CAT 2002 Actual Paper

ANSWERS and EXPLANATIONS

1 3 2 4 3 4 4 3 5 3 6 1 7 1 8 3 9 3 10 3
11 2 12 4 13 1 14 4 15 1 16 1 17 1 18 4 19 2 20 3
21 3 22 3 23 4 24 1 25 3 26 3 27 2 28 2 29 2 30 2
31 2 32 4 33 4 34 2 35 2 36 2 37 3 38 2 39 1 40 4
41 2 42 2 43 2 44 4 45 3 46 1 47 3 48 2 49 4 50 3
51 3 52 2 53 1 54 2 55 1 56 4 57 4 58 2 59 4 60 4
61 3 62 2 63 4 64 3 65 3 66 2 67 2 68 4 69 3 70 1
71 3 72 2 73 3 74 4 75 4 76 1 77 1 78 4 79 2 80 4
81 4 82 3 83 4 84 3 85 1 86 3 87 *2 88 3 89 2 90 2
91 4 92 4 93 4 94 3 95 4 96 2 97 2 98 4 99 3 100 3
101 3 102 2 103 4 104 2 105 4 106 3 107 1 108 3 109 4 110 2
111 3 112 1 113 4 114 3 115 1 116 4 117 3 118 2 119 3 120 2
121 1 122 4 123 1 124 3 125 1 126 3 127 2 128 3 129 4 130 1
131 1 132 4 133 4 134 4 135 2 136 4 137 2 138 2 139 4 140 4
141 4 142 1 143 1 144 2 145 1 146 3 147 4 148 3 149 1 150 3

Scoring table

Section Question Total Total Total Total Net Time

number questions attempted correct incorrect score taken
DI 1 to 50 50

QA 51 to 100 50

EU + RC 101 to 150 50

Total 150

CAT 2002 Actual Paper Page 1

1. 3 Statement I tells us that 7. 1
(1) Ashish is not an engineer, (2) Ashish got more N
offers than the engineers.
Hence, Ashish did not have 0 offers. W E
After this the following table can be achieved.

Profession Names Offers S

FINISH F Vth Sig nal
3 2 1 0 X Profession
@ 4 0 km ph
CA Ashish 2 X Engineer @ 1 00 km p h
t = 2 4 m inu te s 1 0 km t = 1 5 m inu te s
MD Dhanraj 2 X Engineer s = 10 km
IIIrd s = 40 km
Economist Sameer 2 Sig nal
@ 4 0 km ph 4 0 km IVT H
Engineer 2 Sig nal
t = 3 0 m inu te s
From statement IV, Dhanraj is not at 0 and 1. s = 20 km
2 0 km @ 4 0 km ph
2. 4 Option (3) is ruled out by statement VII. t = 1 5 m inu te s
Option (1) is ruled out by statements VII and VIII. s = 10 km
From statement IV, Sandeep had Rs. 30 to start and I Sig nal
Daljeet Rs. 20. 1 0 km
IInd M oves @ 2 0 km p h
From statement II, option (2) is not possible as Sandeep Sig nal t = h r = 30 m in utes
was left with Re 1, he spent Rs. 29. But according to 1 0 km
s = 20 3 0 = 1 0 km
(2) he spent Rs. 1.50 more than Daljeet. But Daljeet 60
S
had only Rs. 20. Hence option (4) is correct.
START
3. 4 Data insufficient, please check the question.
Note: s = Distance covered; v = Velocity (km/hr)
4. 3 Statements V and VI rule out options (1) and (2). Since t = Time taken; s = v t
contestants from Bangalore and Pune did not come
first, school from Hyderabad can come first. Convent The total distance travelled by the motorist from the starting
is not in Hyderabad which rules out option (4). point till last signal = 10 + 10 + 20 + 40 + 10 = 90 km.

