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Connection Calculation: Dop Dop Wdop

The document describes the calculation of connection requirements for two pin connections. For the first connection using an IPE120 profile, it is determined that 4 M12 bolts are required. Each bolt would experience a tensile load of 1.25 kN and shear load of 2.5 kN, within allowable limits. For the second connection using an HEA100 profile, 2 M12 bolts are sufficient and would also experience loads within allowable limits. The document provides details on load cases, material properties, bolt properties, and calculations to determine the minimum number of bolts required.

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209 views2 pages

Connection Calculation: Dop Dop Wdop

The document describes the calculation of connection requirements for two pin connections. For the first connection using an IPE120 profile, it is determined that 4 M12 bolts are required. Each bolt would experience a tensile load of 1.25 kN and shear load of 2.5 kN, within allowable limits. For the second connection using an HEA100 profile, 2 M12 bolts are sufficient and would also experience loads within allowable limits. The document provides details on load cases, material properties, bolt properties, and calculations to determine the minimum number of bolts required.

Uploaded by

bobbyneba
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
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Download as PDF, TXT or read online on Scribd
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CONNECTION CALCULATION

- PIN CONNECTION
V= 10,00 kN
H= 5,00 kN
load case I
material 0361
sdop= 16,0 kN/cm2
tdop= 9,0 kN/cm2
swdop= 12,0 kN/cm2
profile IPE120
minimal element thickness
tmin= 8 mm
optdo=(5tmin)-0.2= 1,80 cm
Assume the bolts M 12 ... 10,9
Bearing capacity of bolts

tensile strength of bolt 10,9 fu = 100 kN/cm2


allowable shear stress tdop= 28 kN/cm2
allowable compressive load along the inner hole b,dop = 27,2 kN/cm2
allowable tensile stress z,dop = 27,5 kN/cm2

number of shear planes m= 1


shearing Fv = m*Av *dop= 31,67 kN
pressure along inner hole Fb = mint*d0*b,dop = 28,29 kN

allowable shear load Fv,dop=min(Fv,Fb) = 28,29 kN


allowable tensile load Fz,dop = As*z,dop = 23,10 kN

number of bolts required n= Rz/Fv,dop


n > 0,395
Adopted number of bolts n= 4 kom
Load of one bolt: Ft= T/n= 1,25 kN < Fv,dop
Fz= Z/n= 2,50 kN < Fz,dop

Straining of bolt exposed to complex stress:


(Ft/ Fv,dop)2+(Fz/Fz,dop)2 = 0,01 < 1 OK!

ADOPTED BOLT 4 M 12... 10,9


CONNECTION CALCULATION
- PIN CONNECTION
V= 10,00 kN
H= 5,00 kN
load case I
material 0361
sdop= 16,0 kN/cm2
tdop= 9,0 kN/cm2
swdop= 12,0 kN/cm2
profile HEA(IPB1)100
minimal element thickness
tmin= 5 mm
optdo=(5tmin)-0.2= 1,38 cm
Assume the bolts M 12 ... 10,9
Bearing capacity of bolts

tensile strength of bolt 10,9 fu = 100 kN/cm2


allowable shear stress tdop= 28 kN/cm2
allowable compressive load along the inner hole b,dop = 27,2 kN/cm2
allowable tensile stress z,dop = 27,5 kN/cm2

number of shear planes m= 1


shearing Fv = m*Av *dop= 31,67 kN
pressure along inner hole Fb = mint*d0*b,dop = 17,68 kN

allowable shear load Fv,dop=min(Fv,Fb) = 17,68 kN


allowable tensile load Fz,dop = As*z,dop = 23,10 kN

number of bolts required n= Rz/Fz,dop


n > 0,484
Adopted number of bolts n= 2 kom
Load of one bolt: Ft= T/n= 2,50 kN < Fv,dop
Fz= Z/n= 5,00 kN < Fz,dop

Straining of bolt exposed to complex stress:


(Ft/ Fv,dop)2+(Fz/Fz,dop)2 = 0,07 < 1 OK!

ADOPTED BOLT 2 M 12... 10,9

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