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WS Calculation

The document presents the design of a water supply system for a 328-room building project in Egypt. It includes calculations for water demand, sizing of an underground water tank and roof water tank, and pump specifications. The underground tank is designed to store 808 cubic meters of water over 2 days. A lifting pump will fill the 132 cubic meter upper roof tank in 0.38 hours. Pump sizing calculations determine a 3 horsepower lifting pump and 4 horsepower booster pump are required.

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Mac Shaik
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0% found this document useful (0 votes)
167 views29 pages

WS Calculation

The document presents the design of a water supply system for a 328-room building project in Egypt. It includes calculations for water demand, sizing of an underground water tank and roof water tank, and pump specifications. The underground tank is designed to store 808 cubic meters of water over 2 days. A lifting pump will fill the 132 cubic meter upper roof tank in 0.38 hours. Pump sizing calculations determine a 3 horsepower lifting pump and 4 horsepower booster pump are required.

Uploaded by

Mac Shaik
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as PDF, TXT or read online on Scribd
You are on page 1/ 29

Project : Example Date : May 30, 2009

Location : Egypt Designed : Zanitty

Assumed Data * You are allowed to change


Calculated data * You are NOT ALLOWED to change
No. of Rooms = 328
No. of persons per room = 2
Building Lowest level (m) = 0
Building Highest level (m) = 20
Total No. of persons = 656
Project : Example Date
Location : Egypt Designed

Assumed Data
Calculated data

Table of total fixtures

Fixture type private

FIXTURES / POINT NO. B3 B2 B1 G.F. F.F

Water closet (flush valve) 1 1 1 1 1


Water closet (flush tank) 1 1 1 1 1
Water Bidet 1 1 1 1 1
Hose for W.C 1 1 1 1 1
Lavatory (& H.B.) 1 1 1 1 1
Janitor Sink 1 1 1 1 1
Service sink 1 1 1 1 1
Shower 1 1 1 1 1
Bath tub 1 1 1 1 1
Kitchen sink 1 1 1 1 1
Dishwashing machine 1 1 1 1 1
Laundry 1 1 1 1 1
Ablution (Public) 1 1 1 1 1
Urinal (1" flush valve) 1 1 1 1 1
Urinal (3/4" flush valve) 1 1 1 1 1
Urinal (flush tank) 1 1 1 1 1
: May 30, 2009
: Zanitty

* You are allowed to change


* You are NOT ALLOWED to change

2nd.F 3rd F 4th F. 5th F 6th F 7th F 8th F 9th F 10th F

1 1 1 1 1 1 1 1 1
1 1 1 1 1 1 1 1 1
1 1 1 1 1 1 1 1 1
1 1 1 1 1 1 1 1 1
1 1 1 1 1 1 1 1 1
1 1 1 1 1 1 1 1 1
1 1 1 1 1 1 1 1 1
1 1 1 1 1 1 1 1 1
1 1 1 1 1 1 1 1 1
1 1 1 1 1 1 1 1 1
1 1 1 1 1 1 1 1 1
1 1 1 1 1 1 1 1 1
1 1 1 1 1 1 1 1 1
1 1 1 1 1 1 1 1 1
1 1 1 1 1 1 1 1 1
1 1 1 1 1 1 1 1 1
Total
11th F 12th F 13th F 14th F
fixtures

1 1 1 1 15
1 1 1 1 15
1 1 1 1 15
1 1 1 1 15
1 1 1 1 15
1 1 1 1 15
1 1 1 1 15
1 1 1 1 15
1 1 1 1 15
1 1 1 1 15
1 1 1 1 15
1 1 1 1 15
1 1 1 1 15
1 1 1 1 15
1 1 1 1 15
1 1 1 1 15
Project : Example Date : May 30, 2009
Location : Egypt Designed : Zanitty

Assumed Data * You are allowed to change


Calculated data * You are NOT ALLOWED to change
Given Data:
Number of persons = 656
Design Basis of Water Supply System
Water Supply Demand:

Water Consumption(L/person/day) = 400


Water demand per day(m3/ day) = 263

Main Water Feeder :