5. 3 The only two possible combinations are: 8. 3

Younger Older N
2 4
W E
3 9
Cubes of natural numbers are 1, 8, 27, 64, ... . 3 0 km
F S
Here, 64 and above are not possible as the age will go T
above 10 years.
If younger boy is 2 years old, then older boy is 4 years 1 0 km
old. Then, Fathers age is 24 years and Mothers age
III
42 4 0 km IV
is = 21 years.
2 4 0 km
Also, 24 21 = 3 2 0 km
Age of younger boy = 2 years
I
6. 1 Total seats in the hall 200 II 1 0 km
Seats vacant 20
Total waiting 180 1 0 km
Ladies 72
2 S
Seating capacity of flight 180 = 120
3 By Pythagoras Theorem,
Number of people in flight A = 100
For flight B = 180 100 = 80 SF = ST 2 + TF2 = 402 + 302 = 2500 = 50 km
80
Thus, airhostess for A = =4
20
Empty seats in flight B = 120 80 = 40
40 : 4 = 10 : 1

Page 2 CAT 2002 Actual Paper

9. 3 For the case when 1st signal were 1 red and 2 green 11. 2 Total five lie between 10 E and 40 E.
lights, the surface diagram will be as given below. Austria, Bulgaria, Libya, Poland, Zambia
N N N N S
N
1
= 20%
W E 5

F S 12. 4 Number of cities starting with consonant and in the

5 0 km northern hemisphere = 10.
T
Number of countries starting with consonant and in
1 0 km the east of the meridian = 13.
III Hence, option (4) is the correct choice.
The difference is 3.
4 0 km 4 0 km IV
13. 1 Three countries starting with vowels and in southern
hemisphere Argentina. Australia and Ecuador and
2 0 km
two countries with capitals beginning with vowels
Canada and Ghana.
I II
1 0 km 14. 4 Let us consider two cases:
(a) If 5 min remaining the score was 0 2. Then final
1 0 km
score could have been 3 3. [Assuming no other
Indian scored]
S (b) But if the score before 5 min was 1 3, then final
score could have been 4 3.
TF = 50 km; ST = 40 km
Considering the above figure, option (3) is correct, From statement A, we know only the number of goals
50 km to the east and 40 km to the north. made by India is the last 5 minutes. But, as we dont
know what the opponent team did in the last 5 minutes,
10. 3 If the car was heading towards South from the start we cant conclude anything. So statement A alone is
point, then the surface diagram will be as given below. not sufficient.
Similarly, statement B does not talk about the total
N number of goals scored by India. So statement B is not
sufficient.
W E Using both the statements, we have two possibilities:
(I) If Korea had scored 3 goals 5 minutes before the
S end of the match India would have scored 1 goal. In
S
S TA R T the last 5 minutes as India made 3 goals and Korea on
the whole made 3 goals, we can conclude that India
had won the game.
1 0 km (II) If Korea had scored 3 goals 5 minutes before the
end of the match, India would have scored zero goals.
II
In the last 5 minutes, as India made 3 goals and Korea
I 1 0 km on the whole made 3 goals, we can say the match
was drawn.
4 0 km Hence, we cannot answer the question even boy
2 0 km
using both the statements together.
3 0 km
15. 1 From A, if by adding 12 students, the total number of
IV students is divisible by 8. By adding 4 students, it will
4 0 km III be divisible by 8.
1 0 km

F 1 1 y + x
16. 1 From (A), (x + y) x + y = 4 or (x + y) xy = 4
FIN IS H
Hence, we can see that option (3) is correct. (x + y)2 = 4xy
(x y)2 = 0
x=y ... (i)

CAT 2002 Actual Paper Page 3

 From (B), (x 50)2 = (y 50)2 23. 4 80% attendance = 80% of 25 = 20 days
On solving Emp. numbers 47, 51, 72, 73, 74, 79, 80.
x(x 100) = y(y 100) ... (ii) Thus, total = 7
This suggests that the values of x and y can either be
0 or 100. 24. 1 Em p. No. Earnings No. of days E/D
17. 1 Statement: E D
A. Let the wholesale price is x. (m edium ) (m edium )
Thus, listed prices = 1.2x
2001151 159.64 13.33 11.97
After a discount of 10%, new price = 0.9 1.2x
= 1.08x 2001158 109.72 9.61 11.41
1.08 x = 10$. 2001164 735.22 12.07 60.91
Thus, we know x can be found. 2001171 6.10 4.25 -

