CALCULATION NON GRAPH METHOD

1a) The reaction of Na2S2O3 with H2SO4 solution

3Na2S2O3 (aq) + H2SO4 (aq) 3Na2SO4 (aq) + 4S (s) + H2O (l)

a) Determine the concentration of Na2S2O3

- Beaker A - Beaker B
1 1 = 2 2 1 1 = 2 2
0,1 10 = 2 10 0,1 7.5 = 2 10
2 = 0,1 2 = 0,075

-
Beaker C
1 1 = 2 2
0,1 5 = 2 10
2 = 0,05
Volume Volume (mL) Time Turbidity Concentration
H2SO4 (mL) Na2S2O3 H2O Total (second) Na2S2O3 (M)
5 10 - 10 48 +++ 0,1 M
5 7,5 2,5 10 68 ++ 0,075 M
5 5 5 10 102 + 0,005 M

b) Determine the reaction order of Na2S2O3

[] []
=

[2 4 ] [2 2 3 ]
=

0,5 0,1 0,4
= = = 0,0083
39 48
0,50,075 0,425
= = = 0,0063
68 68

0,50,05 0,45
= = = 0,0044
120 102
 Beaker r (M/s) [Na2S2O3] [H2SO4]
A 0,0083 0,1 0,5
B 0,0063 0,075 0,5
C 0,0044 0,05 0,5

1 [2 2 3 ] [2 4 ]
=
2 [2 2 3 ] [2 4 ]

0,0083 0,1
= ( )
0,0063 0,075

1,317 = 1,3

log 1,317
=
log 1,3

= 1,05

= 1

1b) The reaction of Na2S2O3 with H2SO4 solution

3Na2S2O3 (aq) + H2SO4 (aq) 3Na2SO4 (aq) + 4S (s) + H2O (l)

a) Determine the concentration of H2SO4

- Beaker A - Beaker B
1 1 = 2 2 1 1 = 2 2
0,5 10 = 2 10 0,5 7.5 = 2 10
2 = 0,5 2 = 0,375

- Beaker C
1 1 = 2 2
0,5 5 = 2 10
2 = 0,025
Volume Volume (mL) Time Turbidity Concentration
Na2S2O3(mL) H2SO4 H2O Total (second) H2SO4 (M)
5 10 - 10 467 +++ 0,5 M
5 7,5 2,5 10 477 ++ 0,375 M
5 5 5 10 488 + 0,25 M
 b) Determine the reaction order of Na2S2O3
[] []
=

[2 4 ] [2 2 3 ]
=

0,5 0,1 0,4
= = = 0,0009
467 467
0,375 0,1 0,275
= = = 0,0006
477 477
0,25 0,1 0,15
= = = 0,0003
488 488

Beaker r (M/s) [Na2S2O3] [H2SO4]

A 0,0009 0,1 0,5
B 0,0006 0,1 0,375
C 0,0003 0,1 0,25

1 [2 2 3 ] [2 4 ]
=
2 [2 2 3 ] [2 4 ]

0,0009 0,5
= ( )
0,0003 0,375

1,5 = 1,3

log 1,5
=
log 1,3

= 1,28

=1

Total Orde is 1 + 1 = 2
 mol mol
[Na2S2O3] [H2SO4] Log[Na2S2O3] Log[H2SO4] Na2S2O3 H2SO4 mol endapan t r Log r
0.1 0.5 -1 -0.301029996 1 5 0.0013 48 0.0083 -2.07918
0.075 0.5 -1.124938737 -0.301029996 0.75 5 0.001 68 0.0063 -2.20412
0.05 0.5 -1.301029996 -0.301029996 0.5 5 0.00067 102 0.0044 -2.35539
0.1 0.5 -1 -0.301029996 1 5 0.00067 467 0.0009 -3.06726
0.1 0.375 -1 -0.425968732 1 3.75 0.00067 477 0.0006 -3.23919
0.1 0.25 -1 -0.602059991 1 2.5 0.00067 488 0.0003 -3.51233

Order Reaction of Na2S2O3 Order Reaction of H2SO4

y = 0.9137x - 1.1695
-2.05 y = 1.4833x - 2.6158 -3
R = 0.9982
-1.4 -1.2 -1 -0.8 -0.6 -0.4 -0.2 0 -0.7 -0.6 R-0.5
= 0.9989 -0.4 -0.3 -0.2 -0.1 -3.05 0
-2.1
-3.1
-2.15
Log r -3.15
-3.2
-2.2

Log r
-3.25
-2.25 -3.3
-3.35
-2.3 -3.4
-3.45
-2.35
-3.5
-2.4 -3.55
Log [Na2S2O3] Log [H2SO4]
2ndExperiment : 6B The Reaction Of Mg and HCl

a) Non-Graphic Method
Data Label
No. [HCl] t1 t2 r
(second) (second) (second) (1/t)
1 2 17 19 18 0.055556
2 1.8 18 20 19 0.052632
3 1.6 24 26 25 0.04
4 1.4 45,5 48,5 47 0.021277
5 1.2 51 53 52 0.019231
6 1 60 66 63 0.015873
7 0.8 73 79 76 0.013158
8 0.6 98 102 100 0.01

Calculation of Order Reaction

1 1 []
1
= where 1 = 2
2 2 []2
0,05556 1 2
=
0,05263 2 1.8
1.0556= 1,11
=0,52
=1
So based on the non graphic method the reaction order of this experiment
Reaction of Mg and HCl is at order 1
b) Graphic Method
Data Labels :
No. [HCl] Log t1 t2 r Log r
[HCl] (second) (second) (second) (1/t)
1 2 0.30103 17 19 18 0.055556 -1.25527
2 1.8 0.255273 18 20 19 0.052632 -1.27875
3 1.6 0.20412 24 26 25 0.04 -1.39794
4 1.4 0.146128 45,5 48,5 47 0.021277 -1.6721
5 1.2 0.079181 51 53 52 0.019231 -1.716
6 1 0 60 66 63 0.015873 -1.79934
7 0.8 -0.09691 73 79 76 0.013158 -1.88081
8 0.6 -0.22185 98 102 100 0.01 -2

Order Reaction of HCl

0
-0.4 -0.2 0 0.2 0.4
-0.5
Log r

-1
y = 1.4905x - 1.7493
-1.5 R = 0.9128

-2

-2.5
Log [HCl]

So based on the graphic method the reaction order of this experiment

Reaction of Mg and HCl is at order 1