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SLAB2

This document provides the design parameters and calculations for a reinforced concrete slab for the Indochina Plaza project in Ha Noi, Vietnam. The slab thickness is 200mm with 30mm concrete cover. Design loads include a dead load of 3.5kPa and live load of 2kPa. Reinforcing steel yield strength is 390MPa. Calculations determine the required reinforcement as 2 bars of 12mm diameter spaced at 500mm to resist the design moment of 12.47kNm from a service load of 13.4kN/m2.

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Safi Zabihullah Safi
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94 views1 page

SLAB2

This document provides the design parameters and calculations for a reinforced concrete slab for the Indochina Plaza project in Ha Noi, Vietnam. The slab thickness is 200mm with 30mm concrete cover. Design loads include a dead load of 3.5kPa and live load of 2kPa. Reinforcing steel yield strength is 390MPa. Calculations determine the required reinforcement as 2 bars of 12mm diameter spaced at 500mm to resist the design moment of 12.47kNm from a service load of 13.4kN/m2.

Uploaded by

Safi Zabihullah Safi
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
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Download as PDF, TXT or read online on Scribd
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Client: Indochina Land Date: 6/10/2008

Project/Job: Indochina Plaza, Ha Noi Job No: H016 Sheet No: A - 2


Subject: Design slab based on ACI - 318 By: Linh vu

Thickness = 200 mm
Cover = 30 mm
Imposed DL = 3.5 KPa
Imposed LL = 2 KPa
Concrete f'c = 28 Mpa
Steel fy = 390 Mpa
Ly = 8.5 m
Lx = 3.05 m
Ln(y) = 8.5 m
Ln(x) = 3.05 m

1. Area, gridline
Ly
 2.8 ---> one - way slab
Lx
2. Self weight, slab
= 5 kN/m2

3. Total design load


Wu = 1.2 DL + 1.6LL
= 13.4 kN/m2

Consider design with salb width 1000mm


Wu = 13.4 kN/m

4. Moment Mu for support ( at edge span )


Wu  l 2
Mu   12.47 kNm
10
5. Concrete depth, d
 bar
d = Slab - cover -
= 164 mm 2
bar = 12 mm

6. Determine moment from force couple


Moment arm
Jd = d - a/2
Opposition a = 10 mm
Jd = 159 mm
Mu
As  = 223.44 mm2
0.9  f y  jd

7. Required reinforcement
As = 223.44 mm2
Take rebar size = 12 mm

Total area
  d2 = 113
4
Total rebar = 2
Spacing = 500 mm
Check a
As  f y As
a = 3.7 mm the opposition a = 10 mm  100%
b  jd
0.85  f c  b
Rebar 12 mm @ 150 mm c/c As = 753.33 mm2 0.47
(%)

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