B. We do not know at what percentage profit, or at 2001172 117.46 8.50 13.81

what amount of profit the dress was actually 2001179 776.19 19.00 40.85
sold. 2001180 1262.79 19.00 66.46
18. 4 A gives 500 as median and B gives 600 as range. Hence, Emp. number 2001180 earns the maximum
A and B together do not give average. earnings per day.
Therefore, it cannot be answered from the given
statements. 25. 3 Emp. numbers 51, 58, 64, 71, 72 satisfy the
condition.
19. 2 From statement A, we know that for all 1 < x < 1, [For emp. 64, you see 12 is not the double of 5. And
we can determine |x 2| < 1 is not true. Therefore, 735 is not even double of 402.
statement A alone is sufficient.
402 735
From statement B, 1 < x < 3, we cannot determine Hence, > .
whether |x 2| < 1 or not. Therefore, statement B 5 12
alone is sufficient. Note: Emp. numbers 48, 49, 50 are not eligible for
earnings. Hence, they are not counted.
20. 3 From statement A, we cannot find anything.
From B alone we cannot find. 26. 3 Total revenue of 1999 = 3374
From A and B, 5
5% of 3374 = 3374 = 168.7
3 00 100
R For 1999, revenue for Spain is 55, Rest of Latin America
F is 115, North Sea is 140, Rest of the world is 91.
X 196 58 So total four operations of the company accounted
for less than 5% of the total revenue earned in the
year 1999.
x + 196 + 58 = 300. Thus, x can be found.
27. 2 The language in the question is ambiguous.
21. 3 Jagdish (J), Punit (P), Girish (G) Taking the question to be more than 200% growth in
revenue, the revenue in 2000 will be more than 3
2 times that in 1999. Hence, (2) is the answer.
Statement A: J = [P + G]W Taking the revenue in 2000 to be more than 200% of
9
that in 1999, the revenue in 2000 should be more than
P + G + J = 38500 twice of that in 1999. Then there will be 4 operations.
Thus, only J can be found.
28. 2 Four operations, as given below:
(1) North Africa and Middle-East
Statement B: Similarly, from this only P can be found. (2) Argentina
Combining we know J, P and G can be (3) Rest of Latin America
found. (4) Far East
have registered yearly increase in income before taxes
22. 3 Emp. numbers 51, 58, 64, 72, 73 earn more than and charges from 1998 to 2000.
50 per day in complex operations.
Total = 5

Page 4 CAT 2002 Actual Paper

29. 2 Percentage increase in net income before tax and 36. 2 BC AC AAC = 0
charges for total world (1998-99)
1375 248 37. 3 0 95.2
BD AE AAB
= 100 = 454.4%
248
Spain is making loss.
Least cost of sending one unit from any refinery
to AAB
Percentage increase for North Africa and Middle-East
= 0 + 95.2 = 95.2.
341 111
111
100 = 207.2% 38. 2 BB AB AAG = 311.1
Same as above.
838 94
Percentage increase for Argentina = 100 39. 1 First we will have to check the minimum cost for
94
= 791.5% receiving at AAA. This is 0 for AE. But, BB to AE is
From the table one can directly say that there is no very high. Next is AC [314.5]. BB to AC is 451.1. After
operation other than Argentina, whose percentage AC, the others are high. Hence, 314.5 + 451.1 = 765.6
increase in net income before taxes and charges is is the least cost.
higher than the average (world).
40. 4 Number of refineries = 6
30. 2 Statement 1 is obviously wrong. Number of depots = 7
54 20 Number of districts = 9
(2) > . Hence, (2) is correct. Therefore, number of possible ways to send petrol
65 52
from any refinery to any district is 6 7 9 = 378.
500 61
(3) > . Hence (3) is wrong.
1168 187 41. 2 The highest cost is for the route
BE AE AAH = 2193.0
31. 2 Profitability of North Africa and Middle-East in 2000
356 For questions 42 to 47:
= = 0.67
530
225 Position
Profitability of Spain in 2000 = = 5.23 of
43 Year
169 States
Profitability of Rest of Latin America in 2000 = , (Rank)
252
i.e. < 1. 96-97 97-98 98-99 99-00 00-01
189
Profitability of Far East in 2000 = =<1 1 MA MA MA MA MA
311
2 TN TN TN TN TN
32. 4 Except Rest of Latin America and Rest of the World all 3 GU AP AP AP AP
the operations are greater than 2. 4 AP GU GU GU UP changed
33. 4 Options (1), (2) and (3), are ruled out. So the correct 5 KA UP UP UP GU } tw ice
option is (4). 6 UP KA KA KA KA
7 WB WB WB WB WB
34. 2 It can be easily observed from the two charts that
20 42. 2 From above table, we can conclude that option (2) is
Switzerlands ratio of chart 1 to chart 2 is has the correct.
11
highest price per unit kilogram for its supply.
43. 2 On referring to the table, we can see that UP is the
state which changed its relative ranking most number
35. 2 Total value of distribution to Turkey is 16% of 5760
of times.
million Euro.
Total quantity of distribution to Turkey is 15% of 1.055
44. 4 We can say directly on observing the graph that the
million tonnes.
sales tax revenue collections for AP has more than
So the average price in Euro per kilogram for Turkey is
doubled from 1997 to 2001.
16
5760 100
; 5.6
15

