15.082J/6.855J/ESD.
78J September 14, 2010
Data Structures
Overview of this Lecture
A very fast overview of some data structures that we will be using this semester lists, sets, stacks, queues, networks, trees a variation on the well known heap data structure binary search Illustrated using animation We are concerned with O( ) computation counts, and so do not need to get down to C++- level (or Java level).
Two standard data structures
1 2 3 4 5 6 7 8 9 10 1 0 1 1 0 1 0 1 0 0 Array: a vector: stored consecutively in memory, and typically allocated in advance first This is a singly linked list
cells: hold fields of numbers and pointers to implement lists.
3
Representations of subsets of a set
subset S = {1, 3, 4, 6, 8}
1 2 3 4 5 6 7 8 9 10
Array A 1 0 1 1 0 1 0 1 0 0
first
List L
The choice of data structure depends on what operations need to be carried out.
Example 1:
Creating an empty set
Initialize: subset S =
1 2 3 4
0 0 0 0
n
0 O(n) steps
first
O(1) steps 0
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Example 2:
Is 9 S?
Is x S?
1 2 3 4 5 6 7 8 9 10
1 0 1 1 0 1 0 1 0 0 O(1) steps
first
To determine if 9 S?, one needs to scan the entire list.
4
O(n) steps
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Representing a linked list as an array
first
1 2 3 4 5 6 7 8 9 10 Array: Next 6 8 3 4
If Next(j) is empty, then j is not on the list If Next(j) = , then j is the last element on the list
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Two key concepts
Abstract data types: a descriptor of the operations that are permitted, e.g., abstract data type: set S initialize(S): creates an empty set S add(S, s): replaces S by S {s}. delete(S, s): replaces S by S \{s} IsElement(S, s): returns true if s S etc.
Data structure: usually describes the high level implementation of the abstract data types, and can be analyzed for running time. doubly linked list, etc
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A note on data structures
Preferences Simplicity Efficiency In case there are multiple good representations, we will choose one
Abstract data type: SetOperations
(assume S {1, 2, 3, n}.
S := S := S {j} S := S\{j} returns TRUE if s S if S , returns j for some j S
Operation
initialize(S): add(S, j): delete(S, j): IsElement(S, j): FindElement(S):
Next(S, j) :
if j S, it finds the next element
after j on S (viewed as a list)
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Implementation using doubly linked list
first 2 8 4 2 4
First = 8
1 2 3 4 5 6 7 8 9 10
Next( ) 4 2
1 2 3 4 5 6 7 8 9 10 Prev 8 2
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Add element 5 to the set (in first position)
5 first 2 8 4 2 4
1 2 3 4 5 6 7 8 9 10 Next( ) Prev( ) Temp:= First 4 8 2 2 5 Elt First Temp
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5 8
First:= Elt Prev(Temp): = Elt Prev(Elt): = Next(Elt): = Temp
Add element 5 to the set (in first position)
5 first 2 8 4 2 4
1 2 3 4 5 6 7 8 9 10 Next( ) Prev( ) 4 8 8 2 2 5 Elt 5
First
Temp
8 5
8
Temp:= First
First:= Elt Prev(Temp): = Elt Prev(Elt): = Next(Elt): = Temp
Adding an element to a set takes O(1) steps using this implementation.
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Delete element 2 from the set (assume it is neither in first or last position)
5 first 2 8 4 2 4
1 2 3 4 5 6 7 8 9 10 Next( ) Prev( ) 4 8 8 2 2 5 Elt 2
First
Temp
8 5
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Delete element 2 from the set (assume it is neither in first or last position)
5 first 2 8 2 4
1 2 3 4 5 6 7 8 9 10 Next( ) Prev( ) 4 8 8 2 8 2 4 5 Elt 2
First
8 5
Next(Prev(Elt)):=Next(Elt)
Prev(Next(Elt)):=Prev(Elt) Prev(Elt) := 0 Next(Elt): = 0
Deleting an element from the set takes O(1) steps using this implementation.
