Mark Scheme (Results)
January 2017
International GCSE
Physics (4PH0) Paper 2P
Pearson Edexcel Certificate in Physics (KPH0)
Paper 2P
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January 2017
Publications Code 4PH0_2P_1701_MS
All the material in this publication is copyright
Pearson Education Ltd 2017
General Marking Guidance
All candidates must receive the same treatment. Examiners must
mark the first candidate in exactly the same way as they mark the
last.
Mark schemes should be applied positively. Candidates must be
rewarded for what they have shown they can do rather than
penalised for omissions.
Examiners should mark according to the mark scheme not
according to their perception of where the grade boundaries may
lie.
There is no ceiling on achievement. All marks on the mark scheme
should be used appropriately.
All the marks on the mark scheme are designed to be awarded.
Examiners should always award full marks if deserved, i.e. if the
answer matches the mark scheme. Examiners should also be
prepared to award zero marks if the candidates response is not
worthy of credit according to the mark scheme.
Where some judgement is required, mark schemes will provide the
principles by which marks will be awarded and exemplification may
be limited.
When examiners are in doubt regarding the application of the mark
scheme to a candidates response, the team leader must be
consulted.
Crossed out work should be marked UNLESS the candidate has
replaced it with an alternative response.
Question
Answer Notes Marks
number
1 (a) (i) 1 mark for each correct property;; 2
Type of Relative Ionising
Nature
Radiation Charge Ability
reject -2
alpha () helium nucleus (+)2 high
(high energy)
beta () -1 medium
electron
gamma electromagnetic
0 low
() wave
(ii) alpha / ; 1
(iii) alpha and beta / and ; both 1
required
but can be
in either
order
(b) top line correct; e.g. 14, 0 2
bottom line correct; e.g. 7
e.g.
Total for question = 6 marks
Question
Answer Notes Marks
number
2 (a) (sum of) clockwise moments equals (sum 2
of) anti-clockwise moments;
(for a system) to be balanced / in
equilibrium;
(b) (i) measure mass of plastic strip (in kg); 2
multiply mass by g; allow multiply by
10 / 9.8 / 9.81
allow idea of
setting balance to
zero for 1 mark if
no other mark
scored
(ii) any 1 of: 1
use a ruler with smaller divisions;
use a mm ruler;
use a balance that measures to more
decimal places;
(iii) moment = force x (perpendicular) allow correct 1
distance (from the pivot); symbols e.g.
moment = F x d
condone use of M
or m for moment
(iv) calculates one moment correctly; allow distances in 3
cm throughout
correct use of principle of moments;
evaluation; 0.4 (N) gets 1
mark max.
e.g.
0.2 x 0.3 = 0.06
0.06 = 0.1 x F
(force =) 0.6 (N)
(v) any 1 of: ignore references 1
to mass/weight of
rule
idea that calculated force includes weight allow mass/weight
of beaker / weight of beaker should be of beaker not
subtracted; considered
mass of paperclip / string not considered;
centre of mass of ruler may not be at 50
cm;
Total for question = 10 marks
Question
Answer Notes Marks
number
3 (a) B sound waves are transverse; 1
(b) (i) calculation of time period; 3
substitution into correct frequency allow ecf for
equation; incorrect time
evaluation; period
e.g.
(time period / T) = 0.02 (s) allow 0.02 seen
anywhere
(f =) 1/0.02
(f =) 50 (Hz)
16.7, 100 (Hz) get
2 marks max.
