ENERGY BALANCE
Cumene Peroxidation Process is the process where the raw material, cumene and oxygen gas that
is 100% purity is react. The product form is cumene hydroperoxide. The calculation of the energy
balance is done in the first reactor.
C6H5CH(CH3)2 (l) + O2 (g) C6H5C (CH3)2OOH (l)
Cp= A + BT + CT2 + DT3(J/mol.K)
Coefficient of Heat Capacity for the Components
A B C D
C6H5CH(CH3)2 139.2×10-3 53.76×10-5 -39.79×10-8 120.5×10-12
O2 29.1×10-3 1.158×10-5 -0.6706×10-8 1.311×10-12
C6H5C 1.345×105 3.8060×102 - -
(CH3)2OOH
Equation for Energy Balance:
Q = ΔHout - ΔHin + rΔHof
Where,
Q = Heat absorbed or heat released in the reactor
ΔHout = Change of enthalpy in the system out
ΔHin = Change of enthalpy in the system in
r = Rate of reaction
ΔHof = Heat of formation at 298.15 K
Enthalpy change for the component
ΔH = 2 1 T T pdT C@@@@
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where,
T1 = Reference Temperature (298.15 K)
T2 = Input / Output Temperature
Enthalpy change for the inflow,
T1 = 110oC = 383.15 K
For Cumene:-
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For Oxygen:
@@@@@
Enthalphy change for outflow,
T2 = 115oC = 388.15 K
For Cumene Hydroperoxide,
For Cumene:-@@@@@
For Oxygen:
@@@@@
For overall enthalpy at inflow, ΔHin,
@@
For overall enthalpy at outflow,
ΔHin,
ΔHout= (ΔHoCumene Hydroperoxide × NoCumene hydroperoxide ) + (ΔHoCumene × NiCumene ) + (ΔHoOxygen ×
NiOxygen)
= (23859.2601kJ/kmol × 613330 mol/h) + (25.336 kJ/mol × 367998 mol/h) + (2.917 kJ/mol ×
61333 mol/h) = 9503960.298 kJ/h
For Heat of formation,
Hof Hof = ΣΔHofproduct - Σ ΔHofreactant
= [-149.67kJ/mol] – [ (-41.1kJ/mol) + 0 kJ/mol]
= -108.57kJ/mol
From the overall energy balance equation,
Q = ΔHout - ΔHin + rΔHo
f= 69753.978kJ/h – 66.011kJ/h + (184000 mol/h × -108.57kJ/mol)
= -24156019.02 kJ/hr
= 24156019.02 kJ/h × (1h/3600s)
= -6710.005 kJ/s