Flow rate required ; Q(m3/ sec) = 0.003

Under Ground Water Tank :

Duration Assumption (day) = 2


Storage Fire Fighting Demand (m3) = 150

Storage water supply Demand (m3) = 658


Total Storage Demand (m3) = 808

Tank depth (m) = 3 * Could be changed according to Arch. Requirement


Tank Length (m) = 10 * Could be changed according to Arch. Requirement
Tank Width (m) = 27
Actual Area of Tank (m2) = 269
Tank depth (m) = 3
Tank Length (m) = 10
Tank Width (m) = 27

Upper Roof Water Tank :


Duration Assumption (day) = 0.5
Tank Storage Required (m3) = 132
Project : Example Date : May 30, 2009
Location : Egypt Designed : Zanitty

Assumed Data * You are allowed to change


Calculated data * You are NOT ALLOWED to change
Q (m3/day) = 263
Pump working hours = 12
Then

Lifting Pump Calculations

Pump Discharge

Q (GPM) = 97

Pump Head

Static Head Hs (m) = 22


Losses = 1.93

Pump Head (m) = 27

Time Required to Fill Upper Roof Tank

T (Hr) = 0.38

Power

Pump Efficiency = 0.8


Power (Hp) = 3

Booster Pump Calculations

Pump Discharge

Q (L/s) = 10
Pump Head (m) = 22

Power

Pump Efficiency = 0.8


Power (Hp) = 4
Project : Example Date : May 30, 2009
Location : Egypt Designe : Zanitty

Assumed Data * You are allowed to change


Calculated data * You are NOT ALLOWED to change
Head loss calculation using (1) COLBROOK Formula For DOMESTIC WATER BOOSTER

Total head (DH+GH) / pipe


Local factors of fittings

Accumulative Pressure
ID Pipe Inner diameter

RE Reynolds number
DN Nominal diameter

Loss m per 100 m


K Pipe roughness

F Liner loss factor


Total local factors

V Mean Velocity

dh(2) Local loss


dh(1) Liner loss
1.0 discharge outlet
no. part of pipe

GH Static head
1.0 Multimedia filter

0.3 elbow ( 45 leg.)


0.3 elbow ( 90 leg.)

DH Total loss
L Pipe length

Q Flow rate

2.0 check valve


1.0 Foot valve
0.2 gate valve

2.0 Strainer
0.5 reducer
0.9 tee
no. DN mm m mm GPM l/s 1/1 m m/s 1/1 1/1 m m m m m m

PUMP TO A 300 PVC 267.4 10 0.01 40 2.52 3 1 1 1 1 1 6.9 10 0.04487 11999.116 0.0295 0 0 0.001 0 10 10
A TO B 300 PVC 267.4 83 0.01 400 25.2 1 0.9 0 0.44873 119991.16 0.01754 0.07 0.06 0.009 0.07 0.07 10.07
B TO C 350 PVC 302.4 879 0.01 350 22.1 8 1 2.9 0 0.30701 92840.383 0.01844 0.03 0.26 0.014 0.27 0.27 10.34
C TO D 250 PVC 212.8 195 0.01 100 6.3 2 1 1.1 0 0.17714 37694.592 0.02241 0.02 0.03 0.002 0.03 0.03 10.37
D TO E 200 PVC 170.2 322 0.01 100 6.3 3 1 1 3.4 0 0.27691 47129.313 0.02137 0.05 0.16 0.013 0.17 0.17 10.54
E TO F 150 PVC 136.2 47 0.01 50 3.15 2 1 1.1 0 0.21621 29447.17 0.02377 0.04 0.02 0.003 0.02 0.02 10.57
F TO G 63 PVC 53.6 32 0.01 50 3.15 1 1 1 1.8 30 1.39602 74826.578 0.01993 3.69 1.18 0.179 1.36 31.4 41.93

TOTAL 1,568 3 1 1 1 1 16 1 5 2 1 18.1 40 2.86688 413928.31 0.15297 3.9 2 0 2 41.93


###
Static head = 40.00 m ###
Outlet pressure 35 PSI = 5.00 m ###
total friction loss = 1.93 m ###
total dynamic head = 46.93 m ###
Add 10 % safety 0.00 = 51.62 m ###
Head Loss Calculations:

The total friction loss Hs Consist of:

Hs = Hs1 + Hs2 . (1)

Where: Hs1 : Friction loss Inside pipes


Hs2 : Friction loss inside fittings

Linear friction loss equation:

Hs = J . L ... .... (2)

J = l . V / ( 2 g D ) .... (3)

Where: J : linear loss factor


L : length Of the pipe (m.)
l : friction loss factor (COLBROOK-WHITE formula)
V : velocity of water (m/s)
g : gravity acceleration (9.81 m/s)
D : pipe inside diameter (m.)

COLBROOK WHITE formula:.. ( 4 )

1 k 2.51
= - 2 x log [ + )
sqr(l) 3.7 x D Re x sqr( l )

Where: K : pipe inside Surface roughness (m.)


D : pipe inside diameter (m.)
RE : REYNOLDS no. is given as follows: (1/1)

RE = V x D / n . ( 5 )

Where: n : water viscosity= ( n = 1E-06 m2/s)


V : velocity of water (m/s)
D : pipe inside diameter (m.)

V = Q/A .... ( 6 )

Where: Q : flow rate (m/s)


A : cross section are of the pipe (m)
Data for the First pipe : 300 PVC Pipe type & size 300
#N/A mm Out side diameter (mm)
#N/A mm Wall thickness (mm)

D = 0.2674 m : pipe inside diameter (m.)


K = 0.00001 m : pipe inside Surface roughness (m.)

Flow : Q = 400.0 GPM = 25.2 l/s = 0.0252 m/sec

A = p x D2 / 4 = 3.14 x 0.267 / 4 = 0.05616 m

V = Q/A = 0.449 m/s

Re = V x D / n = 0.449 x 0.2674 / 0.000001 = 119991.16

1 0.00001 2.51
= - 2 log [ + ]
sqr(l) 3.7 x 0.267 119991.2 x sqr( l )

By solving above equation :

l= 0.01754

0.01754 x 0.4487 x 0.449


J = l . V / ( 2 g D ) = = 0.00067 m/m
2 x 9.81 x 0.2674

Loss m per 100 m = J x 100 = 0.00067 x 100 m = 0.067 m / 100m

Pipe length L = 10.0 m

dh(1) Liner loss = J x L = 0.00067 x 10.0 = 0.007 m

Local losses equation is given as follows:

HS2 = SUM ZE . V / ( 2 . G ) .... (7)

Where: G : Gravity acceleration (9.81 m/s)


V : Velocity of water (m/s)
SUM ZE : Sum of local loss factors

SUM ZE = gate valve 3 x 0.2 = 0.6


Multimedia filter 1 x 1 = 1
Foot valve 1 x 1 = 1
check valve 1 x 2 = 2
elbow ( 45 leg.) 1 x 0.3 = 0.3
elbow ( 90 leg.) 0 x 0.3 = 0
tee 0 x 0.9 = 0
reducer 0 x 0.5 = 0
Strainer 1 x 2 = 2
discharge outlet 0 x 1 = 0
Total local factors = 6.90

HS2 = SUM ZE . V / ( 2 . g )

0.4487 X 0.4487
HS(2) = SUM ZE.x V / ( 2 g ) = 6.9 x = 0.0708 m
2 x 9.81

DH Total loss = HS1 + HS2 = 0.007 + 0.071 = 0.078 m

Total head (DH+GH) / pipe = Static head + Friction losses . ( 8 )

= 10.0 + 0.078 = 10.078 m


Data for the Second pipe : 300 PVC Pipe type & size =f_loss!B11
#N/A mm Out side diameter (mm)
#N/A mm Wall thickness (mm)

D = 0.2674 m : pipe inside diameter (m.)


K = 0.00001 m : pipe inside Surface roughness (m.)