100
1055

CAT 2002 Actual Paper Page 5

45. 3 Growth rate of tax revenue can be calculated as:
4x 3x
(Sales tax revenue of correct year Sales tax revenue Hence, BD = ; DC =
of previous year) 7 7
7826 7290 16x 2
For year 1997-98 = 0.068 (4)2 + y 2
7826 In ABD, cos30 = 49
8067 7826 2 4 y
For year 1998-99 = 0.030
7826 3 16x 2
2 4 y = 16 + y 2
10284 8067 2 49
For year 1999-2000 = 0.274
8067
16x 2
12034 10284 4 3y = 16 + y 2 ... (i)
For year 2000-01 = 0.170 49
10284
9x 2
9 + y2
46. 1 For increase by the same amount for 2 successive Similarly, from ADC, cos30 = 49
years, eliminate the options by subtracting only the 23 y
last digit.
For Karnataka, increase in 2000-01 is 5413 4839 = 9x 2
3 3y = 9 + y 2 ... (ii)
574 and increase in 1999-2000 is 4839 4265 = 574. 49
Hence, (1) is the correct option. Now (i) 9 16 (ii), we get
47. 3 On referring to the table, we can see that Tamil Nadu 12 3
36 3y 48 3y = 9y 2 16y 2 y =
has been maintaining a constant rank over the years 7
in terms of its contribution to total tax collections.
Alternate solution:
48. 2 Only R9 is that region which produces medium quality Area of ABC = Area of ABD + Area of ADC
of crop 2 and low quality of crop 4.

49. 4 Statement (1) is not satisfied by R9. 1 1 1

4 3sin 60 = 4 ysin30 + 3 y sin30
Statement (2) is not satisfied by R3. 2 2 2
Statement (3) is incorrect as there are six such regions
R1, R2, R3, R4, R9 and R11. 12 3 = 4y + 3y
Statement (4) is correct.
12 3
y=
50. 3 Three regions namely R9, R10 and R11. 7

51. 3 Total possible arrangements = 10 9 8

C
Now 3 numbers can be arranged among themselves
in 3! ways = 6 ways 53. 1 1 5 cm 2 0 cm
Given condition is satisfied by only 1 out of 6 ways. A B
Hence, the required number of arrangements 2 5 cm
10 9 8
= = 120
6 Let the length of the chord be x cm.
Alternate solution: 1 1 x
10
C3 = 120 (15 20) = 25 x = 24 cm
2 2 2
Any three numbers selected out of 10 numbers will
have only one possible arrangement.
1+ x 1+ y
54. 2 f(x) + f(y) = log 1 x + log 1 y

52. 2 A
3 0 3 0 (1 + x) (1 + y)
= log
y 3 (1 x)(1 y)
4
1 + x + y + xy
= log
B D C 1 + xy x y
Let BC = x and AD = y.
BD AB 4 1 + xy + x + y
As per Bisector Theorem, = = = log
DC AC 3 1 + xy (x + y)

