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0.167 m3/dt 1 M/DT

This document summarizes the calculations to determine the necessary pump specifications for a water pumping system. It calculates the pipe diameter as 0.46m, flow rate as 1 cubic meter per day, and total head of 6 meters. Based on these values and an assumed pump efficiency of 80%, the required pump power is calculated to be 12.287 kilowatts. Regulations specify using a minimum of 3 pumps plus 1 backup for this calculated flow rate of 0.167 cubic meters per second. The remaining pressure at the IPAM is calculated to be 4 meters.

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Hertha Furaida Erlangga
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37 views3 pages

0.167 m3/dt 1 M/DT

This document summarizes the calculations to determine the necessary pump specifications for a water pumping system. It calculates the pipe diameter as 0.46m, flow rate as 1 cubic meter per day, and total head of 6 meters. Based on these values and an assumed pump efficiency of 80%, the required pump power is calculated to be 12.287 kilowatts. Regulations specify using a minimum of 3 pumps plus 1 backup for this calculated flow rate of 0.167 cubic meters per second. The remaining pressure at the IPAM is calculated to be 4 meters.

Uploaded by

Hertha Furaida Erlangga
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
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Pompa

Qpompa = Qaliran = 0.167 m3/dt


 V rencana = 1 m/dt
 Nilai f = 0.02 (kriteria: 0.016 – 0.02)
 Pipa suction =4m
 Pipa discharge = 167 m
𝑄
 A =
𝑉
0.167 m3/dt
=
1 m/dt
= 0.167 m2
4𝐴
D =√
𝜋

4 × 0.167 m²
=√
3.14

= 0.46 m ≈ 18 inch
 Check V 
1
A =4 𝜋 × 𝑟²
1
= 4 3.14 × (0.46 m)²

= 0.166 m2
𝑄
V =
𝐴
0.167 m3/dt
=
0.166 m²
= 1 m/dt ≈ (OK!!)

 Tinggi tekan (Hd) = Tinggi IPAM – Tinggi Intake 
=7m–5 m
=2m
 Mayor Losses 
𝐿 𝑉²
Pipa Suction Hfs =𝑓
𝐷 2𝑔

4m (1 m/dt)²
= 0,02
0.46 m 2 ×9.81

= 0,0088 m3/dt

𝐿 𝑉²
Pipa Discharge Hfd =𝑓
𝐷 2𝑔
167 m (1 m/dt)²
= 0,02
0.46 m 2 ×9.81

= 0,37 m3/dt
 Minor Losses
o Flexible joint 2
 Gate Valve 1
o Check Valve 1
 Bend 90o 1

 Hms = Bend 90o


𝑉²
= (𝐾 × )
2𝑔
(1 m/dt)²
= ( 0,3 × 2 ×9.81
)
= 0,03058 m

 Hmd = (1 Gate Valve) + (1 Check Valve) + (Flexible Joint 2)


𝑉² 𝑉² 𝑉2
=(𝐾 × )+(𝐾 × ) + 2 (𝐾 × )
2𝑔 2𝑔 2𝑔
(1 m/dt)² (1 m/dt)² (1 m/dt)²
= ( 0,2 × 2 ×9.81
) + ( 3,0 × 2 ×9.81
) + 2 (10,0 × 2 ×9.81
)
= 0.0102 m + 0.153 m + 1.019
= 1.182 m

 Tinggi Hisap 
Tinggi muka air max =2m
Tinggi Freeboard = 0.5 m
 Hs = Tinggi Muka Air Maksimum + Tinggi Freeboard
= 2 m + 0.5 m
= 2.5 m
 Ht = Hd + Hfs + Hfd + Hms + Hmd + Hs
= 2m + 0,0088m3/dt + 0,37 m3/dt + 0,03058 m+ 1.182 m + 2.5 m

= 6.09 m
≈6m
Maka, dengan efisiensi Pompa 80% didapat Daya Pompa yaitu:
𝛾 ×𝑔 ×𝑄 ×𝐻𝑡
P =
80%
𝑘𝑔 m³
1000 3 ×9.81 × 0.167 × 6 m
𝑚 dt
P =
80%
= 12287.025 Watt
= 12.287KWatt
Berdasarkan Permen PU No.18 Tahun 2007, jumlah pompa yang digunakan dengan debit
0,167 m3/detik atau 14.429 m3/hari adalah sebanyak 3 pompa ditambah 1 cadangan = 4 pompa.

Tabel 4.22 Jumlah dan Debit Pompa Sistem Transmisi Air Minum
Debit (m3/hari) Jumlah Pompa Total Unit
Sampai 2.800 1 (1) 2
2.500 s.d. 10.000 2 (1) 3
Lebih dari 90.000 Lebih dari 3 (1) Lebih dari 4
Sumber : Peraturan Menteri Pekerjaan Umum No. 18 Tahun 2007

Sisa tekanIPAM = Beda elevasi intake-IPAM – HeadTotal


= 2m–6m
= 4m

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