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ME410: Engine Combustion Analysis

This document contains a homework problem to calculate the air flow rate, mass of fuel and air entering each cylinder per cycle, and volumetric efficiency of a 4-cylinder spark ignition engine. Key details include: the engine takes in 2.0 g/s of isooctane fuel at 1500 revolutions per minute. Using equations, the air-fuel ratio, air and fuel mass flow rates, and volumetric efficiency are calculated. The volumetric efficiency is determined to be 85.13%.

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154 views2 pages

ME410: Engine Combustion Analysis

This document contains a homework problem to calculate the air flow rate, mass of fuel and air entering each cylinder per cycle, and volumetric efficiency of a 4-cylinder spark ignition engine. Key details include: the engine takes in 2.0 g/s of isooctane fuel at 1500 revolutions per minute. Using equations, the air-fuel ratio, air and fuel mass flow rates, and volumetric efficiency are calculated. The volumetric efficiency is determined to be 85.13%.

Uploaded by

owaiskhan
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as PDF, TXT or read online on Scribd
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File:C:\Personal\Class\ME410\Heywood\HW3-1.

EES 9/30/02 10:20:34 AM Page 1


EES Ver. 6.577: #659: for use by Students and Faculty of the ME Dept, Rose-Hulman

Homework Problem 3.1 in Heywood

Isooctane is supplied to a four cylinder spark ignition engine at 2.0 g/s. Calculate the air
flow rate for
stoichiometric combustion. If the engine is operating at 1500 rev/min estimate the mass
of fuel and
air entering each cylinder per cycle. The engine displaced volume is 2.4 liters. What is
the volumetric
efficiency?

Data

a = 8

b = 18

b
y =
a

mdot fuel = 0.002 [Kg/sec] mass flow rate of fuel

Vd = 0.0024 [m3] engine displacement

Vd
Vcyl = [m3] cylinder displacement
4

W = 1500 [rev/min]

fac = 2 [rev/cycle]

tf = 60 [sec/min]

Use Equation 3.6 on Page 69 to get stoichiometric AF

34.56 4 + y
AF =
12.01 +1.008 y

Air flow rate for stoichiometric combustion

mdot air
= AF
mdot fuel

Air and mass flow per cycle per cylinder

mdot fuel tf
mdot fuel,cycle = fac [Kg/cycle]
W 4

mdot air tf
mdot air,cycle = fac [Kg/cycle]
W 4

Volumetric efficiency

mdot air,cycle
v air = [m3]
'Air' , T=298, P=101.3

v air
vol =
Vcyl
File:C:\Personal\Class\ME410\Heywood\HW3-1.EES 9/30/02 10:20:35 AM Page 2
EES Ver. 6.577: #659: for use by Students and Faculty of the ME Dept, Rose-Hulman

Unit Settings: [kJ]/[K]/[kPa]/[kg]/[radians]


a =8 AF = 15.13 b = 18
vol = 0.8513 fac = 2 [rev/cycle] mdotair = 0.03025
mdotair,cycle = 0.0006051 [Kg/cycle] mdotfuel = 0.002 [Kg/sec] mdotfuel,cycle = 0.00004 [Kg/cycle]
tf = 60 [sec/min] Vcyl = 0.0006 [m3] Vd = 0.0024 [m3]
vair = 0.0005108 [m3] W = 1500 [rev/min] y = 2.25

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