Flow : Q = 400.0 GPM = 25.2 l/s = 0.0252 m/sec

A = p x D2 / 4 = 3.14 x 0.267 / 4 = 0.05616 m

V = Q/A = 0.177 m/s

Re = V x D / n = .177 x 0.2674 / 0.000001 = 37694.59

1 0.00001 2.51
= - 2 log [ + ]
sqr(l) 3.7 x 0.267 37694.6 x sqr( l )

By solving above equation : l= 0.02241

0.02241 x 0.1771 x 0.177


J = l . V / ( 2 g D ) = = 0.00017 m/m
2 x 9.81 x 0.2674

Loss m per 100 m = J x 100 = 0.00017 x 100 m = 0.017 m / 100m

Pipe length L = 83.0 m

dh(1) Liner loss = J x L = 0.00067 x 83.0 = 0.056 m

Local losses equation is given as follows:

HS2 = SUM ZE . V / ( 2 . G )

SUM ZE = gate valve 0 x 0.2 = 0


Multimedia filter 0 x 1 = 0
Foot valve 0 x 1 = 0
check valve 0 x 2 = 0
elbow ( 45 leg.) 0 x 0.3 = 0
elbow ( 90 leg.) 0 x 0.3 = 0
tee 1 x 0.9 = 0.9
reducer 0 x 0.5 = 0
Strainer 0 x 2 = 0
discharge outlet 0 x 1 = 0
Total local factors = 0.90

HS2 = SUM ZE . V / ( 2 . g )

0.1771 X 0.1771
HS(2) = SUM ZE.x V / ( 2 g ) = 0.9 x = 0.0018 m
HS(2) = SUM ZE.x V / ( 2 g ) = 0.9 x = 0.0018 m
2 x 9.81

DH Total loss = HS1 + HS2 = 0.056 + 0.009 = 0.065 m

Total head (DH+GH) / pipe = Static head + Friction losses

= 0.0 + 0.035 = 0.035 m


Data for the Third pipe : 350 PVC Pipe type & size
#N/A mm Out side diameter (mm)
#N/A mm Wall thickness (mm)

D = 0.3024 m : pipe inside diameter (m.)


K = 0.00001 m : pipe inside Surface roughness (m.)

Flow : Q = 350.0 GPM = 22.05 l/s = 0.02205 m/sec

A = p x D2 / 4 = 3.14 x 0.302 / 4 = 0.07182 m

V = Q/A = 0.307 m/s

Re = V x D / n = .307 x 0.3024 / 0.3 = 92840.38

1 0.00001 2.51
= - 2 log [ + ]
sqr(l) 3.7 x 0.302 47129.3 x sqr( l )

By solving above equation : l= 0.01844

0.01844 x 0.307 x 0.307


J = l . V / ( 2 g D ) = = 0.0 m/m
2 x 9.81 x 0.3024

Loss m per 100 m = J x 100 = 0.00029 x 100 m = 0.029 m / 100m

Pipe length L = 879.0 m

dh(1) Liner loss = J x L = 0.00029 x 879.0 = 0.257 m

Local losses equation is given as follows:

HS2 = SUM ZE . V / ( 2 . G )

SUM ZE = gate valve 0 x 0.2 = 0


Multimedia filter 0 x 1 = 0
Foot valve 0 x 1 = 0
check valve 0 x 2 = 0
elbow ( 45 leg.) 0 x 0.3 = 0
elbow ( 90 leg.) 8 x 0.3 = 2.4
tee 0 x 0.9 = 0
reducer 1 x 0.5 = 0.5
Strainer 0 x 2 = 0
discharge outlet 0 x 1 = 0
0 = 2.90

HS2 = SUM ZE . V / ( 2 . g )

0.307 X 0.307
HS(2) = SUM ZE.x V / ( 2 g ) = 2.9 x = 0.0 m
2 x 9.81

= HS1 + HS2 = 0.257 + 0.014 = 0.271 m

= Static head + Friction losses

= 0.0 + 0.271 = 0.271 m


Data for the Fourth pipe : 250 PVC Pipe type & size 250
#N/A mm Out side diameter (mm)
#N/A mm Wall thickness (mm)

D = 0.2128 m : pipe inside diameter (m.)


K = 0.00001 m : pipe inside Surface roughness (m.)

