Basic data regarding soil shear strength
a. For cohesive soils.
qu = N / 7.50 kg/cm2
c = qu / 2 kg/cm2
or
c = N / 15 kg/cm2
Where
c = Shear strength of soil
N = No of blows from SPT test
qu = Unconfined compressive strength
b. For cohesionless soils .
For cohesionless soil corrections in N values shall be use
as per graph given in IS:2131-1981
Modulus of subgrade reaction (ks) in kn/m3
ksf = 0.65 x Es Es x B4 .. Vesic equation
1- M2 Eb x I
Where
Eb = Modulus of elasticity of footing material in kn/cum
Es = Modulus of elsticity of soil in kn/cum
I = Moment of inertia of footing in m4
M = Poisson's ratio for soil
Rigidity of members resting on soil
a. Member is rigid if, L < / 4
b. Member is intermidiate if , / 4 < L<
c. Member is flexible if , L<
1/4
where , = ksf x B
4Eb x I
B = Width of footing
Data
Width of section = 3000
Depth of section = 500
Total design moment = 30.7
Grade of concrete = 25
Grade of reinforcement steel = 415
Permissible stress in concrete, bending compression = 8.5
Clear cover at tension face = 50
Clear cover at compression face = 50
Effective depth for tension side = 442
Effective depth for compression face = 442
Reinforcement calculation
Dia-1 No Dia-2 No Area of steel
Compression 16 4 12 2 1029.92
Tension 16 15 12 0 3014.4
Section parameters
Modular ratio (m) m = 280
3 cbc
= 18.667
Modulus of elasticity of steel Es = 200000
Compression face
58 50
500
192.27
acr
58 50
Tension face
3000
Depth of neutral axis (under reinforced section)
1/2
Neutral axis x = (m x Ast) 2
+ 2xmxAstxd - m x Ast
(b)2 b b
1/2
= 351.7975 + 16580.5397 - 18.756
= 130.1243 - 18.756
= 111.3680 mm
Lever arm z = d- x/3
= 404.88 mm
Stress in steel at level of reinforcement bar
st = M
z x Ast
= 251.544 N/mm2
Strain in steel
s = st
Es
= 0.001257720
Strain in steel,calculated ignoring the stiffness of concrete in tension zone
1 = D-x x s
d-x
= 0.0014783516
Average strain at the level where the cracking is being considered
m = 1 - b (D-x) 2
3x EsxAstx(d-x)
= 0.0014783516 - 0.00075771
= 0.0007206446
Minimum cover to tension steel
Cm = 50
Distance from the point considered to the surface of the nearest longitudinal bar
acr = (d1)2 +
(d2)2 -
8
= 36966.471111 +
2500 - 8
= 190.66170016 mm
Design surface crack width
3 x acr x m
W max = 1+ 2(acr-cm)
(h-x)
= 0.4121979618
1.7238812941
= 0.2391104093 mm safe