4/3/2017 NormalDistributionApplet
NormalDistribution
X N (, )
= 60.5 = 17.84
x = 34.13 P(X<x)= 0.06969
0.024
0.018
f(x)
0.012
0.006
0.000
0 20 40 60 80 100 120
x
2
= E(X) = 60.5 = SD(X) = 17.84 = V ar(X) = 318.266
Help
2016MattBognar
DepartmentofStatisticsandActuarialScience
UniversityofIowa
http://homepage.stat.uiowa.edu/~mbognar/applets/normal.html 1/1