Flow : Q = 100.0 GPM = 06.3 l/s = 0.0063 m/sec

A = p x D2 / 4 = 3.14 x 0.213 / 4 = 0.03556 m

V = Q/A = 0.177 m/s

Re = V x D / n = .177 x 0.2128 / = 92840.38

1 0.00001 2.51
= - 2 log [ + ]
sqr(l) 3.7 x 0.213 0.0 x sqr( l )

By solving above equation :

l= 0.02241

0.02241 x 0.1771 x 0.177


J = l . V / ( 2 g D ) = = 0.0 m/m
2 x 9.81 x 0.2128

Loss m per 100 m = J x 100 = 0.00017 x 100 m = 0.017 m / 100m

Pipe length L = 195.0 m

dh(1) Liner loss = J x L = 0.00017 x 195.0 = 0.033 m

Local losses equation is given as follows:

HS2 = SUM ZE . V / ( 2 . G ) .... (7)

Where: G : Gravity acceleration (9.81 m/s)


V : Velocity of water (m/s)
SUM ZE : Sum of local loss factors

SUM ZE = gate valve 0 x 0.2 = 0


Multimedia filter 0 x 1 = 0
Foot valve 0 x 1 = 0
check valve 0 x 2 = 0
elbow ( 45 leg.) 0 x 0.3 = 0
elbow ( 90 leg.) 2 x 0.3 = 0.6
tee 0 x 0.9 = 0
reducer 1 x 0.5 = 0.5
Strainer 0 x 2 = 0
discharge outlet 0 x 1 = 0
Total local factors = 1.10

HS2 = SUM ZE . V / ( 2 . g )

0.1771 X 0.1771
HS(2) = SUM ZE.x V / ( 2 g ) = 1.1 x = 0.0018 m
2 x 9.81

= HS1 + HS2 = 0.033 + 0.002 = 0.035 m

= Static head + Friction losses . ( 8 )

= 0.0 + 0.035 = 0.035 m


Data for the Fifth pipe : 200 PVC Pipe type & size 200
#N/A mm Out side diameter (mm)
#N/A mm Wall thickness (mm)

D = 0.1702 m : pipe inside diameter (m.)


K = 0.00001 m : pipe inside Surface roughness (m.)

Flow : Q = 100.0 GPM = 06.3 l/s = 0.0063 m/sec

A = p x D2 / 4 = 3.14 x 0.17 / 4 = 0.02275 m

V = Q/A = 0.277 m/s

Re = V x D / n = 0.277 x 0.1702 / = 47129.31

1 0.00001 2.51
= - 2 log [ + ]
sqr(l) 3.7 x 0.17 47129.3 x sqr( l )

By solving above equation :

l= 0.02137

0.02137 x 0.2769 x 0.277


J = l . V / ( 2 g D ) = = 0.00049 m/m
2 x 9.81 x 0.1702

Loss m per 100 m = J x 100 = 0.00049 x 100 m = 0.049 m / 100m

Pipe length L = 322.0 m

dh(1) Liner loss = J x L = 0.00049 x 322.0 = 0.158 m

Local losses equation is given as follows:

HS2 = SUM ZE . V / ( 2 . G ) .... (7)

Where: G : Gravity acceleration (9.81 m/s)


V : Velocity of water (m/s)
SUM ZE : Sum of local loss factors

SUM ZE = gate valve 0 x 0.2 = 0


Multimedia filter 0 x 1 = 0
Foot valve 0 x 1 = 0
check valve 0 x 2 = 0
elbow ( 45 leg.) 0 x 0.3 = 0
elbow ( 90 leg.) 3 x 0.3 = 0.9
tee 0 x 0.9 = 0
reducer 1 x 0.5 = 0.5
Strainer 1 x 2 = 2
discharge outlet 0 x 1 = 0
Total local factors = 3.40

HS2 = SUM ZE . V / ( 2 . g )

0.2769 X 0.2769
HS(2) = SUM ZE.x V / ( 2 g ) = 3.4 x = 0.0133 m
2 x 9.81

= HS1 + HS2 = 0.158 + 0.013 = 0.171 m

= Static head + Friction losses . ( 8 )

= 0.0 + 0.171 = 0.171 m


Data for the Sexth pipe : 150 PVC Pipe type & size 150
#N/A mm Out side diameter (mm)
#N/A mm Wall thickness (mm)

D = 0.1362 m : pipe inside diameter (m.)