Page 6 CAT 2002 Actual Paper

 1
x + y 59. 4 Check choices, E.g. Diagonal = 5
1+ 2
= log 1 + xy Distance saved = 3 5 0.75 Half the larger side.
x + y Hence, incorrect.
1 1 + xy
3
Diagonal = 5
4
x+y Distance saved = (4 + 3) 5 = 2 = Half the larger side.
= f
1 + xy
60. 4 If speed of N = 4, speed of S = 1,
55. 1 Total area = 14 14 = 196 m 2 2 4 1
Average speed = = 1.6
4 +1
r2
Grazed area = 4 4 2 3
Because time available is , speed =
3 2
= r = 22 7 (r = 7 m) = 154 m2
2
Now average speed = 2.4
Ungrazed area is less than (196 154) = 42 m 2, Now speed of N = 8
for which there is only one option i.e. 22 m2. Now speed of S = y
28 y
56. 4 Every trip will need more than 180 m and there are = 2.4 y = 1.3
8+y
1
4 trips. Hence, the distance covered will be greater Required ratio = 1.3 : 8 1:6
2
than 750 m, for which there is only one option = 860.
61. 3 1 5 km
Alternative method: A B
2 .5 km
For the first stone, he will cover 100 m. G1 G2 G 2 .5 km
3
For second, 200 4 = 196 m
For third, 200 8 = 192 m Let G1, G2 and G3 be the three gutters such that G2G3 =
For fourth, 200 12 = 188 m 2 G1G2 .
For fifth, 200 16 = 184 m AG1 = 5 min 30km/hr = 2.5 km
Hence, total distance = 860 m G1 G3 = 20 2 2.5 = 15 km
Time taken to cover AG1 = 5 min
Time taken to cover (G1G3 + G3A)
A F D
57. 4
(15 + 17.5 )km = 32.5 60 = 32.5 minutes
=
2 30 km / hr 60
The patient reaches the hospital in a total of (32.5 + 5)
= 37.5 minutes
Maximum time that the doctor gets to attend the patient
= 40 37.5 1 = 1.5 minutes.
B E C
Area of ABE = 7 cm 2 62. 2 Check choices
Area of rectangle ABEF = 14 cm2 Choice (2) 54 S = (5 + 4)2 = 81
Area of ABCD = 14 4 = 56 cm2 D S = 81 54 = 27. Hence, the number = 54

58. 2 63. 4 x0 = x
x1 = x
(1 , 1 ) x2 = x
x3 = x
x4 = x
(0 , 0 ) (2 , 0 ) x5 = x
x6 = x
Let a = 0 ..
1 Choices (1), (2), (3) are incorrect.
Hence, area = (2) (1) = 1
2
Note: Answer should be independent of a and area
of the triangle does not have square root.

CAT 2002 Actual Paper Page 7

64. 3 xy + yz + zx = 3 1
70. 1 Coefficient of xn = (n + 1)(n + 4)
xy + (y + x)z = 3 2
xy + (y + x)(5 x y) = 3
S = 2 + 5x + 9x 2 + 14x 3 + ....
x + y + xy 5x 5y + 3 = 0
2 2
xS = 2x + 5x 2 + .....

y 2 + (x 5) y + x 2 5x + 3 = 0 S(1 x) = 2 + 3x + 4x 2 + 5x 3 + ....
As it is given that y is a real number, the discriminant
Let S1 = S(1 x) S1 = 2 + 3x + 4x 2 + ...
for above equation must be greater than or equal to
zero.
xS1 = 2x + 3x 2 + ...
Hence, (x 5)2 4(x 2 5x + 3) 0
S1(1 x) = 2 + x + x 2 + ....
3x 10x 13 0
2
x
S1(1 x) = 2 +
3x2 13x + 3x 13 0 1 x
x S= 2x
13 S(1 x)2 = 2 +
x 1, 1 x (1 x)3
3

13
Largest value that x can have is . 71. 3 x 2 + 5y 2 + z2 = 4yx + 2yz
3
(x 2 + 4y 2 4yx) + z2 + y 2 2yz = 0
65. 3 Area = 40 20 = 800 m2.
If 3 rounds are done, area = 34 14 = 476 m2 (x 2y)2 + (z y)2 = 0
Area > 3 rounds It can be true only if x = 2y and z = y
If 4 rounds Area left = 32 12 = 347 m2
Hence, area should be slightly less than 4 rounds. 72. 2 Let the number be ab.
Arithmetic mean is more by 1.8 means sum is more
66. 2 Since thief escaped with 1 diamond, by 18.
Before 3rd watchman he had (1 + 2) 2 = 6 diamonds. (10b + a) (10a + b) = 18
Before 2nd watchman he had (6 + 2) 2 = 16 diamonds. 9 (b a) = 18
Before 1 st watchman he had (16 + 2) 2 = 36
b a = 2.
diamonds.
73. 3 By trial and error:
1 30 12 = 360 > 300
67. 2 Mayank paid of the sum paid by other three. 30 7.5 = 225 < 300
2
50 6 = 300. Hence, he rented the car for 6 hr.
1
Mayank paid rd of the total amount = $20.
3 n2 + n
74. 4 575 = x
Similarly, Mirza paid $15 and Little paid $12. 2
Remaining amount of $60 $20 $15 $12 = $13 is
1150 = n2 + n 2x
paid by Jaspal.
n(n + 1) 1150
68. 4 Let the number of gold coins = x + y
n2 + n 1150
48(x y) = x2 y2
The smallest value for it is n = 34.
48(x y) = (x y)(x + y) x + y = 48
For n = 34
Hence, the correct choice will be none of these.
40 = 2x x = 20
69. 3 Lets assume that
p days : they played tennis 75. 4 x 1 [x] x
y days : they went for yoga 2x + 2y 3 L(x,y) 2x + 2y a 3 L a
T days : total duration for which Ram and Shyam
stayed together 2x + 2y 2 R(x,y) 2x + 2y a 2 R a
p + y = 22 Therefore, L R
(T y) = 24 and (T p) = 14
Adding all of them, Note: Choice (2) is wrong, otherwise choice (1) and
2T = 22 + 24 + 14 T = 30 days. choice (3) are also not correct. Choose the numbers
to check.

