Engineering Beam Deflection Study
Engineering Beam Deflection Study
Except where mentioned, we verify that the experimental work, results, analysis
and conclusions are set out in this project is entirely our own efforts.
MFO 04/2012 large deflections of beams. Laboratory validation of proposed
project.
ACHOLA KEVIN
: F18/1887/2007
The above named students have submitted this report to the department of
Mechanical and manufacturing Engineering, University of Nairobi with my
approval as the supervisor (s)
DEDICATION
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Abstract
The deflection of a large cantilever beam made of linear elastic aluminum under the
action of a vertical concentrated load applied at mid span was analyzed .this was
done experimentally and numerically using Professor Oduoris1 theory of large
beam deflections.
The experiment was done using aluminum beam of dimension length 47cm by 5cm
and thickness of 1.7cm
From first principles, we derived the equation for the determination of large
deflection of beams. We set up tests in the laboratory in order to validate the theory;
we then compared theoretical and experimental results. They were in good
agreement.
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Acknowledgements
We take this opportunity to express our thanks to Professor Oduori and Engineer
Munyasi for their inspiration, support and the appreciation for their work under
taken in this project .we also express sincere gratitude to the staff at the
mechanical engineering workshop. We also appreciate the moral and general
support accorded to us by our friends.
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Nomenclature
b -Breath of the specimen
d Thickness of the specimen (depth)
E Youngs modulus
F Force causing deflection of the beam
I Second moment of area elasticity of aluminum
L, M Coordinates perpendicular to, and parallel to the force causing deflection of
aluminum
M Bending moment
P Axial force
q Uniformly distributed load
R Radius of curvature
S Length along the deflected cantilever beam
w, y -deflection
X, Y Cartesian coordinates in the plane respectively
- Angular deformation of the deflected cantilever beam
b Bending stress
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Table of contents
Declaration and certification .......i
Dedication ii
Abstract iii
Acknowledgements ....iv
Nomenclature ..v
Chapter One
1.0 Introduction .1
1.1Assumptions.....3
1.2Objective ..4
Chapter Two
2.0 Literature review5
2.1Theoretical Analysis 6
2.2 Formulation of the model ..21
2.3 Model Validation and adaptation for laboratory experimentation .28
Chapter Three
3.0 Description of apparatus used 32
3.1 Hand tools .....32
3.1.1 Tape measure 32
3.1.2 Steel rule 32
3.1.3 Vernier calipers 32
3.1.4 Vernier Height gauge ..32
3.1.5 Try-square ..33
3.1.6 Dial gauge ..33
3.1.7 Rough and smooth file 33
3.1.8 Spirit level ..34
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Chapter four
4.0 laboratory data acquisition ..40
4.1 specimen preparation .40
4.1.1 Procedure of preparation 40
4.2 Test Rig preparation 42
4.2.1 Preparation of the support roller bearings..43
4.3 Test of specimen 45
Chapter five
5.0 Analysis of experimental results..51
5.1 Results ....52
5.2 Data analysis .56
5.2.1 Sample calculation.56
Chapter Six
6.0 Discussion, conclusion and recommendations .66
6.1 Discussions 66
6.2 Conclusion .....................................................67
6.3 Recommendations for further work .68
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Table of figures
Figure
page
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Table of pictures
Unless otherwise stated all pictures were taken at the department of mechanical and manufacturing
Engineering workshop at the university of Nairobi.
Picture
page
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Table of tables
Table
page
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Table of graphs
Graph
page
..59
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Chapter one
1.0 Introduction
Beams are common elements of many architectural, civil and mechanical engineering
structures and the study of the bending of straight beams forms an important and
essential part of the study of the broad field of mechanics of materials and structural
mechanics. All undergraduate courses on these topics include the analysis of the
bending of beam but only small deflections of the beam are usually considered. In such
a case, the differential equation that governs the behavior of the beam is linear and can
easily be solved. Here we consider large deflections in cantilever beams.
