2 Biology in Minutes 應考必讀概要 3
應考必讀概要 Solution
標註 x- 軸 ( 橫向 )
和 y- 軸 ( 縱向 ) ，
必讀概要 1 圖像繪畫 (Graph Plotting) 並連同準確單位。
例子 1：線圖 (Line Graph)
Question
An experiment about the rate of photosynthesis of plants A and B
under different light intensity was carried out. Two lamps were placed 回答圖表
50 cm away from a beaker containing an inverted test-tube covering 題時，千萬
plants A and B respectively. The volume of oxygen collected by the 不要遺漏
test-tube per minute at each distance for each plant represents the rate 題目文字
of photosynthesis. The results are as follow. 中提供的
Using the data provided, plot a graph to show the results of the 有用資料。
experiment. (4 marks)
Rate of photosynthesis
Light intensity
應 變 項 (dependent
(mm3 / min) variables) 多展示於第二直
(arbitrary unit)
Plant A Plant B 行 (vertical column) 或之後。
0.3 0 0
0.6 1 0.8 用 y- 軸代表應變 用 x- 軸代表獨立變項 若一曲線圖顯示
獨 立 變 項 (independent
1.5 2.5 1.8 variable) 通常出現在第一直
項 (dependent (independent variable)。 兩條曲線或以上，
2.5 3.5 2.5 行。
variables) 。 考生必須加上圖
解 (key) 說明。
5 4 3.25
8 4 3.25
10 4 3.25
50 Biology in Minutes 必考必讀 51
17 Experimental Set-up II of Respiration 1. After 1 hour, the liquid level inside the U-tube near the grasshopper was
higher than that of the opposite side. The change in liquid level represents
A. the amount of water vapour given out by the grasshopper.
建議答題時間 2 分鐘
Direction: Q uestions 1 and 2 refer to the set-up below which was used to B. the amount of heat produced by the grasshopper.
investigate the rate of respiration of grasshopper. The liquid levels C. the amount of carbon dioxide released by the grasshopper.
on both sides of the U-tube were the same at the beginning of the D. the amount of oxygen absorbed by the grasshopper.
experiment.
Solution
When grasshopper uses oxygen for respiration, it will release similar volume of
carbon dioxide. The carbon dioxide released is absorbed by potassium hydroxide
and this decreases the pressure in the test-tube. The pressure decrease causes the
increase of liquid level. Thus, the change in liquid level eventually represents the
volume of oxygen absorbed.
∴ The answer is D.
2. To show that carbon dioxide is related to the change in liquid level, which of
the following modifications should be made in the above set-up?
A. replacing potassium hydroxide with distilled water
B. removing the grasshopper from the set-up
C. putting the set-up in a water bath at 30℃
D. covering both boiling tubes with black paper
概念速遞 Solution
在歷屆的公開試中，這個實驗裝置曾作出不同形式的修改，例如：將 U 型管內 The rate of respiration is measured by the rate of oxygen absorption that
is reflected by the rate of carbon dioxide produced by grasshopper. The control
的液體轉變為氫氧化鉀溶液 (potassium hydroxide solution) 或碳酸氫鹽指示劑
set-up is used to indicate the carbon dioxide produced by respiration causing the
(hydrogencarbonate indicator) ，但其背後的生物學原理也是相似的。 change in liquid level.
∴ The answer is A.
82 Biology in Minutes 必讀考題 83
42 Seed Germination 43 Density of Rods and Cones on Retina
建議答題時間 1 分鐘 建議答題時間 1 分鐘
The diagram below shows an experiment used to investigate the conditions The graph below shows the densities of two types of photoreceptors, A and B, on
for seed germination. The test-tubes were kept at 15°C and illuminated under the retina.
sunlight. Seeds in test-tube 2 germinated but others did not. 概念速遞
概念速遞 光感細胞 A 和 B 分別是視
錐 細 胞 (cones) 和 視 桿 細
考生應懂得實驗 胞 (rods) 。 視 錐 細 胞 對 強
(experimental set- 光十分敏感，主要集中在黃
up) 和 對 照 裝 置 點 (yellow spot) ， 視 網 膜
(control set-up) 只 邊緣數量很少。視桿細胞對
可以存在一個差別， 昏暗光線較敏感，遍佈視網
Based on the design of the set-up, what conclusion 其結果和結論才會 膜 (retina) ，但黃點和盲點
can be drawn from the results above? Which of the following descriptions about the (blind spot) 均沒有此細胞。
可信，因為兩個裝
(1) Light is necessary for germination. photoreceptors is/are correct?
置 結 果 (dependent
(2) Water is necessary for germination. (1) Photoreceptor A cannot be found at yellow spot.
variable) 的 差 異 是
(3) Oxygen is necessary for germination. 源自於這個差別。 (2) The total number of photoreceptor B is more than that of A.
(3) Photoreceptor B is absent at the blind spot.
A. (1) only B. (3) only
A. (1) only B. (1) and (2) only
C. (1) and (2) only D. (2) and (3) only
C. (2) and (3) only D. (1), (2) and (3)
Solution
Solution
Comparing the results of test-tubes 1 and 2, oxygen is required for seed
germination. Comparing the results of test-tubes 2 and 3, water is required for For (1), photoreceptor B cannot be found at yellow spot.
seed germination. For (3), both photoreceptors A and B are absent at the blind spot.
∴ The answer is D. ∴ The answer is C.
