Scribd
Upload
236 views2 pages

SRM University Department of Mechanical Engineering

This document contains an exam answer key for a manufacturing and assembly drawing course. It includes: - Multiple choice questions about technical drawing topics - Sketches of machine elements to label - A limit dimension problem calculating tolerances between a shaft and hole using the shaft basis system - A multi-view drawing problem to assemble and draw a milling fixture from different views.

Uploaded by

Sachi Dhanandam
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as PDF, TXT or read online on Scribd
236 views2 pages

SRM University Department of Mechanical Engineering

This document contains an exam answer key for a manufacturing and assembly drawing course. It includes: - Multiple choice questions about technical drawing topics - Sketches of machine elements to label - A limit dimension problem calculating tolerances between a shaft and hole using the shaft basis system - A multi-view drawing problem to assemble and draw a milling fixture from different views.

Uploaded by

Sachi Dhanandam
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as PDF, TXT or read online on Scribd
You are on page 1/ 2

SRM UNIVERSITY

Faculty of Engineering & Technology

Department of Mechanical Engineering

MEJ018 Manufacturing and Assembly Drawing

University Exam 2015-2016

Year/Semester: IIIIIl

Duration: 3hrs

ANSWER KEY

Part- A (10 x 1= 10 Marks)

].
2.
3.
4.
5.
6.
7.
8.
9.
10.

As per the latest 81S, SP: 46-1988,


method of projection is to be used for drawing.
ofthe object is imagined to be removed.
In half sectional view,
is the included angle of ISO metric screw thread.
The distance across corners of a hexagonal nut is equal to
_
fit exists between feather key and keyway.
_
Non-aligned couplings are used to transmit power between two shafts which are
Work piece location should prevent
degrees of motion.
The algebraic difference between the maximum limit and nominal size is known as
_
_
Fundamental tolerance of a shaft of size 30 mm for grade 6 is
Two inverted triangles indicate
finish.

I.
2.
3.
4.
5.
6.

I st angle
One fourth
60
20
Clearance
Non-coaxial

ANSWERS

7. 6
8. Upper deviation
9. ]3

]0. Fine

A.

Part- B (2 x 10 = 20 Marks)
Sketch the conventional representation of the following machine elements

(Each machine elements - 2 Marks each)


a. Bevel gear

c.

Semi elliptic leaf spring

d. External screw thread

e.

Bearings

lyFind the limit dimensions of the shaft and hole on the shaft basis system for a basic size of 20 mm
diameter with an interference of 0.10 mm. The tolerance on the hole is 0.025 mm and the tolerance on
the shaft is 0.050 mm.

Shaft basis system


Minimum limit of hole = Maximum limit of shaft - Maximum interference = 20 - 0.1 = <j> 19.9 mm
(3 Marks)

Maximum limit of hole = Minimum limit of hole + Tolerance on hole = 19.9 + 0.025 = <j> 19.925 mm
(3 Marks)

Maximum limit of shaft = <j> 20.000 mm


(1

Mark)

Minimum limit of shaft = Maximum limit of shaft - Tolerance on shaft = 20 - 0.05 = <j> 19.950 mm

(3 Marks)
Limits of Hole:
Maximum limit =

19.925 mm

Minimum limit =

19.900 mm

Limits of Shaft:
Maximum limit = 4> 20.000 mm
Minimum limit =

19.950 mm

Part- C (1 x 70 = 70 marks)
13. Assemble the parts of Milling fixture and draw the following views:
Front view half section, Top View and left side view

Front view with section - 30 Marks

Top view - 20 Marks

Side view - 20 Marks

------------------

You might also like