Page 8 CAT 2002 Actual Paper

 83. 4 Number of oranges at the end of the sequence
76. 1 Number of regions = n(n + 1) + 1 , where n = Number = Number of (2s) Number of (4s) = 6 4 = 2
2
of lines, i.e. for 0 line we have region = 1.
For 1 line we have region = 2. 84. 3 Number of (1s + 2s + 3s) 2(Number of 4s) = 19 8
It can be shown as: = 11
85. 1 11 10 9 8 = 7920

Num ber of lines 0 1 2 3 4 5 10 86. 3 Total number of passwords with atleast 1 symmetric
Num ber of regions 1 2 4 7 11 16 56 letter
= Total number of passwords using all letters Total
10 11 number of passwords using no symmetric letters
Therefore, for n = 10, it is + 1 = 56 = (26 25 24) (15 14 13 ) = 12870
2
87. *2 AB is the tunnel and d km be its length.

(2 )
64
77. 1 4
= (17 1) 64
= 17n + ( 1)
64
= 17n + 1 A X B
Hence, remainder = 1 3d
8
A2 B2 d
78. 4 + = 1 A 2 (x 1) + B2 x = x 2 x
x x 1
When one of A or B is zero, it will be a linear equation Let the current position of the cat be X. If it runs to-
which will have one real root. When both A and B are wards A, it would reach A at the same time as the train
non-zero, it will be a quadratic equation which can reaches A.
have two real roots. However, if it runs towards the other end B, it would
reach point Y at the same time when the train reaches
79. 2 Since each word is lit for a second, least time after 3d
which the full name of the bookstore can be read A. Hence, point Y would be at a distance of km
8
again
from X
5 17 41 7 21 49
= LCM + 1, + 1, + 1 = LCM , A X Y B
2 4 8
,
2 4 8
3d 3d
LCM (7,21,49) 49 3 8
= = = 73.5 s. 8
HCF(2,4,8) 2 d

As the cat and the train would reach B simultaneously,

9 27 36 HCF (9, 27, 36) = 9
80. 4 HCF , , = LCM (2, 4, 5) 20
lb 2d d
2 4 5 the cat would cover the rest = km distance in
8 4
= Weight of each piece
Also, total weight of three pieces of cakes = 18.45 lb the same time that the train takes to cover the whole
Maximum number of guests that could be entertained tunnel i.e. d km.
Therefore, the speed of the train = 4 the speed of
18.45 20 the cat
= = 41.
9 Hence, ratio of the speeds of the train and cat is 4 : 1.

81. 4 3(4(7x + 4) + 1) + 2 = 84x + 53 * The language in the question is slightly

Therefore, remainder is 53. ambiguous. A possible interpretation is that the ratio
of their speeds is to be determined which is correctly
82. 3 4 : 1.
S S
Y D D Y 88. 3 Let the largest piece = 3x
Middle = x
Shortest = 3x 23
3x + x + (3x 23) = 40
P A R A x=9
R P The shortest piece = 3(9) 23 = 4
Before After

Suresh is sitting to the left of Dhiraj.

