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4.0 Velocity and Discharge of Flow

The document describes calculating the velocity and discharge of flow through a trapezoidal channel using Manning's equation. It provides the channel dimensions, slope, roughness coefficient and calculates the velocity, flow area, wetted perimeter, hydraulic radius, and discharge. The velocity is calculated to be 0.68 m/s and the discharge is calculated to be 0.4 m3/s.

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Nor Syazwani Sharudin
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45 views2 pages

4.0 Velocity and Discharge of Flow

The document describes calculating the velocity and discharge of flow through a trapezoidal channel using Manning's equation. It provides the channel dimensions, slope, roughness coefficient and calculates the velocity, flow area, wetted perimeter, hydraulic radius, and discharge. The velocity is calculated to be 0.68 m/s and the discharge is calculated to be 0.4 m3/s.

Uploaded by

Nor Syazwani Sharudin
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as DOCX, PDF, TXT or read online on Scribd
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4.

0 VELOCITY AND DISCHARGE OF FLOW

0.17m

0.08m 0.08m 0.59m

0.28m

Length = 3 m Top width, T = 0.75m Z=1

Slope = 0.0004 Flow area, A = 0.5881 m2

Perimeter, P = 2.729 m Manning coefficient, n = 0.0015

Flowrate, Q = Velocity of flow, v = max = 0.59

Current water depth = 0.05 time taken = 4.41

2 1
1
= = 3 02

2 1
3 1
= 4.41 0.68 = (0.216)3 02
0.015

1
0.68
= 0.68 1 02 = 1
2
(0.216)3
0.015

0 = (0.283)2

0 = 0.0784
Area 1 = By Area 2 = By + Zy2

= 0.44(0.17) = (0.28)(0.59) + (1)(0.59)2

= 0.0748 m = 0.5133 m

Total area = 0.0748 + 0.5133

= 0.5881 m

Perimeter 1 = B + 2y Perimeter 2 = B + 2y1 +

= 0.44 + 2(0.17) = 0.28 + 2(0.59)1 + 1

= 0.78 m = 1.949 m

Total perimeter = 0.78 + 1.949

= 2.729 m


= =

0.5881
= 0.68 = 0.5881
2.729

= 0.216 m = 0.4 1

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