FREQUENCY
DISTRIBUTION
Raw Data: data which
have not been organized
numerically.
Array: an arrangement of raw
numerical data according
to magnitude which
ascending or descending
order.
FREQUENCY DISTRIBUTIONS
Class Interval: grouping defined by a
lower limit and an upper limit.
Class Frequency: the number of
observations belonging to a
class interval.
Class Mark: midpoint or middle
value of the class interval
Class Boundary: the most precise
expressions of the class limits
(true limits)
Class Size: the width of each class
interval
STEPS IN CONSTRUCTING A
FREQUENCY DISTRIBUTION
1. Array the given data in ascending
order.
2. Compute the range.
Range: HS-LS
3. Determine the number of classes by
using the Sturges formula
K=1+3.22 log n
n is the number of observations
Steps..
4. Compute for the class size. C=R/K.
The computed value of C should
be rounded-off for convenience
5. Determine the lowest class limit.
6. Tally each score to the category of
class interval it belongs to. Sum
the frequency and check if its
total is equal to the total number
of observations.
Relative Frequency
Distribution
Denote by % (rf), is defined
by getting the ratio of the
number of items in each class
to the total frequency
Cumulative Frequency
Distribution
the accumulated frequencies of the
classes ; it can be either at the beginning
or end of the distribution.
The less than cumulative frequency
is the number of observations that are
less than the upper class boundary,
The greater than cumulative
frequency is the number of observations
that are greater than the lower class
boundary in a given interval.
Example: Grouped Data
Age (yrs) of 100 Residents of Brgy
New Banican, Olongapo City
14
27
27
23
29
21
20
12
22
17
23
24
18
20
27
16
12
22
19
19
15
20
29
25
24
20
20
17
18
18
12
22
23
17
23
26
16
21
21
20
17
18
26
18
28
27
18
22
19
16
14
16
19
20
20
18
25
19
26
15
28
13
18
17
14
27
24
20
18
25
17
20
23
18
18
24
19
19
14
18
21
21
25
24
14
25
20
17
17
17
15
12
26
23
17
20
24
25
18
15
Solution
1. Arrange the given raw data in ascending
order.
12
12
12
12
13
14
14
14
14
14
15
15
15
15
16
16
16
16
17
17
17
17
17
17
17
17
17
17
18
18
18
18
18
18
18
18
18
18
18
18
18
19
19
19
19
19
19
19
20
20
20
20
20
20
20
20
20
20
20
20
21
21
21
21
21
22
22
22
22
23
23
23
23
23
23
24
24
24
24
24
24
25
25
25
25
25
25
26
26
26
26
27
27
27
27
27
28
28
29
29
Solution
Step 2: Compute the range
range= Highest score-lowest score
Step 3:
K = 1 + 3.322 log n
Step 4: Compute the class size
C = R/K
Step 5: Organize the class interval.
Step 6: Tally each to the category of
class interval it belongs to.
Frequency Distribution of Age (years) of 100
Residents of Banican, Olongapo City
Class
Interval
Frequenc
y
Class
Mark
Class
Boundaries
<cf
>cf
Relative
Frequency
12-13
12.5
11.5-13.5
100
5%
14-15
14.5
13.5-15.5
14
95
9%
16-17
14
18-19
20
20-21
17
22-23
10
24-25
12
26-27
28-29
100
N=100
The End of Chapter 2