Design of Mechanical Systems
Quiz and Exam Resource
Geometry
1 3
Rectangle: = =
12
2
Circle: = = 4 = 4
4 64 32
Stress Transformations
2 + 1 3
, = 2
+ = , 1 2 3 =
2 2 2
Stresses and deformations
2
Tension, Compression: = = =
2
Direct Shear: =
2
Torsion: = = = =
2
2 2 1
Pure bending: = = = 2 = =
2
Singularity functions:
Concentrated moment: () = 0 < >0
Concentrated force: () = < >1
1
Uniformly distributed load: () = < >2
2
1 3
Ramp: () = < >
6
< > = ( ) if x a, 0 otherwise
1
< > = +1 < >+1 if n > 0
< > = < >+1 if n 0
Shear stress due to bending: =
4 3
= (circular section) ; = (rectangular section) ; = (structural shape)
3 2
Castigliano's Theorem: =
Columns
1/2
22
Critical slenderness ratio: =
1
1/4
2 2 64 2
Euler columns: = ; = (/)2 ; =
2 3
1/2
2 1 2
Johnson Columns: = ; = 2 +
2 2
Failure Theories
Maximum Shear Stress Theory: max =
2
Distortion Energy Theory: max =
(1 2 )2 +(2 3 )2 +(1 3 )2
von Mises stress: = = 2 + 2 + 3
2
2
Brittle Coulomb-Mohr Theory:
0 =
1
0 =
0 =
Endurance limit: = 0.5 200 (1400 ), 100 (1400 )
(0.9 )2 1 0.9
Fatigue strength: = ; = ; = log
3
Endurance limit: =
Surface finish factor: =
Size factor: = 0.8790.107 0.11 2 ; = 0.9100.157 2 < 10
= 1.240.107 2.79 51 ; = 1.51 0.157 51 < 254
= 0.370 , = 0.808
k b = 1 for axial loads
Loading factor: = 1 , 0.85 , 0.59
+ +
Mean stress, stress amplitude: = ; =
2 2
1
Modified Goodman criteria: + = ; =
1( )
2
Gerber criterion: + =1 ; =
1( )2
Static (Langer) failure: + =
Fasteners
+ sec sec
Power screws: raising: = ; lowering: = ;
2 sec 2 + sec
self-locking: >
0.5774
Bolt stiffness: = = ; Member stiffness: = (1.155+)(+) ; =
+ (1.155++)() +
Bolt torque: T = 0.2 F i d
Load factor against overload: = ; Factor of safety against yielding: = =
+ +
Factor of safety against joint separation: =
(1)
Non-permanent connections: F i = 0.75 A t S p ; permanent connections, F i = 0.9 A t S p
Fatigue loading between no-load and max load P:
2 ( )
= ; = + ; Goodman: = ) with < (1 )
2 2 ( +
Welds
Butt and fillet welds: = =
0.707
Joints in torsion: = ;
= =
0.707
Joints in bending: = ; =
=
0.707
Helical springs
Mean diameter: D =OD d = ID + d ; Spring index: C = D/d
8 4+2
Stress: = 3 ; = ;
43
4
Spring rate: =
83
Absolute stability of steel compression springs: 0 < 2.63
Spring materials: = ; S su = 0.67S ut ; S sy = 0.45S ut
1
Critical frequency of helical springs: =
2
Fatigue loading: unpeened: S sa = 35 ksi (241 MPa), S sm = 55 ksi (379 MPa)
peened: S sa = 57.5 ksi (398 MPa), S sm = 77.5 ksi (534 MPa)
8 8
= 3 ; = 3 ; = =
Goodman: = ; = ; =
1 +
Gearing
Circular pitch = p
Diametral pitch = P = N/d ; module = d/N
pP =
Train value: = ; = (1)#
Planetary systems: =
= 33000 ; W t (pounds), H (hp), = 12 = pitch-line velocity in ft/min, d (in), n(rpm)
60000
= ; W t (kN), H (kW), d (mm), n (rpm)
NOTE: The size range for Class 8.8 is M1.6 - M36