BITS Pilani
Hyderabad Campus
Carburettors
Principle of Carburetion
BITS Pilani, Hyderabad Campus
Calculation of the A/F Ratio
Point 1 – inlet to the carburetor ( section A-A)
Point 2 – At the Venturi throat (section B-B)
Assume an adiabatic flow
Velocity at the throat (C2)
√ [()]
ϒ −1
p2 ϒ
C 2= 2 C p T 1 1 −
p1
Theoretical mass flow rate of air
√ [( ) ( ) ]
2 ϒ +1
𝐴2 𝑝1 p2 ϒ p2 ϒ
𝑚˙ 𝑎= 2𝐶 𝑝 −
𝑅√𝑇 1 p1 p1
BITS Pilani, Hyderabad Campus
Calculation of the A/F Ratio
Substitute Cp=1005 J/kg ; ϒ=1.4 ; R=287J/kg K
Actual Mass flow rate of air
𝑚
˙ 𝑎 ,𝑎𝑐𝑡𝑢𝑎𝑙 =𝐶 𝑑, 𝑎 ∗ 𝑚˙ 𝑎
√[( ) ( ) ]
1.43 1.71
𝐴2 𝑝 1 p2 p2
˙ 𝑎 ,𝑎𝑐𝑡𝑢𝑎𝑙 =0.1562
𝑚 𝐶 𝑑 ,𝑎 −
√𝑇 1 p1 p1
Actual mass flow rate of fuel
𝑚˙ 𝑓 ,𝑎𝑐𝑡𝑢𝑎𝑙 =𝐶 𝑑,𝑓 𝐴𝑓 √ 2𝜌 𝑓 ( p1 − p 2 −𝑔𝑧 𝜌 𝑓 )
A/F ratio =
BITS Pilani, Hyderabad Campus
Calculation of the A/F Ratio
√ [( ) ( ) ]
1.43 1.71
p2 p2
−
𝐴 𝐶 𝐴2 p1 p1
= 0.1562∗ 𝑝 1 ∗ 𝑑 , 𝑎
𝐹 𝐶𝑑 , 𝑓 𝐴 𝑓 2 𝑇 1 𝜌 𝑓 ( p 1 − p 2 − 𝑔𝑧 𝜌 𝑓 )
If compressibility of air neglected
˙ a , 𝑎𝑐𝑡𝑢𝑎𝑙 =𝐶 𝑑, 𝑎 𝐴2 √ 2 𝜌 𝑎 ( p1 − p2 )
𝑚
Cd - Coefficient if discharge; P –Pressure; A-cross sectional area; T- Temperature
z – Height of the nozzle exit above the level of fuel in the float bowl; - Density;
Subscripts : a- air ; f- fuel
BITS Pilani, Hyderabad Campus
Problem -1
1. A four cylinder four-stroke engine having diameter
and length of stroke as 100mm and 120mm
respectively is running at 1800 r.p.m. Its carburettor
venturi has a 28mm throat. Assuming co-efficient of
air flow 0.8, density of air 1.2kg/ and volumetric
efficiency of the engine as 75%,determine the
suction at the throat.
BITS Pilani, Hyderabad Campus
Solution-1
Suction at throat ():
Stroke volume =
=
= 0.00377
Actual volume per stroke =
= 0.75 0.00377
= 0.00283
BITS Pilani, Hyderabad Campus
Solution-1
Actual volume suction per second ():
= 0.00283
= 0.0424
=
= 0.05094
BITS Pilani, Hyderabad Campus
Solution-1
Initial T,P are not given, neglecting the compressibility of air
=
0.05094 = 0.8()
= 0.04457 bar.
BITS Pilani, Hyderabad Campus
Problem -2
2. A simple carburettor under a certain condition delivers
5.45kg/h of petrol with an air-fuel ratio of 15. The fuel jet
area is 2 with a co-efficient of discharge of 0.75. If the tip of
the fuel jet is 0.635cm above the level of petrol in the float
chamber and the venture throat coefficient of discharge is
assumed to be 0.8. calculate
(i) The venturi depression necessary to cause air and fuel
flow at the desired rate.
(ii) Venturi throat diameter
(iii) Velocity of air across the venture throat.
Take density of air=1.29kg/ and specific gravity=0.72
BITS Pilani, Hyderabad Campus
Solution -2
1. The Venturi throat depression
BITS Pilani, Hyderabad Campus
Solution -2
2. Venturi throat diameter,
Air flow rate = kg/s
BITS Pilani, Hyderabad Campus
Solution -2
3. Velocity of air across the venture throat
BITS Pilani, Hyderabad Campus
Thank you
BITS Pilani, Hyderabad Campus