K = 0.00001 m : pipe inside Surface roughness (m.)

Flow : Q = 50.0 GPM = 03.15 l/s = 0.00315 m/sec

A = p x D2 / 4 = 3.14 x 0.136 / 4 = 0.01457 m

V = Q/A = 0.216 m/s

Re = V x D / n = 0.216 x 0.1362 / = 29447.17

1 0.00001 2.51
= - 2 log [ + ]
sqr(l) 3.7 x 0.136 0.0 x sqr( l )

By solving above equation :

l= 0.02377

0.02377 x 0.2162 x 0.216


J = l . V / ( 2 g D ) = = 0.0 m/m
2 x 9.81 x 0.1362

Loss m per 100 m = J x 100 = 0.00042 x 100 m = 0.042 m / 100m

Pipe length L = 47.0 m

dh(1) Liner loss = J x L = 0.00042 x 47.0 = 0.02 m

Local losses equation is given as follows:

HS2 = SUM ZE . V / ( 2 . G ) .... (7)

Where: G : Gravity acceleration (9.81 m/s)


V : Velocity of water (m/s)
SUM ZE : Sum of local loss factors

SUM ZE = 0 0 x 0.2 = 0
0 0 x 1 = 0
0 0 x 1 = 0
0 0 x 2 = 0
0 0 x 0.3 = 0
0 2 x 0.3 = 0.6
0 0 x 0.9 = 0
0 1 x 0.5 = 0.5
0 0 x 2 = 0
0 0 x 1 = 0
0 = 1.10

HS2 = SUM ZE . V / ( 2 . g )

0.2162 X 0.2162
HS(2) = SUM ZE.x V / ( 2 g ) = 1.1 x = 0.0026 m
2 x 9.81

= HS1 + HS2 = 0.02 + 0.003 = 0.022 m

= Static head + Friction losses . ( 8 )


= 0.0 + 0.022 = 0.022 m
Data for the Seventh pipe : 63 PVC Pipe type & size 63
#N/A mm Out side diameter (mm)
#N/A mm Wall thickness (mm)

D = 0.0536 m : pipe inside diameter (m.)


K = 0.00001 m : pipe inside Surface roughness (m.)

Flow : Q = 50.0 GPM = 03.15 l/s = 0.00315 m/sec

A = p x D2 / 4 = 3.14 x 0.054 / 4 = 0.00226 m

V = Q/A = 1.396 m/s

Re = V x D / n = 1.396 x 0.0536 / = 74826.58

1 0.00001 2.51
= - 2 log [ + ]
sqr(l) 3.7 x 0.054 0.0 x sqr( l )

By solving above equation :

l= 0.01993

0.01993 x 1.396 x 1.396


J = l . V / ( 2 g D ) = = 0.0 m/m
2 x 9.81 x 0.0536

Loss m per 100 m = J x 100 = 0.03694 x 100 m = 3.694 m / 100m

Pipe length L = 32.0 m

dh(1) Liner loss = J x L = 0.03694 x 32.0 = 1.182 m

Local losses equation is given as follows:

HS2 = SUM ZE . V / ( 2 . G ) .... (7)

Where: G : Gravity acceleration (9.81 m/s)


V : Velocity of water (m/s)
SUM ZE : Sum of local loss factors

SUM ZE = 0 0 x 0.2 = 0
0 0 x 1 = 0
0 0 x 1 = 0
0 0 x 2 = 0
0 0 x 0.3 = 0
0 1 x 0.3 = 0.3
0 0 x 0.9 = 0
0 1 x 0.5 = 0.5
0 0 x 2 = 0
0 1 x 1 = 1
0 = 1.80

HS2 = SUM ZE . V / ( 2 . g )

1.396 X 1.396
HS(2) = SUM ZE.x V / ( 2 g ) = 1.8 x = 0.1788 m
2 x 9.81

= HS1 + HS2 = 1.182 + 0.179 = 1.361 m

= Static head + Friction losses . ( 8 )


