Fold on dotted lines

Chemistry!
n=!grams
N=
equ
KE = m v
1
q = ΔH 2 2

! MM volume of solution
2
Max # of electrons = 2n
A A A

MM ! • 100 m = moles of solute rate = MM Dipole Moment = q ⋅ d ΔG = ΔH - TΔS

MM!
A B
% = A
A
kilogram of solvent rate
! Total MM
ΔT = k mi
B
ΔG = -nFE
A
f f

= !ratio of n
% moles of solute
A
x= PV = nRT ΔT = k mi
!
A b b
1 MM A total moles of solution c d
[C] [D] ⎛ - EA ⎞

6.022 × 10! things = 1 mol

K = ⎜⎝
RT ⎠
⎟
23
ppm = x × 10 P =P +P +P 6 k = Ae [A] [B]
eq a b

! total 1 2 n

M =
moles ! of solute
% Yield =
A Yield
× 100
%n
=
n
=
P Rate = k [B]
1 1
pH = pK + log ⎜
⎛ A ⎞
⎝ HA ⎟⎠
1
n -

volume! of soln T Yield 100 n P

q = MCΔT
total total
a

M V != M V
!
1 1 2 2

Physics!
distance!( ) s + sf Friction = F i µ
c=λf L g Fout Dv2
! ( ) Friction ≤ F i µ π ω
K N K
s= = o T=2 = MA = c = P + Dgy +
Δ time 2 g L Fin 2
!
S N s
Δ displacement v + vf 2 2 f =|f -f | beat 1 2 Stress
v= = o mv v ΔL = α L ΔT W YM =
! ( ) F =Workr = Fa i=d r ΔA = γ A ΔT dB = 10 log ⎛⎜⎝ II ⎞⎟⎠
Δ time 2 c
o E = out
Win
q
Strain
q
a=
Δ time!
Δ velocity
= o
a + af
2 ΔV = β V ΔT Q=ADv=c
o
o
E=k 2 V=k
r r
v = v +!
Energy o
F = qE
at ΔE = W P= Dsubstance E

v = v + !2aΔx
f o K time SG =
work Work = qEΔx
D water
2 2 P = =F v Power
f
!
Δx = v t + .5 at
o
F = -kΔx time
average
I =
SA
net

DL SG=
% below water

!
2
100
o R=
p = mv 2 Δf v Δλ v A
∑ F =0 ∑! Work = .5 kΔx
F = ma
p =p f
=
c λ
=
c
F =D V g
F = qvB = BIL
B liquid object

!
s s
final initial
Gm m m k
T = 2π ω = τ = ( F sin θ ) r
F
i = Δp = Ft
!!r
1 2
F = g 2 k m P=I R P=
A
P = Dgy 2

Organic Chemistry!
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