By definition beams are structural members capable of sustaining loads normal to their
axis, a cantilever beam is a beam that is fixed at one end, while the other end is
unsupported but suspended.
A beam in application may be strong enough to resist safely the bending moments due
to applied load yet not be suitable because its deflection is too great. Excessive
deflection may impair the strength and stability of the structure giving rise to minor
troubles such as cracking as well as affecting the functional needs and aesthetic
requirements. Thus, there is always a need to consider deflection when designing
beams.
In much of the study and practice of mechanical and structural engineering, the
equations used for determination of beam deflections, are derived with assumption of
small deflections .This is appropriate because, in most mechanical and structural
engineering applications, small deflections are a functional requirement. However, there
arise cases in agricultural machinery engineering for instance, where beam deflections
can no longer be assumed small. Then, it becomes necessary to develop and use
equations other than those commonly found in mechanical and structural 1 engineering
documents, which are largely based on small deflections. Timoshenko and Gere
derived solutions to large deflection problems, which led to an elliptical integral. Elliptical
integral problems can only be evaluated numerically, which is tedious and long. Hence,
there is sufficient reason therefore to seek analytical solutions to problems of large
deflections .such an equation is developed and evaluated in this presentation.
An example of an application that would involve large crop stem (beam) deflections, in
the design and operation of the combine harvester reel as illustrated in fig 1.10
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Reel tine
Ground
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1.1 Assumptions
The assumptions made in formulating a model of the deflected crop stems include
A bunch of deflected crop stems deflected by the reel shall be considered by the
reel shall be considered to behave like a single, initially vertical cantilever that is
fixed at the base.
At its point of action, the deflecting force shall be considered directed normal to
the curvature of the cantilever beam.
The stress-strain relationship for the deflected stems shall be tentatively
assumed linearly elastic.
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1.2 Objective
The purpose of this work is to validate a new theory for the determination of large beam
deflections of a class of cantilever beams under the action of a concentrated force or
load. This is done both experimentally and theoretically then the results compared to
ascertain the validity of the theory and hence formula presented for use in deriving
solutions analytically to large beam deflections.
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Chapter two
2.0 Literature review
In the literature, large deflections behavior of beams continues to be the subject of
intensive research. Numerous researchers have studied the problem under different
conditions and using different conditions and methods of solutions
N. Tolou and J.L. Herder developed a semi analytical approach to large deflections
in compliant beams under point load. In their work, they successfully investigated
the feasibility of ADM (Adomian decomposition method) in analyzing compliant
mechanisms.
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The stress-strain relationship for the deflected beam is to be linearly elastic. The
material of the beam is homogeneous and its stress-strain curve is linear, i.e. the
stress is proportional to strain by Hookes law.
It will also be assumed that the cross section of the beam remains constant
across the length of the beam, meaning that the effect of poisons ratio, or the
ratio of axial elongation to lateral contraction can be neglected.
It is assumed that the Bernoulli Eurler theorem is valid, which states that the
curvature of the beam is proportional to the bending moment.
The beam has the same modulus of elasticity in compression as in tension
The deflection due to the weight of the beam is neglected
load
Neutral axis
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Several beam theories are in use to calculate and analyze deflections of beams under
the action of different kinds of loading .The most common ones are Eurler-Bernoulli
beam theory and Timoshenko beam theory.
Euler-Bernoulli beam theory which is also known as engineers beam theory or
classical beam theory is a simplification of the linear theory of elasticity which provides a
means of calculating the load carrying and deflection characteristics of beams .It
covers the case for small deflections of the beam which is subjected to lateral loads
only.
Timoshenko beam theory covers beams under both lateral and axial loading.
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The Euler-Bernoulli equation describes the relationship between the beams deflection
and the applied load. Each cross-section of the beam is at 90 degree to the neutral axis
The curve
describes the deflection
of the beam at some position considering
the beam model is a one-dimensional object. q is a distributed load. It is force per unit
length analogous to pressure, that is force per unit area. It may be a function of
or
other variables.
