CONSTRUCTION OF TWO STOREY RESIDENTIAL BUILDING (SOFT STOREY AT GROUND FLOOR)
DESIGN OF FOOTING
Isolated Footing 54
Input Values
Footing Geomtery
Design Type : Calculate Dimension
Footing Thickness (Ft) : 300.000 mm
Footing Length - X (Fl) : 1400.000 mm
PREPARED BY : ENGR CAREN HAZEL ORTIZ
CONSTRUCTION OF TWO STOREY RESIDENTIAL BUILDING (SOFT STOREY AT GROUND FLOOR)
DESIGN OF FOOTING
Footing Width - Z (Fw) : 1400.000 mm
Eccentricity along X (Oxd) : 50.000 mm
Eccentricity along Z (Ozd) : 0.000 mm
Column Dimensions
Column Shape : Rectangular
Column Length - X (Pl) : 0.350 m
Column Width - Z (Pw) : 0.300 m
Design Parameters
Concrete and Rebar Properties
Unit Weight of Concrete : 23.000 kN/m3
Strength of Concrete : 20.700 N/mm2
Yield Strength of Steel : 248.000 N/mm2
Minimum Bar Size : #16
Maximum Bar Size : #32
Minimum Bar Spacing : 200.000 mm
Maximum Bar Spacing : 300.000 mm
Pedestal Clear Cover (P, CL) : 50.000 mm
Footing Clear Cover (F, CL) : 50.000 mm
Soil Properties
Soil Type : Drained
Unit Weight : 22.000 kN/m3
Soil Bearing Capacity : 100.000 kN/m2
Soil Surcharge : 0.000 kN/m2
Depth of Soil above Footing : 0.000 mm
Cohesion : 0.000 kN/m2
Sliding and Overturning
Coefficient of Friction : 0.500
Factor of Safety Against Sliding : 1.500
Factor of Safety Against Overturning : 1.500
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PREPARED BY : ENGR CAREN HAZEL ORTIZ
CONSTRUCTION OF TWO STOREY RESIDENTIAL BUILDING (SOFT STOREY AT GROUND FLOOR)
DESIGN OF FOOTING
Design Calculations
Footing Size
Initial Length (Lo) = 1.400 m
Initial Width (Wo) = 1.400 m
Load Combination/s- Service Stress Level
Load Combination
Load Combination Title
Number
3 DL + LL
Load Combination/s- Strength Level
Load Combination
Load Combination Title
Number
3 DL + LL
Applied Loads - Service Stress Level
Axial Shear X Shear Z Moment X Moment Z
LC
(kN) (kN) (kN) (kNm) (kNm)
3 80.175 0.112 -2.103 -1.158 -4.091
Applied Loads - Strength Level
Axial Shear X Shear Z Moment X Moment Z
LC
(kN) (kN) (kN) (kNm) (kNm)
3 80.175 0.112 -2.103 -1.158 -4.091
Reduction of force due to buoyancy = 0.000 kN
Effect due to adhesion = 0.000 kN
Area from initial length and width, Ao =Lo X Wo = 1.960 m2
Min. area required from bearing pressure, Amin =P / qmax = 0.937 m2
Note: Amin is an initial estimation.
P = Critical Factored Axial Load(without self weight/buoyancy/so
qmax = Respective Factored Bearing Capacity.
PREPARED BY : ENGR CAREN HAZEL ORTIZ
CONSTRUCTION OF TWO STOREY RESIDENTIAL BUILDING (SOFT STOREY AT GROUND FLOOR)
DESIGN OF FOOTING
Final Footing Size
Length (L2) = 1.400 m Governing Load Case : #3
Width (W2) = 1.400 m Governing Load Case : #3
Depth (D2) = 0.300 m Governing Load Case : #3
Area (A2) = 1.960 m 2
Pressures at Four Corners
Pressure at Pressure at Pressure at Pressure at Area of footing
Load Case corner 1 (q1) corner 2 (q2) corner 3 (q3) corner 4 (q4) in uplift (Au)
(kN/m2) (kN/m2) (kN/m2) (kN/m2) (m2)
3 42.6976 60.7373 52.9136 34.8739 0.000
3 42.6976 60.7373 52.9136 34.8739 0.000
3 42.6976 60.7373 52.9136 34.8739 0.000
3 42.6976 60.7373 52.9136 34.8739 0.000
If Au is zero, there is no uplift and no pressure adjustment is necessary. Otherwise, to account for
uplift, areas of negative pressure will be set to zero and the pressure will be redistributed to
remaining corners.