= 30.0 + 1.361 = 31.361 m
Project : Example Date : May 30, 2009
Location : Egypt Designed : Zanitty

Assumed * You are allowed to change


Calculated* You are NOT ALLOWED to change

Given Data:
Number of persons = 656

Boiler Design

Water Consumption(L/person/day) = 400


Hot Water Consumption (L) = 120
Hot Water demand per day(m3/ day) = 79
Average Demand per Hour (m3/h) = 4
Peak Duration (h) = 3
Volume of Heated Water (m3) = 12
Cold Water Tank Volume % = 25%
Tank Volume (m3) = 15

Tank Diameter (m) =2


Tank Length (m) =5
Project : Example Date : May 30, 2009
Location : Egypt Designed : Zanitty

Assumed * You are allowed to change


Calculated* You are NOT ALLOWED to change

Design of Circulating Pump

Q (m3/h) = 4
Q (l/s) = 2
Head (m) = 22
Pump Efficiency = 0.8
Power (Hp) = 1
Project : Example Date : May 30, 2009
Location : Egypt Designed : Zanitty

Assumed * You are allowed to change


Calculated* You are NOT ALLOWED to change

Drain Sump

Sewer Drainage
No. of Drainage Fixtures = 48
Fixtures Flow Rate (L / min) = 285

Parking Area Drainage


Car Demand (L / car / day) = 30
No. of cars = 20
Parking Drainage (L / min) = 1

Laundry Drainage
Laundry Demand (L / bed / day) = 130
No. of beds = 656
Laundry Drainage (L / min) = 60

Kitchen Drainage
Kitchen Demand (L / person / day) = 160
No. of persons = 656
Kitchen Drainage (L / min) = 73

Total Drainage Flow (L / min) = 419

Duration Time of Empting Sump (min) = 10

Sump Capacity (m3) = 4

Sump Depth (m) = 1.5


Water Surface Area (m2) = 3

Pump occupancy of Sump Area = 40%


Water occupancy of Sump Area = 60%
Sump Surface Area (m2) = 5

Sump Dimension
Sump depth (m) = 2
Sump Length (m) = 3
Sump Width (m) = 3
Project : Example Date : May 30, 2009
Location : Egypt Designed : Zanitty

Assumed * You are allowed to change


Calculated* You are NOT ALLOWED to change

Design of submersible Pump


Sump Capacity (m3) = 18
Sump Empting Time (min) = 10

Q (L/S) = 30
Q (m3/s) = 0.03
Main Pipe Velocity (m/s) = 1
Main Pipe Diameter (mm) = 200 * Take the larger Standard Size

Pump Head

Static Head Hs (m) = 6 *From Sump Bottom Level to Septic Tank


Assume Losses (m) = 0.1 of static Head
Losses = 0.6

Pump Head (m) = 8

Power

Pump Efficiency = 0.8


Power (Hp) = 4
Project : Example Date : May 30, 2009
Location : Egypt Designed : Zanitty

Assumed D* You are allowed to change


Calculated * You are NOT ALLOWED to change

Design of Reaction Tank

Q (m3/day) = 263
Q Sewer (m3/day) = 237
Sewerage Flow to Be Treated (m3/day) = 214

Assume

Reaction Tank Dimension


Length (m) = 3
Width (m) = 3
Depth (m) = 3
Water Dimensions
Length (m) = 3
Width (m) = 3
Depth (m) = 2.5

Reaction Tank Capacity (m3) = 22.5

Times to Fill Tank (time/day) = 10

Filter Design

Filtration Rate (m3/m2/h) = 22.5


Qpump (m3/h) = 22
Filter Area (m2) = 1.02
Filter Diameter (m) = 1.15
Project : Example Date : May 30, 2009
Location : Egypt Designed : Zanitty

Assumed * You are allowed to change


Calculated* You are NOT ALLOWED to change

Filtration Pump

Capacity (m3) = 23
Pump working hours = 12
Working time (h) = 1.2
Qpump (L/S) = 6
Pump Head (m) = 22
Pump Efficiency = 0.8
Power (Hp) = 3

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