
y P P (a) (b) (c) P
Figure 9.3 Column with pinned ends. (a) Assembly; (b) deformation shape; (c) load acting.
Hamrock Fundamentals of Machine Elements
P y x
Buckling of Columns
Euler Equation:
n2!2EI Pcr = l2
Figure 9.4 Buckling of rectangular section. Hamrock Fundamentals of Machine Elements
Column Effective Lengths
End condition description Both ends pinned One end pinned and one end fixed Both ends fixed One end fixed and one end free P
le = 0.7l Illustration of end condition l = le l l le = 0.5l le = 2l
Theoretical effective column length AISC (1989) recommended effective column length
le = l le = l
le = 0.7l le = 0.8l
le = 0.5l le = 0.65l
le = 2l le = 2.1l
Table 9.1 Effective length for four end conditions. Hamrock Fundamentals of Machine Elements
Buckling for Different Slenderness Ratio
Critical Slenderness Ratio
Yielding Yield strength A Buckling Normal stress, Johnson equation T Safe AISC Equations (le /rg) T Slenderness ratio, le /rg Euler equation
Cc =
le rg
=
E
2E ! 2 Sy
Euler Equation
(Pcr )E "2 E (!cr )E = = A (le/rg)2
Johnson Parabola
2 Sy (Pcr )J (!cr )J = = Sy 2 A 4" E
Figure 9.5 Normal stress as a function of slenderness ratio.
le rg
Hamrock Fundamentals of Machine Elements
AISC Buckling Criterion
12"2E 23 (le/rg)2
(le /rg )2 2 2Cc
Elastic Buckling Inelastic Buckling
!all =
!all =
Sy
n!
Allowable Stress Reduction
5 3 (le/rg) (le/rg)3 n! = + 3 3 8Cc 8Cc
Hamrock Fundamentals of Machine Elements
50 mm 27.6 mm
Example 9.3
41.7 mm
Pcr = 738.6 N Pcr = 4094 N (a) 50 mm 24.5 mm (b)
43.6 mm
Pcr = 773.5 N Pcr = 5672 N (c) (d)
Figure 9.6 Cross-sectional areas, drawn to scale, from results of Exampe 9.3, aas well as critical buckling load for each cross-sectional area.
Hamrock Fundamentals of Machine Elements
P e A x y l l x
P M = Pe y x y
P e
Eccentrically Loaded Column
M y P (c)
Secant Equation:
le ymax = e sec 2 P EI 1
B e P x (a) x (b)
M = Pe P
Figure 9.7 Eccentrically loaded column. (a) Eccentricity; (b) statically equivalent bending moment; (c) free-body diagram through arbitrary section.
Hamrock Fundamentals of Machine Elements