Note that E is the elastic modulus and that I is second moment of area I must be
calculated with respect to the centroidal axis perpendicular to the applied loading. For a
Eurler-Bernoulli beam not under any axial loading, this axis is axial loading.
Often,
This equation describing the deflection of a uniform, static beam is used widely in
engineering practice. For more situations that are complicated, the deflection can be
determined by solving the Eurler-Bernoulli equation using techniques such as slope,
moment distribution method, moment area method, conjugate beam method, the
principle of virtual work, direct integration, Castiglianos method, Macaulays method or
the direct stiffness method and elastic curve method, the most commonly used methods
include.
1. Area moment method
2. The elastic curve method
The elastic method requires the use of calculus since it is based on the solution of the
differential equation for the elastic curve by double integration. In its analysis, we get the
equation of the elastic curve.
From fig.2, it is evident that the magnitude of the bending stresses varies directly with
the distance from the neutral axis, that is;
Where R is the radius of curvature of the elastic curve. Taking the general flexure
expression;
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Then
Now consider unloaded beam AB as shown in fig 4, the beam is deflects to A1B1 under
a load q.
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O
d
B1
R
D
dy
Q
A1
dx
A
ds
C
Fig. 5 Triangle CDQ
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dx
dy
CD=
The curved line A1B1 in fig.3 represents the neutral surface of a beam after bending .It is
the elastic surface of a deflected beam of indefinite length. C and D are points on this
elastic surface and are separated by a small distance
When two lines are constructed perpendicular to the elastic curve at points C and D,
their extensions will intersect at the centre of curvature O, a distance R from the
curvature and will form a small angle,
The curvature is actually very slight; therefore, CQ can replace the horizontal length
Then from geometry
And
Therefore,
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But
Substituting and evaluating, we get the differential equation of elastic curve as shown
below
Hence,
Where
EI-is the flexural stiffness
- is the curvature of the neutral axis
In the above derivation of the elementary theory, the assumption of small deflections
has been made. Hence, this equation cannot be used in analyzing large beam
deflections problems. The elementary theory also neglects the square of the first
derivative in the curvature formula and provides no correction for the shortening of the
moment arm as the loaded end of the beam deflects.
From the area moment principle, the neutral surface of a homogeneous beam is
considered to be on a continuous plane, which passes through the centre of gravity of
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each right section. When the beam deflects, the neutral surface becomes a continuous
curved surface. Deflections are measured from the original position of the neutral
surface to the elastic surface.
The derivation of the area moment equations is shown in the semi-graphic form in fig 6
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C
A
B1
d
A1
M
EI
dx
X
Fig 6 first area principle (semi-graphic form)
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From fig.6, the angle between the two tangents AA1 and BB1 is equal to
summation of all elemental areas of the
. And the
This is the first area moment. it considers the assumptions of small deflections and thus
cannot be used to determine large deflections .
Timoshenko and Gere analyzed large deflections by considering the case of buckled
bars (the elastic) as shown below.
P
m
xa
ya
Fig 7 large deflections of buckled bars (the elastica)
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At the critical loading, the bar can have any value of deflection, provided the deflection
remains small, the differential equations used to calculate the critical loads are based on
the approximate expression
expression for the curvature is used, there will be no indefiniteness in the value of
deflection. The shape of the elastic curve, when found from the exact differential
equation is called the elastica.