Summary of Adjusted Pressures at 4 corners Four Corners
Pressure at Pressure at Pressure at Pressure at
corner 1 (q1) corner 2 (q2) corner 3 (q3) corner 4 (q4)
Load Case (kN/m2) (kN/m2) (kN/m2) (kN/m2)
3 42.6976 60.7373 52.9136 34.8739
3 42.6976 60.7373 52.9136 34.8739
3 42.6976 60.7373 52.9136 34.8739
PREPARED BY : ENGR CAREN HAZEL ORTIZ
CONSTRUCTION OF TWO STOREY RESIDENTIAL BUILDING (SOFT STOREY AT GROUND FLOOR)
DESIGN OF FOOTING
3 42.6976 60.7373 52.9136 34.8739
Check for stability against overturning and sliding
Factor of safety against Factor of safety against
-
sliding overturning
Load
Along X- Along Z- About X- About Z-
Case
Direction Direction Direction Direction
No.
3 416.986 22.282 36.662 14.928
Critical Load Case And The Governing Factor Of Safety For Overturning And Sliding - X
Direction
Critical Load Case for Sliding along X-Direction : 3
Governing Disturbing Force : 0.112 kN
Governing Restoring Force : 46.849 kN
Minimum Sliding Ratio for the Critical Load Case : 416.986
Critical Load Case for Overturning about X-Direction : 3
Governing Overturning Moment : -1.789 kNm
Governing Resisting Moment : 65.588 kNm
Minimum Overturning Ratio for the Critical Load Case : 36.662
Critical Load Case And The Governing Factor Of Safety For Overturning And Sliding - Z
Direction
PREPARED BY : ENGR CAREN HAZEL ORTIZ
CONSTRUCTION OF TWO STOREY RESIDENTIAL BUILDING (SOFT STOREY AT GROUND FLOOR)
DESIGN OF FOOTING
Critical Load Case for Sliding along Z-Direction : 3
Governing Disturbing Force : -2.103 kN
Governing Restoring Force : 46.849 kN
Minimum Sliding Ratio for the Critical Load Case : 22.282
Critical Load Case for Overturning about Z-Direction : 3
Governing Overturning Moment : -4.125 kNm
Governing Resisting Moment : 61.579 kNm
Minimum Overturning Ratio for the Critical Load Case : 14.928
Shear Calculation
Punching Shear Check
Total Footing Depth, D = 0.300m
Calculated Effective Depth, deff = D - Ccover - 1.0 = 0.225 m
For rectangular column, = Bcol / Dcol = 1.167
Effective depth, deff, increased until 0.75XVc Punching Shear Force
Punching Shear Force, Vu = 67.845 kN, Load Case # 3
From ACI Cl.11.12.2.1, bo for column= 2.198 m
Equation 11-33, Vc1 = 1012.619 kN
Equation 11-34, Vc2 = 1135.367 kN
Equation 11-35, Vc3 = 746.141 kN
PREPARED BY : ENGR CAREN HAZEL ORTIZ
CONSTRUCTION OF TWO STOREY RESIDENTIAL BUILDING (SOFT STOREY AT GROUND FLOOR)
DESIGN OF FOOTING
Punching shear strength, Vc = 0.75 X minimum of (Vc1, Vc2, Vc3) = 559.605 kN
0.75 X Vc > Vu hence, OK
Along X Direction
(Shear Plane Parallel to Global X Axis)
From ACI Cl.11.3.1.1, Vc = 237.581 kN
Distance along X to design for shear,
0.325 m
Dx =
Check that 0.75 X Vc > Vux where Vux is the shear force for the critical load cases at a distance deff
from the face of the column caused by bending about the X axis.
From above calculations, 0.75 X Vc = 178.186 kN
Critical load case for Vux is # 3 20.003 kN
0.75 X Vc > Vux hence, OK
One-Way Shear Check
Along Z Direction
(Shear Plane Parallel to Global Z Axis)
PREPARED BY : ENGR CAREN HAZEL ORTIZ
CONSTRUCTION OF TWO STOREY RESIDENTIAL BUILDING (SOFT STOREY AT GROUND FLOOR)
DESIGN OF FOOTING
From ACI Cl.11.3.1.1, Vc = 237.581 kN
Distance along X to design for shear, Dz = 1.150 m
Check that 0.75 X Vc > Vuz where Vuz is the shear force for the critical load cases at a distance
deff from the face of the column caused by bending about the Z axis.