(ii) line drawn has smaller amplitude than ignore vertical 2
existing line throughout; position of line
line drawn has higher frequency (pitch)
throughout;
Total for question = 6 marks
Question
Answer Notes Marks
number
4 (a) (i) number of layers (of insulation); 1
(ii) final temperature (of the water) / temperature allow temperature 1
after 15 minutes / rate at which the water cools difference (of the
down; water)
ignore unqualified
temperature
(b) (i) 2
Number Final Temperature
of layers temperature difference in
of in C C
insulation
0 43 42
1 47 38
2 50 35
3 50 35
4 50 35
47 in first answer space;
50 in last three answer spaces; must be seen in
all three spaces
(ii) suitable scale chosen longest bar occupies at ignore orientation 4
least half of the grid;
temperature scale
should be linear
but need not start
at 0
axes labelled correctly with quantities and
temperature difference unit;
all 5 bars correctly plotted;; reject both
plotting marks if a
line graph is
drawn
award 3 marks
max. if graph is
drawn using final
temperature
values instead of
temperature
difference values
(iii) any 2 of: 2
MP1. idea of inverse relationship; allow
pattern
statements
negative
correlation
MP2. idea that each additional layer gives a
smaller decrease in temperature difference;
MP3. idea of no effect on temperature difference
with more than 2 layers;
(iv) repeat AND {average (mean)/discard anomalies}; 1
Total for question = 11 marks
Question
Answer Notes Marks
number
5 (a) conversion of hours to seconds; 3
substitution and rearrangement of equation; no mark for equation
as given in paper
evaluation;
e.g.
time = 40 x 60 x 60 (= 144 000 (s)) seen anywhere in
working
energy = 50 x 144 000
(energy) = 7 200 000 (J) allow 2 000, 120 000
(J) for 2 marks
(b) ignore statements 2
about student being
right/wrong
MP1. energy is wasted / lost (to the allow heat
surroundings) as thermal energy; allow RA e.g. heat is
not useful
MP2. idea that light energy (output) is less e.g. not all electrical
than the electrical / input energy; energy is converted to
light
(c) MP1. two coils of wire; marks can be awarded 3
from diagram if clear
MP2. iron core; allow magnetically
soft core
MP3. more turns (of wire) on the primary coil allow input for primary
than on the secondary coil; and output for
secondary
(d) (i) input power = output power; allow 1
V PI P = V S I S
rearrangements
Use of 1,2 in place of
P,S
(ii) substitution into a correct equation; 3
rearrangement;
evaluation; 0.21 (A) gets 2 marks
only
e.g.
230 x IP = 12 x 4.2
(IP =) 12 x 4.2/230
(IP =) 0.22 (A) allow 0.2, 0.21913
Total for question = 12 marks
Question
Answer Notes Marks
number
6 (a) B energy; 1
(b) (i) (resultant force =) 6750 (N); 1
(ii) (resultant) force = mass x acceleration; allow in standard 1
symbols and
rearrangements
e.g.
F=mxa
(iii) substitution OR rearrangement; allow ecf from 3
(b)(i)
evaluation;
unit; unit mark is
independent
e.g.
acceleration = 6750/2500
(acceleration =) 2.7
m/s2 allow m s-2
(c) any 5 of: allow 5
MP1. there is a resultant force (to the idea that driving
right); force is greater
than air resistance
and friction
MP2. (so) it accelerates (0 to 50 s); the speed/velocity
increases
MP3. air resistance (and friction) increase
as speed increases;
MP4. so acceleration decreases;
MP5. eventually air resistance (+ friction) forces are equal /
= driving force; balanced
MP6. (hence) resultant force is zero (after
50 s);
MP7. (hence) car travels at a constant no acceleration /
speed (after 50 s); terminal velocity
Total for question = 11 marks
Question
Answer Notes Marks
number
7 (a) D newtons per square metre (N/m2); 1
(b) any 3 of: allow particles for 3
molecules
throughout
MP1. air is heated / temperature of air allow pressure is
increases; proportional to
(kelvin)
temperature
MP2. (air) molecules move faster / gain
kinetic energy;
MP3. more (frequent) collisions between
molecules and walls;
MP4. molecules collide with walls with allow molecules
more force; collide harder with
walls
allow rate of
change of
momentum for
force
Total for question = 4 marks
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