Consider the slender rod shown in fig.7, which is fixed at the base and free at the upper
end. If the load P is taken somewhat larger than the critical value, a large deflection of
the bar is produced. Taking the axis as shown in the figure and measuring the distance
s along the axis of the bar from the origin O, we find that the exact expression for the
radius of the curvature of the bar is
Since the bending moment in the bar is equal to the product of flexural rigidity the
curvature, the exact differential equation of deflection is;
We obtain,
Multiplying through by
Where
Hence
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Therefore
Boundary conditions
At the upper end of the bar;
And also,
Therefore, we have,
Or
is negative we have,
In addition, for the total length of the bar, after the limits of integration are interchanged
we have
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such that,
Differentiating equation
We obtain
As the value of
The total deflection of the top of the top of the bar in the horizontal direction becomes
And therefore,
We find that;
Substituting expression (v)(vi) and (ix) into equation (viii) and changing the limits
accordingly, we obtain;
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Fcos m
dy
Beam
Y
dx
ds
r + dr
d
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Xm
We have
Therefore
Then
The following figure 9 illustrates the deflection model transformed in a manner similar to
the transformation of rectangular Cartesian coordinates, common in the study of
kinematics
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Ym
Nm
m
Y
dy
dL
Lm
Ground
dx
Xm
Accordingly,
Since L and N are both zero when X and Y are both zero, then
The transformation matrix of equations (3a) and (3b) is symmetric and therefore equal
to its own transpose i.e.
It is also orthogonal and therefore its transpose is equal to its inverse, considering the
context of the plane transformation geometry, this matrix has the form of reflection
matrix, which implies that;
Lm = X m
and
Nm = Y m
.(3c)
And,
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But
Lm = X m
and Nm = Ym
Therefore
From trigonometry
Thus
Therefore
Equation (11) and (12) are based entirely on the geometry of deflection .they do not
involve material properties of the deflected cantilever.
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And,
dL
A
ds
But
Hence
Rearranging gives,
Cos (
The introduction of L as the variable of integration instead of s, greatly simplifies the
problem. Equation (15) can be integrated if the relationship between EI and L is known.
The following assumptions may be made as a matter of investigations.
The product EI does not vary with L since =0 when L=0.
By integrating equation (15) we get;
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Rh
Rh
Rv
Xm
Rv
Fsin m
Ym
0.5 Xm
F cos m
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From the figure Rh is the horizontal component of the reaction and Rv is the vertical
component of the reaction
From statics
Therefore
L- axis
Lm
Nm
c
m
A
m
N-axis
Fig 12 the transformed model adopted for laboratory validation
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m
F
From trigonometry;
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Now, in accordance with equation (3c) of chapter two, it follows from fig 10 and 11 that
And
Substituting equation (21), for Lm into equation (20), we get;
The experimental results were also in agreement with the predictions of the theory from
equation (12) below
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CHAPTER THREE
3.0 A DESCRIPTION OF APPARATUS USED.
3.1 HAND TOOLS
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3.1.5 TRY-SQUARE
The try square was for marking and measuring the aluminium work piece. It was also
used to check the straightness to the adjoining surface.
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3.1.9 SCRIBER
A scriber was used in conjunction with the rule and the try square to obtain thin semipermanent lines where they were required for machining of the specimen.
3.2 MACHINES
3.2.1 POWER HACKSAW
The power hacksaw shown in figure below was for cutting the aluminium specimen.
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CHAPTER FOUR
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The bar was then marked using a vernier height gauge to produce a cross-section
of 17mm thickness by 50mm width. A 2mm allowance was put into consideration
for the cutting disc and for the planning.
3. The bar was then carefully set and clamped on the bed of the milling machine.
A vernier caliper was used to measure accurately the length from the edge of
the bed to ensure the bar lied parallel to its axis.
4. The milling machine was used to split the bar lengthwise to produce a bar of the
cross-section 17mm by 50mm. Paraffin coolant was used to keep the work
piece at a stable low temperature and reduce tip welding of the cutter.
5. The bar was then carefully mounted on the bed of the planar with the flat side
facing downwards. The machine was turned on and the work was given a
reciprocating movement while the tool was fed crosswise. A thickness of 17mm
was achieved.
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6. We filled the machined surface to smoothen the edge. A spirit level was used to
check for the flatness of the bar indicated that it was level.
7. The edges were verified to be perpendicular by means of a try-square. The
prepped beam is as shown below.