From above calculations, 0.75 X Vc = 178.186 kN
Critical load case for Vuz is # 3 16.936 kN
0.75 X Vc > Vuz hence, OK
Design for Flexure about Z Axis
(For Reinforcement Parallel to X Axis)
PREPARED BY : ENGR CAREN HAZEL ORTIZ
CONSTRUCTION OF TWO STOREY RESIDENTIAL BUILDING (SOFT STOREY AT GROUND FLOOR)
DESIGN OF FOOTING
Calculate the flexural reinforcement along the X direction of the footing. Find the area of steel
required, A, as per Section 3.8 of Reinforced Concrete Design (5th ed.) by Salmon and Wang (Ref.
1)
Critical Load Case # 3
The strength values of steel and concrete used in the formulae are in ksi
Factor from ACI Cl.10.2.7.3 = 0.850
From ACI Cl. 10.3.2, = 0.04267
From ACI Cl. 10.3.3, = 0.03200
From ACI Cl. 7.12.2, = 0.00140
From Ref. 1, Eq. 3.8.4a, constant m = 14.095
Calculate reinforcement ratio for critical load case
Design for flexure about Z axis is
performed at the face of the column at a 0.575 m
distance, Dx =
Ultimate moment, 7.952 kNm
Nominal moment capacity, Mn = 8.835 kNm
Required = 0.00051
Since OK
Area of Steel Required, As = 440.216 mm2
Selected bar Size = #16
Minimum spacing allowed (Smin) = = 200.000 mm
Selected spacing (S) = 300.000 mm
Smin <= S <= Smax and selected bar size < selected maximum bar size...
The reinforcement is accepted.
According to ACI 318-05 Clause No- 10.6.4
Max spacing for Cracking Consideration = 508.433 mm
Safe for Cracking Aspect.
PREPARED BY : ENGR CAREN HAZEL ORTIZ
CONSTRUCTION OF TWO STOREY RESIDENTIAL BUILDING (SOFT STOREY AT GROUND FLOOR)
DESIGN OF FOOTING
Based on spacing reinforcement increment; provided reinforcement is
#16 @ 7620.000 mm o.c.
Required development length for bars = =0.305 m
Available development length for bars, DL = 0.475 m
Try bar size # 16 Area of one bar = 201.064 mm2
Number of bars required, Nbar = 5
Because the number of bars is rounded up, make sure new reinforcement ratio < ρmax
Total reinforcement area, As_total = Nbar X (Area of one bar) = 1005.321 mm2
deff = D - Ccover - 0.5 X (dia. of one bar) = 0.242 m
Reinforcement ratio, = 0.00297
From ACI Cl.7.6.1, minimum req'd clear max (Diameter of one bar, 1.0, Min. 300.000 mm
distance between bars, Cd = User Spacing) =
Check to see if width is sufficient to accomodate bars
Design for Flexure about X axis
(For Reinforcement Parallel to Z Axis)
PREPARED BY : ENGR CAREN HAZEL ORTIZ
CONSTRUCTION OF TWO STOREY RESIDENTIAL BUILDING (SOFT STOREY AT GROUND FLOOR)
DESIGN OF FOOTING
Calculate the flexural reinforcement along the Z direction of the footing. Find the area of steel
required, A, as per Section 3.8 of Reinforced Concrete Design (5th ed.) by Salmon and Wang (Ref.
1)
Critical Load Case # 3
The strength values of steel and concrete used in the formulae are in ksi
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PREPARED BY : ENGR CAREN HAZEL ORTIZ
CONSTRUCTION OF TWO STOREY RESIDENTIAL BUILDING (SOFT STOREY AT GROUND FLOOR)
DESIGN OF FOOTING
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PREPARED BY : ENGR CAREN HAZEL ORTIZ
CONSTRUCTION OF TWO STOREY RESIDENTIAL BUILDING (SOFT STOREY AT GROUND FLOOR)
DESIGN OF FOOTING
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PREPARED BY : ENGR CAREN HAZEL ORTIZ
CONSTRUCTION OF TWO STOREY RESIDENTIAL BUILDING (SOFT STOREY AT GROUND FLOOR)
DESIGN OF FOOTING
Selected Bar Size = #16
Minimum spacing allowed (Smin) = 200.000 mm
Selected spacing (S) = 300.000 mm
Smin <= S <= Smax and selected bar size < selected maximum bar size...
The reinforcement is accepted.
According to ACI 318-05 Clause No- 10.6.4
Max spacing for Cracking Consideration = 508.433 mm
Safe for Cracking Aspect.