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Operations using doubly linked lists
Operation
Number of steps O(n) O(1)
initialize(S): add(S, j):
delete(S, j):
IsElement(S, j): FindElement(S): Next(S, j): Previous(S, j) :
O(1)
O(1) O(1) O(1) O(1)
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Maintaining disjoint subsets of elements
S1 = {8, 2, 4} First(1) First(2) 2 8 2 5 S1 = {5, 7, 1} 4 2 4 7 4 1
1 2 3 4 5 6 7 8 9 10 Next( ) Prev( ) First( ) 4 7 8 8 5
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7 2
1 2 5
Maintaining ordered lists
The doubly linked list is not efficient for maintaining ordered lists of nodes. first 2 4 8
1 2 3 4 5 6 7 8 9 10
Next( )
Prev( )
4
8
2
5
Inserting an element into the set (such as 7) requires finding Prev and Next for 7 (4 and 8), and this requires O(n) time with this implementation.
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Mental Break
Who created the cartoon characters "The Simpson's?
Matt Groening
Which country would you be in if you were to ski in the
Dolomites? Italy Who was the first U.S. president to adopt the informal version of his first name?
Jimmy Carter
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Mental Break
Which country owns the island of Bermuda?
Great Britain
What colors do most color blind persons have trouble
distinguishing? red and green What bird is used as the sign of peace? the dove
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Complete binary tree with n elements
Complete binary trees for storing ordered lists of nodes or arcs. We assume that the number of nodes is n (e.g., 8) and the number of arcs is m. S = {2, 4, 8} n = 8.
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Complete binary tree with n elements
Build up the binary tree. In each parent store the least value of its children.
S = {2, 4, 8}
n = 8.
2 2
4 4
8 8
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Complete binary tree with n elements
Build up the binary tree. In each parent store the least value of its children.
S = {2, 4, 8}
n = 8.
2 2
4 4
8 8
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Complete binary tree with n elements
Build up the binary tree. In each parent store the least value of its children. S = {2, 4, 8} n = 8. 2
2 2
4 4
8 8
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Find greatest element less than j
e.g., find the greatest element less than 7
O(log n) steps for finding greatest element less than j.
start at 7 go up the tree until a node has label < 7. Take left branch. Choose the largest label child going down.
8 5
2 2
4 4 5
8 8
25
Delete an element
e.g., delete element 2 O(log n) steps for an deletion Start at node 2 and update it and its ancestors. 2 4 S = {4, 5, 8} n = 8.
2 4
8 5
2 2
4 4 5
8 8
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Operations using complete binary trees
Operation
Number of steps O(n) O(log n) O(log n) O(1)
initialize(S): add(S, j): delete(S, j): IsElement(S, j):
FindElement(S):
Next(S, j): Previous(S, j) : MinElement(S) MaxElement(S)
O(1)
O(log n) O(log n) O(1) O(log n)
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A network
2 We can view the arcs of a networks as a collection of sets. 3 Let A(i) be the arcs emanating from node i.
e.g., A(5) = { (5,3), (5,4) }
5 4
Note: these sets are usually static. They stay the same.
Common operations: scanning the list A(i) one arc at a time starting at the first arc.
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Storing Arc Lists: A(i)
Operations permitted Find first arc in A(i) Store a pointer to the current arc in A(i) Find the arc after CurrentArc(i) i 1 2 j cij uij
2 25 30 4 15 40 2 45 10 5 45 60 3 23 35 5 15 40
3
4 5
3 25 20
4 35 50
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Scanning the arc list
CurrentArc(i) is a pointer to the arc of A(i) that is being scanned or is the next to be scanned.
CurrentArc(1) CurrentArc(1) CurrentArc(1)
2 25 30
3 23 35
5 15 40
Initially, CurrentArc(i) is the first arc of A(i)
After CurrentArc(i) is fully scanned, CurrentArc(i) := Next(CurrentArc(i))
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Scanning the arc list
CurrentArc(i) is a pointer to the arc of A(i) that is being scanned or is the next to be scanned.