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A block of cast iron with two grooves for holding the support roller
bearings as shown in picture 10
Four roller bearings each of inside diameter 25mm and outside diameter
of 50mm are required.
Two pieces of smoothened mild steel bar of length 96mm and diameter
of 25.4 are required.
The cast iron block of length 520mm, and cross section 98mm by 70mm
with two grooves on upper surface, which had a diameter of 30mm and
depth of 10mm each was made available. The grooves that were 300mm
apart were thoroughly smoothened.
the roller bar. Sand paper was used on the surface to obtain a smooth
finish.
e. The pressing machine was then used to press fit the roller bearing onto
each either side of the mild steel roller bar.
f. The above step (e) was repeated for the other mild steel roller bar and
the resulting support roller bearing were as shown in picture 11
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4.2.1Test of specimen
i.
The test rig was placed at the base of the T. I. C such that the centre of
the cast iron block coincided with the centre of the lower tip of the loading
point of the machine. ( Knife edge )
Picture 12 knife-edge
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I.
iii.
iv.
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The beam to be tested was then placed on the two roller bearing such
that its centre at 235mm coincided with the centre of the test rigs well as
the centre of the loading point. In this way, the beam specimen would be
a simply supported member. This ensured that a span of 30mm of the
beam was between the two roller bearings.
The dial gauge was mounted onto the setup as shown in the figure
below.
The load was lowered such that the loading point is just touching the
specimen. The reading of the T. I. C machine and the dial gauge was
adjusted such that the readings of the load applied and deflection
respectively, were zero. The picture next illustrates the loading
arrangement.
v.
vi.
vii.
viii.
ix.
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The length of the overhanging span on one side of the beam was noted
and denoted by the letter x. the heights of the beam before loading were
also noted from the base of the test rig and noted by h1 and h2 as shown
in figure X below
The two measurements of height h1 coincided with that at the roller while
h2 coincided with the end of the beam span (test specimen).
A load of 454.8N (0.41.137KN) was then applied slowly and carefully.
The dial gauge was let to stabilize before that reading corresponding to
the load was taken.
The values of x, h1, and h2 were taken and recorded as well.
With an increment of 0.41.137KN steps (viii) and (ix) were repeated
each time noting the readings while also making sure the loading was still
within the elastic limit
Chapter five
Analysis of experimental results
The test was carried out using T.I.C machine found in the strength of materials
laboratory of the University of Nairobi, department of mechanical and manufacturing
engineering workshop. After a series of preliminary tests on the specimens, finally
stable results were recorded in the tables that follow.
We recorded the exact values of load and deflections as shown in table 2.
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Deflection (y)
(mm)
h1 (mm)
h2 (mm)
X (mm)
0.0
0.4
0.8
1.2
1.6
2.0
2.4
2.8
3.2
3.6
4.0
4.4
4.8
5.2
5.6
6.0
6.4
6.8
7.2
7.6
8.0
8.4
8.8
0
0.28
0.52
0.79
1.04
1.27
1.52
1.75
1.99
2.22
2.46
2.72
2.97
3.2
3.46
3.69
4.01
4.24
4.49
4.86
5.16
5.62
6.06
6.52
7.08
7.76
37.50
37.57
37.65
37.75
37.85
37.93
37.99
38.07
38.16
38.24
38.31
38.36
38.45
38.56
38.62
38.70
38.79
38.85
39.10
39.24
39.41
39.60
39.82
37.50
37.68
37.86
38.05
38.25
38.42
38.58
38.75
38.94
39.11
39.27
39.42
39.60
39.80
39.95
40.13
40.31
40.46
40.82
41.97
42.13
42.34
42.60
54.00
53.90
53.81
53.74
53.67
53.56
53.44
53.38
53.26
53.17
53.11
53.00
52.90
52.83
52.74
52.66
52.55
52.49
52.37
52.27
52.13
51.97
51.78
40.08
40.43
40.85
41.34
42.91
43.30
43.75
44.43
51.55
52.35
51.12
50.88
41.86
42.38
42.74
45.22
46.13
47.04
50.65
50.41
50.12
9.2
9.6
10.0
10.4
10.8
11.2
11.6
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8.78
9.92
10.88
12.2
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Deflection (mm)
0
0.28
0.52
0.79
1.04
1.27
1.52
1.75
1.99
2.22
2.46
2.72
2.97
3.2
3.46
3.69
4.01
4.24
4.49
4.86
5.16
5.62
6.06
6.52
7.08
7.76
8.78
9.92
10.88
12.2
From table 2, we plotted a graph of load against deflection as shown below graph 1.