CAT 2002 Actual Paper Page 9

 8
89. 2 Each traveller had loaves. 93. 4 76n 66n
3 Putting n = 1.
8
First traveller has given 5 loaves to the third. 76 66 = (73 63 )(73 + 63 )
3
8 1
Second traveller sacrificed only 3 = rd of a loaf. This is a multiple of 73 63 = 127 and 73 + 63 = 559
3 3 and 7 + 6 = 13. Hence, all of these is the right answer.
So, first should get 7 coins.
1 1
90. 2 94. 3 Given pqr = 1 pq = and = qr
B r p
1 1 1
+ +
20 1 + p + q1 1 + q + r 1 1 + r + p 1
15
Q q r 1
P M = + +
1 + q + pq 1 + qr + r 1 + r + qr
A C
D qr r 1 1 + r + qr
x 25 x = + + = = 1.
1 + qr + r 1 + qr + r 1 + r + qr 1 + r + qr
(15)2 x 2 = (20)2 (25 x)2
Alternate solution:
x=9 Putting x = y = z = 1, we get
BD = 12
1 1 1
+ +
1
Area of ABD = 12 9 = 54 1 + p + q1 1 + q + r 1 1 + r + p 1
2
1 1 1 1 1 1
1 = + + = + + = 1.
s= (15 + 12 + 9) = 18 1+ 1+ 1 1+ 1+ 1 1+ 1+ 1 3 3 3
2

Area 95. 4 Total amount of work = 60 man-hours

r1 = r1 = 3 From 11 am to 5 pm, 6 technicians = 36 man-hours
s
From 5 pm to 6 pm, 7 technicians = 7 man-hours
1 From 6 pm to 7 pm, 8 technicians = 8 man-hours
Area of BCD = 16 12 = 96 From 7 am to 8 pm, 9 technicians = 9 man-hours
2
Total = 60 man-hours
1
s = (16 + 20 + 12) = 24 96. 2 Number of samosas = 200 + 20n, n is a natural num-
2
ber.
Area Price per samosa = Rs.(2 0.1n)
r2 = r2 = 4 Revenue = (200 + 20n)(2 0.1n) = 400 + 20n 2n2
s
= 450 2 (n 5)2
In PQM, PM = r1 + r2 = 7 cm Revenue will be maximum if n 5 = 0
QM = r2 r1 = 1 cm
n=5
Hence, PQ = 50 cm Maximum revenue will be at (200 + 20 5)
= 300 samosas.
91. 4 um + vm = wm 97. 2 Three small pumps = Two large pumps
u2 + v 2 = w 2
Three small + One large pumps = Three large pump
Taking Pythagorean triplet 3, 4 and 5, we see
that m < min (u, v, w). 1
Also, 11 + 21 = 31 and hence, m min (u, v, w). rd of total time is taken by the large pump alone.
3

92. 4 A black square can be chosen in 32 ways. Once a

black square is there, you cannot choose the 8 white 98. 4 If KL = 1, then IG = 1 and FI = 2
squares in its row or column. So the number of white
2
squares available = 24 Hence, tan = =2
Number of ways = 32 24 = 768 1
Thus, none of 30, 45 and 60.

Page 10 CAT 2002 Actual Paper

 1 108. 3 BEA form a mandatory sequence. They in E refers to
99. 3 Area of quadrilateral ABCD (2x 4x ) 4 x 12x ambassadors in B. Further E also follows B because
2
it goes on to explain why ambassadors have to choose
1 their words as stated in B. A carries forward the
Area of quadrilateral DEFG (5 x 2x ) 2x 7 x
2 same argument by elaborating further about their job.
Hence, ratio = 12 : 7 Hence, option (3) is correct.

100. 3 Number of ways for single digit = 2 109. 4 The recent revival in C elaborates an inadequate
2 digits = 2 3 = 6 monsoon in E. Hence, EC forms a mandatory pair. D
3 digits = 2 3 3 = 18 follows B and A concludes the paragraph. Hence,
4 digits = 2 3 3 3 = 54 option (4) is correct.
5 digits = 2 3 3 3 3 = 162
6 digits = 2 3 3 3 3 3 = 486 110. 2 BE is a mandtory pair. B talks about a question regarding
Total number of ways = 728 the shape of the earth and E answers the question.
ED is another mandatory pair wherein E talks about
101. 3 The size of the pitch is the usage of measure. the question of how much more and D answers the
The vessel is used to take out a litre of oil. question by stating One way of doing that is to
Action against tresspassers was instituted in the determine... The mandatory sequence BED is only
campus. there in option (2). Hence, option (2) is correct.
Sheila ascertained the measurement of each item.
111. 3 Obviously is the right answer as it matches the tone
102. 2 Dinesh could not stand the discussion and he was of great simplifications.
forced to walk out.
Vidyas story is the limit, very hard to believe. 112. 1 Numerical value in the earlier paragraph points to
Jyoti wanted to go to the Bar. quantitatively as the answer.
The forces were such that he was certain to go over
the edge. 113. 4 Assess alternatives that follows the blank gives the
answer alternatives.
103. 4 Hussain tried to capture the spirit of India in this painting
(on the canvas). 114. 3 The passage deals with firing employees.
Sorry, I could not understand what you just said.
Is there s ome deception (vanishing ac t) in this 115. 1 Resolve means to find a solution to something.
proposal?
All her friends agreed that Prakash was a person 116. 4 The failed product would not be present had it not
worth entrapping in the snares of romance. passed through the process.