CurrentArc(1) CurrentArc(1) CurrentArc(1)
2 25 30
3 23 35
5 15 40
2 1 3 5
Finding CurrentArc and the arc after CurrentArc takes O(1) steps. These are also implemented often using arrays called forward star representations.
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The Adjacency Matrix (for directed graphs)
b 1 2 c e
1 2
a 4
A Directed Graph
1 2 3 4
0 0 0 0
1 0 1 0 1 0 0 0 0 1 1 0
Have a row for each node
Have a column for each node Put a 1 in row i- column j if (i,j) is an arc
What would happen if (4,2) became (2,4)?
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The Adjacency Matrix (for undirected graphs)
b 1 a c 2 e
1 2
4 degree
1 2 3 4
0 1 0 1
1 0 1 0 1 1 1 0 1 1 1 0
2 3 2 3
An Undirected Graph
Have a row for each node
Have a column for each node Put a 1 in row i- column j if (i,j) is an arc The degree of a node is the number of incident arcs
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Adjacency Matrix vs Arc Lists
Adjacency Matrix? Efficient storage if matrix is very dense. Can determine if (i,j) A(i) in O(1) steps. Scans arcs in A(i) in O(n) steps. Adjacency lists? Efficient storage if matrix is sparse. Determining if (i,j) A(i) can take |A(i)| steps Can scan all arcs in A(i) in |A(i)| steps
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Trees
A tree is a connected acyclic graph. (Acyclic here, means it has no undirected cycles.) If a tree has n nodes, it has n-1 arcs. 3 This is an undirected tree. To store trees efficiently, we hang the tree from a root node. (In principle, any node can be selected for the root.) 4 2 5
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Forest
A forest is an acyclic graph that includes all of the nodes. A subtree of a forest is a connected component of the forest. 10 3 1 6 9 2 5 7 To store trees efficiently, each subtree has a root node. 4 8
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One way of storing subtrees
Lists of children
1 2
4
5 4 2 node parent 5 1 3 2 1 6 3 4 1
5
5 6
6 3
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parent (predecessor) array
On storing trees
Trees are important parts of flow algorithms
3
Some data structures are expressed as trees
The best implementation of trees depends on what operations need to be performed in the abstract data type.
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Stacks -- Last In, First Out (LIFO)
Operations: create(S) push(S, j) pop(S) top(S) 6 5 2 7 3 6 5 2 7 3 creates an empty stack S adds j to the top of the stack deletes the top element in S returns the top element in S
pop(S)
pop(S)
5 2 7 3
push(S,9)
2 7 3
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Queues First in, First Out (FIFO)
Operations: create(Q) Insert(Q, j) Delete(Q) first(Q) 6 6 5 5 5 2 2 2 2 creates an empty queue Q adds j to the end of the queue deletes the first element in Q returns the top element in S 7 7 7 7 3 3 3 3 9
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Delete(Q) Delete(Q) Insert(Q,9)
Binary Search
In the ordered list of numbers below, stored in an array, determine whether the number 25 is on the list.
10 11 12 13 14
13 17 22 24 27 31 33 36 42 45
Left
Right
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Binary Search
In the ordered list of numbers below, stored in an array, determine whether the number 25 is on the list.
10 11 12 13 14
13 17 22 24 27 31 33 36 42 45
Left
Left
Right
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Binary Search
In the ordered list of numbers below, stored in an array, determine whether the number 25 is on the list.
10 11 12 13 14
22 24 27 31 33 36 42 45
Left
Right
Right
After two more iterations, we will determine that 25 is not on the list, but that 24 and 27 are on the list. Running time is O( log n) for running binary search.
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Summary
Review of data structures Lists, sets, complete binary trees, trees queues, stacks binary search Next Lecture: Search algorithms
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15.082J / 6.855J / ESD.78J Network Optimization
Fall 2010
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