The graph illustrates that the elastic limit of the beam is reached when a load of 8186.4 KN is applied all
the values after this are insignificant to this project.
12000
10000
Load(N)
8000
6000
4000
2000
0
0
Deflection (mm)
Graph 1
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10
12
14
The graph for load against deflection for the elastic region
lo
Elastic region
9000
y = 1844.6x - 44.532
8000
7000
6000
Load(N)
5000
4000
2000
1000
0
0
-1000
Graph 2
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Deflection(mm)
Data analysis
Sample calculations
From figure 15
h2-h1
For a load of 2.274 KN, deflection of 1.27, h1 of 37.93 mm, h2 of 38.42mm and x of 53.56 mm
And
Therefore
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Hence
We calculated the value of the right hand term of equation (22) using the above values as;
For
P=2.274 KN
E = 70 109 NM-2
Where
E is youngs modulus of aluminium
I
b
Fig 17 beam cross section
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Therefore;
Then
=0.017853
The other values of m , sin 2m and
table3
We then plotted a graph of
against
h1 (mm)
h2 (mm)
X (mm)
0
454.8
909.6
1364.4
1819.2
2274
2728.2
3183.6
3638.4
4093.2
4548
5002.8
5457.6
5912.4
6367.2
6822
7276.8
7731.6
8186.4
37.50
37.68
37.86
38.05
38.25
38.42
38.58
38.75
38.94
39.11
39.27
39.42
39.60
39.80
39.95
40.13
40.31
40.46
40.82
37.5
37.57
37.65
37.75
37.85
37.93
37.99
38.07
38.16
38.24
38.31
38.36
38.45
38.56
38.62
38.70
38.79
38.85
39.10
54.00
53.90
53.81
53.74
53.67
53.56
53.44
53.38
53.26
53.17
53.11
53.00
52.90
52.83
52.74
52.66
52.55
52.49
52.37
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(degrees)
0
0.002041
0.003903
0.005582
0.007468
0.009169
0.011052
0.012767
0.014669
0.016381
0.018113
0.020038
0.021768
0.023511
0.025218
0.027345
0.029305
0.030673
0.032843
0
0.23388
0.44725
0.63964
0.85575
1.05066
1.26641
1.46291
1.68082
1.87695
2.07536
2.29587
2.49403
2.69366
2.88915
3.13272
3.35714
3.51376
3.76217
0
0.0040816
0.0078059
0.0111635
0.014935
0.018336
0.022101
0.025529
0.029331
0.032753
0.036213
0.040059
0.043515
0.046995
0.050403
0.054649
0.058559
0.061288
0.065615
0
0.003571
0.007141
0.010712
0.014282
0.017853
0.021424
0.024994
0.028565
0.032135
0.035707
0.039276
0.042847
0.046418
0.049988
0.053560
0.057129
0.060700
0.064271
A graph of
0.07
y = 1.0105x + 0.0003
0.06
0.05
sin 2m
0.04
0.03
0.02
0.01
0
0
0.01
0.02
0.03
pX2m
Graph 3
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0.04
/8EI
0.05
0.06
0.07
=1.3391mm
Sample 2
For a load of 4.0932
=2.4106mm
Values of Ym for corresponding loads in the elastic region were calculated and tabulated as shown in
table 4 below.
