OTHER TREATMENT PROCESSES
Other processes include:
Septic tank
Imhoff tank
Ponds
Lagoons
Ditches
TREAT SEWAGE SO THAT IT IS MADE HARMLESS.
SEPTIC TANK
Process:
Horizontal continuous flow bed tank (with longer
detention time)
Extended sedimentation tank
12-36 hours detention
Closed tank – Anaerobic decomposition of settled
sludge
Three purposes
Sedimentation
Digestion tank
Storage of digested sludge
Digestion - Evolution of gases – gas vent
Cleaning/ Removing digested sludge – once in a year (6 months to 2
years)
Thus Two processes-Sedimentation and Anaerobic Sludge digestion
Construction details:
Long, continuous flow tank of RCC and sides water proof.
Facility for gas vent through vent pipe.
Bottom (slope) to facilitate pumping of sludge.
Manhole with for removal of sludge
Inlet and outlet,Tee’s will be provided
Sometimes baffles to reduce disturbances.
Septage:
Effluent from septic tank disposal
Soak pit/ Cess pool
A closed circular or rectangular pit through which effluent
will be soaked or absorbed into the surrounding soil
Two- Filled or Empty type
Under drain /absorption /dispersion trenches.
3-4 distributions@2m spacing, L shall not be more than30cm
Design criteria(Septic Tank):
Quantity of sludge -30 l/capita/ years - Sludge storage
Depth - 1.2 – 1.8 m
Length: Breadth - 2-4 times
Min width - 120cm
Outlet ~ in let level difference = 5-7.5 or up to 15 cm
Detention time = 24 hours
Free board: 30cm
Design criteria for absorption system:
Calculation of Total subsurface soil area required for soak pits/
dispersion trenches
Lq = 130/√t
t- standard percolation rate for the soil min/cm
Lq-Maximum rate of effluent application in Lpd/m2 of
leaching surface
Total trench area required = Total flow per day/ Lq
COMPONENTS OF A SEPTIC SYSTEM
Distribution Box
Septic Tank
Leach Line
Problem:
Design a septic tank for the hostels of the Engineering
college:
Number of Hostels = 3
Students / Hostel = 200
Water supply = 120 lpcd
Assume Detention period 24 hours and
Sludge volume = 30l/cap/year
Solution:
Design for one hostel:
Waste water = 200x120x80/100 = 19.2 m3
Let us assume that sludge withdrawal once in a year
Volume required for sludge storage for one year
= 200x30
= 6000l= 6m3
Capacity of septic tank = 25.2 m3
Assuming a depth of 1.8 m , Area = 25.2/1.8=14 m2
3B2 = 14m2,
B2 = 14/3,
B = 2.16 say 2.20m
Length = 6.60m
Dimension = 6.6x2.2x2.1m (1.8m+0.3m free board)
26.16m3 > 25.2 m3
Assuming 1.5m depth, Area = 16.8 m2
3B2= 16.8, B= 2.36 say 2.4 m
Provide 7.2x2.4x1.8m septic tank
Design of absorption system:
Lq = 130/√t
Say t=20min/cm
Lq = 130√20 = 29lpd/m2
Area required = 200x120x0.8/29 =
662m2
L = 30m
W=1m
TREAT SEWAGE SO THAT IT IS MADE HARMLESS.
DISPOSE OF SEWAGE (MAKE IT GO AWAY)