Based on spacing reinforcement increment; provided reinforcement is
#16 @ 7620.000 mm o.c.
Required development length for bars = =0.305 m
Available development length for bars, DL = 0.500 m
Try bar size # 16 Area of one bar = 201.064 mm2
Number of bars required, Nbar = 5
Because the number of bars is rounded up, make sure new reinforcement ratio < ρmax
Total reinforcement area, As_total = Nbar X (Area of one bar) = 1005.321 mm2
deff = D - Ccover - 0.5 X (dia. of one bar) = 0.218 m
Reinforcement ratio, = 0.00329
From ACI Cl.7.6.1, minimum req'd clear max (Diameter of one bar, 1.0, Min. 300.000 mm
distance between bars, Cd = User Spacing) =
Check to see if width is sufficient to accomodate bars
Bending moment for uplift cases will be calculated based solely on selfweight, soil depth and
surcharge loading.
As the footing size has already been determined based on all servicebility load cases, and design
moment calculation is based on selfweight, soil depth and surcharge only, top reinforcement value
for all pure uplift load cases will be the same.
PREPARED BY : ENGR CAREN HAZEL ORTIZ
CONSTRUCTION OF TWO STOREY RESIDENTIAL BUILDING (SOFT STOREY AT GROUND FLOOR)
DESIGN OF FOOTING
Design For Top Reinforcement Parallel to Z Axis
Calculate the flexural reinforcement for Mx. Find the area of steel required
The strength values of steel and concrete used in the formulae are in ksi
Factor from ACI Cl.10.2.7.3 = 0.850
From ACI Cl. 10.3.2, = 0.04267
From ACI Cl. 10.3.3, = 0.03200
From ACI Cl. 7.12.2, = 0.00140
From Ref. 1, Eq. 3.8.4a, constant m = 14.095
Calculate reinforcement ratio for critical load case
Design for flexure about A axis is
performed at the face of the column at 0.550 m
a distance, Dx =
Ultimate moment, 1.461 kNm
Nominal moment capacity, Mn = 1.623 kNm
Required = 0.00011
PREPARED BY : ENGR CAREN HAZEL ORTIZ
CONSTRUCTION OF TWO STOREY RESIDENTIAL BUILDING (SOFT STOREY AT GROUND FLOOR)
DESIGN OF FOOTING
Since OK
Area of Steel Required, As = 408.856 mm2
Selected bar Size = #16
Minimum spacing allowed (Smin) = 200.000 mm
Selected spacing (S) = 300.000 mm
Smin <= S <= Smax and selected bar size < selected maximum bar size...
The reinforcement is accepted.
According to ACI 318-05 Clause No- 10.6.4
Max spacing for Cracking Consideration = 508.433 mm
Safe for Cracking Aspect.
Based on spacing reinforcement increment; provided reinforcement is
#16 @ 300 mm o.c.
Design For Top Reinforcement Parallel to X Axis
First load case to be in pure uplift #
Calculate the flexural reinforcement for Mz. Find the area of steel required
The strength values of steel and concrete used in the formulae are in ksi
Factor from ACI Cl.10.2.7.3 = 0.850
PREPARED BY : ENGR CAREN HAZEL ORTIZ
CONSTRUCTION OF TWO STOREY RESIDENTIAL BUILDING (SOFT STOREY AT GROUND FLOOR)
DESIGN OF FOOTING
From ACI Cl. 10.3.2, = 0.04267
From ACI Cl. 10.3.3, = 0.03200
From ACI Cl.7.12.2, = 0.00140
From Ref. 1, Eq. 3.8.4a, constant m = 14.095
Calculate reinforcement ratio for critical load case
Design for flexure about A axis is
performed at the face of the column at 0.575 m
a distance, Dx =
Ultimate moment, 1.597 kNm
Nominal moment capacity, Mn = 1.774 kNm
Required = 0.00010
Since OK
Area of Steel Required, As = 440.216 mm2
Selected bar Size = #16
Minimum spacing allowed (Smin) = 200.000 mm
Selected spacing (S) = 300.000 mm
Smin <= S <= Smax and selected bar size < selected maximum bar size...
The reinforcement is accepted.
According to ACI 318-05 Clause No- 10.6.4
Max spacing for Cracking Consideration = 508.433 mm
Safe for Cracking Aspect.
Based on spacing reinforcement increment; provided reinforcement is
#16 @ 300 mm o.c.
PREPARED BY : ENGR CAREN HAZEL ORTIZ