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For Example: Qty of Earth Work 9,60,000 Cum. % OMC 12.5 After Soil Test % OMC Comes As Per Laboratory Test 8 To 9% (Say 8.9 %)

The document describes a formula to calculate the amount of water required for soil compaction during earthwork projects. The formula uses variables like desired dry density, desired and actual moisture content percentages, compacted soil volume, and a conversion factor. An example calculation is provided to demonstrate how the formula is applied using project-specific values for soil quantity, optimum and actual moisture contents to determine the total water needed, including an addition for evaporation losses.

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HegdeVenugopal
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0% found this document useful (0 votes)
664 views1 page

For Example: Qty of Earth Work 9,60,000 Cum. % OMC 12.5 After Soil Test % OMC Comes As Per Laboratory Test 8 To 9% (Say 8.9 %)

The document describes a formula to calculate the amount of water required for soil compaction during earthwork projects. The formula uses variables like desired dry density, desired and actual moisture content percentages, compacted soil volume, and a conversion factor. An example calculation is provided to demonstrate how the formula is applied using project-specific values for soil quantity, optimum and actual moisture contents to determine the total water needed, including an addition for evaporation losses.

Uploaded by

HegdeVenugopal
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as PDF, TXT or read online on Scribd
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𝑨𝒎𝒐𝒖𝒏𝒕 𝒐𝒇 𝑾𝒂𝒕𝒆𝒓 𝑹𝒆𝒒𝒖𝒊𝒓𝒆𝒅 𝒊𝒏 𝑳𝒊𝒕𝒓𝒆𝒔 ∶

= {[𝐷𝑒𝑠𝑖𝑟𝑒𝑑 𝑑𝑟𝑦 𝑑𝑒𝑛𝑠𝑖𝑡𝑦 𝑜𝑓 𝑆𝑜𝑖𝑙 𝑴𝑫𝑫 𝑖𝑛 𝑡𝑜𝑛𝑒𝑠 𝑝𝑒𝑟 𝑚3 ]


𝐷𝑒𝑠𝑖𝑟𝑒𝑑 𝑶𝑴𝑪 % − 𝐴𝑐𝑡𝑢𝑎𝑙 𝑭𝑴𝑪 %
× [ ]
𝟏𝟎𝟎
× [𝐶𝑜𝑚𝑝𝑎𝑐𝑡𝑒𝑑 𝑉𝑜𝑙𝑢𝑚𝑒 𝑜𝑓 𝑆𝑜𝑖𝑙 𝑸𝒖𝒂𝒏𝒕𝒊𝒕𝒚 𝑖𝑛 𝑚3 ]
× 𝟏𝟎𝟎𝟎 𝑙𝑖𝑡𝑟𝑒𝑠/𝑚3 }

∴ 𝑨𝒎𝒐𝒖𝒏𝒕 𝒐𝒇 𝑾𝒂𝒕𝒆𝒓 𝑹𝒆𝒒𝒖𝒊𝒓𝒆𝒅 𝒊𝒏 𝑳𝒊𝒕𝒓𝒆𝒔 ∶


3]
𝑶𝑴𝑪 % − 𝑭𝑴𝑪 %
[
= { 𝑴𝑫𝑫 𝑖𝑛 𝑡𝑜𝑛𝑒𝑠 𝑝𝑒𝑟 𝑚 × [ ]
𝟏𝟎𝟎
× [𝑸𝒖𝒂𝒏𝒕𝒊𝒕𝒚 𝑖𝑛 𝑚3 ] × 𝟏𝟎𝟎𝟎 𝑙𝑖𝑡𝑟𝑒𝑠/𝑚3 }

For Example:

Qty of earth work = 9,60,000 cum.


% OMC = 12.5
After soil test % OMC comes as per laboratory test = 8 to 9% ( say 8.9 %).

So OMC now = 12.5 - 8.9 = 3.6 % ( usually Depending on the soil type, an in-situ
moisture content deviating 2% to 4% from the optimum moisture content as
determined from the Proctor test, may create impossible conditions to achieve the
required compaction).i.e 3.6 % is ok.

Now, Qty = 9,60,000 x 3.6/100 = 34560 cum or 34560000 lit water required.

Now add evaporation losses @ 10%.

So, now the exact volume of water required for compaction of earth work is
3,80,16,000 lit.

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