104. 2 I decided not to do business in handmade cards. 117. 3 This is a simple question of parallelism, not that it is ...
My brother is a trader of cards. but that it is.
Dinesh insisted on giving out the cards to the players.
This contract is concerned with handmade cards. 118. 2 You generate money through deals, and not by deals
or on deals. The two factors escalated costs and
105. 4 Ashish asked Laxman to turn his face in a new black money are lucidly given in (2).
direction.
Leena never sent a beggar away without offering 119. 3 W e always have to use the conjunction between to
anything. compare prices at two levels.
The old school building has taken the form of a museum.
Now he had the opportunity to voice his protest. 120. 2 Reduce and encourage will make a parallel
construction. Action is taken by someone, not of
106. 3 The reason why the demand for branded diapers may someone.
be price-sensitive is given in A. This is supported by
DB. C contrasts, supported by the example in E. F can 121. 1 Opprobrium is the state of being abused or scornfully
be linked with private-labels. criticized.

107. 1 (3) is a haphazard choice with no definite beginning, 122. 4 Portend means to predict or foreshadow.
middle or end. Discipline goes better with strong focus
as in AC. E further elaborates. DBF talks about making 123. 1 Prevaricate means to speak evasively with intent to
strategy foolproof through the value chain. deceive.

124. 3 Restive means to be restless or nervous.

CAT 2002 Actual Paper Page 11

125. 1 Ostensible means what is apparent or seeming to be 138. 2 (1), (3) and (4) are factually incorrect as per information
the situation. given in the 3rd paragraph. (2) comes closest to the
central idea in the third paragraph.
126. 3 Refer 2nd para, especially to the part: Then Indian
historians trained in mainly political. 139. 4 The writer does not harbour a very favorable view of
theologians, refer to all too definite.
127. 2 (1), (3) and (4) seem to be superficial answers. (2)
matches the syntax of the statement given in the 140. 4 (1), (2) and (3) take the form of questions raised by
question. the writer in the course of the passage.

128. 3 Refer to the part glamour departed from politics. 141. 4 Refer towards the end of the second paragraph.

129. 4 (4) is mentioned as a desirable characteristic towards 142. 1 Refer to inside of a cell bustles with more traffic and
the end of the passage. polymers, along which bundles of molecules travel
like trams.
130. 1 In (1), the writers and their respective approaches
are correctly matched as per the information given in 143. 1 Refer to The dynein motor ... is still poorly understood
the passage. and without motor proteins. Our muscles wouldnt
contract.
131. 1 Refer to the part abortion access when their countries
were perceived to have an overpopulation problem. 144. 2 Refer to the part without motor proteins ... We couldnt
grow and these particles create an effect that seems
132. 4 (1), (2) and (3) are stated towards the end of the to be so much more than the sum of its parts.
second paragraph and the beginning of the third
paragraph. 145. 1 Refer to the part three families of proteins, called
133. 4 (1), (2) and (3) are too far-fetched and find no place in myosin, kinesin and dynein and the growth process
the passage. requires cells to duplicate their machinery and pulls
the copies apart.
134. 4 (1) need not be necessarily true as an inference. (2)
and (3) are explicitly stated towards the end of the 146. 3 Refer to the part They think for us and is giving the
penultimate paragraph. language a lot of responsibility.

135. 2 Refer towards the end of the fourth paragraph. (2) 147. 4 (4) does not qualify as rhetoric on the basis of
comes closest to what the writer wants to say. information given in the fourth paragraph. Commands
are, at best, staid.
136. 4 (1), (2) and (3) find no place in the passage to support
the pro-choice lobby. 148. 3 (1), (2) and (4) cannot qualify as an answer as they
sound extreme or implausible. (3) comes closest to
137. 2 Simple. Just read the last line of the passage. what the writer would like to suggest.

149. 1 Arcane in the context of usage in the passage means

esoteric.

150. 3 Refer to the part bringing scholars to accept the better

argument and reject the worse.

Page 12 CAT 2002 Actual Paper