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Click Here To See ALL Problems On Exponential-And-Logarithmic-Functions

The document provides an answer to finding the value of the exponent x in the equation 2^x = 66. It explains that you can take the log of both sides, which results in x*log(2) = log(66). Isolating x gives the solution x = log(66)/log(2), which evaluates to approximately 6.0444.

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96 views1 page

Click Here To See ALL Problems On Exponential-And-Logarithmic-Functions

The document provides an answer to finding the value of the exponent x in the equation 2^x = 66. It explains that you can take the log of both sides, which results in x*log(2) = log(66). Isolating x gives the solution x = log(66)/log(2), which evaluates to approximately 6.0444.

Uploaded by

Tai Pan
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
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 Click here to see ALL problems on Exponential-and-logarithmic-functions

Question 417496: Is there a way to find the value of the exponent in the 2^x = 66
mathematically?

Answer by stanbon(64236) (Show Source):


You can put this solution on YOUR website!
Is there a way to find the value of the exponent in the 2^x = 66
mathematically?
----
You get a variable value out of the exponent by taking the log.
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log(2^x) = log(66)
x*log(2) = log(66)
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x = log(66)/log(2)
---
x = 6.0444

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