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Energy Balanc1

The document discusses the energy balance calculation for the cumene peroxidation process. The process involves reacting cumene and oxygen gas to form cumene hydroperoxide. The energy balance equation accounts for the heat absorbed or released in the reactor based on the change in enthalpy of the components flowing in and out of the reactor, and the heat of formation of the reaction. The example calculation shows the enthalpy changes for cumene, oxygen and cumene hydroperoxide at the input and output temperatures, and determines that the overall process absorbs 6710.005 kJ/s of heat.

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0% found this document useful (0 votes)
52 views3 pages

Energy Balanc1

The document discusses the energy balance calculation for the cumene peroxidation process. The process involves reacting cumene and oxygen gas to form cumene hydroperoxide. The energy balance equation accounts for the heat absorbed or released in the reactor based on the change in enthalpy of the components flowing in and out of the reactor, and the heat of formation of the reaction. The example calculation shows the enthalpy changes for cumene, oxygen and cumene hydroperoxide at the input and output temperatures, and determines that the overall process absorbs 6710.005 kJ/s of heat.

Uploaded by

R.d. Poshiya
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
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ENERGY BALANCE

Cumene Peroxidation Process is the process where the raw material, cumene and oxygen gas that
is 100% purity is react. The product form is cumene hydroperoxide. The calculation of the energy
balance is done in the first reactor.

C6H5CH(CH3)2 (l) + O2 (g) C6H5C (CH3)2OOH (l)

Cp= A + BT + CT2 + DT3(J/mol.K)

Coefficient of Heat Capacity for the Components

A B C D
C6H5CH(CH3)2 139.2×10-3 53.76×10-5 -39.79×10-8 120.5×10-12
O2 29.1×10-3 1.158×10-5 -0.6706×10-8 1.311×10-12
C6H5C 1.345×105 3.8060×102 - -
(CH3)2OOH

Equation for Energy Balance:

Q = ΔHout - ΔHin + rΔHof

Where,

Q = Heat absorbed or heat released in the reactor

ΔHout = Change of enthalpy in the system out

ΔHin = Change of enthalpy in the system in

r = Rate of reaction

ΔHof = Heat of formation at 298.15 K

Enthalpy change for the component

ΔH = 2 1 T T pdT C@@@@

@@@@@

where,

T1 = Reference Temperature (298.15 K)

T2 = Input / Output Temperature


Enthalpy change for the inflow,

T1 = 110oC = 383.15 K

For Cumene:-

@@@@@

For Oxygen:
@@@@@

Enthalphy change for outflow,

T2 = 115oC = 388.15 K

For Cumene Hydroperoxide,

For Cumene:-@@@@@

For Oxygen:
@@@@@

For overall enthalpy at inflow, ΔHin,


@@

For overall enthalpy at outflow,


ΔHin,
ΔHout= (ΔHoCumene Hydroperoxide × NoCumene hydroperoxide ) + (ΔHoCumene × NiCumene ) + (ΔHoOxygen ×
NiOxygen)

= (23859.2601kJ/kmol × 613330 mol/h) + (25.336 kJ/mol × 367998 mol/h) + (2.917 kJ/mol ×


61333 mol/h) = 9503960.298 kJ/h

For Heat of formation,

Hof Hof = ΣΔHofproduct - Σ ΔHofreactant

= [-149.67kJ/mol] – [ (-41.1kJ/mol) + 0 kJ/mol]

= -108.57kJ/mol
From the overall energy balance equation,

Q = ΔHout - ΔHin + rΔHo

f= 69753.978kJ/h – 66.011kJ/h + (184000 mol/h × -108.57kJ/mol)

= -24156019.02 kJ/hr

= 24156019.02 kJ/h × (1h/3600s)

= -6710.005 kJ/s

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