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Deflection y (mm)
0
0.2678
0.5355
0.8034
1.0712
1.3391
1.6069
1.8748
2.1427
2.4106
2.6787
2.9466
3.2146
3.4828
3.7509
4.0192
4.2873
4.5557
4.8240
Load P (N)
0
454.8
909.6
1364.4
1819.2
2274.0
2728.2
3183.6
3638.4
4093.2
4548.0
5002.8
5457.6
5912.4
6367.2
6822.0
7276.8
7731.6
8186.4
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Experimental
0
0.28
0.52
0.79
1.04
1.27
1.52
1.75
1.99
2.22
2.46
2.72
2.97
3.20
3.46
3.69
4.01
4.24
4.49
Calculated
0
0.2678
0.5355
0.8034
1.0712
1.3391
1.6069
1.8748
2.1427
2.4106
2.6787
2.9466
3.2146
3.4828
3.7509
4.0192
4.2873
4.5557
4.8240
5
y = 1.0869x - 0.0269
theoritical
0
0
-1
Graph 4
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0.5
1.5
2.5
experimental
3.5
4.5
Percentage deviations
Sample calculations
=8.8375
For a load of 6.3672 KN
=8.4075
The percentage deviations representing relative errors for the corresponding loads were calculated and
tabulated as below.
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Chapter six
Discussions, conclusions and recommendations
Discussion
The results as tabulated were extensively analyzed as shown previously in the previous chapter. The
analysis was restricted to the elastic region before yielding as we had made a prior assumption of linear
elasticity in the project formulation.
To determine the accuracy and the validity of the method of solution proposed in this study an in depth
analysis of experimental and theoretical values was done. We first obtained the results experimentally
of the large deflection of a simply supported beam under the action of a concentrated load P. secondly;
the numerical results are calculated using the proposed theory. Comparison of the two set of values was
then established. The agreement between the values obtained using our numerical method and those
obtained experimentally was good.
The distributed load due to the weight of the beam was considered negligible and therefore was not
used in the analysis. The numerically calculated deflections were obtained using the Oduoris proposed
method, which is given by the following equation:
Where
is the deflection, P is load, E is youngs modulus, I is the second moment of area and
the mean distance between the roller supports.
Using equation 22,
derived, a graph of
is
above was
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The comparisons above show there are some errors that were incurred during the experiment that
caused the deviations from theoretical values. These errors could include:
Conclusion
The study was a success. The laboratory validation of the new theory (Oduoris formulae) for
determination of large deflections for a class of cantilever beams by laboratory experimentation was
carried out to satisfaction and found to hold.
The theoretical analysis resulted in the following deflection equation corresponding to the general case
of large deflections.
And as shown in chapter 2 this equation is directly derived from equation 22 as quoted below.
From values of
1.662 against the expected gradient of 1. The variation occurred because of the experimental errors
It can be concluded that the theory as proposed by professor Oduori is valid for linear analysis of large
deflections of cantilever beams
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Chapter 7 References
B. Shvartsman, large deflections of a cantilever beam subjected to a follower force, J. Sound and
Vib.304, pp.969-973 (2007) .
F.V. Rhode, ` Large deflections of cantilever beams with uniformly distributed load, Q. Appl. Math. ,
11, pp. 337-338 (1953)
J. M Gere, S.P .Timoshenko, `Mechanics of materials, second edition, books Engineering Division,
California (1984)
M.F Oduori, J. Sakai, E. Inoue, `A paper on Modeling of crop stem Deflection in the context of the
combine harvester reel design and operation.
J. Case, C. Lord, and Carl T.F.R., `Strength of materials and structures , fourth edition chapter 13,
deflections of beams,
S.W. Crawley, R.M. Dillon steel buildings analysis and design, second edition, chapter 4, beam
deflections
Wikipedia: http://en.wikipedia.org/wiki/Timoshenko beam theory
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