Prof.
Alexandru Suciu
MATH 3175                            Group Theory                                Fall 2010
                              The dihedral groups
The general setup. The dihedral group Dn is the group of symmetries of a regular
polygon with n vertices. We think of this polygon as having vertices on the unit circle,
with vertices labeled 0, 1, . . . , n − 1 starting at (1, 0) and proceeding counterclockwise
at angles in multiples of 360/n degrees, that is, 2π/n radians.
   There are two types of symmetries of the n-gon, each one giving rise to n elements
in the group Dn :
     • Rotations R0 , R1 , . . . , Rn−1 , where Rk is rotation of angle 2πk/n.
     • Reflections S0 , S1 , . . . , Sn−1 , where Sk is reflection about the line through the
       origin and making an angle of πk/n with the horizontal axis.
   The group operation is given by composition of symmetries: if a and b are two
elements in Dn , then a · b = b ◦ a. That is to say, a · b is the symmetry obtained by
applying first a, followed by b.
  The elements of Dn can be thought as linear transformations of the plane, leaving
the given n-gon invariant. This lets us represent the elements of Dn as 2 × 2 matrices,
with group operation corresponding to matrix multiplication. Specifically,                                                       
                               cos(2πk/n) − sin(2πk/n)
                         Rk =                             ,
                                sin(2πk/n)   cos(2πk/n)                                                       
                               cos(2πk/n)    sin(2πk/n)
                         Sk =                             .
                                sin(2πk/n) − cos(2πk/n)
  It is now a simple matter to verify that the following relations hold in Dn :
                                      Ri · Rj   = Ri+j
                                      Ri · Sj   = Si+j
                                      Si · Rj   = Si−j
                                      Si · Sj   = Ri−j
where 0 ≤ i, j ≤ n − 1, and both i + j and i − j are computed modulo n.
  The Cayley table for Dn can be readily computed from the above relations. In
particular, we see that R0 is the identity, Ri−1 = Rn−i , and Si−1 = Si .
MATH 3175                             Handout 2                               Fall 2010
The group D3 . This is the symmetry group of the equilateral triangle, with vertices
on the unit circle, at angles 0, 2π/3, and 4π/3. The matrix representation is given by
                                                √ !                     √ !
                                           1     3                  1     3
                   
               1 0                      − −2                      −√2
       R0 =           ,         R1 = √32            ,    R 2 =           2     ,
               0 1                           − 12                − 23 − 12
                                         2
                                             √ !                           √ !
                                           1   3                    1        3
                     
               1 0                      −                         −    −
       S0 =             ,        S1 = √32 21 ,           S2 =      √2       2    .
               0 −1                                              − 23     1
                                         2    2                           2
while the Cayley table for D3 is:
                              R0    R1    R2      S0   S1   S2
                      R0      R0    R1    R2      S0   S1   S2
                      R1      R1    R2    R0      S1   S2   S0
                      R2      R2    R0    R1      S2   S0   S1
                      S0      S0    S2    S1      R0   R2   R1
                      S1      S1    S0    S2      R1   R0   R2
                      S2      S2    S1    S0      R2   R1   R0
The group D4 . This is the symmetry group of the square with vertices on the unit
circle, at angles 0, π/2, π, and 3π/2. The matrix representation is given by
                                                                      
            1 0                 0 −1              −1 0                   0 1
    R0 =           ,    R1 =            , R2 =              , R3 =             ,
            0 1                 1 0                0 −1                 −1 0
                                                                        
            1 0                 0 1               −1 0                   0 −1
    S0 =             , S1 =           ,    S2 =           ,     S3 =             .
            0 −1                1 0                0 1                  −1 0
while the Cayley table for D4 is:
                        R0    R1    R2    R3      S0   S1   S2    S3
                R0      R0    R1    R2    R3      S0   S1   S2    S3
                R1      R1    R2    R3    R0      S1   S2   S3    S0
                R2      R2    R3    R0    R1      S2   S3   S0    S1
                R3      R3    R0    R1    R2      S3   S0   S1    S2
                S0      S0    S3    S2    S1      R0   R3   R2    R1
                S1      S1    S0    S3    S2      R1   R0   R3    R2
                S2      S2    S1    S0    S3      R2   R1   R0    R3
                S3      S3    S2    S1    S0      R3   R2   R1    R0